Can not move file using file object in adobe air - apache-flex

I have an update utility in adobe air that needs to replace an existing file in application directory. but when I try to move file in application directory it throws IOError describing that file can not be deleted.
I did the following;
protected function onBtnTest(event:MouseEvent):void
{
try
{
service = new File(File.applicationDirectory.nativePath + File.separator +
"assets" + File.separator + "oldFile.exe");
servic_ = new File(File.userDirectory.nativePath + File.separator + "newFile.exe");
servic_.addEventListener(Event.COMPLETE, OnMoveComplete);
servic_.addEventListener(IOErrorEvent.IO_ERROR, OnIOError);
if(service.exists)
servic_.moveToAsync(service, true);
}
catch(err:Error)
{
trace(err.message);
}
}
private function OnMoveComplete(event:Event):void
{
trace("Move Complete.");
trace("File Deleted.");
}
private function OnIOError(event:IOErrorEvent):void
{
trace("OnIOError.");
}
it always execute OnIOError function. but when I try to move same file to some other directory it works fine. How can I do this. Thanks

Just one thing: You CAN'T write into the application directory, it's a flex security.
There is nothing you can do, sorry. Think about using another directory. Personally, I use the application storage directory instead.

Related

Glassfish 5: specify document base to store the uploaded files on Server's file system [duplicate]

I read here that one should not save the file in the server anyway as it is not portable, transactional and requires external parameters. However, given that I need a tmp solution for tomcat (7) and that I have (relative) control over the server machine I want to know :
What is the best place to save the file ? Should I save it in /WEB-INF/uploads (advised against here) or someplace under $CATALINA_BASE (see here) or ... ? The JavaEE 6 tutorial gets the path from the user (:wtf:). NB : The file should not be downloadable by any means.
Should I set up a config parameter as detailed here ? I'd appreciate some code (I'd rather give it a relative path - so it is at least Tomcat portable) - Part.write() looks promising - but apparently needs a absolute path
I'd be interested in an exposition of the disadvantages of this approach vs a database/JCR repository one
Unfortunately the FileServlet by #BalusC concentrates on downloading files, while his answer on uploading files skips the part on where to save the file.
A solution easily convertible to use a DB or a JCR implementation (like jackrabbit) would be preferable.
Store it anywhere in an accessible location except of the IDE's project folder aka the server's deploy folder, for reasons mentioned in the answer to Uploaded image only available after refreshing the page:
Changes in the IDE's project folder does not immediately get reflected in the server's work folder. There's kind of a background job in the IDE which takes care that the server's work folder get synced with last updates (this is in IDE terms called "publishing"). This is the main cause of the problem you're seeing.
In real world code there are circumstances where storing uploaded files in the webapp's deploy folder will not work at all. Some servers do (either by default or by configuration) not expand the deployed WAR file into the local disk file system, but instead fully in the memory. You can't create new files in the memory without basically editing the deployed WAR file and redeploying it.
Even when the server expands the deployed WAR file into the local disk file system, all newly created files will get lost on a redeploy or even a simple restart, simply because those new files are not part of the original WAR file.
It really doesn't matter to me or anyone else where exactly on the local disk file system it will be saved, as long as you do not ever use getRealPath() method. Using that method is in any case alarming.
The path to the storage location can in turn be definied in many ways. You have to do it all by yourself. Perhaps this is where your confusion is caused because you somehow expected that the server does that all automagically. Please note that #MultipartConfig(location) does not specify the final upload destination, but the temporary storage location for the case file size exceeds memory storage threshold.
So, the path to the final storage location can be definied in either of the following ways:
Hardcoded:
File uploads = new File("/path/to/uploads");
Environment variable via SET UPLOAD_LOCATION=/path/to/uploads:
File uploads = new File(System.getenv("UPLOAD_LOCATION"));
VM argument during server startup via -Dupload.location="/path/to/uploads":
File uploads = new File(System.getProperty("upload.location"));
*.properties file entry as upload.location=/path/to/uploads:
File uploads = new File(properties.getProperty("upload.location"));
web.xml <context-param> with name upload.location and value /path/to/uploads:
File uploads = new File(getServletContext().getInitParameter("upload.location"));
If any, use the server-provided location, e.g. in JBoss AS/WildFly:
File uploads = new File(System.getProperty("jboss.server.data.dir"), "uploads");
Either way, you can easily reference and save the file as follows:
File file = new File(uploads, "somefilename.ext");
try (InputStream input = part.getInputStream()) {
Files.copy(input, file.toPath());
}
Or, when you want to autogenerate an unique file name to prevent users from overwriting existing files with coincidentally the same name:
File file = File.createTempFile("somefilename-", ".ext", uploads);
try (InputStream input = part.getInputStream()) {
Files.copy(input, file.toPath(), StandardCopyOption.REPLACE_EXISTING);
}
How to obtain part in JSP/Servlet is answered in How to upload files to server using JSP/Servlet? and how to obtain part in JSF is answered in How to upload file using JSF 2.2 <h:inputFile>? Where is the saved File?
Note: do not use Part#write() as it interprets the path relative to the temporary storage location defined in #MultipartConfig(location). Also make absolutely sure that you aren't corrupting binary files such as PDF files or image files by converting bytes to characters during reading/writing by incorrectly using a Reader/Writer instead of InputStream/OutputStream.
See also:
How to save uploaded file in JSF (JSF-targeted, but the principle is pretty much the same)
Simplest way to serve static data from outside the application server in a Java web application (in case you want to serve it back)
How to save generated file temporarily in servlet based web application
I post my final way of doing it based on the accepted answer:
#SuppressWarnings("serial")
#WebServlet("/")
#MultipartConfig
public final class DataCollectionServlet extends Controller {
private static final String UPLOAD_LOCATION_PROPERTY_KEY="upload.location";
private String uploadsDirName;
#Override
public void init() throws ServletException {
super.init();
uploadsDirName = property(UPLOAD_LOCATION_PROPERTY_KEY);
}
#Override
protected void doGet(HttpServletRequest req, HttpServletResponse resp)
throws ServletException, IOException {
// ...
}
#Override
protected void doPost(HttpServletRequest req, HttpServletResponse resp)
throws ServletException, IOException {
Collection<Part> parts = req.getParts();
for (Part part : parts) {
File save = new File(uploadsDirName, getFilename(part) + "_"
+ System.currentTimeMillis());
final String absolutePath = save.getAbsolutePath();
log.debug(absolutePath);
part.write(absolutePath);
sc.getRequestDispatcher(DATA_COLLECTION_JSP).forward(req, resp);
}
}
// helpers
private static String getFilename(Part part) {
// courtesy of BalusC : http://stackoverflow.com/a/2424824/281545
for (String cd : part.getHeader("content-disposition").split(";")) {
if (cd.trim().startsWith("filename")) {
String filename = cd.substring(cd.indexOf('=') + 1).trim()
.replace("\"", "");
return filename.substring(filename.lastIndexOf('/') + 1)
.substring(filename.lastIndexOf('\\') + 1); // MSIE fix.
}
}
return null;
}
}
where :
#SuppressWarnings("serial")
class Controller extends HttpServlet {
static final String DATA_COLLECTION_JSP="/WEB-INF/jsp/data_collection.jsp";
static ServletContext sc;
Logger log;
// private
// "/WEB-INF/app.properties" also works...
private static final String PROPERTIES_PATH = "WEB-INF/app.properties";
private Properties properties;
#Override
public void init() throws ServletException {
super.init();
// synchronize !
if (sc == null) sc = getServletContext();
log = LoggerFactory.getLogger(this.getClass());
try {
loadProperties();
} catch (IOException e) {
throw new RuntimeException("Can't load properties file", e);
}
}
private void loadProperties() throws IOException {
try(InputStream is= sc.getResourceAsStream(PROPERTIES_PATH)) {
if (is == null)
throw new RuntimeException("Can't locate properties file");
properties = new Properties();
properties.load(is);
}
}
String property(final String key) {
return properties.getProperty(key);
}
}
and the /WEB-INF/app.properties :
upload.location=C:/_/
HTH and if you find a bug let me know

uploaded image not appearing on new page until I refresh cache [duplicate]

I read here that one should not save the file in the server anyway as it is not portable, transactional and requires external parameters. However, given that I need a tmp solution for tomcat (7) and that I have (relative) control over the server machine I want to know :
What is the best place to save the file ? Should I save it in /WEB-INF/uploads (advised against here) or someplace under $CATALINA_BASE (see here) or ... ? The JavaEE 6 tutorial gets the path from the user (:wtf:). NB : The file should not be downloadable by any means.
Should I set up a config parameter as detailed here ? I'd appreciate some code (I'd rather give it a relative path - so it is at least Tomcat portable) - Part.write() looks promising - but apparently needs a absolute path
I'd be interested in an exposition of the disadvantages of this approach vs a database/JCR repository one
Unfortunately the FileServlet by #BalusC concentrates on downloading files, while his answer on uploading files skips the part on where to save the file.
A solution easily convertible to use a DB or a JCR implementation (like jackrabbit) would be preferable.
Store it anywhere in an accessible location except of the IDE's project folder aka the server's deploy folder, for reasons mentioned in the answer to Uploaded image only available after refreshing the page:
Changes in the IDE's project folder does not immediately get reflected in the server's work folder. There's kind of a background job in the IDE which takes care that the server's work folder get synced with last updates (this is in IDE terms called "publishing"). This is the main cause of the problem you're seeing.
In real world code there are circumstances where storing uploaded files in the webapp's deploy folder will not work at all. Some servers do (either by default or by configuration) not expand the deployed WAR file into the local disk file system, but instead fully in the memory. You can't create new files in the memory without basically editing the deployed WAR file and redeploying it.
Even when the server expands the deployed WAR file into the local disk file system, all newly created files will get lost on a redeploy or even a simple restart, simply because those new files are not part of the original WAR file.
It really doesn't matter to me or anyone else where exactly on the local disk file system it will be saved, as long as you do not ever use getRealPath() method. Using that method is in any case alarming.
The path to the storage location can in turn be definied in many ways. You have to do it all by yourself. Perhaps this is where your confusion is caused because you somehow expected that the server does that all automagically. Please note that #MultipartConfig(location) does not specify the final upload destination, but the temporary storage location for the case file size exceeds memory storage threshold.
So, the path to the final storage location can be definied in either of the following ways:
Hardcoded:
File uploads = new File("/path/to/uploads");
Environment variable via SET UPLOAD_LOCATION=/path/to/uploads:
File uploads = new File(System.getenv("UPLOAD_LOCATION"));
VM argument during server startup via -Dupload.location="/path/to/uploads":
File uploads = new File(System.getProperty("upload.location"));
*.properties file entry as upload.location=/path/to/uploads:
File uploads = new File(properties.getProperty("upload.location"));
web.xml <context-param> with name upload.location and value /path/to/uploads:
File uploads = new File(getServletContext().getInitParameter("upload.location"));
If any, use the server-provided location, e.g. in JBoss AS/WildFly:
File uploads = new File(System.getProperty("jboss.server.data.dir"), "uploads");
Either way, you can easily reference and save the file as follows:
File file = new File(uploads, "somefilename.ext");
try (InputStream input = part.getInputStream()) {
Files.copy(input, file.toPath());
}
Or, when you want to autogenerate an unique file name to prevent users from overwriting existing files with coincidentally the same name:
File file = File.createTempFile("somefilename-", ".ext", uploads);
try (InputStream input = part.getInputStream()) {
Files.copy(input, file.toPath(), StandardCopyOption.REPLACE_EXISTING);
}
How to obtain part in JSP/Servlet is answered in How to upload files to server using JSP/Servlet? and how to obtain part in JSF is answered in How to upload file using JSF 2.2 <h:inputFile>? Where is the saved File?
Note: do not use Part#write() as it interprets the path relative to the temporary storage location defined in #MultipartConfig(location). Also make absolutely sure that you aren't corrupting binary files such as PDF files or image files by converting bytes to characters during reading/writing by incorrectly using a Reader/Writer instead of InputStream/OutputStream.
See also:
How to save uploaded file in JSF (JSF-targeted, but the principle is pretty much the same)
Simplest way to serve static data from outside the application server in a Java web application (in case you want to serve it back)
How to save generated file temporarily in servlet based web application
I post my final way of doing it based on the accepted answer:
#SuppressWarnings("serial")
#WebServlet("/")
#MultipartConfig
public final class DataCollectionServlet extends Controller {
private static final String UPLOAD_LOCATION_PROPERTY_KEY="upload.location";
private String uploadsDirName;
#Override
public void init() throws ServletException {
super.init();
uploadsDirName = property(UPLOAD_LOCATION_PROPERTY_KEY);
}
#Override
protected void doGet(HttpServletRequest req, HttpServletResponse resp)
throws ServletException, IOException {
// ...
}
#Override
protected void doPost(HttpServletRequest req, HttpServletResponse resp)
throws ServletException, IOException {
Collection<Part> parts = req.getParts();
for (Part part : parts) {
File save = new File(uploadsDirName, getFilename(part) + "_"
+ System.currentTimeMillis());
final String absolutePath = save.getAbsolutePath();
log.debug(absolutePath);
part.write(absolutePath);
sc.getRequestDispatcher(DATA_COLLECTION_JSP).forward(req, resp);
}
}
// helpers
private static String getFilename(Part part) {
// courtesy of BalusC : http://stackoverflow.com/a/2424824/281545
for (String cd : part.getHeader("content-disposition").split(";")) {
if (cd.trim().startsWith("filename")) {
String filename = cd.substring(cd.indexOf('=') + 1).trim()
.replace("\"", "");
return filename.substring(filename.lastIndexOf('/') + 1)
.substring(filename.lastIndexOf('\\') + 1); // MSIE fix.
}
}
return null;
}
}
where :
#SuppressWarnings("serial")
class Controller extends HttpServlet {
static final String DATA_COLLECTION_JSP="/WEB-INF/jsp/data_collection.jsp";
static ServletContext sc;
Logger log;
// private
// "/WEB-INF/app.properties" also works...
private static final String PROPERTIES_PATH = "WEB-INF/app.properties";
private Properties properties;
#Override
public void init() throws ServletException {
super.init();
// synchronize !
if (sc == null) sc = getServletContext();
log = LoggerFactory.getLogger(this.getClass());
try {
loadProperties();
} catch (IOException e) {
throw new RuntimeException("Can't load properties file", e);
}
}
private void loadProperties() throws IOException {
try(InputStream is= sc.getResourceAsStream(PROPERTIES_PATH)) {
if (is == null)
throw new RuntimeException("Can't locate properties file");
properties = new Properties();
properties.load(is);
}
}
String property(final String key) {
return properties.getProperty(key);
}
}
and the /WEB-INF/app.properties :
upload.location=C:/_/
HTH and if you find a bug let me know

Windows Store Application Place SQLite File in LocalState Folder

I am building a Windows 8 application using sql-net and mvvmcross for data access to a sqlite database. This would be applicable to any Win-8 or Win-Phone app.
I need to install an existing sqlite file on app start.
When using the connection you use syntax such as this
public FlashCardManager(ISQLiteConnectionFactory factory, IMvxMessenger messenger)
{
_messenger = messenger;
_connection = factory.Create("Dictionary.sqlite");
_connection.CreateTable<FlashCardSet>();
_connection.CreateTable<FlashCard>();
}
public void CreateCard(FlashCard flashCard)
{
_connection.Insert(flashCard);
}
That connection creates a file in: C:\Users\USER\AppData\Local\Packages\793fd702-171e-474f-ab3b-d9067c58709b_ka9b83fa3fse2\LocalState
My application uses an existing sqlite database file that I have created. I need to place it in this folder when the application is installed. How would I go about doing this?
Thanks,
JH
Make sure you have the database file you want your app to start off with in one of your apps folders (as in the folders visible in visual studios solution explorer). For this example I'll call this folder "Assets"
All you need to do then is copy this file to the LocalState folder the first time your app runs. This can be done in App.xaml.cs
private async void InitializeAppEnvironment()
{
try
{
if (!(await AppHelper.ExistsInStorageFolder(AppHelper.localFolder, dbName)))
{
StorageFile defaultDb = await AppHelper.installedLocation.GetFileAsync("Assets\\" + dbName);
await defaultDb.CopyAsync(AppHelper.localFolder);
}
}
catch (Exception e)
{
System.Diagnostics.Debug.WriteLine(e);
}
}
I made an AppHelper class to simplify accessing the app data folders, here's the parts I used above:
static class AppHelper
{
public static StorageFolder installedLocation = Windows.ApplicationModel.Package.Current.InstalledLocation;
public static StorageFolder localFolder = ApplicationData.Current.LocalFolder;
public static async Task<bool> ExistsInStorageFolder(this StorageFolder folder, string fileName)
{
try
{
await folder.GetFileAsync(fileName);
return true;
}
catch (FileNotFoundException)
{
return false;
}
}
}
For a more detailed response on MVVM cross I found the current discussion about cross platform file placement in this discussion: Link
The current thought is that you have to inject platform specific code for this sort of functionality.

obtain resources relative path in WebContent

I have built a dynamic web project MusicStore in Eclipse, and I want to access an xml file located in WebContent/_res/Songs.xml. The method I used to access it in a regular Java class[not a servlet] is:
URL url = this.getClass().getClassLoader().getResource("/");
String filePath = url.getFile();
String webAppLoc=new File(filePath).getParentFile().getParent();
String resLoc=webAppLoc+"/_res/Songs.xml";
It seems to me that this is very cumbersome. Is there a better, more efficient way? thanks!
Here you can try this to access file
public class Test {
public static void main(String[] args){
//This gives me path for the current working directory.
String fileName = System.getProperty("user.dir");
//This gives me path for the file that is residing in folder called "xml_tutorial".
File file = new File(fileName + "../../xml_tutorial/sample.xlsx" );
System.out.println(file.getCanonicalPath());
}
}

Ignore file attributes with MSDeploy?

When using msdeploy to do a sync operation, one of the things that MSDeploy checks to determine if a file should be synced or not is the attributes on the file (readonly, archive, etc.). If the attributes are different between the two copies of the file, then the file will be synced. Is there a way to tell MSDeploy to ignore file attributes when determining if a file should be synced or not?
It is possible, however, not merely on the command line. You'd have to build a custom DeploymentRuleHandler, like this:
namespace CustomRuleHandlers
{
using Microsoft.Web.Deployment;
[DeploymentRuleHandler]
internal class IgnoreFileAttributesRuleHandler : DeploymentRuleHandler
{
public override int CompareAttribute(DeploymentSyncContext syncContext, DeploymentObject destinationObject, DeploymentObjectAttribute destinationAttribute, DeploymentObject sourceObject, DeploymentObjectAttribute sourceAttribute, int currentComparison)
{
if ((destinationObject.Name.Equals("filePath", StringComparison.Ordinal))
&& destinationAttribute.Name.Equals("attributes", StringComparison.Ordinal))
{
return 0;
}
return currentComparison;
}
public override string Description
{
get { return "Ignores file attributes when determining if a file should be synched or not."; }
}
public override string FriendlyName
{
get { return "IgnoreFileAttributes"; }
}
public override string Name
{
get { return "IgnoreFileAttributes"; }
}
public override bool EnabledByDefault
{
get { return false; }
}
}
}
Compile that into an assembly (targeting .Net 3.5 for WebDeploy v2!) and put the assembly into the "Extensibility" subfolder in the WebDeploy folder (normally, C:\Program Files\IIS\Microsoft Web Deploy V2\Extensibility).
Then, you can easily leverage your custom rule when running msdeploy from the command-line by adding this argument:
-enableRule:IgnoreFileAttributes
Of course, that assembly needs to be present on both, the source and the target machine, of a sync operation.
Unfortunately, there's no easier way of getting there!

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