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I currently am trying to use a linear-gradient from CSS3 as the background of a site, and from what I can tell, am following the spec to comply with Internet Explorer right, but I can't tell what's not working here.
body {
padding: 0px;
margin: 0px 0px 0px 0px;
background: rgb(0,0,0); /* Old browsers */
background: -moz-linear-gradient(top, rgba(0,0,0,1) 0%, rgba(26,42,132,1) 40%, rgba(33,29,155,1) 50%, rgba(26,42,132,1) 60%, rgba(0,0,0,1) 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(0,0,0,1)), color-stop(40%,rgba(26,42,132,1)), color-stop(50%,rgba(33,29,155,1)), color-stop(60%,rgba(26,42,132,1)), color-stop(100%,rgba(0,0,0,1))); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, rgba(0,0,0,1) 0%,rgba(26,42,132,1) 40%,rgba(33,29,155,1) 50%,rgba(26,42,132,1) 60%,rgba(0,0,0,1) 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, rgba(0,0,0,1) 0%,rgba(26,42,132,1) 40%,rgba(33,29,155,1) 50%,rgba(26,42,132,1) 60%,rgba(0,0,0,1) 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(bottom, rgba(0,0,0,1) 0%,rgba(26,42,132,1) 40%,rgba(33,29,155,1) 50%,rgba(26,42,132,1) 60%,rgba(0,0,0,1) 100%); /* IE10+ */
background: linear-gradient(to bottom, rgba(0,0,0,1) 0%,rgba(26,42,132,1) 40%,rgba(33,29,155,1) 50%,rgba(26,42,132,1) 60%,rgba(0,0,0,1) 100%); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#000000', endColorstr='#000000',GradientType=0 ); /* IE6-9 */
}
We are using following CSS in one of our projects and it works on Chrome, Firefox and IE11.
background-image: -webkit-gradient(linear, 0 0, 0 100%, from(#000), to(transparent));
background-image: -webkit-linear-gradient(#000, transparent);
background-image: -moz-linear-gradient(#000, transparent);
background-image: -o-linear-gradient(#000, transparent);
background-image: linear-gradient(#000, transparent);
See this Fiddle as well: http://jsfiddle.net/3ck72fbc/
I am new for html and css. Here Is My css code:
background: -moz-linear-gradient(center top, #F9F9F9, #F0F0F0) repeat scroll 0 0 rgba(0, 0, 0, 0);
this background color effect not working in IE and Chrome How to change this code to work.
Vendor prefixes are no longer needed for gradients.
background: linear-gradient(to bottom, #F9F9F9, #F0F0F0);
Done.
The -moz- prefix is only used by Firefox - so you need to copy the exact line to use in the other browser-familys:
background: linear-gradient(center top, #F9F9F9, #F0F0F0) repeat scroll 0 0 rgba(0, 0, 0, 0);
background: -webkit-linear-gradient(center top, #F9F9F9, #F0F0F0) repeat scroll 0 0 rgba(0, 0, 0, 0);
background: -o-linear-gradient(center top, #F9F9F9, #F0F0F0) repeat scroll 0 0 rgba(0, 0, 0, 0);
You are doing a gradient only for Mozilla, you need to do it for IE and Chrome separately
Please check this site out as it will do the code for you but, provide comments so you get an idea how each browser responds to each line of code
http://www.colorzilla.com/gradient-editor/
Example code
background: #1e5799; /* Old browsers */
background: -moz-linear-gradient(top, #1e5799 0%, #2989d8 50%, #207cca 51%, #7db9e8 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,#1e5799), color-stop(50%,#2989d8), color-stop(51%,#207cca), color-stop(100%,#7db9e8)); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, #1e5799 0%,#2989d8 50%,#207cca 51%,#7db9e8 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, #1e5799 0%,#2989d8 50%,#207cca 51%,#7db9e8 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(top, #1e5799 0%,#2989d8 50%,#207cca 51%,#7db9e8 100%); /* IE10+ */
background: linear-gradient(to bottom, #1e5799 0%,#2989d8 50%,#207cca 51%,#7db9e8 100%); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#1e5799', endColorstr='#7db9e8',GradientType=0 ); /* IE6-9 */
Check the documentation https://developer.mozilla.org/en-US/docs/Web/CSS/linear-gradient. It depends on javascript engine used by browsers.
As it states the doc for crossbrowser:
.grad {
background-color: #F07575; /* fallback color if gradients are not supported */
background-image: -webkit-linear-gradient(top, hsl(0, 80%, 70%), #bada55); /* For Chrome and Safari */
background-image: -moz-linear-gradient(top, hsl(0, 80%, 70%), #bada55); /* For old Fx (3.6 to 15) */
background-image: -ms-linear-gradient(top, hsl(0, 80%, 70%), #bada55); /* For pre-releases of IE 10*/
background-image: -o-linear-gradient(top, hsl(0, 80%, 70%), #bada55); /* For old Opera (11.1 to 12.0) */
background-image: linear-gradient(to bottom, hsl(0, 80%, 70%), #bada55); /* Standard syntax; must be last */
}
-moz-linear-gradient is for Mozilla Browser(Firefox). You should use webkit-linear-gradient for chrome.
-moz is a prefix for Mozilla Firefox, please check this site:
http://colorzilla.com/gradient-editor/
and look through the code and comments:
background: #1e5799; /* Old browsers */
background: -moz-linear-gradient(top, #1e5799 0%, #2989d8 50%, #207cca 51%, #7db9e8 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,#1e5799), color-stop(50%,#2989d8), color-stop(51%,#207cca), color-stop(100%,#7db9e8)); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, #1e5799 0%,#2989d8 50%,#207cca 51%,#7db9e8 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, #1e5799 0%,#2989d8 50%,#207cca 51%,#7db9e8 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(top, #1e5799 0%,#2989d8 50%,#207cca 51%,#7db9e8 100%); /* IE10+ */
background: linear-gradient(to bottom, #1e5799 0%,#2989d8 50%,#207cca 51%,#7db9e8 100%); /* W3C */
I have the following CSS:
.main {
padding-right: 15px;
padding-left: 15px;
/* IE9 SVG, needs conditional override of 'filter' to 'none' */
background: url(data:image/svg+xml;base64,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)top;
background: -moz-linear-gradient(top, rgba(229,229,229,1) 0%, rgba(255,255,255,0) 100%)top; /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(229,229,229,1)), color-stop(100%,rgba(255,255,255,0)))top; /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, rgba(229,229,229,1) 0%,rgba(255,255,255,0) 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, rgba(229,229,229,1) 0%,rgba(255,255,255,0) 100%)top; /* Opera 11.10+ */
background: -ms-linear-gradient(top, rgba(229,229,229,1) 0%,rgba(255,255,255,0) 100%)top; /* IE10+ */
background: linear-gradient(to bottom, rgba(229,229,229,1) 0%,rgba(255,255,255,0) 100%) top; /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#e5e5e5', endColorstr='#00ffffff',GradientType=0 )top; /* IE6-8 */
background-size: Auto 200px;
background-repeat: repeat-x;
background: url(data:image/svg+xml;base64,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)bottom;
background: -moz-linear-gradient(top, rgba(229,229,229,1) 0%, rgba(255,255,255,0) 100%)bottom; /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(229,229,229,1)), color-stop(100%,rgba(255,255,255,0)))bottom; /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, rgba(229,229,229,1) 0%,rgba(255,255,255,0) 100%)bottom; /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, rgba(229,229,229,1) 0%,rgba(255,255,255,0) 100%)bottom; /* Opera 11.10+ */
background: -ms-linear-gradient(top, rgba(229,229,229,1) 0%,rgba(255,255,255,0) 100%)bottom; /* IE10+ */
background: linear-gradient(to bottom, rgba(229,229,229,1) 0%,rgba(255,255,255,0) 100%) bottom; /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#e5e5e5', endColorstr='#00ffffff',GradientType=0 )bottom; /* IE6-8 */
background-size: Auto 200px;
background-repeat: repeat-x;
padding-top: 50px;
min-height:600px;
}
And here is a live example: http://jsfiddle.net/ZtJmM/
I want that one gradient be at the top, and one at the bottom of the element. Is that possible?
Thanks!
Yes, use them in the same statement like:
background: linear-gradient(to bottom, rgba(229,229,229,1) 0%,
rgba(255,255,255,0) 100%) top,
linear-gradient(to bottom, rgba(229,229,229,1) 0%,
rgba(255,255,255,0) 100%) bottom;
I am trying to get The degree of color of the box in the picture
http://i46.tinypic.com/iefcpl.png
i like the box in the picture and i want make similar one
This is my code, and i can't make similarty
<style>
.b{
background:-moz-linear-gradient(top, #fff, #ebebeb);
height:25px;
border:1px #efefef solid;
}
</style>
<div class="b">
</div>
.b{
background: #ffffff; /* Old browsers */
background: -moz-linear-gradient(top, #ffffff 0%, #ebebeb 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,#ffffff), color-stop(100%,#ebebeb)); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, #ffffff 0%,#ebebeb 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, #ffffff 0%,#ebebeb 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(top, #ffffff 0%,#ebebeb 100%); /* IE10+ */
background: linear-gradient(top, #ffffff 0%,#ebebeb 100%); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#ffffff', endColorstr='#ebebeb',GradientType=0 ); /* IE6-9 */
height:25px;
border:1px #DDDDDD solid;
}
I used Ultimate CSS Gradient Generator to generate the gradient for all browsers.
DEMO
Other browers like chrome shows up fine. IE9 just shows the gradients no images.
Code CSS
body {
background:
url('../images/adventure/background.png')
background: url('../images/adventure/background.png'), -moz-linear-gradient(top, rgba(255,255,255,0) 0%, rgba(255,255,255,0.4) 40%, rgba(149,147,160,1) 100%); /* FF3.6+ */
background: url('../images/adventure/background.png'), -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(255,255,255,0)), color-stop(40%,rgba(255,255,255,0.4)), color-stop(100%,rgba(149,147,160,1))); /* Chrome,Safari4+ */
background: url('../images/adventure/background.png'), -webkit-linear-gradient(top, rgba(255,255,255,0) 0%,rgba(255,255,255,0.4) 40%,rgba(149,147,160,1) 100%); /* Chrome10+,Safari5.1+ */
background: url('../images/adventure/background.png'), -o-linear-gradient(top, rgba(255,255,255,0) 0%,rgba(255,255,255,0.4) 40%,rgba(149,147,160,1) 100%); /* Opera 11.10+ */
background: url('../images/adventure/background.png'), -ms-linear-gradient(top, rgba(255,255,255,0) 0%,rgba(255,255,255,0.4) 40%,rgba(149,147,160,1) 100%); /* IE10+ */
background: url('../images/adventure/background.png'), linear-gradient(top, rgba(255,255,255,0) 0%,rgba(255,255,255,0.4) 40%,rgba(149,147,160,1) 100%); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#00ffffff', endColorstr='#9593a0',GradientType=0 ); /* IE6-8 */
You need a closing semicolon (;) on the first background like this:
background: url('../images/adventure/background.png');