PROGRAMS USED: Sencha Architect with ExtJS 4.2.
CURRENT SITUATION: My Button use a Start Menu style. The Start Menu is Panel type. I put both the Button and the Start Menu Panel in a Taskbar. Since I can't point the Button to use the Panel as a Menu in Architect (it automatically creates a Menu type when I click create Menu), so I use this code in the Taskbar afterLayout event:
container.getComponent('StartButton').menu = container.getComponent('StartMenuView');
PROBLEMS: The StartMenu displayed correctly when I click the Button, but I can't close it no matter where I click. What did I miss? Any help is appreciated.
Decided to switch to another much simpler approach that I've just figured: Use my "StartMenu" Panel as a Menu Item in my "Start" Button.
Related
I would like to create context menu in my project. On android it's called PopupMenu. On click of button, I have to show the popup with 3 rows and it's clickable event. How I can implement this in my code? Example of this menu here:
http://www.javatpoint.com/images/androidimages/popup2.png
The Xamarin.Forms way to handle this is to call DisplayActionSheet() on the Page.
It's not exactly a popup, but on the other hand it has better chances to be fully displayed and visible on screen if your view can scroll.
I'm very new to pywinauto ans I love it already. But I have a problem:
I want to automate an old software program with pywinauto and can control most of the buttons. But there is a certain button when clicked, there appaers a menu with icons (not the windows style of menu but a custom menu). The button's name is "Toolbar2" so I guess it's not a normal button.
With this code I can click the button I want to. When I use "ctrl.Click(), the button doesn't get clicked, I need to use ClickInput(). With the normal buttons I do can use Click().
w_handle = pywinauto.findwindows.find_windows(title=u'P2-NLTlog013', class_name='TfrmDisplayFilteredData')[0]
window = pwa_app.window_(handle=w_handle)
window.Click()
ctrl = window['ToolBar2']
ctrl.ClickInput()
My question now is: How can I get the names of the items of the hidden menu And click them. I already used this code, but then he gives a 'MatchError'.
window = pwa_app.Window_(best_match='ToolBar2', top_level_only=True).ChildWindow(best_match='PopupMenu').Click()
window.Click()
I don't know what language the software was written in...
Thanks in advance,
Fred
You may get the menu object by window.Menu() and then try to access subitem by menu.Items()
Useful methods: menu_item.Index(), menu_item.SubMenu()
I have a webhierarchicaldatagrid and its first column is a template column which is a hyperlink. So onmouseover on the data of that column I want a small popup window to be open right next to that data so that user can drag the mouse on that popup window. The window contains few links which on click will navigate to another page. I want to know how to get the popup window to be open right next to the data and also how to keep it open only when the mouse is on it. as soon as the mouse is not on the popup I want the popup to close.
qTip is a pretty popular jQuery plugin that can do what you are wanting. Here is the demo page for the type of functionality you are describing:
Demo Fixed tooltips on hover
Here is another link, with 30 popular tooltip plugins:
30 Stylish jQuery Tooltip Plugins For Catchy Designs
I'm trying to design a UI in Qt and I can't find anywhere in the designer a button which can be "droped down" like combobox. What I mean by that is that I would like to have this button with his "default" option choosen so if I like it I would have to just click on it but if I would like to choose different option I would be able to clik the little arrow on the right side of this button and then pick option suitable for me at that moment.
You're looking for a QToolButton that has a set of actions or a menu set on it. From the documentation, the QToolButton::ToolButtonPopupMode...
Describes how a menu should be popped up for tool buttons that has a menu set or contains a list of actions.
Of it's values, the two that I see most frequently are DelayedPopup:
After pressing and holding the tool button down for a certain amount of time (the timeout is style dependant, see QStyle::SH_ToolButton_PopupDelay), the menu is displayed. A typical application example is the "back" button in some web browsers's tool bars. If the user clicks it, the browser simply browses back to the previous page. If the user presses and holds the button down for a while, the tool button shows a menu containing the current history list
And MenuButtonPopup:
In this mode the tool button displays a special arrow to indicate that a menu is present. The menu is displayed when the arrow part of the button is pressed.
I created a Button in MXMXL. On button click, I create a Menu as a child of the Button. I am using an XML datasource. The reason for creating it this way, was due to the amount of custom skinning involved. A popupmenubutton was not an option. Anyway, so my question is this: when clicking the button, the menu is displayed. However, if you click the button again, the menu reopens. I want the menu to close if the user clicks the button a second time. Now, I got it to work by setting a var after opening the menu, and then I check that var on each click to make sure that the menu isn't already open. If true, then it will close the menu, instead of reopening it. This works, until the user clicks away, in which the HIDE event gets dispatched and the menu closes. My hack no longer works.
Any suggestions? I spent hours trying different things. The hardest part is trying to destinguish from that second button click when the menu is open, and when the user clicks away from the menu. They both dispatch the HIDE event.
Help!!!
Have you tried adding another eventlistener to the button...FlexMouseEvent.MOUSE_DOWN_OUTSIDE ? You should then be able to set the preventDefault event to true to stop the event from firing anything else and stop the menu from closing.