Replacement by dictionary possible with AWK or Sed? [closed] - dictionary

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You have a dictionary, Dictionary.txt, and an input file, inFile.txt. The dictionary tells you about possible translations. The solution to a similar problem in unix shell: replace by dictionary seems to hardcode things here that I cannot fully understand. You can come up with better replacement technique than dictionary but AWK/Sed script should be able to read in multiple files, in the simplest case only one dictionary file and one infile.
How to replace elegantly by dictionary with AWK or Sed?
Example
Dictionary.txt
1 one
2 two
3 three
four fyra
five fem
inFile.txt
one 1 hello hallo 2 three hallo five five
Output from the Command, we are after for the command like awk/sed {} Dictionary.txt inFile.txt
one one hello hallo two three hallo fem fem
AWK example where specifically selected the replacements but one-one replacements not working.
awk 'BEGIN {
lvl[1] = "one"
lvl[2] = "two"
lvl[3] = "three"
# TODO: this does not work
# lvl[four] = "fyra"
# lvl[five] = "fem"
# lvl[one] = "one"
# lvl["hello"] = "hello"
# lvl[hallo] = "hallo"
# lvl[three] = "three"
}
NR == FNR {
evt[$1] = $2; next
}
{
print $1, evt[$2], $3, $4, evt[$5], $6, $7, evt[$8], evt[$9]
#TODO: this dos not work, eg. one-one mapping
# print evt[$1], evt[$2], evt[$3], evt[$4], evt[$5], evt[$6], evt[$7], evt[$8], evt[$9]
}' dictionary.txt infile.txt

Answer 1

$ awk 'NR==FNR{map[$1]=$2;next} { for (i=1;i<=NF;i++) $i=($i in map ? map[$i] : $i) } 1' fileA fileB
one one hello hallo two three hallo fem fem
Note that it will compress any chains of contiguous white space to a single blank char. Tell us if that is an issue.

Answer 2

if you have gnu sed, it supports script-file with -f:
`-f SCRIPT-FILE'
`--file=SCRIPT-FILE'
Add the commands contained in the file SCRIPT-FILE to the set of
commands to be run while processing the input.
you could write your substitutions in "c.sed" for example, then
sed -f c.sed file
example c.sed:
s/1/one/g
s/2/two/g
...
EDIT
just now you didn't tag the question with awk, sure, the awk one-liner would be simpler: (with your example)
awk '$1=$2' file
test:
kent$ echo "1 one
2 two
3 three
four fyra
five fem"|awk '$1=$2'
one one
two two
three three
fyra fyra
fem fem

Answer 3

EDIT
This answers the original post. doesn't answer the multiple times edited and restructured question...
on top of that I get a -1 from the OP who asked this question... Damn!
Yes, much simpler in awk :
This will print both column as the value for the second column :
awk '{print $2, $2}' file
If you want to flip first with second column:
awk '{print $2, $1}' file

Answer 4

If ReplaceLeftWithRight_where_you_do_not_replace_things.txt contains pairs of string replacements, where any occurrence of the text in the first column should be replaced by the second column,
1 one
2 two
3 three
four fyra
five fem
then this can trivially be expressed as a sed script.
s/1/one/g
s/2/two/g
s/3/three/g
s/four/fyra/g
s/five/fem/g
and you can trivially use sed to create this sed script:
sed 's%.*%s/&/g%;s% %/%' ReplaceLeftWithRight_where_you_do_not_replace_things.txt
then pass the output of that to a second instance of sed:
sed 's%.*%s/&/%;s% %/%' ReplaceLeftWithRight_where_you_do_not_replace_things.txt |
sed -f - someFile_Where_You_Replace_Things.txt
to replace all the matches in the file someFile_Where_You_Replace_Things.txt and have the output printed to standard output.
Sadly, not all sed dialects support the -f - option to read a script from standard input, but this should work at least on most Linuxes.
Sorry if I misunderstood your problem statement.