When I Hover on #main, Style of #box and #box2 want to change. But it is not working.
Html code is
<div id="main">Main</div>
<div id="box">Text</div>
<div id="box1" >Text1</div>
Css is
#main:hover + #box,#box1 {
background-color: green;
}
Here is the demo link
I'd suggest the following:
#main:hover + #box,
#main:hover ~ #box1 {
/* CSS */
}
JS Fiddle demo.
The problems you had, originally, were the two selectors:
#main:hover + #box,
#box1 {
background-color: green;
}
The first of which worked, unfortunately the comma separates entire selectors, it doesn't give a comma-separated list of descendants/siblings to be affected. So the #box1 was always background-colored, rather than just on :hover of #main.
The combinators I've used are the adjacent-sibling combinator (+) and the general-sibling combinator (~), the latter of which will affect any later sibling of #main that has the given id of box1.
The second rule, written with ~ could be rewritten by specifying the exact sequence of elements using multiple (in this case two) adjacent-sibling combinators, to give:
#main:hover + #box,
#main:hover + #box + #box1 {
/* CSS */
}
But this does become increasingly fragile over time, and maintenance becomes more trying when the HTML structure changes, or new elements are inserted between the relevant elements.
References:
CSS Selectors.
probably cleaner to use a class and the general sibling selector (~):
HTML:
<div id="main">Main</div>
<div class="box">Text</div>
<div class="box" >Text1</div>
CSS:
#main:hover ~ .box {
/* CSS */
}
Related
Is this possible, with CSS ?
Apply this rule if .div1 doesn't exist:
.div2{
property: value;
}
like
<div class="div1">
...
</div>
<div class="div2">
<!-- it exists, so do nothing -->
</div>
and
<div class="div2">
<!-- it doesn't exist, apply the css -->
</div>
Exists, or doesn't exist? Your question confuses me :)
Apply style to .div2 if .div1 exists:
Option 1: .div2 follows directly after .div1
.div1 + .div2 {
property: value;
}
Option 2: .div2 follows .div1 as a sibling:
.div1 ~ .div2 {
property: value;
}
Style .div2 without .div1:
It's a bit of a hack, but you could do the reverse.
Style .div2 normally, and then override the styling with the selectors above.
If .div1 doesn't exist, .div2 gets the normal styling.
.div2 {
background: #fff;
}
.div1 + .div2 {
background: #f00; /* override */
}
/* or */
.div1 ~ .div2 {
background: #f00; /* override */
}
If you know the 'unstyled' styles of the div, you could use a css sibling selector to style it one way if it follows .div1, and the 'plain' way if it doesnt - ie
.div2 {
/* styled however you want */
}
.div1 + .div2 {
/* 'plain' styling */
}
See the fiddle. Try removing div1 to see div2 as it would be styled without div1
Generally speaking, no, you can't do that.
But you may 'hack' it using CSS selectors, I'm referring to to:
+ .something selector
~ .something selector
I'd use the second selector, which is the "general sibling" selector.
Given the HTML you posted you can apply the style to the .div2 class and then reset it using the .div1 ~ .div2 selector.
So something like this:
.div1 {
color: red;
}
.div2 {
color: blue;
}
.div1 ~ .div2 {
color: black;
}
In this way, with the first HTML snippet the div2 will be black and with the second snippet it will be blue.
NO
With CSS alone, the if conditions which check the availability of an element, is not possible. You should use JavaScript, (jQuery is recommended).
Notes: With CSS you can check some conditions of an element, like checking if an element has an attribute (like input[type=text]), or checking if an element is the first element of a list (like p:first-child), etc. But you can't check anything from the element's sibling elements, or ancestors. Also you can't check the negative conditions most of the times.
No, this is not possible. But you can create class "div3" and in your code determine whether DIV1 exists and in that case apply the "div3" class instead of "div2"
Say I have a parent div with three child divs inside and I want to give each child a different background colour, can this be done with only one nth-child selector - my parent div has a class of "parent" and the three children have classes of "child1", "child2", "child3".
Thanks.
Yoy can't set 3 background-color in one selector (the 2 override by last defenition) as in image
I recommand you learn about selector in css:https://www.w3schools.com/cssref/css_selectors.asp
and more learn here(thanks to #Mosh Feu):https://developer.mozilla.org/en-US/docs/Web/CSS/Descendant_selectors
and: https://developer.mozilla.org/en-US/docs/Web/CSS/Child_selectors
SO you have to do it as below:
.parent .child1{
background-color:red;
}
.parent .child2{
background-color:orange;
}
.parent .child3{
background-color:blue;
}
<div class="parent">
<div class="child1">one </div>
<div class="child2">tow </div>
<div class="child3">three </div>
</div>
You won't be able to do this with just one rule and just one selector.
In CSS, every rule applies a specific set of styles to all the elements that match its selector(s). This is a fundamental aspect of how CSS works. You can't have different declarations in a single rule apply selectively to specific elements — they will all just get overridden, leaving you with just one winning declaration that gets applied to all the elements that are matched. This is true even if you have multiple selectors in the same rule, and even if you use :nth-child() instead of class selectors.
For example,
.child1, .child2, .child3 {
background-color: red;
background-color: blue;
background-color: yellow;
}
is treated as
.child1, .child2, .child3 {
background-color: yellow;
}
which applies a yellow background to all three children, both despite and because of the fact that all three children are listed. The same holds true with .parent > :nth-child(1), .parent > :nth-child(2), .parent > :nth-child(3) as the selector.
Therefore, if you want to style three elements differently, you will need three rules, one for each element:
.child1 {
background-color: red;
}
.child2 {
background-color: blue;
}
.child3 {
background-color: yellow;
}
Again, this is true regardless of what selector you use to actually reach each child element. The point is that each set of style declarations (property: value pairs) needs to appear in its own set of selector {} rules.
Why do you want to use nth selector if your child elements use different classes? Nth-selector should be used for elements that haven't got class selector or where the content is dynamic. In this particular case you don't need nth selector, just use
.parent .child1 {
background-color: #d3d3d3;
}
.parent .child2 {
background-color: #000;
}
<div class="parent">
<div class="child1">child1</div>
<div class="child2">child2</div>
</div>
JS Fiddle
Without altering the html is there any way to target the last .red class using CSS?
<div class="row">
<div class="red">Red</div>
<div class="red">Red</div>
<div class="red">Target Me With CSS???</div>
<div class="blue">Blue</div>
<div class="blue">Blue</div>
<div class="blue">Blue</div>
</div>
here's what I've tried :
.row > div{
display:inline-block;
padding:10px;
}
.row .red{
background-color:#770000;
color:#fff;
}
.row .red:first-child{
background-color:#440000;
color:#fff;
}
/*have tried :last-of-type too*/
.row .red:last-child{
background-color:#FF0000;
}
.row div:last-child{
background-color:#0000BB;
}
I don't believe there is a way to do that without using JS.
The closest you can get is to target the 3rd item with:
.row div:nth-child(3) {
background: chucknorris;
}
You can include a qualifier to only target the third child if it is .red like so:
.red:nth-child(3) {
background: chucknorris;
}
http://jsfiddle.net/s76J3/3/
Unfortunately, you can't do this with CSS alone. Here are a few other SO questions that are related to yours:
Using :last-child with class selector
CSS last-child selector: select last-element of specific class, not last child inside of parent?
However, if your last .red sometimes is in different positions, and you can't change the HTML at all, then you will have to rely on some light JS/jQuery.
$(function() {
$('.row .red').last().addClass('last-red-class');
});
You can use it to add another class to the last .red, and just reference that in your CSS.
http://jsfiddle.net/s76J3/2/
HTH
:last-of-type description
The :last-of-type CSS pseudo-class represents the last sibling of its type in the list of children of its parent element.
and syntax
element:last-of-type { style properties }
So, what really going in your example is that the browser selected the right div element but it was not the last div element of its parent; therefore, nothing was applied. To test this, change all your .red class div into a span and do the following
.row span:last-of-type{
background-color:#FF0000;
}
then you will get a working code.
http://jsfiddle.net/s76J3/4/
Source: https://developer.mozilla.org/en-US/docs/Web/CSS/:last-of-type
I’m trying to learn a bit more about the CSS3 transitions and “cool stuff”. So I have some nifty animations on my site, and I did some google research that helped me out quite a bit.
I wanted to select an element outside of my hover element. I found out that using the + sign you can target an element that comes after the hover element. A small example (in LESS):
header{
display: inline-block;
div#bg_2{
color:#000;
}
div#container{
float:left;
&:hover{
& + nav {
ul{
opacity: 0;
}
li{
.transition(1200ms, ease-in-out);
margin-left:-100px;
}
}
}
}
nav{
height:30px;
}
}
So this example allows me to give a transition to the element after the hover element. But my question is, is it possible to do the reverse? To target the element before the hover element? In the example, the bg_2 element.
The ! subject selector in the CSS Selectors 4 draft specification would be a way to select a previous element. It proposes that instead of writing .one + .two { … } to style .two, you could write !.one + .two { … } to style .one.
However, ! is currently not implemented in any browser. And the CSS Selectors 4 specification can still change, because it is a draft. Also, the spec currently marks the ! subject selector as being in the “complete” profile, which is meant to be used by JavaScript, but not in the “fast” profile, which CSS must use.
Since you can’t use !, there is currently no way to select what you want with pure CSS.
See also this answer about there being no parent selector, which links to the CSS specifications where you can find all defined selectors.
CSS alone can't currently achieve what you're after. We have sibling selectors (+ and ~), but the element being targeted must come after the first element.*
As a simple example, check out this fiddle. Given this markup:
<p class="one">One</p>
<p class="two">Two</p>
and this CSS:
.one ~ .two { background: red; }
.two ~ .one { background: green; }
You might expect .one to end up green and .two red. In reality, only .two receives a background colour, because the second line is trying to style an element that comes earlier in the DOM.
* + is the adjacent sibling combinator, ~ the general sibling combinator. See this CSS Tricks article for details. They are very similar: + will only target an element that is directly after another specific element whereas ~ will target a sibling that appear anywhere after it.
Example:
<div class="one">
</div>
<div class="two">
</div>
Let's say I want to change the background color of .two when I :hover over .one, is it possible to do that kind of selection?
Let's say I want to change the background color of .two when I :hover over .one, is it possible to do that kind of selection?
Yes, one option is to use
.one:hover + .two {
background: olive; /* + will select an immediate sibling */
}
http://jsfiddle.net/N6peE/1/
That would only work if .two is adjacent to .one, so what if they're not adjacent to one another?
You would just use the general sibling combinator, ~
.one:hover ~ .two {
background: olive;
}
http://jsfiddle.net/N6peE/2/
If they're next to each other (as you've shown them), then you can use the adjacent (+) selector:
.one:hover+.two { ... }
If they're a bit further away, but still siblings - ie at the same level in the DOM tree - then you can use the sibling (~) selector:
.one:hover~.two { ... }
If they're further apart than that, then you may struggle -- CSS doesn't make it easy at the moment.
.one:hover + .two{
background-color: red;
}
This works only when .two is appears after .one in your source