load an object as values to ObjectChoiceField from sqlite database - sqlite

Question

I can load an object as values into an ObjectChoiceField from a sqlite database. I need an example, I get the values of the database into a vector, but the drop-down list does not accept this type single array.
clase BaseData
public Vector verSectores(){
Vector v=new Vector();
try{
URI uri=URI.create("/SDCard/Databases/app/semana_calculadora.db");
sqliteDB= DatabaseFactory.open(uri);
Statement st= sqliteDB.createStatement("select Sector from sectores_app");
st.prepare();
Cursor c= st.getCursor();
Row r;
while (c.next()){
r=c.getRow();
Sectores s= new Sectores(r.getString(0));
v.addElement(s);
}
st.close();
sqliteDB.close();
}catch(Exception e){}
return v;
}
class Result
public class Resultados extends MainScreen{
private Vector v;
public Resultados(Vector v) {
this.v = v;
for (int i = 0; i < v.size(); i++) {
Sectores s=(Sectores)v.elementAt(i);
//add(new LabelField(s.getName_sector()+ ""));
add(new SeparatorField());
}
}
as I have to pass the value of the vector to ObjectChoiceField?
class Screen
comboFormato = new ObjectChoiceField("Format:", ********, 0){
public void layout(int width, int height){
width=350;
super.layout(getWidth(), getHeight());
super.layout(width, height);
setExtent(width, super.getHeight());
}
public void paint(Graphics g) {
g.setColor(Color.RED);
super.paint(g);
}
};

Answer 1

You can't use a Vector as the basis of an ObjectChoiceField, but you can use an array of Objects, and it is easy to convert a Vector to an array, using, for example, facilities provided by the Arrays class or just brute force as follows:
Sectores [] array = new Sectores [v.size()];
for ( int i = 0; i < array.length; i++ ) {
array[i] = (Sectores)v.elementAt(i);
}
Now you can provide 'array' to your ObjectChoiceField, but be aware the text that the ObjectChoiceField will display for each choice, will be the String generated by using each element's toString() method.