This question already has answers here:
Sass - Manipulate inherited property?
(4 answers)
Closed 9 years ago.
I am trying to create a top level <a> styling for the for my application using sass. Most of the links across the site are green so I have this as a style. (I'm using compass for the darken function)
a {
color: green;
&:hover {
color: darken(green, 10%);
}
}
However, in certain cases the links aren't green. In these cases I'll have to specify both the text color and the hover color, otherwise it will default to hovering to green. I am wondering if there is a way to do this DRYer. Ideally I would be able to get the parent classes color, like so.
a {
color: green;
&:hover {
color: darken(parent(color), 10%);
}
}
That way the hover will always default to whatever the color of the specific is. Does this make sense? Is something like this possible? If not, what's the best way to handle this? A Mixin?
Thanks!
What you ask is not possible with SASS. SASS does not build an object model with all elements and properties (it is impossible without HTML).
A mixin is an appropriate solution for a reusable case, but for an ad-hoc case it is an overkill.
Just use a variable:
a {
$link-color: green;
color: $link-color;
&:hover {
color: darken($link-color, 10%);
}
}
Note that you can move the variable into a separate partial where you store all your variables.
I'd use a mixin:
#mixin link($color) {
a { color: $color};
&:hover { color: darken($color, 10%) };
}
.foo {
#include link(green);
}
Rendered CSS:
.foo a { color: green; }
.foo a:hover { color: #004d00; }
Related
I am trying to reuse a background-color definition of the parent rule set in background-color definition of a child rule set. However, Less evaluates the lookup as a recursion.
I would like this:
.button {
background-color: whitesmoke;
&:hover {
background-color: darken($background-color, 10%);
}
}
to work the same way as this:
#the-color: whitesmoke;
.button {
background-color: #the-color;
&:hover {
background-color: darken(#the-color, 10%);
}
}
but without the need for an extra variable.
The documentation isn't very specific on this. Am I missing something or is this just not possible?
I am aware of other solutions to changing the tint of a button on hover (e.g. using the filter property).
EDIT 1:
The closest I can get to is this. I just need it to be background-color instead of color.
.button {
background-color: whitesmoke;
&:hover {
color: darken($background-color, 10%);
}
}
The problem is the lookup of $background-color evaluates to the background-color of the same row (which, I think, doesn't ever make sense) and refuses to compile instead of evaluating to a rule in the parent rule set or just simply evaluating to one of the previous rows.
Assuming that I have the following HTML:
<div class="navigation__item">
<span class="navigation__item__icon"></span>
</div>
I want to apply some rules to an icon, when hovering an item, which can be described with the following CSS:
.navigation__item__icon {
color: black;
}
.navigation__item:hover .navigation__item__icon {
color: white;
}
I can achieve this using the following SCSS:
.navigation__item {
&:hover {
.navigation__item__icon { <-- here
color: white;
}
}
&__icon {
color: black;
}
}
Here, is there any way to avoid writing navigation__item? Something like "parent rule \ element".
I like Sass for logical structure so that if I want to rename the whole navigation block with elements, I can simply change navigation class name in the root, and everything is renamed. This case breaks this advantage.
Update: Actually, I have found a way to do this without using {} braces. & can be repeated more than once:
.navigation__item {
&:hover &__icon {
color: white;
}
&__icon {
color: black;
}
}
It is great, but it doesn't make much sense if I have many rules and rules for &:hover itself. The question is still open - is this possible to access sibling element definition from within the {} block.
In Stylus there is a Partial reference but I don't know anything similar in SASS. One solution could be using a variable for the parent selector:
.navigation__item {
$selector: &;
&:hover {
#{$selector}__icon {
color: white;
}
}
&__icon {
color: black;
}
}
Is usefull is you change navigation__item class for another.
EDIT: I had used a wrong example, it's OK now.
This question already has answers here:
Sass - Manipulate inherited property?
(4 answers)
Closed 7 years ago.
Or maybe there's preprocessor solution.
Suppose you have 20 buttons. Each with a different color.
The colors are set like this:
button {
background: red;
}
So you can write something like this
button:hover {
this.background: darken(10%);
}
And this will darken each button's background color.
Instead of writing color codes for each button which is red, blue, green, etc... And this can be applied also to more CSS properties.
Without JS of course.
Do they plan to introduce it? Is there a solutin via SASS/LESS/Stylus ?
There is nothing like that in Sass, but you can use a mixin like this code:
#mixin addColor($color) {
background: $color;
&:hover {
background: darken($color, 10%);
}
}
.foo {
#include addColor(red);
}
.anotherFoo {
#include addColor(blue);
}
I should have asked this in my previous question (CSS style declaration reusage), but I didn't think of it at the time. Since that question is answered, I'll start a new one.
I am trying to create color palette in CSS that will be used through out my application.
For example:
.blue { color: #434544; }
.green { color: #G99933; }
I do not want to define colors anywhere else in my CSS. The problem I am running into is how do i use the .blue style when, for example, I need a background-color definition? Take a look at this:
.editor { background-color: #434544 }
I want to reference back to the .blue style instead of defining it here again. How can I do that?
UPDATE
I found the perfect solution for my question:
Chirpy -> http://chirpy.codeplex.com/
There's no way to do this in native CSS. You should look into pre-processing your CSS, since all those pre-processors have support for variables.
Here's what it looks like using (scss-flavored) SASS:
$blue: #434544;
$green: #G99933;
.blue { color: $blue; }
.green { color: $green; }
.editor { background-color: $blue }
I would like to have a property reference its "self", I am not sure how to do this in LESS. Heck I am having a hard time crafting the wording of the question. Basically I would like to accomplish the following:
a:visited {
color: lighten(color, 10%);
}
Where a's color could vary based on its container div.
So I might have the following selectors:
div#blue-text a {
color: #00F;
}
div#black-text a {
color: #000;
}
Once I visit the links, I should have a lighter blue and gray link texts respectively.
Note: this is a very simple scenario, but I have much more complicated needs, and if there is a clean way to do this, then I would be a happy camper.
Basically, since you're going to set the parent's color in LESS as well, you would store the color in a variable and reference it.
Here is an example:
#column1Color: #aaaaaa;
#column2Color: #bbbbbb;
#column3Color: #cccccc;
.columns {
// set the color of the first column
.column:nth-child(1) {
background-color: #column1Color;
a {
color: lighten(#column1Color, 10%);
}
}
// set the color of the second column
.column:nth-child(2) {
background-color: #column2Color;
a {
color: lighten(#column2Color, 10%);
}
}
// set the color of the third column
.column:nth-child(3) {
background-color: #column3Color;
a {
color: lighten(#column3Color, 10%);
}
}
}
LESS would not know what the color of the hyperlink is unless you "told" it. Same goes for the browser, it would not know the color unless it executes all the linked CSS files.
So, what you need (if I understood you correctly) can not be achieved the way you're thinking about it.