I have a regex but it's not quite working the way i want
page[0-9]*
/pages/search.aspx?pageno=3&pg=232323&hdhdhd/page73733/xyz
In the above example, the only thing I want to match is page73733. But my regex matches the page in /pages and it matches page in pageno=3
i also tried page[0-9].*, then it matches page73733 but it also matches everything that comes after it so that it actually matches page73733/xyz
page[0-9].*[^a-zA-Z&?/=]
That seems to do what i want, but that also seems like a ugly way to do it. Plus if i had something like /page123/xyz/page456 it'll match that whole string.
So is there a better way to do this? I want to match ONLY the string page when it is followed by any number of digits, and if anything comes after the digits it should stop.
* means 0 or more occurrences. + means 1 or more occurrences.
page[0-9]+ should work.
page[0-9]*
Will match page followed by zero or more numbers. What you want is:
page[0-9]+
Which will match page followed by one or more numbers.
You almost got it. Just use + instead of * as that will force a match that has numbers after it.
Another way to type that expression would be
/page[0-9]+
note the / , this would be helpful because without it you might get a match with something like "notApage123"
The regex page[0-9]* will match [0-9] 0 or more times. + would match it 1 or more times, and ? would match it 0 or 1 times. An equivalent method to ?+* is as follows:
?={0,1}
*={0,}
+={1,}
This may be helpful for if you wanted to match a date:\\d{4}(-\\d{1,2}){2} which would match 2013-5-31
-
That said, the resulting Regex for your particular problem would be:
page\\d+
page\\d{1,}
page[0-9]+
or page[0-9]{1,}
In your example "/page123/xyz/page456" you may want to match all occurrences, so don't forget the g or global modifier.
If I understand your problem correctly, you only need to add $ to your original regex to specify that after page you want the string to end. So the regex would be
page[0-9]*$
Also, this will match strings that end in page too, if you want only strings that end in page followed by any number, use this regex
page[0-9]+$
Related
I need to extract the first element ("adidas-originals") after "designer" in the following URL using regular expressions.
xxx/en-ca/men/designers/adidas-originals/shorts
This needs to be done in Google Big Query API (standard SQL). To this end, I have tried several ways to get the desired valued without any success. Below is the best solution that I have found so far which obviously is not the right one as it returns "/adidas-originals/shorts".
REGEXP_EXTRACT(hits.page.pagePath, r'designers([^\n]*)')
Thanks!
The [^\n]* matches 0 or more chars other than a newline, LF, so no wonder it matches too much.
You need a pattern to match up to the next /, so you may use
designers/([^/]+)
Or a more precise:
(?:^|/)designers/([^/]+)
See the regex demo
Details
(?:^|/) - either start of a string or / (you may just use / if designers is always preceded with /)
designers/ a designers/ substring
([^/]+) - Capturing group 1 (just what will be returned with the REGEXP_EXTRACT function): one or more chars other than /.
I'm trying to validate the following in a password field:
-at least 1 alpha
-at least 1 numeric
-at least 1 special (non alphanumeric)
My reg exp is this:
Regex.IsMatch("jpere33z#1?hs", #"^\w*(?=\w*\d)(?=\w*[a-z])(?=\W*)\w*$")
and it says it is not valid. The \W part is what is not working.
Could you please tell me why?
\w*$ will only match letters, numbers, and underscore. This is what you want:
Regex.IsMatch("#1?hsjpere33z", #"^(?=.*?\d)(?=.*?[a-z])(?=.*?\W).*$", RegexOptions.IgnoreCase)
I moved the validation to the left, and added \w* right before the \W.
Edit: Also used .* instead of \w for test lookaheads.
Your regex doesn't allow more then 1 digit.
Your easiest route would probably be to have 3 regex checks, one for the existance of each character type.
This is difficult to do with regex (at least only one). In the regex you are giving the fields an order, so the parser expects them in that order.
One alternative would be to use a choice, but that would make difficult to check that you have one of each of the terms:
[\w|\d|\W]{4,}
If you want to use regex, check three of them:
1) Is there a digit?
2) Is there a character?
3) Is there a special?
If all of them are true.... bingo!
Sample text =
legacycard.ashx?save=false&iNo=3&No=555
Sample pattern =
^legacycard.ashx(.*)No=(\d+)
Want to grab group #2 value of "555" (the value of "No=" in the sample text)
In Expresso, this works, but in ASP.NET UrlRewrite, it is not catching.
Am I missing something?
Thanks!
I would do something along these lines:
^legacycard.ashx\?(?:.+&)*No=(\d+)
The \? will escape the question mark that normally separates the URL and the parameters, then you make sure that it will capture every parameter key/value pair (anything that ends on &) before the parameter you actually care about. Using ?: lets you specify that the set of brackets is non capturing (I'm assuming you won't need any of the data, has the potential to slightly speeds up your regex) and leaves you just 555 captured. The added benefit of this approach is that it'll work regardless of parameter order.
Just use this regex:
^legacycard\.ashx\?save=(false|true)&iNo=(?<ino>\d+)&No=(?<no>\d+)
Then Regex Replace with
${no}
Looks fine to me, your regex should match the entire string
legacycard.ashx?save=false&iNo=3&No=555
not sure why you have groups, but groups should also return
?save=false&iNo=3&
and
555
For good measure you should know that the . in legacycard.ashx is also interpreted by regex and you would normally escape it, in this case it dosen't matter because a single dot matches everything, also a dot. :)
Try this
^legacycard.ashx(\?No=|.*?&No=)(\d+)
this should work.
Hi I'm trying to right a regular expression that will take a string and ensure it starts with an 'R' and is followed by 4 numeric digits then anything
eg. RXXXX.................
Can anybody help me with this? This is for ASP.NET
You want it to be at the beginning of the line, not anywhere. Also, for efficiency, you dont want the .+ or .* at the end because that will match unnecessary characters. So the following regex is what you really want:
^R\d{4}
This should do it...
^R\d{4}.*$
\d{4} matches 4 digits
.* is simply a way to match any character 0 or more times
the beginning ^ and end $ anchors ensure that nothing precedes or follows
As Vincent suggested, for your specific task it could even be simplified to this...
^R\d{4}
Because as you stated, it doesn't really matter what follows.
/^R\d{4}.*/ and set the case insensitive option unless you only want capital R's
^R\d{4}.*
The caret ^ matches the position before the first character in the string.
\d matches any numeric character (it's the same as [0-9])
{4} indicates that there must be exactly 4 numbers, and
.* matches 0 or more other characters
To use:
string input = "R0012 etc..";
Match match = Regex.Match(input, #"^R\d{4}.*", RexOptions.IgnoreCase);
if (match.Success)
{
// Success!
}
Note the use of RexOptions.IgnoreCase to ignore the case of the letter R (so it'll match strings which start with r. Leave this out if you don't want to undertake a case insensitive match.
I'm trying to complete a regular expression that will pull out matches based on their opening and closing characters, the closest I've gotten is
^(\[\[)[a-zA-Z.-_]+(\]\])
Which will match a string such as "[[word1]]" and bring me back all the matches if there is more than one, The problem is I want it to pick up matchs where there may be a space in so for example "[[word1 word2]]", now this will work if I add a space into my pattern above however this pops up a problem that it will only get one match for my entire string so for example if I have a string
"Hi [[Title]] [[Name]] [[surname]], How are you"
then the match will be [[Title]] [[Name]] [[surname]] rather than 3 matches [[Title]], [[Name]], [[surname]]. I'm sure I'm just a char or two away in the Regex but I'm stuck, How can I make it return the 3 matches.
Thanks
You just need to make you regex non-greedy by using a ? like:
^(\[\[)[a-zA-Z.-_ ]+?(\]\])
Also there is a bug in your regex. You've included - in the char class thinking of it as a literal hyphen. But - in a char class is a meta char. So it effectively will match all char between . (period) and _ (underscore). So you need to escape it as:
^(\[\[)[a-zA-Z.\-_ ]+?(\]\])
or you can put is in some other place in the regex so that it will not have things on both sides of it as:
^(\[\[)[a-zA-Z._ -]+?(\]\])
or
^(\[\[)[-a-zA-Z._ ]+?(\]\])
You need to turn off greedy matching. See these examples for different languages:
asp.net
java
javascript
You should use +? instead of +.
The one without the question mark will try to match as much as possible, while the one with the question mark as little as possible.
Another approach would be to use [^\]] as your characters instead of [a-zA-Z.-_]. That way, a match will never extend over your closing brackets.