Advanced Custom Fields/PHP issue - wordpress

I apologize if this is answered elsewhere, but I'm having an issue with this ACF code here: http://goo.gl/9onrFN I want the client to be able to add a portfolio site link (if applicable) to the artist page and the link would say "View Artist's Website" and the link would take the user to the artist's site in a new window. How would I go about not making this text not visible, unless there was a url entered into the custom field on the post? Here's the code:
<p><?php the_field('contact_phone_number'); ?><br />
or <?php the_field('contact_email'); ?><br />
View Artist's Website</p>
Thanks in advance!

You can check if a ACF field is set with:
if(get_field('artist_website')) {
the_field('artist_website');
}
Using the_field will simple echo the contents of your field, whereas get_field will return the value which is a lot more helpful. For example you could write the above code as:
Note: get_field simple returns the value of the field, if you want to check if a valid url has been entered you will have to use a regular expression.
Below is your code with an if statement performing an empty field check:
<p>
<?php the_field('contact_phone_number'); ?><br />
or <?php the_field('contact_email'); ?>
<?php if(get_field('artist_website')) { ?>
<br />View Artist's Website
You may find your code easier to read by pre-setting your variables and including HTML in the echo:
<p>
<?php
$contact_phone_number = get_field('contact_phone_number');
$contact_email = get_field('contact_email');
$artist_website = get_field('artist_website');
echo "{$contact_phone_number}<br />";
echo "or <a href='mailto:{$contact_email}'>{$contact_email}</a><br/ >;
if($artist_website) {
echo "View <a href='{$artist_website}' target='_blank'>Artist's website</a>";
}
?>
</p>

Related

How to show multiple Google Maps with different locations created in Advance Custom Fields Wordpress plugin?

I have created two Maps fields in Advanced Custom Fields (ACF) Plugin in its field group area, please check the screenshot
But on the front end when I try to add the code as per Google Maps custom field code only one Map is showing not the second one https://www.advancedcustomfields.com/resources/google-map/
Ah yes, I'm able to figure this out. There has no need of any other different settings, just need to add one more field in ACF fields group area and show that field in the front end by doing the same settings as did on the first field but just change the location variable name and pass the second field value in it. Below is the complete code example to show the first and second map in different HTML elements.
First Map:
<?php
$location = get_field('map');
if( !empty($location) ):
?>
<div class="acf-map">
<div class="marker" data-lat="<?php echo $location['lat']; ?>" data-lng="<?php echo $location['lng']; ?>"></div>
</div>
<?php endif; ?>
Second Map:
<?php
$location_second = get_field('map_second');
if( !empty($location_second) ):
?>
<div class="acf-map">
<div class="marker" data-lat="<?php echo $location_second['lat']; ?>" data-lng="<?php echo $location_second['lng']; ?>"></div>
</div>
<?php endif; ?>
As I have created two map fields in ACF plugin, first map field's name is Map and Second map field name is Map Second, so these will be used as map and map_second in code as given above.
I hope you have ACF Pro version :)
then you can use repeater field
Create repeater field "locations" then inside only one field with name "location" and use code from example "Render multiple markers onto a map"

Wordpress ACF Plugin - wp_get_attachment_image function doesn't work with ACF Options Page?

I'm trying to get an image asset shown on the front-end using the wp_get_attachment_image WordPress function, but it doesn't seem to work with my options page on ACF.
Here is my code:
<?php
$image = get_field('logo', 'option');
$size = 'full'; // (thumbnail, medium, large, full or custom size)
if( $image ) {
echo wp_get_attachment_image( $image, $size );
}
?>
Which looks like this on the back-end:
The picture you see above is an options page in ACF and when I try to query that image into the wp_get_attachment_image function, it doesn't work. However, when I run this code:
<img data-src="<?php the_field('logo', 'option'); ?>" alt="footer logo" class="lazyload" />
which is within an image tag, it works just fine.
I copied and pasted what was shows on the ACF docs located here (Basic Display ID), but it's not showing the image on the front-end.
Anything I'm missing guys?
Thanks a lot!
Return value in field should be Image ID. See Screenshot
What is the return value type you used? Image Array, Image URL, Image ID
And you need to get a field like this:
get_field('logo'); why do you add option?
More info here:
https://www.advancedcustomfields.com/resources/image/
wp_get_attachment_image requires the first parameter to be an image ID. In your case, if you are seeing the image using the code <img data-src="<?php the_field('logo', 'option'); ?>" alt="footer logo" class="lazyload" /> then get_field('logo', 'option') is returning the url of the image.. not the ID which is what you need if you are using wp_get_attachment_image.
What you need to do is change the Return Value of your logo field to Image ID.
Then you might have to re upload the image.
And also change this code <img data-src="<?php the_field('logo', 'option'); ?>" alt="footer logo" class="lazyload" /> to <img data-src="<?php echo wp_get_attachment_url(get_field('logo', 'option')); ?>" alt="footer logo" class="lazyload" />
ACf plugin returns value as you have set the return type.
If you have sent the return type as Image array then :
$image[0] -> full or $image[0][$full] or $image[$full] depending on the number of image uploaded.
If you have set return type as Image url:
<img src="<?php $image; ?>"> would do the work.
If you are setting return type as Image Id:
$img2 = wp_get_attachment_image_src(get_post_thumbnail_id($image),
$full); echo $img2[0];
I guess above methods will surely help you out.
Thanks

How to submit form in custom wp plugin

I am trying to make a wp plugin to show a list from table,which can be edited and
deleted .
I am succeed in showing a list in plugin.but not getting how to update .
can any one tell me what will be the path in form action,
,and after form get submited where does it goes ie on which page.
on which page should i write update query
You can place all your form handlers on the same page, but be sure to place them before any output. Like this:
<?
if (isset($_POST['my-form-submit'])) : // check if form is submitted
/*
Here goes update process etc
*/
endif;
get_header();
?>
<form action="<?php echo $_SERVER['REQUEST_URI']; ?>" method="POST">
/* Here come form fields */
<input type="submit" name="my-form-submit" value="Update" />
</form>
<?php
get_footer();
?>

Home Page Only Footer

I have a blog, http://sweatingthebigstuff.com and I would like to add an extra line in the footer which will display only from the homepage. I found this code, but it is not working for me. Do I have the wrong syntax or is there something else I can try to get this to work?
<?php if ( is_home() ) { ?>
text
<?php } ?>
Here is where footer.php is called
<?php include (TEMPLATEPATH . '/sidebar1.php'); ?>
<div class="cleared"></div>
<?php get_footer(); ?>
And here is the footer code:
text 2
Contact | Disclaimer | Privacy StatementCopyright © 2009-2010 Sweating The Big Stuff. All Rights Reserved.
and then some sitemeter crap.
is_home() sets a global var that doesn't seem to reset itself or re-evaluate, wp kinda strange.
Try putting wp_reset_query() at the end start of your if statement code
Actually, it'll be better to call it before as we can ensure the queries are reset
<?php wp_reset_query();
if ( is_home() ) { ?>
text
<?php } ?>
Now that the php is working, ideally you'd want the code above.
text
I just did a view source and I can plainly see the php code, which shouldn't be visible since it is meant to be parsed server side. The following shouldn't be there in the view source.... wrong file being edited?
<p>
<?php if ( is_home() ) { ?>
text
<?php } ?>
<wp_reset_query()>
<br />
<br />
The footer.php file should be located in wp-content/themes/nameofyourtheme folder
is_home() is a method that should return true or false. You need to implement this method somewhere. If blogspot doesn't implement this method for you, you need to do it yourself. For your website I think this function would do what you want:
<?php
function is_home(){
$r = $_SERVER['REQUEST_URI'];
return $r == '/' || $r == '' || $r == '/index.php';
}
if(is_home()) {
?>
text
<?php } ?>
And where you want the footer, put:
<?php include 'footer.php'; ?>
instead of the line:
<?php get_footer(); ?>
I believe your problem is that get_footer() is reading the footer as text, so it isn't executing the PHP beforehand. If you do it this way you can add as much PHP in the header as you want.
There is nothing wrong with your syntax, and when I view your page source, I see " text "
What is the file extension of your footer page? if it is "footer.php" then I shouldn't see the opening and closing terms for php (). php won't run unless the file extension is ".php"
as to a previous answer:
<?php wp_reset_query();?> should go BEFORE <?php if(is_home()){?>text<?php } ?> in this scenario. is_home() depends on a loop being present on the page. Maybe somewhere you used a custom query, or one of your plugins used a custom query that upset the default query vars. Like I said, use the reset statement before your if statement.
You need to modify the code to include a check for is_front_page() like so:
<?php
$ishomepage = ( is_home() || is_front_page() );
switch( $ishomepage )
{
case true :
echo 'Your homepage-only snippet of text goes here';
break;
case false :
default :
// Do nothing... or do something else...
break;
}
?>
Reference: WordPress Codex: is_front_page()
Default WP installations don't have a homepage defined, it uses your index.php and checks for other templates like a home.php template as a starting point (home.php only if your theme has it.) Here's a diagram from their online docs that shows how their hierarchy works: WordPress Template Hierarchy.
By default, WordPress shows your most recent posts on the front page
of your site. But many WordPress users want to have a static front
page or splash page as the front page instead. This "static front
page" look is common for those who wish to not have a "blog" look to
their site, giving it a more CMS (content management system) feel.
If you want to know how to set a static homepage, read this article and follow the instructions: Creating a Static Frontpage. When you set a static front page, is_home() will work as expected.

Wordpress if else requirements for comments

I am not sure where to start, but I want to add in a symbol or change the css for the comments for registered users. Show a difference between non registered user comments and registered user comments.
How would I go about adding this to my wordpress website?
<div class="commentdetails">
<p class="commentauthor"><?php comment_author_link() ?></p>
<?php if ($comment->comment_approved == '0') : ?>
<em>Your review is pending approval by gsprating staff.</em>
<?php endif; ?>
<p class="commentdate"><?php comment_date('F jS, Y') ?>
IP/Hostname: <small>(coming soon)</small>
<?php edit_comment_link('Edit Comment','',''); ?>
</p>
I want to add make it so that the entire class is a different color if the user is a registered logged in user.
Here's an all php version of Saladin's code using the standard if/else sysntax:
<?php
if ($comment->user_ID) {
echo "<div class='comment_registeredUser'>";
}
else { // The user is not logged in
echo "<div class='commentdetails'>";
}
?>
Putting all the code in php has fixed execution errors for me. Of course, that may have been because I was doing something else wrong.
As comments are displayed in the wp_list_comments() function, you will need to edit the code there. The easiest way to achieve this is to use a simple if/else statement checking whether or not the comment has a user ID associated with it. If it does, that means the comment was made by a registered user.
Of course, as well as this, you will need to create a new CSS class to give the distinction. Here is some example code:
<?php if($comment->user_ID) : ?>
<div class="comment_registeredUser"> <!-- Or whatever you decide to call the CSS class -->
<?php else : ?> <!-- The commenter isn't a registered user -->
<div class="commentdetails">
<?php endif; ?>
// Then include the rest of the code as is
The $comment->user_ID variable will return a true if the comment poster is a registered user and was logged in when they posted the comment. The code above will assign your custom CSS class to the div if it does indeed return true. If not, it will simply apply the standard class and styling.
There is also a really good tutorial for developing themes over at the Wordpress Codex. Definitely worth having a read through if you are unsure on what you need to do to create/edit your WordPress theme.
Edit: Cleaned up the answer and better explained the correct logic.

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