I am trying to make a webpage with a navigation functionality EXACTLY like this one: http://www.rex-ny.com/ where you click a list item and its children items appear and stay.
I can do it with hover, but I can't figure out how to make it stay when not hovering.
It seems like the most simple thing is the most difficult to do.
<ul id="menu">
<li>Menu 1
<ul>
<li>Item A</li>
<li>Item B</li>
<li>Item C</li>
</ul>
</li>
<li>Menu 2
<ul>
<li>Item A</li>
<li>Item B</li>
<li>Item C</li>
</ul>
</li>
<li>Menu 3
<ul>
<li>Item A</li>
<li>Item B</li>
<li>Item C</li>
</ul>
</li>
</ul>
Thanks
Here is a jsfiddle http://jsfiddle.net/phzuC/
Here is a CSS only solution as the OP requested, using tabindex
DEMO http://jsfiddle.net/kevinPHPkevin/phzuC/2/
#menu li > ul {
display:none;
}
#menu li:focus > ul {
display:block;
}
li {
outline: 0;
}
EDITED
Here is a jQuery solution should you ever need it. It keeps the submenus open and it's simple to implement. 11 lines of code.
DEMO http://jsfiddle.net/kevinPHPkevin/phzuC/5/
$(document).ready(function() {
$(".nav-top > li").click(function(e) {
if($(this).find('ul').hasClass('expanded')) {
$(this).find('ul').removeClass('expanded').hide();
} else {
$(this).find('ul').addClass('expanded').show();
}
});
$('.nav-top a').click(function(e){
e.preventDefault();
});
});
Here is another CSS only solution that uses either:
Checkboxes if you want the menus to toggle on click
radio buttons if you want the menus to auto close when another is selected
Reference:
CSSTricks: Stuff you can do with the “Checkbox Hack”
The CSS Ninja: CSS Tree
Demo
Basic behavior CSS (the demo has more styling to remove the default list indentation/bullets):
.sideMenu input[type='radio'],
.sideMenu input[type='checkbox'] {
display: none;
}
.sideMenu input[type='radio'] + ul,
.sideMenu input[type='checkbox'] + ul {
position: relative;
display: none;
}
.sideMenu input[type='radio']:checked + ul,
.sideMenu input[type='checkbox']:checked + ul {
display: block;
}
HTML (can be arbitrarily deep):
<nav class="sideMenu">
<ul>
<li>
<label for="menu1">Menu 1</label>
<input id="menu1" type="checkbox" name="menu1">
<ul>
<li>Item A</li>
<li>Item B</li>
<li>Item C</li>
</ul>
</li>
<!-- repeat -->
</ul>
</nav>
Related
I am trying to hide several menu items from my mobile menu using the nth-child selector in CSS.
Here is the source code HTML and CSS: https://jsfiddle.net/jf1r12wh/
The HTML is something like this:
<ul class="mobile">
<li>Item 1</l1>
<li>Item 2</li>
<li>Item 3</li>
<ul><li>Submenu item 1</li>
<li>Submenu item 2</li>
<li>Submenu item 3</li></ul></ul>
I want to use the nth-child (or similar) to hide Item 1 and 2 on the mobile menu, but I don't want it to hide Submenu item 1 and Submenu Item 2, which it's doing.
I'm using this:
.mobile li:nth-child(1){
display: none !important;
}
.mobile li:nth-child(2) {
display: none !important;
}
The problem is that it's applying this to the submenu as well. How can I make it not to do that, and only apply to the main menu items?
All you have to do is show that the rule should only apply to direct children via the use of >
Like this:
.mobile > li:nth-child(2) {
display: none !important;
}
As Paulie_D mentioned in his comment, this is a part of specificity.
EDIT:
Here is a working snippet:
.mobile li:nth-child(1){
color: red;
}
.mobile > li:nth-child(2) {
color: red;
}
<ul class="mobile">
<li>Item 1</li>
<li>Item 2</li>
<li>Item 3</li>
<li>
<ul>
<li>Submenu item 1</li>
<li>Submenu item 2</li>
<li>Submenu item 3</li>
</ul>
</li>
</ul>
For future reference, I would also like to point out that the correct semantic for a ul inside a ul is for the second ul to be inside it's own li
"The children (direct descendants) of a ul element must all be li elements". I've made sure that my code snippet reflects this for you.
We have eBook, in that one of the list has strike through the text as well as the bullet. i can able to strike the text using (text-decoration: line-through;). But i can strike through the bullet in the list, please help me to get a solution?
Here is one way to implement
with Order list
HTML :
<body>
This fiddle is used to demonstrate the list styling with CSS
<ol>
<li> Item 1 </li>
<li> Item 2 </li>
<li> Item 3 </li>
<li> Item 4 </li>
</ol>
</body>
and CSS :
ol li
{
list-style-type: none;
counter-increment: item;
text-decoration:line-through;
}
ol li::before
{
content:counter(item) ".";
text-decoration:line-through;
}
With unordered list, it is a little bit more complicated
HTML:
<body>
This fiddle is used to demonstrate the unordered list styling with CSS
<ul>
<li>item 1</li>
<li>item 2</li>
<li>item 3</li>
<li>item 4</li>
</ul>
</body>
and CSS:
ul{
float:left;
}
li {
list-style: circle;
list-style-position: inside;
margin-top:8px;
}
li:after{
border-top:1px solid red;
display:block;
content:"";
margin-top:-8px;
}
how can i summarize the following css code? The current css code will display all li element as none.
ul.cmpro-accordion > li:not(.cid-2),
ul.cmpro-accordion > li:not(.cid-61){
display: none;
}
It's about specificity.
<ul class="cmpro-accordion">
<li>li text 1</li>
<li class="cid-2">li text 2</li>
<li class="cid-61">li text 3</li>
<li>li text 4</li>
<li>li text 5</li>
</ul>
Css:
ul.cmpro-accordion > li.cid-2,
ul.cmpro-accordion > li.cid-61 {
display: block
}
ul > li:not(.cid-2),
ul > li:not(.cid-61) {
display: none;
}
Example
This question already has answers here:
A CSS selector to get last visible div
(11 answers)
Closed 8 years ago.
Is there a way in CSS to apply CSS rules to a last visible child without knowing the class which makes an element invisible?
Example:
<ul>
<li>Item 1</li>
<li>Item 2</li>
<li>Item 3</li>
<li>Item 4</li>
<li style="display: none">Item 5</li>
<ul>
<style>
ul > li {
border: 1px solid black;
}
// Remove right border from last visible child
// This does not work of course, but this is what I am looking for
ul > li:last-child:not([style="display: none"]) {
border-right: none;
}
</style>
To be clear: I'm looking for a rule-based selector not class-based in CSS not Javascript. But this answer A CSS selector to get last visible div for example does not work. The problem here is that :last-child and :not can not be combined. :last-child([style="display: block"]) also does not work (when li has dispay: block), because it looks at the style attribute and not at the CSS rule.
Example in bootstrap (NOTE: hidden-md is an example, it could also be an other class which uses display:none):
<ul>
<li>Item 1</li>
<li>Item 2</li>
<li>Item 3</li>
<li>Item 4</li>
<li class="hidden-md">Item 5</li>
<ul>
It is not possible with CSS, however you could do this with jQuery. Try this clumsy code.
jQuery:
$('li').not(':hidden').last().addClass("red");
HTML:
<ul>
<li>Item 1</li>
<li>Item 2</li>
<li>Item 3</li>
<li class="hideme">Item 4</li>
</ul>
CSS:
.hideme {
display:none;
}
.red {
color: red;
}
jQuery (previous solution):
var $items = $($("li").get().reverse());
$items.each(function() {
if ($(this).css("display") != "none") {
$(this).addClass("red");
return false;
}
});
From CSS it is not possible :)
maybe if you draw the right border from the left border of next element or next pseudo element , you get half of the job done :http://codepen.io/gc-nomade/pen/ohKwv/
/* basic and naive workaround for borders */
ul {
text-align:center;
}li {
display:inline-block;
padding:0 1em
}
li + li {
border-left:solid;
}
ul:hover li:nth-child(even) {/* test : hide every even lis at once */
display:none;
}
I was wondering if it's possible to style nested unordered lists with CSS only, without using any scripts. The problem is that CSS needs to work for any depth of the list tree.
For example, I have a list:
<ul>
<li>Item 1</li>
<li>Item 2</li>
<li>Item 3</li>
<li class="holder">
<ul>
<li>Item 4</li>
<li>Item 5</li>
<li class="holder">
<ul>
<li>Item 6</li>
<li>Item 7</li>
<li>Item 8</li>
<li class="holder">
<ul>
<li>Item 9</li>
<li>Item 10</li>
<li>Item 11</li>
</ul>
</li>
</ul>
</li>
</ul>
</li>
</ul>
And this is my CSS:
li{
background: gray;
border: 1px solid;
display: block;
margin: 2px;
}
.holder{
background: none;
border: none;
}
/*replace these styles*/
li > ul > li{
background: white;
}
li > ul > li > ul > li{
background: gray;
}
li > ul > li > ul > li > ul > li{
background: white;
}
If node's parent has background A, node should have background B. If node's parent has background B, node should have background A.
Please check : http://jsfiddle.net/bCU34/6/
CSS selectors allow you to select all named elements of a parent node by separating the named element from the parent element with a space. To select all unordered list elements, for example, you would do like below. Notice all ul elements at any depth inherit the style no bullets/margin/padding. In order do style nth layer for an element type, you need to use the parent selector >. See below. I used font color but you could set background images the same way. Note there is no decendant level selector at this time that I know of. This was addressed on another post CSS select nested elements up to N levels deep.
.container ul {
list-style-type: none;
margin: 0;
padding: 0;
}
.container > ul > li {
color: green;
}
.container > ul > li > ul > li {
color: red;
}
.container > ul > li > ul > li > ul > li {
color: blue;
}
<section class="container">
<h1>CSS Nested List Styling</h1>
<ul>
<li>
<h3>Section 1</h3>
<ul>
<li>
<h4>Foo</h4>
<ul>
<li>
<h5>Bar</h5>
</li>
<li>
<h5>Bar</h5>
</li>
</ul>
</li>
<li>
<h4>Foo Bar</h4>
<ul>
<li>
<h5>Bar</h5>
</li>
<li>
<h5>Bar</h5>
</li>
</ul>
</li>
</ul>
</li>
<li>
<h3>Section 2</h3>
<ul>
<li>
<h4>Hello</h4>
<ul>
<li>
<h5>World</h5>
</li>
</ul>
</li>
</ul>
</li>
</ul>
</section>
There isn’t any specific way of doing this currently with Selectors level 3, and the current draft of Selectors level 4 doesn’t seem to add anything either. I had a dig through the www-style mailing list and came up with this post by Lachlan Hunt from April 2005 that suggests that an :nth-descendant() style selector had been considered but never specified.