Merge two dataframes with repeated columns - r

Question

I have several .csv files, each one corresponding to a monthly list of customers and some information about them. Each file consists of the same information about customers such as:
names(data.jan)
ID AGE CITY GENDER
names(data.feb)
ID AGE CITY GENDER
To simplify, I will consider only two months, january and february, but my real set of csv files go from january to november:
Considering a "customer X",I have three possible scenarios:
1- Customer X is listed in the january database, but he left and now is not listed in february
2- Customer X is listed in both january and february databases
3- Customer X entered the database in february, so he is not listed in january
I am stuck on the following problem: I need to create a single database with all customers and their respective information that are listed in both dataframes. However, considering a customer that is listed in both dataframes, I want to pick his information from his first entry, that is, january.
When I use merge, I have four options, acording to http://www.dummies.com/how-to/content/how-to-use-the-merge-function-with-data-sets-in-r.html
data <- merge(data.jan,data.feb, by="ID", all=TRUE)
Regardless of which all, all.x or all.y I choose, I get the same undesired output called data:
data[1,]
ID AGE.x CITY.x GENDER.x AGE.y CITY.y GENDER.y
123 25 NY M 25 NY M
I think that what would work here is to merge both databases with this type of join:
Then, merge the resulting dataframe with data.jan with the full outer join. But I don't know how to code this in R.
Thanks,
Bernardo

Answer 1

d1 <- data.frame(x=1:9,y=1:9,z=1:9)
d2 <- data.frame(x=1:10,y=11:20,z=21:30) # example data
d3 <- merge(d1,d2, by="x", all=TRUE) #merge
# keep the original columns from janary (i.e. y.x, z.x)
# but replace the NAs in those columns with the data from february (i.e. y.y,z.y )
d3[is.na(d3[,2]) ,][,2:3] <- d3[is.na(d3[,2]) ,][, 4:5]
#> d3[, 1:3]
# x y.x z.x
#1 1 1 1
#2 2 2 2
#3 3 3 3
#4 4 4 4
#5 5 5 5
#6 6 6 6
#7 7 7 7
#8 8 8 8
#9 9 9 9
#10 10 20 30
This may be tiresome for more than 2 months though, perhaps you should consider #flodel's comments, also note there are demons when your original Jan data has NAs (and you still want the first months data, NA or not, retained) although you never mentioned them in your question.

Answer 2

Try:
data <- merge(data.jan,data.frame(ID=data.feb$ID), by="ID")
although I haven't tested it since no data, but if you just join the ID col from Feb, it should only filter out anything that isn't in both frames

Answer 3

#user1317221_G's solution is excellent. If your tables are large (lots of customers), data tables might be faster:
library(data.table)
# some sample data
jan <- data.table(id=1:10, age=round(runif(10,25,55)), city=c("NY","LA","BOS","CHI","DC"), gender=rep(c("M","F"),each=5))
new <- data.table(id=11:16, age=round(runif(6,25,55)), city=c("NY","LA","BOS","CHI","DC","SF"), gender=c("M","F"))
feb <- rbind(jan[6:10,],new)
new <- data.table(id=17:22, age=round(runif(6,25,55)), city=c("NY","LA","BOS","CHI","DC","SF"), gender=c("M","F"))
mar <- rbind(jan[1:5,],new)
setkey(jan,id)
setkey(feb,id)
join <- data.table(merge(jan, feb, by="id", all=T))
join[is.na(age.x) , names(join)[2:4]:= join[is.na(age.x),5:7,with=F]]
Edit: This adds processing for multiple months.
f <- function(x,y) {
setkey(x,id)
setkey(y,id)
join <- data.table(merge(x,y,by="id",all=T))
join[is.na(age.x) , names(join)[2:4]:= join[is.na(age.x),5:7,with=F]]
join[,names(join)[5:7]:=NULL] # get rid of extra columns
setnames(join,2:4,c("age","city","gender")) # rename columns that remain
return(join)
}
Reduce("f",list(jan,feb,mar))
Reduce(...) applies the function f(...) to the elements of the list in turn, so first to jan and feb, and then to the result and mar, etc.