(I have not put code in this question since the actual code probably doesn't matter here. If you say it does though then I can edit the question later to put it in.)
I'm new to using winsock2 or any other networking API for that matter. I have a very simple server application and client application in which the server sends a string to the client and then disconnects.
The applications work fine when I use localhost or 127.0.0.1 as the inet_addr() argument, but when I use my "real" IP, the client application just gets WSAECONNREFUSED and the server doesn't see it. I made sure that the port was the same for both applications and that also the protocol was the same.
[Edit] I have come back to this issue after abandoning networking for a while. I think this may actually have something to with the fact I am using a router, and not something in my code.
WSAECONNREFUSED is an active refusal of the connection by the peer or by an intermediate firewall. If it was the peer who issued it, it means you got the IP address or the port wrong, or else you got it right but the server isn't actually running; anyway, nothing is listening at that IP:port. If it was the firewall, adjust it.
Did you use htons() on the port number?
inet_addr() only works with IP address strings, you have to use gethostbyname() or getaddrinfo() to resolve localhost or any other hostname string to an IP address.
WSACONNREFUSED means the connection was actively refused on the remote end that you are trying to connect to.
If the server machine is refusing, that means either there is no socket listening on the requested IP:Port, or that there is one but its queue of pending client connections is full so it cannot accept a new connection at that moment.
If a router is refusing, that usually means the router is not configured to forward inbound connections for the requested IP:Port to a machine on the router's network. If you have a server running behind a router and are trying to connect to it using the router's public IP address, then the router has to be setup for port forwarding.
If a firewall is refusing, that usually means the requested port is not open.
Either way, there is no way for the client to know in code why the connection was refused. All it can do is wait for a period of time and then try again.
Related
I'm trying to build a peer-to-peer game, where each player is both a server and a client with tcp sockets. The sockets can connect fine when I'm using local ip:s, but of course fails when I'm trying to use external ip:s.
But I'm thinking that the players should be able to connect to each other if they just knew the external address + port that the router assigns to them.
Setting up port forwarding is out if the question since I don't have access to the players routers.
I'm thinking of having a server in between, just to be able to read the external address and port of the players, and tell the other player about it so that it can connect.
But I haven't found any info anywhere if that's how port forwarding works. If computer A makes a request from a local address and a port to the server, and the router assigns this address + port to an external address + port, and the server tell computer B which address + port to use. Can computer B use that external address + port to connect to the computer A and start a tcp socket with it? Is there any way to know that this external address + port stays the same when another computer makes a request against them?
The problem is that most people don't expose their PC directly to the internet. They have a router that has an external address. When you send a packet to their IP address, it is going to their router. The router doesn't know where to forward it to and what port to use without port forwarding.
So, getting everyone to enable port forwarding is out of the question, as it should be. A simpler mechanism is to have a server on the internet that you control. It has a firewall with port forwarding setup. The clients are just clients, they connect to the server on a port and send and receive info about the current status of the game. That way, everyone has real-time updates on their local game engine. Plus, this way is much easier to program and implement.
No, TCP doesn't work like that.
The source port that has been used to talk to the rendezvous server will be transient and specific to that particular initial TCP socket connection and can only be used as a destination for return traffic on the same connection from the rendezvous server, and can't be used by a third party to make new inbound connections.
The typical (only?) practical solution when NATs are involved and port forwarding is not available is to have that central server relay all messages bidirectionally between the peers.
Hole punching is what I was looking for.
https://en.wikipedia.org/wiki/Hole_punching_(networking)
When we open a TCP Listening, we use a fixed port, like "9870".
But the clients which connect to this listening, use different ports like "1024, 1025" or other. I don't know what is the name of this port, "client port", "dynamic port" or "ephemeral port"... But I need to know if is possible to change this client port.
Because, like in the second image, it shows the error "Port numbers reused", and I think this is related to this port configuration.
I think if I could configure these ports, the connections of the equipments on my network will be stabilized.
TL;TR: there is usually no need to configure the clients source ports and you can definitely not set the clients source port at the server.
The client can bind to a address+port the same way the server can do and this port is then used as the source port for the connection. But usually this is not done and instead the socket is not specifically bound and a free source port is automatically assigned by the system. The client source port can only be set by the client itself and can not be changed by the server.
Usually it is not possible that a port number gets reused by the client since the OS will not let the client do this. But what you see can happen if the client crashes . After the restart the client is not aware of any connections which were established (and never closed) before the reboot so it will happily use the same source port again. In this case it gets a RST from the server since the new data do not match the old connection.
This can also happen if the client is connected with some router doing NAT and the router crashes. After restart the router is not aware of any previous connections and will thus create new translations which might conflict with old connections.
I've been investigating networking for use in a two-player game I'm writing, and I'm still not clear on when a device must have a port forwarded in order to communicate with the outside world.
From what I've seen in other games, port forwarding is always required in order to host a server, but is not required on the client. In addition, there are other situations, such as skype (which, to my understanding is ultimately client to client), where neither end must forward a port.
So my question is, in over-the-Internet communication, when is and isn't port forwarding necessary, and what steps can i take as a developer to make it so my users don't have to worry about it? Thanks in advance!
Port forwarding is needed when a machine on the Internet needs to initiate a connection to a machine that's behind a firewall or NAT router. If the connection is initiated by the machine behind the firewall, the firewall/router automatically recognizes the reply traffic and sends it to the machine that opened the connection.
But if a packet arrives on the external interface, and it's not a part of such a connection, the router needs to know what to do with it. By default, it will reject it. But if forwarding is configured for the port, that tells it what internal machine to send it to.
Put another way: you need port forwarding if you want to run a server behind the NAT firewall/router, you don't need it if you're just running a client.
There is reason why Skype don't (not always) need manual setting of port forwarding:
When you install Skype, a port above 1024 is chosen at random as the
port for incoming connections. You can configure Skype to use a
different port for incoming connections if you wish, but if you do,
you must open the alternative port manually.
If the port chosen for incoming connections becomes unavailable, by
default ports 80 and 443 will be used as alternatives. If another
application (such as Apache HTTP server or IIS) uses these ports, you
can either configure the application to use other ports, or you can
configure Skype to not use these ports.
Port forwarding is must if you host a server.
You can use same technique as Skype...
I am not sure if there is any other option...
Port forwarding (occurs) when a NAT, firewall or some other device blocks communication on all or some ports.
To answer your question as an example, most commercial routers use NAT to allow multiple people to use the same IP(As view from the outside world) provided by ISPs. Most ISP's use NAT to allow multiple customers to use the same IP(As viewed from the outside world). To get this to work, the NAT changes the internal IP and the port number of a communication to THE(there is only one for the entire sub network) external IP and a new port number. By doing this, the router/isp/ect can tell which internal IP and port each external communication goes to.
Anytime one of the computers communicating over the internet are behind a NAT, port forwarding is required. I'm sure there are way more situations than this, and the solution to each can be quite complicated. But this covers the vast majority.
When some network connection isn't working right, one thing in my bag of tricks is to try opening a telnet connection to it. I don't expect to be able to do anything useful with this connection, but knowing if I can or can't connect is helpful in diagnosing the problem.
So today we had a problem where our app server couldn't open the JDBC connection to our database. However, it works fine when the app server is on the same physical box as the database. Aha, I thought, there must be a firewall blocking that port. So I tried to telnet to that port, and couldn't connect. As a control though, I also telnetted to a database on a box we could connect to and that failed as well. So, the situation is, somehow whatever is listening on that port accepts a JDBC connection from JBoss, but rejects a connect from telnet. How does it distinguish these two connections? Different protocol? Password embedded in the connection request?
Sounds like the database is only accepting connections on the local interface. Is your app server configured to connect to the database via its IP or via either localhost or 127.0.0.1?
To my understanding by serverSocket = new ServerSocket(portNumber) we create an object which potentially can "listen" to the indicated port. By clientSocket = serverSocket.accept() we force the server socket to "listen" to its port and to "accept" a connection from any client which tries to connect to the server through the port associated with the server. When I say "client tries to connect to the server" I mean that client program executes "nameSocket = new Socket(serverIP,serverPort)".
If client is trying to connect to the server, the server "accepts" this client (i.e. creates a "client socket" associated with this client).
If a new client tries to connect to the server, the server creates another client socket (associated with the new client). But how the server knows if it is a "new" client or an "old" one which has already its socket? Or, in other words, how the clients are identified? By their IP? By their IP and port? By some "signatures"?
What happens if an "old" client tries to use Socket(serverIP,serverIP) again? Will server create the second socket associated with this client?
The server listens on an address and port. For example, your server's IP address is 10.0.0.1, and it is listening on port 8000.
Your client IP address is 10.0.0.2, and the client "connects" to the server at 10.0.0.1 port 8000. In the TCP connect, you are giving the port of the server that you want to connect to. Your client will actually get its own port number, but you don't control this, and it will be different on each connection. The client chooses the server port that it wants to connect to and not the client port that it is connecting from.
For example, on the first connection, your client may get client-side port 12345. It is connecting from 10.0.0.2 port 12345 to the server 10.0.0.1 port 8000. Your server can see what port the client is connecting from by calling getpeername on its side of the connection.
When the client connects a second time, the port number is going to be different, say port 12377. The server can see this by calling getpeername on the second connection -- it will see a different port number on the client side. (getpeername also shows the client's IP address.)
Also, each time you call accept on the server, you are getting a new socket. You still have the original socket listening, and on each accept you get a new socket. Call getpeername on the accepted socket to see which client port the connection is coming from. If two clients connect to your server, you now have three sockets -- the original listening socket, and the sockets of each of the two clients.
You can have many clients connected to the same server port 8000 at the same time. And, many clients can be connected from the same client port (e.g. port 12345), only not from the same IP address. From the same client IP address, e.g. 10.0.0.2, each client connection to the server port 8000 will be from a unique client port, e.g. 12345, 12377, etc. You can tell the clients apart by their combination of IP address and port.
The same client can also have multiple connections to the server at the same time, e.g. one connection from client port 12345 and another from 12377 at the same time. By client I mean the originating IP address, and not a particular software object. You'll just see two active connections having the same client IP address.
Also, eventually over time, the combination of client-address and client-port can be reused. That is, eventually, you may see a new client come in from 10.0.0.2 port 12345, long after the first client at 10.0.0.2 port 12345 has disconnected.
Every TCP connection has as identifier the quadruple (src port, src address, dest port, dest address).
Whenever your server accepts a new client, a new Socket is created and it's indipendent from every other socket created so far. The identification of clients is not implictly handled somehow..
You don't have to think sockets as associated to "clients", they are associated with an ip and a port, but there is not direct correlation between these two.
If the same client tries to open another socket by creating a new one you'll have two unrelated sockets (because ports will be different for sure). This because the client cannot use the same port to open the new connection so the quadruple will be different, same client ip, same server ip, same server port but different client port.
EDIT for your questions:
clients don't specify a port because it's randomly choosen from the free ones (> 1024 if I'm not wrong) from the underlying operating system
a connection cannot be opened from a client using the same port, the operating system won't let you do that (actually you don't specify any port at all) and in any case it would tell you that port is already bound to a socket so this issue cannot happen.
whenever the server receives a new connection request it's is considered new, because also if ip is the same port will be different for sure (in case of old packet resend or similar caveats I think that the request will be discarded)
By the way all these situations are clearly explained in TCP RFC here.
I think the question here is why do you care if the client is new or old. What is new and old?
For example, a web browser could connect to a web server to request a web page. This will create a connection so serverSocket.accept() will return a new Socket. Then the connection is closed by the web browser.
Afer a couple of minutes, the end used click on a link in the web page and the browser request a new page to the server. This will create a connection so serverSocket.accept() will return a new Socket.
Now, the web server do not care if this is a new or old client. It just need to server the requested page. If the server do care if the "client" already requested a page in the past, it should do so using some information in the protocol used on the socket. Check out http://en.wikipedia.org/wiki/OSI_model
In this case, the ServerSocket and Socket ack on the transport level. The question "does this client already requested a page on the server" should be answered by information on the session or even application layer.
In the web browser/server example, the http protocol (which is an application) protocol hold information about who is this browser in the parameters of the request (the browser transmit cookie informations with every request). The http server can then set/read cookie information to known if the browser connected before and eventually maintain a server side session for that browser.
So back to your question: why do you care if it's a new or old client?
A socket is identified by:
(Local IP,Local Port, Remote IP,
Remote Port,IP Protocol(UDP/TCP/SCTP/etc.)
And that's the information the OS uses to map the packets/data to the right handle/file descriptor of your program. For some kinds of sockets,(e.g. an non-connected UDP socket)the remote port/remote IP might be wildcards.
By definition, this is not a Java related question, but about networking in general, since Sockets and SeverSockets apply to any networking-enabled programming language.
A Socket is bounded to a local-port. The client will open a connection to the server (by the Operating System/drivers/adapters/hardware/line/.../line/hardware/adapters/drivers/Server OS). This "connection" is done by a protocol, called the IP (Internet Protocol) when you are connected to the Internet. When you use "Sockets", it will use another protocol, which is the TCP/IP-protocol.
The Internet Protocol will identify nodes on a network by two things: their IP-address and their port. The TCP/IP-protocol will send messages using the IP, and making sure messages are correctly received.
Now; to answer your question: it all depends! It depends on your drivers, your adapters, your hardware, your line. When you connect to your localhost machine, you will not get further than the adapter. The hardware isn't necessairy, since no data is actually sent over the line. (Though often you need hardware before you can have an adapter.)
By definition, the Internet Protocol defines a connection as pair of nodes (thus four things: two IP-adresses and two ports). Also, the Internet Protocol defines that one node can only use one port at a time to initiate a connection with another node (note: this only applies for the client, not the server).
To answer your second question: if there are two Sockets: the "new" and the "old". Since, by the Internet Protocol, a connection is a pair of nodes, and nodes can only use one port at a time for a connection, the ports of "new" and "old" must be different. And because this is different, the "new" client can be discriminated from the "old", since the port-number is differently.