has anyone tried to use a log4j.xml reference within a WinRun4j service configuration. here is a copy of my service.ini file. I have tried many configuration combinations. this is just my latest attempt
service.class=org.boris.winrun4j.MainService
service.id=SimpleBacnetIpDataTransfer
service.name=Simple Backnet IP DataTransfer Service
service.description=This is the service for the Simple Backnet IP DataTransfer.
service.startup=auto
classpath.1=C:\Inbox\DataTransferClient-1.0-SNAPSHOT-jar-with-dependencies.jar
classpath.2=WinRun4J.jar
classpath.3=C:\Inbox\log4j-1.2.16.jar
arg.1=C:\Inbox\DataTransferClient.xml
log=C:\WinRun4J-Service\SimpleBacnetIpDataTransfer\NBP-DT-service.log
log.overwrite=true
log.roll.size=10MB
[MainService]
class=com.shiftenergy.ws.App
vmarg.1=-Xdebug
vmarg.2=-Xnoagent
vmarg.3=-Xrunjdwp:transport=dt_socket,address=8787,server=y,suspend=n
vmarg.4=-Dlog4j.configuration=file:C:\Inbox\log4j.xml
within the log4j.xml file, there is reference to a log file for when the application runs. if I run the java -jar -Dlog4j.configuration=file:C:\Inbox\log4j.xml ...., the log file is created accordingly. if I register my service and start the service, the log file does not get created.
has anyone had success using the -D log4j configuration, using winrun4j?
thanks
I think that you provided the vmarg.4 parameter incorrectly. In your case it has to be like:
vmarg.4=-Dlog4j.configurationFile=[Path for log4j.xml]
I am also using the same and in my case, it is working perfectly fine. Please see below example:
vmarg.1=-Dlog4j.configurationFile=.\log4j2.xml
Have you tried setting the path in your code instead:
System.setProperty("log4j.configurationFile", "config/log4j.xml");
I'm using a relative path to a folder named config that contains log4j.xml. An absolute path is not recommended, but may work as well.
Just be sure to set this before making any calls to log4j, including any log4j config settings or static method calls!
System.setProperty("log4j.configurationFile", "config/log4j.xml");
final Logger log = Logger.getLogger(Main.class);
log.info("Starting up");
I didn't specify the log4j path in the ini file, only placed log4j.xml file at the same place the jar was placed.
Also without specify the
System.setProperty("log4j.configurationFile", "config/log4j.xml");
In the Java project it was stored in (src/main/resources) and will be included in the jar, but it will not be that one used if placed outside the jar.
Related
I'm using hydra to log hyperparameters of experiments.
#hydra.main(config_name="config", config_path="../conf")
def evaluate_experiment(cfg: DictConfig) -> None:
print(OmegaConf.to_yaml(cfg))
...
Sometimes I want to do a dry run to check something. For this I don't need any saved parameters, so I'm wondering how I can disable the savings to the filesystem completely in this case?
The answer from Omry Yadan works well if you want to solve this using the CLI. However, you can also add these flags to your config file such that you don't have to type them every time you run your script. If you want to go this route, make sure you add the following items in your root config file:
defaults:
- _self_
- override hydra/hydra_logging: disabled
- override hydra/job_logging: disabled
hydra:
output_subdir: null
run:
dir: .
There is an enhancement request aimed at Hydra 1.1 to support disabling working directory management.
Working directory management is doing many things:
Creating a working directory for the run
Changing the working directory to the created dir.
There are other related features:
Saving log files
Saving files like config.yaml and hydra.yaml into .hydra in the working directory.
Different features has different ways to disable them:
To prevent the creation of a working directory, you can override hydra.run.dir to ..
To prevent saving the files into .hydra, override hydra.output_subdir to null.
To prevent the creation of logging files, you can disable logging output of hydra/hydra_logging and hydra/job_logging, see this.
A complete example might look like:
$ python foo.py hydra.run.dir=. hydra.output_subdir=null hydra/job_logging=disabled hydra/hydra_logging=disabled
Note that as always you can also override those config values through your config file.
I know you can open files from Symfony profiler or exception file links using this in project/app/config.yml :
framework:
ide: "phpstorm://open?file=%%f&line=%%l"
More info: http://developer.happyr.com/open-files-in-phpstorm-from-you-symfony-application
However as I'm using vagrant, the file path of the server doesn't match my host.
I have created a PHP web application server in PHPStorm with the propper path mappings, but still doesn't work.
Any ideas?
Thanks
When running your app in a container or in a virtual machine, you can tell Symfony to map files from the guest to the host by changing their prefix. This map should be specified at the end of the URL template, using & and > as guest-to-host separators:
// /path/to/guest/.../file will be opened
// as /path/to/host/.../file on the host
// as /path/to/host/.../file on the host
'phpstorm://%f:%l&/path/to/guest/>/path/to/host/&/foo/>/bar/&...'
Symfony FrameworkBundle Configuration - IDE
The answer given by Jeffry no longer works unfortunately :(. When In configure that with my paths the profiler throws:
ParameterNotFoundException
You have requested a non-existent parameter "f:".
I have configured the path according to this line in the SF docs: This map should be specified at the end of the URL template, which results in this:
phpstorm://open?url=file://%%f&line=%%l&/path/to/guest/>/path/to/host/
However, it does open PHPStorm, but phpstorm does not open the file, so i'm a bit stuck here now.
This solves the issue with the file not opening in PhpStorm from a Vagrant:
phpstorm://open?file=%%f&line=%%l&/path/to/guest/>/path/to/host/
Source: https://youtrack.jetbrains.com/issue/IDEA-65879
I am trying to translate a .bat file to a INI file so that I can use WinRun4J to launch a small JAVA app as a service.
Working from the demo that ships with the download, the web page https://github.com/poidasmith/winrun4j and a few samples that have posted I've come up with an .ini file that reads as...
terrainserver.class=ru.ibs.JEPPEG3.ProjectionServer.ProjectionServerDaemon
terrainserver.id=TerrainServer
terrainserver.name=WinRun4J TerrainServer terrainserver
terrainserver.description=Pegasus Terrain Service
classpath.1=*.jar
classpath.2=*.zip
arg.1=prjsrvConfig=.\prjsrv.properties
vmarg.1=-Xdebug
vmarg.2=-Xnoagent
vmarg.3=-Xrunjdwp:transport=dt_socket,address=2121,server=y,suspend=n
vm.heapsize.min.percent=256m
vm.heapsize.preferred=1000m
vm.location=C:\Program Files (x86)\Java\jdk1.7.0_55\jre\bin\server\jvm.dl
from the original batch file...
set JAVA_HOME=c:\jdk1.3.1_03
set PRJSRV_CLASSPATH=.\ProjServer.jar;.\ode.jar;.\classes12.zip;.\JAGR-client.jar;.\PegasusElevAdapter.jar
set PRJSRV_PARAM1=prjsrvConfig=.\prjsrv.properties
start %JAVA_HOME%\bin\java.exe -classpath %PRJSRV_CLASSPATH% -D%PRJSRV_PARAM1% -Xms256m -Xmx1000m ru.ibs.JEPPEG3.ProjectionServer.ProjectionServerDaemon
My question is is using arg key the correct method of setting a reference to the prjsrv.properties file? Or is there a better method? JAVA isn't my strongest language so please bear with me.
From what I can see your batch will have to be translated into:
vmarg.4=-DprjsrvConfig=.\prjsrv.properties
Besides that I think you need to rename these:
terrainserver.class=ru.ibs.JEPPEG3.ProjectionServer.ProjectionServerDaemon
terrainserver.id=TerrainServer
terrainserver.name=WinRun4J TerrainServer terrainserver
terrainserver.description=Pegasus Terrain Service
to
service.class=ru.ibs.JEPPEG3.ProjectionServer.ProjectionServerDaemon
service.id=TerrainServer
service.name=WinRun4J TerrainServer terrainserver
service.description=Pegasus Terrain Service
because WinRun4j does not support terrainserver but service.* or main.class instead.
I am trying to access static resource (eg. first.html) packed inside the same .jar file (testJetty.jar), which also has a class which starts the jetty (v.8) server (MainTest.java). I am unable to set the resource base correctly.
The structure of my jar file (testJetty.jar):
testJetty.jar
first.html
MainTest.java
==
Works fine on local machine, but when I wrap it in jar file and then run it, it doesn't work, giving "404: File not found" error.
I tried to set the resourcebase with the following values, all of which failed:
a) Tried setting it to .
resource_handler.setResourceBase("."); // Results in directory containing the jar file, D:\Work\eclipseworkspace\testJettyResult
b) Tried getting it from getResource
ClassLoader loader = this.getClass().getClassLoader();
File indexLoc = new File(loader.getResource("first.html").getFile());
String htmlLoc = indexLoc.getAbsolutePath();
resource_handler.setResourceBase(htmloc); // Results in D:\Work\eclipseworkspace\testJettyResult\file:\D:\Work\eclipseworkspace\testJettyResult\testJetty1.jar!\first.html
c) Tried getting the webdir
String webDir = this.getClass().getProtectionDomain()
.getCodeSource().getLocation().toExternalForm();
resource_handler.setResourceBase(webdir); // Results in D:/Work/eclipseworkspace/testJettyResult/testJetty1.jar
None of these 3 approaches worked.
Any help or alternative would be appreciated
Thanks
abbas
The solutions provided in this thread work but I think some clarity to the solution could be useful.
If you are building a fat jar and use the ProtectionDomain way you may hit some issues because you are loading the whole jar!
class.getProtectionDomain().getCodeSource().getLocation().toExternalForm();
So the better solution is the other provided solution
contextHandler.setResourceBase(
YourClass.class
.getClassLoader()
.getResource("WEB-INF")
.toExternalForm());
The problem here is if you are building a fat jar you are not really dumping your webapp resources into WEB-INF but are probably going into the root of the jar, so a simple workaround is to create a folder XXX and use the second approach as follows:
contextHandler.setResourceBase(
YourClass.class
.getClassLoader()
.getResource("XXX")
.toExternalForm());
Or change your build tool to export the webapp files into that given directory. Maybe Maven does this on a Jar for you but gradle does not.
Not unusually, I found a solution to my problem. The 3rd approach mentioned by Stephen in Embedded Jetty : how to use a .war that is included in the .jar from which Jetty starts? worked!
So, I changed from Resource_handler to WebAppContext, where WebAppContext is pointing to the same jar (testJetty.jar) and it worked!
String webDir = MainTest.class.getProtectionDomain()
.getCodeSource().getLocation().toExternalForm(); ; // Results in D:/Work/eclipseworkspace/testJettyResult/testJetty.jar
WebAppContext webappContext = new WebAppContext(webDir, "/");
It looks like ClassLoader.getResource does not understand an empty string or . or / as an argument. In my jar file I had to move all stuf to WEB-INF(any other wrapping dir will do). So the code looks like
contextHandler.setResourceBase(EmbeddedJetty.class.getClassLoader().getResource("WEB-INF").toExternalForm());
so the context looks like this then:
ContextHandler:744 - Started o.e.j.w.WebAppContext#48b3806{/,jar:file:/Users/xxx/projects/dropbox/ui/target/ui-1.0-SNAPSHOT.jar!/WEB-INF,AVAILABLE}
I've got very simple .WAR containing example servlet. I'm able to deploy it in servicemix using the following command:
osgi:install file:///home/seiho/apache-servicemix-4.4.2/deploy/TestServlet.war?Bundle-SymbolicName=TestServlet&Webapp-Context=/TestServlet
And then see it in my browser. But only with full path to a file, e.g.: localhost:8080/TestServlet/index.html or localhost:8080/TestServlet/TestServlet (my servlet is TestServlet class).
I'd like to launch the index.html page automatically after entering: localhost:8080/TestServlet
how to do it?
MORE IMPORTANT
I need a way to convert the .WAR file or servlet project (I've got the sources) so that new .WAR file can be auto-deployed by copying it to $SERVICEMIX_HOME/deploy directory.
I've tried editing the MANIFEST.MF file, but with no success. Probably I'm doing something wrong.
Thanks for any advice/help.
To be recognised as a wab, you need to add a context path header to your manifest:
Web-ContextPath: TestServlet
It's working now! I was doing my MANIFEST.MF according to this page: http://team.ops4j.org/wiki/display/ops4j/Pax+Web+Extender+-+War+-+OSGi-fy
The problem was that for some reason "Bundle-Version: 1.0" line was required as opposed to optional as stated on that page.
Honestly, just adding the Bundle-Version fix-it.
I knew it was something wrong with the MANIFEST.MF and after Holly Cummins' question I played with it a bit more. Thanks Holly.
I still can't do anything with the manual site launching (have to manually enter the index.html).
http://localhost:8080/TestServlet/ gives me this:
HTTP ERROR 404
Problem accessing /TestServlet/. Reason:
Not Found
Powered by Jetty://
http://localhost:8080/TestServlet/index.html gives me proper site.