Convert categorical data in data frame to weighted adjacency matrix - r

Question

I have the following data frame, call it DF, which is a data frame consisting in three vectors: "Chunk" "Name," and "Frequency." I need to turn it into a NameXName adjacency matrix where Names are considered adjacent when they reside in the same chunk. So for example, in the first lines, Gretel and Friedrich are adjacent because they are both in Chunk2. And the weight of the relationship should be based on "Frequency," precisely the number of times they are co-present in the same chunk, so for the Gretel/Friedrich example, Frequency(Gretel)+Frequency(Friedrich)-1 = 5
Chunk Name Frequency
1 2 Gretel 2
2 2 Pollock 1
3 2 Adorno 1
4 2 Friedrich 4
5 3 Max 1
6 3 Horkheimer 1
7 3 Adorno 1
8 4 Friedrich 5
9 4 Pollock 1
10 4 March 1
11 5 Comte 3
12 7 Jaspers 1
13 7 Huxley 2
14 8 Nietzsche 1
15 8 Sade 2
16 8 Felix 1
17 8 Weil 1
18 8 Western 1
19 8 Lowenthal 1
20 8 Kant 1
21 8 Hitler 1
I started to crack at this by splitting the data frame according to DF$Chunk,
> DF.split<-split(DF, DF$Chunk)
$`2`
Chunk Name Frequency
1 2 Gretel 2
2 2 Pollock 1
3 2 Adorno 1
4 2 Friedrich 4
$`3`
Chunk Name Frequency
5 3 Max 1
6 3 Horkheimer 1
7 3 Adorno 1
$`4`
Chunk Name Frequency
8 4 Friedrich 5
9 4 Pollock 1
10 4 March 1
which I thought got closer, but it returns list items that I am having trouble turning back into workable data frames.
I have also tried to start by turning this into a ChunkXName adjacency matrix:
> chunkbyname<-tapply(DF$Frequency , list(DF$Name,DF$Chunk) , as.character )
with the hopes of multiplying chunkbyname by its transpose to get the NAmeXName matrix, but it seems this is the matrix is too sparse or complex (Error in a %*% b : requires numeric/complex matrix/vector arguments).
Any help getting this data frame into an adjacency matrix greatly appreciated.

Answer 1

Is this what you are looking for?
df3 <- by(df, df$Chunk, function(x){
mm <- outer(x$Frequency, x$Frequency, "+") - 1
rownames(mm) <- x$Name
colnames(mm) <- x$Name
mm
})
df3
# $`2`
# Gretel Pollock Adorno Friedrich
# Gretel 3 2 2 5
# Pollock 2 1 1 4
# Adorno 2 1 1 4
# Friedrich 5 4 4 7
#
# $`3`
# Max Horkheimer Adorno
# Max 1 1 1
# Horkheimer 1 1 1
# Adorno 1 1 1
#
# $`4`
# Friedrich Pollock March
# Friedrich 9 5 5
# Pollock 5 1 1
# March 5 1 1