Please consider the following fiddle. I am trying to create an arrow at the bottom of the callout which has a drop shadow. This is working:
http://jsfiddle.net/tmcconechy/vT4rj/
However, If i want to move the dialog around by setting the root's left/top/width.
left: 9px;
position: absolute;
top: 36px;
Then the :after arrow is out of position. The way i can see to handle this is set the after: element to position: relative;top: 100%. However, as soon as i do that the shape arrow is broken?
Is there anyway i can handle this so the arrow position is relative to the box size and position?
Try this.
All I did was put a relatively positioned div around the one you want, and that's the div you move around. As per MDN, as long as there's an ancestor div that's positioned, your absolute positioning works off of the ancestor's position.
Html:
<div class="positioner" style="position: relative; top: 200px;">
<div class="inline-popup"></div>
</div>
I accomplished this by changing the left position on the arrow to 50% instead of a fixed px.
left: 50%;
h/t http://css-tricks.com/quick-css-trick-how-to-center-an-object-exactly-in-the-center/
You should keep this arrow in absolute position, so you can set it easily anywhere you want.
To shift it bottom to top, gange top position and reverse box-shadow for instance :
http://jsfiddle.net/vT4rj/1/
and then change borders :
http://jsfiddle.net/vT4rj/3/
.inline-popup:after {
background: none repeat scroll 0 0 #FFFFFF;
border-top: 1px solid #CCCCCC;
border-right: 1px solid #CCCCCC;
box-shadow: 1px -1px 0px rgba(0, 0, 0, 0.30);
content: "";
height: 18px;
left: 176px;
position: absolute;
top: -9px;
transform: rotate(-45deg);
-webkit-transform: rotate(-45deg);
width: 18px;
}
Related
I have a situation where, in normal CSS circumstances, a fixed div would be positioned exactly where it is specified (top:0px, left:0px).
This does not seem to be respected if I have a parent that has a translate3d transform. Am I not seeing something? I have tried other webkit-transform like style and transform origin options but had no luck.
I have attached a JSFiddle with an example where I would have expected the yellow box be at the top corner of the page rather than inside of the container element.
You can find below a simplified version of the fiddle:
#outer {
position:relative;
-webkit-transform:translate3d(0px, 20px , 0px);
height: 300px;
border: 1px solid #5511FF;
padding: 10px;
background: rgba(100,180,250, .8);
width: 80%;
}
#middle{
position:relative;
border: 1px dotted #445511;
height: 300px;
padding: 5px;
background: rgba(250,10,255, .6);
}
#inner {
position: fixed;
top: 0px;
box-shadow: 3px 3px 3px #333;
height: 20px;
left: 0px;
background: rgba(200,180,80, .8);
margin: 5px;
padding: 5px;
}
<div id="container">
Blue: Outer, <br>
Purple: Middle<br>
Yellow: Inner<br>
<div id="outer">
<div id="middle">
<div id="inner">
Inner block
</div>
</div>
</div>
</div>
How can I make translate3d work with fixed-positioned children?
This is because the transform creates a new local coordinate system, as per W3C spec:
In the HTML namespace, any value other than none for the transform results in the creation of both a stacking context and a containing block. The object acts as a containing block for fixed positioned descendants.
This means that fixed positioning becomes fixed to the transformed element, rather than the viewport.
There's not currently a work-around that I'm aware of.
It is also documented on Eric Meyer's article: Un-fixing Fixed Elements with CSS Transforms.
As Bradoergo suggested, just get the window scrollTop and add it to the absolute position top like:
function fix_scroll() {
var s = $(window).scrollTop();
var fixedTitle = $('#fixedContainer');
fixedTitle.css('position','absolute');
fixedTitle.css('top',s + 'px');
}fix_scroll();
$(window).on('scroll',fix_scroll);
This worked for me anyway.
I had a flickering on my fixed top nav when items in the page were using transform, the following applied to my top nav resolved the jumping/flickering issue:
#fixedTopNav {
position: fixed;
top: 0;
transform: translateZ(0);
-webkit-transform: translateZ(0);
}
Thanks to this answer on SO
In Firefox and Safari you can use position: sticky; instead of position: fixed; but it will not work in other browsers. For that you need javascript.
In my opinion, the best method to deal with this is to apply the same translate, but break children that need to be fixed out of their parent (translated) element; and then apply the translate to a div inside the position: fixed wrapper.
The results look something like this (in your case):
<div style='position:relative; border: 1px solid #5511FF;
-webkit-transform:translate3d(0px, 20px , 0px);
height: 100px; width: 200px;'>
</div>
<div style='position: fixed; top: 0px;
box-shadow: 3px 3px 3px #333;
height: 20px; left: 0px;'>
<div style='-webkit-transform:translate3d(0px, 20px, 0px);'>
Inner block
</div>
</div>
JSFiddle: https://jsfiddle.net/hju4nws1/
While this may not be ideal for some use cases, typically if you're fixing a div you probably could care less about what element is its parent/where it falls in the inheritance tree in your DOM, and seems to solve most of the headache - while still allowing both translate and position: fixed to live in (relative) harmony.
I ran across the same problem. The only difference is that my element with 'position: fixed' had its 'top' and 'left' style properties set from JS. So I was able to apply a fix:
var oRect = oElement.getBoundingClientRect();
oRect object will contain real (relative to view port) top and left coordinates. So you can adjust your actual oElement.style.top and oElement.style.left properties.
I have an off canvas sidebar that uses -webkit-transform: translate3d. This was preventing me from placing a fixed footer on the page. I resolved the issue by targeting a class on the html page that is added to the tag on initialization of the sidebar and then writing a css :not qualifier to state "-webkit-transform: none;" to the html tag when that class is not present on the html tag. Hope this helps someone out there with this same issue!
Try to apply opposite transform to the child element:
<div style='position:relative; border: 1px solid #5511FF;
-webkit-transform:translate3d(0px, 20px , 0px);
height: 100px; width: 200px;'>
<div style='position: fixed; top: 0px;
-webkit-transform:translate3d(-100%, 0px , 0px);
box-shadow: 3px 3px 3px #333;
height: 20px; left: 0px;'>
Inner block
</div>
</div>
Add a dynamic class while the element transforms.$('#elementId').addClass('transformed').
Then go on to declare in css,
.translat3d(#x, #y, #z) {
-webkit-transform: translate3d(#X, #y, #z);
transform: translate3d(#x, #y, #z);
//All other subsidaries as -moz-transform, -o-transform and -ms-transform
}
then
#elementId {
-webkit-transform: none;
transform: none;
}
then
.transformed {
#elementId {
.translate3d(0px, 20px, 0px);
}
}
Now position: fixed when provided with a top and z-index property values on a child element just work fine and stay fixed until the parent element transforms. When the transformation is reverted the child element pops as fixed again. This should easen the situation if you are actually using a navigation sidebar that toggles open and closes upon a click, and you have a tab-set which should stay sticky as you scroll down the page.
One way to deal with this is to apply the same transform to the fixed element:
<br>
<div style='position:relative; border: 1px solid #5511FF;
-webkit-transform:translate3d(0px, 20px , 0px);
height: 100px; width: 200px;'>
<div style='position: fixed; top: 0px;
-webkit-transform:translate3d(0px, 20px , 0px);
box-shadow: 3px 3px 3px #333;
height: 20px; left: 0px;'>
Inner block
</div>
</div>
I am trying to make a basic tooltip, but i am getting this weird outcome from the css triangle.
main.html
<div class="max"></div>
main.css
.max{
width: 160px;
height: 120px;
padding: 5px;
background: #da6262;
}
.max::before{
border-style: solid;
border-width: 15px 15px 15px 0px;
border-color: transparent #fff;
content: "";
position: relative;
}
The outcome is
I'm not exactly sure where you want to position your arrow, but try changing your ::before property to position: absolute. By doing that, you take the ::before (your arrow) out of the normal flow of the document, so it won't be constrained by the dimensions/padding of your element.
If you then want to position your arrow relative to your .max element, set position: relative to it. The absolute property positions relative to its first non-static element, in this case the .max element.
JSFiddle
Good luck!
I have a situation where, in normal CSS circumstances, a fixed div would be positioned exactly where it is specified (top:0px, left:0px).
This does not seem to be respected if I have a parent that has a translate3d transform. Am I not seeing something? I have tried other webkit-transform like style and transform origin options but had no luck.
I have attached a JSFiddle with an example where I would have expected the yellow box be at the top corner of the page rather than inside of the container element.
You can find below a simplified version of the fiddle:
#outer {
position:relative;
-webkit-transform:translate3d(0px, 20px , 0px);
height: 300px;
border: 1px solid #5511FF;
padding: 10px;
background: rgba(100,180,250, .8);
width: 80%;
}
#middle{
position:relative;
border: 1px dotted #445511;
height: 300px;
padding: 5px;
background: rgba(250,10,255, .6);
}
#inner {
position: fixed;
top: 0px;
box-shadow: 3px 3px 3px #333;
height: 20px;
left: 0px;
background: rgba(200,180,80, .8);
margin: 5px;
padding: 5px;
}
<div id="container">
Blue: Outer, <br>
Purple: Middle<br>
Yellow: Inner<br>
<div id="outer">
<div id="middle">
<div id="inner">
Inner block
</div>
</div>
</div>
</div>
How can I make translate3d work with fixed-positioned children?
This is because the transform creates a new local coordinate system, as per W3C spec:
In the HTML namespace, any value other than none for the transform results in the creation of both a stacking context and a containing block. The object acts as a containing block for fixed positioned descendants.
This means that fixed positioning becomes fixed to the transformed element, rather than the viewport.
There's not currently a work-around that I'm aware of.
It is also documented on Eric Meyer's article: Un-fixing Fixed Elements with CSS Transforms.
As Bradoergo suggested, just get the window scrollTop and add it to the absolute position top like:
function fix_scroll() {
var s = $(window).scrollTop();
var fixedTitle = $('#fixedContainer');
fixedTitle.css('position','absolute');
fixedTitle.css('top',s + 'px');
}fix_scroll();
$(window).on('scroll',fix_scroll);
This worked for me anyway.
I had a flickering on my fixed top nav when items in the page were using transform, the following applied to my top nav resolved the jumping/flickering issue:
#fixedTopNav {
position: fixed;
top: 0;
transform: translateZ(0);
-webkit-transform: translateZ(0);
}
Thanks to this answer on SO
In Firefox and Safari you can use position: sticky; instead of position: fixed; but it will not work in other browsers. For that you need javascript.
In my opinion, the best method to deal with this is to apply the same translate, but break children that need to be fixed out of their parent (translated) element; and then apply the translate to a div inside the position: fixed wrapper.
The results look something like this (in your case):
<div style='position:relative; border: 1px solid #5511FF;
-webkit-transform:translate3d(0px, 20px , 0px);
height: 100px; width: 200px;'>
</div>
<div style='position: fixed; top: 0px;
box-shadow: 3px 3px 3px #333;
height: 20px; left: 0px;'>
<div style='-webkit-transform:translate3d(0px, 20px, 0px);'>
Inner block
</div>
</div>
JSFiddle: https://jsfiddle.net/hju4nws1/
While this may not be ideal for some use cases, typically if you're fixing a div you probably could care less about what element is its parent/where it falls in the inheritance tree in your DOM, and seems to solve most of the headache - while still allowing both translate and position: fixed to live in (relative) harmony.
I ran across the same problem. The only difference is that my element with 'position: fixed' had its 'top' and 'left' style properties set from JS. So I was able to apply a fix:
var oRect = oElement.getBoundingClientRect();
oRect object will contain real (relative to view port) top and left coordinates. So you can adjust your actual oElement.style.top and oElement.style.left properties.
I have an off canvas sidebar that uses -webkit-transform: translate3d. This was preventing me from placing a fixed footer on the page. I resolved the issue by targeting a class on the html page that is added to the tag on initialization of the sidebar and then writing a css :not qualifier to state "-webkit-transform: none;" to the html tag when that class is not present on the html tag. Hope this helps someone out there with this same issue!
Try to apply opposite transform to the child element:
<div style='position:relative; border: 1px solid #5511FF;
-webkit-transform:translate3d(0px, 20px , 0px);
height: 100px; width: 200px;'>
<div style='position: fixed; top: 0px;
-webkit-transform:translate3d(-100%, 0px , 0px);
box-shadow: 3px 3px 3px #333;
height: 20px; left: 0px;'>
Inner block
</div>
</div>
Add a dynamic class while the element transforms.$('#elementId').addClass('transformed').
Then go on to declare in css,
.translat3d(#x, #y, #z) {
-webkit-transform: translate3d(#X, #y, #z);
transform: translate3d(#x, #y, #z);
//All other subsidaries as -moz-transform, -o-transform and -ms-transform
}
then
#elementId {
-webkit-transform: none;
transform: none;
}
then
.transformed {
#elementId {
.translate3d(0px, 20px, 0px);
}
}
Now position: fixed when provided with a top and z-index property values on a child element just work fine and stay fixed until the parent element transforms. When the transformation is reverted the child element pops as fixed again. This should easen the situation if you are actually using a navigation sidebar that toggles open and closes upon a click, and you have a tab-set which should stay sticky as you scroll down the page.
One way to deal with this is to apply the same transform to the fixed element:
<br>
<div style='position:relative; border: 1px solid #5511FF;
-webkit-transform:translate3d(0px, 20px , 0px);
height: 100px; width: 200px;'>
<div style='position: fixed; top: 0px;
-webkit-transform:translate3d(0px, 20px , 0px);
box-shadow: 3px 3px 3px #333;
height: 20px; left: 0px;'>
Inner block
</div>
</div>
I've got a set up similar to this: http://codepen.io/anon/pen/iAJnx where the main content is rather long. What I want to do is to put a border round the visible part of the screen as in this screenshot: http://i.imgur.com/ENtLau4.png
What I want to do is to create 4 divs that are positioned at the edges of the screen, but I'm struggling both with the positioning and giving the divs height and width without content. Does anyone have an idea about this?
Note: I've already tried using an overlay, but it makes the content non-clickable.
Try this:
HTML:
<div class="border-box"></div>
CSS:
body { position: relative; }
.border-box {
border: 5px solid blue;
box-shadow: 0 0 100px 100px #fff;
position: fixed;
pointer-events: none;
bottom: 10px;
left: 10px;
right: 10px;
top: 10px;
}
How it works:
I absolutely positioned an overlay with borders, that will stick the edges of the screen by using top, bottom, left, right definitions. To make the content below selectable, you set pointer-events: none; on the overlay.
Example: http://codepen.io/anon/pen/BxJbh
If you want to achieve the same results without adding additional HTML markup, you can use the :before sudo selector to prepend a block to the body. Simply add this CSS and it will produce the same results:
body:before {
border: 5px solid blue;
box-shadow: 0 0 100px 100px #fff;
display: block;
content: '';
position: fixed;
pointer-events: none;
bottom: 10px;
left: 10px;
right: 10px;
top: 10px;
}
Example: http://codepen.io/anon/pen/BDhql
you have to set in your content id (#content)
border:4px solid blue;
min-width:700px; //change accordingly.
min-height:1600px //change accordingly
The above code will fix the problem of border as well as the height & width you want to set without having any content.
I want the left border of my div to show only to the half of the div. The same I would like to do to my right border but is should be set from the bottom of the div to the middle of the div. How can I achieve it?
A sort-of similar but different approach to #Pekka's: use the :after pseudo-selector, like so:
.mybox {
position: relative;
padding: 10px 20px;
background-color: #EEEEEE;
}
.mybox:after {
content: '';
position: absolute;
bottom: 0px;
left: 25%;
width: 50%;
border-bottom: 1px solid #0000CC;
}
<div class="mybox">
Le content de box.
</div>
...and a jsFiddle for good measure.
Good question. It's not possible using the border property.
The only thing that comes to mind, if you can set your div's position to relative, is to use an absolutely positioned, 1 pixel wide div. Not thoroughly tested but this should work:
<div style='width: 1px; top: 0px; bottom: 50%; left: 0px;
background-color: blue; overflow: hidden'>
</div>
You'd do the same on the right hand side, replacing the left property by right.
Remember, the surrounding div needs to be position: relative for this to work. I'm not sure about whether the 50% height setting will work consistently throughout browsers - make sure you test it. You may have to resort to pixel measures if it doesn't.
2018: For modern browsers:
You can use border-image with gradients something like...
border-image: linear-gradient(to bottom, rgba(0,0,0,0) 25%,rgba(0,0,0,1) 25%,rgba(0,0,0,1) 75%,rgba(0,0,0,0) 75%);
border-image-slice: 1;
Demo: https://jsfiddle.net/hz8wp0L0/
Tool: Gradient Editor
Can I Use : border-image (IE11)
For those trying to implement Aleksandr Belugin's answer above using border-left, here it is:
.mybox {
position: relative;
padding: 10px 20px;
background-color: #EEEEEE;
}
.mybox:after {
content: '';
position: absolute;
left: 0px;
top: 25%;
height: 50%;
border-left: 1px solid #0000CC;
}
<div class="mybox">
Le content de box.
</div>
You can use:
line-height:50%; /*(or less, much less)*/
overflow:visible;
The text is visible, but the border color will be only at half of the div size.