collection findall in an array list - collections

Question

I am using groovy and I have a collection :
person 1: age - 1, weight - 25
person 2: age - 2, weight - 20
person 3: age - 3, weight - 25
I need to find all persons whose age or weight is in the list of valid age/weight returned by a method called getValidAgeForSchool() or getValidWeightForSchool() ex. ages [2,3] or weight [20,25]
I know there is something like this (not working too)
persons.findAll{ it.age == 2 || it.weight == 20}
but how I can say (like the IN Clause)
persons.findAll {it.age in [2,3] || it.weight in [20,25]}.
I also tried this (ignoring the weight for now) but not returning the list when it is supposed to
persons.age.findAll{ it == 2 || it == 3}
thanks.

Answer 1

The code you have works:
def people = [
[ id: 1, age: 1, weight: 25 ],
[ id: 2, age: 2, weight: 20 ],
[ id: 3, age: 3, weight: 25 ]
]
// This will find everyone (as everyone matches your criteria)
assert people.findAll {
it.age in [ 2, 3 ] || it.weight in [ 20, 25 ]
}.id == [ 1, 2, 3 ]
It also works if you have a list of instances like so:
class Person {
int id
int age
int weight
}
def people = [
new Person( id: 1, age: 1, weight: 25 ),
new Person( id: 2, age: 2, weight: 20 ),
new Person( id: 3, age: 3, weight: 25 )
]
I'm assuming your problem is that you have weight as a double or something?
If weight is a double, you'd need to do:
people.findAll { it.age in [ 2, 3 ] || it.weight in [ 20d, 25d ] }.id
But beware, this is doing double equality comparisons, so if you are doing any arithmetic on the weight, you may fall victim to rounding and accuracy errors