This question already has answers here:
Most efficient list to data.frame method?
(2 answers)
Closed 9 years ago.
I have a list of 3000 vectors in R. How can I create a data frame from the first 1000 elements of this list?
Cheers
You can do:
data.frame(myList[1:1000])
This makes the assumption that the vectors are all the same length. If they are not, values will be recycled.
Related
This question already has answers here:
How do I split a data frame among columns, say at every nth column?
(1 answer)
What is the algorithm behind R core's `split` function?
(1 answer)
Closed 4 years ago.
I have a data frame that is 640 rows by 50,002 columns. I need to split the data columns 2:50001 into 5 equal groups. I have tried the split and sample commands but it gave an error.
This question already has answers here:
Getting the last n elements of a vector. Is there a better way than using the length() function?
(6 answers)
Closed 5 years ago.
I am working in a dataframe in R and I want to access the last 5 objects of a particular column in a dataframe.How do i go about it??
One option is tail(dataframe$column, 5)
This question already has answers here:
How do I make a matrix from a list of vectors in R?
(6 answers)
Combine a list of data frames into one data frame by row
(10 answers)
Closed 5 years ago.
I have a dat frame called crimeLARaw_tbl_final.
One of the columns called location_1.coordinates, is a ‘list’ data type column which contains a list of values:
location_1.coordinates
c(-118.3157, 34.0454)
c(-118.2717, 34.001)
c(-118.2671, 34.0294)
c(-118.4517, 33.967)
How could I bring each value in the list to its own column?
long lat
-118.3157 34.0454
-118.2717 34.001
-118.2671 34.0294
-118.4517 33.967
I have tried with dplyr and stringr but not getting anywhere.
Thank you
This question already has answers here:
Getting the last n elements of a vector. Is there a better way than using the length() function?
(6 answers)
Closed 5 years ago.
suppose I have daily time series data under variable name "prices", but im only interested in the past 100 days. How would i extract the last 100 elements from this variable?
Something equivalent to python's prices[-100:] but for R?
If it's a vector:
tail(prices, 100)
This question already has answers here:
How to get all possible combinations of n number of data set?
(2 answers)
How to calculate combination and permutation in R?
(6 answers)
Closed 5 years ago.
I am getting a tough time in selecting the combinations of factors.
I have a vector as ("Ryan", "Leo", "Jack","Harry","Edd").
I want to get the list of of all combinations taken 3 of the names once.
I want to do it in R. Probably a resultant matrix will help me.
We can use combn
t(combn(vec1, 3))