I have the controller in ASP.NET Mvc 6.
public class VendorManagementController : Controller
{
private readonly IVendorRespository _vendorRespository;
public VendorManagementController(IVendorRespository vendorRespository)
{
_vendorRespository = vendorRespository;
}
[Microsoft.AspNet.Mvc.HttpGet]
public dynamic GetVendorById(int pkey)
{
Vendor vendor = _vendorRespository.GetVendor(pkey);
return vendor;
}
// GET
// USing JqGrid
[Microsoft.AspNet.Mvc.HttpGet]
public dynamic GetVendors(string sidx, string sortOrder, int page, int rows, int pkey)
{
var vendors = _vendorRespository.GetAllVendors().AsQueryable();
var pageIndex = Convert.ToInt32(page) - 1;
var pageSize = rows;
var totalRecords = vendors.Count();
var totalPages = (int)Math.Ceiling((float)totalRecords / (float)pageSize);
return something
}
// POST
[System.Web.Http.HttpPost]
public string PostVendor(Vendor item)
{
_vendorRespository.AddVendor(item);
}
The link provides an example to test the controller, but it uses HttpRequestMessage. It doesn't fit my case.
So if I want to test the return Vendors, how?
Say I have the method:
[Fact]
public void GetAllVendors_ShouldReturnAllVendors()
{
var testVendors = GetTestVendors();
var vendorRespository = new VendorRespository();
var controller = new VendorManagementController(vendorRespository);
}
The thing is
var vendors = _vendorRespository.GetAllVendors().AsQueryable();
from the databse, how to mock up it with my fake vendors?
EDIT:
The method returns dynamic type, I can't get the Count of the list.
Install a mocking framework such as Moq from nuget - https://www.nuget.org/packages/Moq/.
using Moq;
[Fact]
public void GetAllVendors_ShouldReturnAllVendors()
{
var testVendors = GetTestVendors();
var vendorRespository = new Mock<IVendorRepository>();
vendorRepository.Setup(m => m.GetAllVendors()).Returns(new List<Vendor> { new Vendor() }); // Guessing a bit on return types
var controller = new VendorManagementController(vendorRespository.Object);
var result = controller.GetVendors( ... )
// Assert you get 1 Vendor back, not sure what you're planning to return by "something". :-)
}
Other frameworks are available, NSubsititute, FakeItEasy
I'm suffering trying to get some views from a library to the main project. I was starting to read about creating your own VirtualPathProvider implementation here: Using VirtualPathProvider to load ASP.NET MVC views from DLLs
I had to set my view = EmbbebedResource to get the resource from the library. But now is throwing another error.
In the header of my partial view I had the following:
#model Contoso.ExercisesLibrary.AbsoluteArithmetic.Problem1
And the error says: External component has thrown an exception. c:\Users\Oscar\AppData\Local\Temp\Temporary ASP.NET Files\root\4f78c765\7f9a47c6\App_Web_contoso.exerciseslibrary.absolutearithmetic.view1.cshtml.38e14c22.y-yjyt6g.0.cs(46): error CS0103: The name 'model' does not exist in the current context
I don't know why the compiler tells that cannot recognized my model. When I'm in design mode, I can see the compiler that the check is all right.
Check the image
What am I doing wrong o what am I missing?
Thanks in advance.
Try adding an #inherits directive to the top of your razor view:
#inherits System.Web.Mvc.WebViewPage
#model Contoso.ExercisesLibrary.AbsoluteArithmetic.Problem1
The reason you need this is because your view comes from an embedded resource and not from the standard ~/Views location. And as you know inside ~/Views there's a file called web.config. And inside this file there's a pageBaseType="System.Web.Mvc.WebViewPage" directive indicating that all Razor files inside ~/Views should inherit from this base type. But since your view is now coming from an unknown location you have nowhere specified that it should be a System.Web.Mvc.WebViewPage. And all the MVC specific stuff such as models, HTML helpers, ... are defined in this base class.+
I faced this issue "The name 'model' does not exist in the current context". What I did was added same "areas" folder structure (from my embedded mvc project) to my main MVC project (Areas/AnualReports/Views/) and copied web.config (default web.config from views folder, not the one from root) to Views folder which solved the issue. I am not sure this will work in your case.
Update:
Adding web.config (from views folder) to root "areas" folder in main MVC project also works.
I have the same problem as you so after all searches I got working solution
Create your own WebViewPage based abstract class (generic for model and non generic)
public abstract class MyOwnViewPage<TModel> : WebViewPage<TModel> { }
public abstract class MyOwnViewPage : WebViewPage { }
Next create VirtualFile based class or embedded view's
class AssemblyResourceFile : VirtualFile
{
private readonly IDictionary<string, Assembly> _nameAssemblyCache;
private readonly string _assemblyPath;
private readonly string _webViewPageClassName;
public string LayoutPath { get; set; }
public string ViewStartPath { get; set; }
public AssemblyResourceFile(IDictionary<string, Assembly> nameAssemblyCache, string virtualPath) :
base(virtualPath)
{
_nameAssemblyCache = nameAssemblyCache;
_assemblyPath = VirtualPathUtility.ToAppRelative(virtualPath);
LayoutPath = "~/Views/Shared/_Layout.cshtml";
ViewStartPath = "~/Views/_ViewStart.cshtml";
_webViewPageClassName = typeofMyOwnViewPage).ToString();
}
// Please change Open method for your scenario
public override Stream Open()
{
string[] parts = _assemblyPath.Split(new[] { '/' }, 4);
string assemblyName = parts[2];
string resourceName = parts[3].Replace('/', '.');
Assembly assembly;
lock (_nameAssemblyCache)
{
if (!_nameAssemblyCache.TryGetValue(assemblyName, out assembly))
{
var assemblyPath = Path.Combine(HttpRuntime.BinDirectory, assemblyName);
assembly = Assembly.LoadFrom(assemblyPath);
_nameAssemblyCache[assemblyName] = assembly;
}
}
Stream resourceStream = null;
if (assembly != null)
{
resourceStream = assembly.GetManifestResourceStream(resourceName);
if (resourceName.EndsWith(".cshtml"))
{
//the trick is here. We must correct our embedded view
resourceStream = CorrectView(resourceName, resourceStream);
}
}
return resourceStream;
}
public Stream CorrectView(string virtualPath, Stream stream)
{
var reader = new StreamReader(stream, Encoding.UTF8);
var view = reader.ReadToEnd();
stream.Close();
var ourStream = new MemoryStream();
var writer = new StreamWriter(ourStream, Encoding.UTF8);
var modelString = "";
var modelPos = view.IndexOf("#model");
if (modelPos != -1)
{
writer.Write(view.Substring(0, modelPos));
var modelEndPos = view.IndexOfAny(new[] { '\r', '\n' }, modelPos);
modelString = view.Substring(modelPos, modelEndPos - modelPos);
view = view.Remove(0, modelEndPos);
}
writer.WriteLine("#using System.Web.Mvc");
writer.WriteLine("#using System.Web.Mvc.Ajax");
writer.WriteLine("#using System.Web.Mvc.Html");
writer.WriteLine("#using System.Web.Routing");
var basePrefix = "#inherits " + _webViewPageClassName;
if (virtualPath.ToLower().Contains("_viewstart"))
{
writer.WriteLine("#inherits System.Web.WebPages.StartPage");
}
else if (modelString == "#model object")
{
writer.WriteLine(basePrefix + "<dynamic>");
}
else if (!string.IsNullOrEmpty(modelString))
{
writer.WriteLine(basePrefix + "<" + modelString.Substring(7) + ">");
}
else
{
writer.WriteLine(basePrefix);
}
writer.Write(view);
writer.Flush();
ourStream.Position = 0;
return ourStream;
}
}
Next create VirtualPathProvider based class (modify it for your purposes)
public class AssemblyResPathProvider : VirtualPathProvider
{
private readonly Dictionary<string, Assembly> _nameAssemblyCache;
private string _layoutPath;
private string _viewstartPath;
public AssemblyResPathProvider(string layout, string viewstart)
{
_layoutPath = layout;
_viewstartPath = viewstart;
_nameAssemblyCache = new Dictionary<string, Assembly>(StringComparer.InvariantCultureIgnoreCase);
}
private bool IsAppResourcePath(string virtualPath)
{
string checkPath = VirtualPathUtility.ToAppRelative(virtualPath);
bool bres1 = checkPath.StartsWith("~/App_Resource/",
StringComparison.InvariantCultureIgnoreCase);
bool bres2 = checkPath.StartsWith("/App_Resource/",
StringComparison.InvariantCultureIgnoreCase);
//todo: fix this
if (checkPath.EndsWith("_ViewStart.cshtml"))
{
return false;
}
if (checkPath.EndsWith("_ViewStart.vbhtml"))
{
return false;
}
return ((bres1 || bres2));
}
public override bool FileExists(string virtualPath)
{
return (IsAppResourcePath(virtualPath) ||
base.FileExists(virtualPath));
}
public override VirtualFile GetFile(string virtualPath)
{
if (IsAppResourcePath(virtualPath))
{
// creating AssemblyResourceFile instance
return new AssemblyResourceFile(_nameAssemblyCache, virtualPath,_layoutPath,virtualPath);
}
return base.GetFile(virtualPath);
}
public override CacheDependency GetCacheDependency(
string virtualPath,
IEnumerable virtualPathDependencies,
DateTime utcStart)
{
if (IsAppResourcePath(virtualPath))
{
return null;
}
return base.GetCacheDependency(virtualPath,
virtualPathDependencies, utcStart);
}
}
At last register your AssemblyResPathProvider in global.asax
string _layoutPath = "~/Views/Shared/_Layout.cshtml";
string _viewstarPath = "~/Views/_ViewStart.cshtml";
HostingEnvironment.RegisterVirtualPathProvider(new AssemblyResPathProvider(_layoutPath,_viewstarPath));
This is not ideal solution but its working for me good. Cheers!
In my case, the solution was to make the virtual Path start with "~Views/" - just like any normal view.
Not working: ~/VIRTUAL/Home/Index.cshtml
Working: ~/Views/VIRTUAL/Home/Index.cshtml
I think, this has to do with the web.config lying around in ~/Views and defining a lot of stuff for the views. Maybe anybody can give more information.
Hope that helps anyway.
I successfully used System.ServiceModel.Syndication.SyndicationFeed to add some Atom10 output from my ASP.NET 3.5 web site. It was my first production use of ServiceStack, and it all work fine.
My first attempt resulted in UTF-16 instead of UTF-8, which was ok for all browsers except IE. So I had to create XmlWriterResult class to solve this. My solution works, but how should I have done?
public class AsStringService : IService<AsString>
{
public object Execute(AsString request)
{
SyndicationFeed feed = new SyndicationFeed("Test Feed " + request.Name, "This is a test feed", new Uri("http://Contoso/testfeed"), "TestFeedID", DateTime.Now);
SyndicationItem item = new SyndicationItem("Test Item", "This is the content for Test Item", new Uri("http://localhost/ItemOne"), "TestItemID", DateTime.Now);
List<SyndicationItem> items = new List<SyndicationItem>();
items.Add(item);
feed.Items = items;
Atom10FeedFormatter atomFormatter = new Atom10FeedFormatter(feed);
return new XmlWriterResult(xmlWriter => atomFormatter.WriteTo(xmlWriter));
}
}
XmlWriterResult is:
public delegate void XmlWriterDelegate(XmlWriter xmlWriter);
/// <summary>
/// From https://groups.google.com/forum/?fromgroups=#!topic/servicestack/1U02g7kViRs
/// </summary>
public class XmlWriterResult : IDisposable, IStreamWriter, IHasOptions
{
private readonly XmlWriterDelegate _writesToXmlWriter;
public XmlWriterResult(XmlWriterDelegate writesToXmlWriter)
{
_writesToXmlWriter = writesToXmlWriter;
this.Options = new Dictionary<string, string> {
{ HttpHeaders.ContentType, "text/xml" }
};
}
public void Dispose()
{
}
public void WriteTo(Stream responseStream)
{
using (XmlWriter xmlWriter = XmlWriter.Create(responseStream))
{
_writesToXmlWriter(xmlWriter);
}
}
public IDictionary<string, string> Options { get; set; }
}
(Yes, I like delegates, I also do a lot of F#)
As this isn't a question with any clear answer I'd just tell you how I'd do it.
Assuming SyndicationFeed is a clean DTO / POCO you should just return that in your service:
public class AsStringService : IService
{
public object Any(AsString request)
{
SyndicationFeed feed = new SyndicationFeed("Test Feed " + request.Name,
"This is a test feed", new Uri("http://Contoso/testfeed"),
"TestFeedID", DateTime.Now);
SyndicationItem item = new SyndicationItem("Test Item",
"This is the content for Test Item",
new Uri("http://localhost/ItemOne"),
"TestItemID", DateTime.Now);
List<SyndicationItem> items = new List<SyndicationItem>();
items.Add(item);
feed.Items = items;
return feed;
}
}
This example uses ServiceStack's New API which is much nicer, you should try using it for future services.
This will allow you to get Content Negotiation in all of ServiceStack's registered Content-Types.
Registering a Custom Media Type
You could then register a Custom Media Type as seen in ServiceStack's Northwind v-card example:
private const string AtomContentType = "application/rss+xml";
public static void Register(IAppHost appHost)
{
appHost.ContentTypeFilters.Register(AtomContentType, SerializeToStream,
DeserializeFromStream);
}
public static void SerializeToStream(IRequestContext requestContext,
object response, Stream stream)
{
var syndicationFeed = response as SyndicationFeed;
if (SyndicationFeed == null) return;
using (XmlWriter xmlWriter = XmlWriter.Create(stream))
{
Atom10FeedFormatter atomFormatter = new Atom10FeedFormatter(feed);
atomFormatter.WriteTo(xmlWriter);
}
}
public static object DeserializeFromStream(Type type, Stream stream)
{
throw new NotImplementedException();
}
Now the rss+xml format should appear in the /metadata pages and ServiceStack will let you request the format in all the supported Content-Negotation modes, e.g:
Accept: application/rss+xml HTTP Header
Using the predefined routes, e.g: /rss+xml/syncreply/AsString
Or appending /route?format=rss+xml to the QueryString
Note: you may need to url encode the '+' character
I'm looking to add some basic theme support to my web application, with users being able to customise various parts of the look. These include things like colours, text sizes, fonts, other basic things. I will be storing these in the database and loading them each time a page is accessed.
My question is, how do I go about generating a dynamic CSS file based upon these database values?
I would prefer to do something that is cache-able, but extensible so that if I want to add more editable styles then it wouldn't be a bit issue.
I think the simplest way would be to add something like the following action method to a controller:
public class CssController : Controller {
public ActionResult GetCss() {
StringBuilder sb = new StringBuilder();
Dictionary<string, string> cssValues = new Dictionary<string, string>();
// populate dictionary with values from your database
sb.AppendLine(".myDivClass {");
foreach (var entry in cssValues) {
sb.AppendLine(entry.Key + ": " + entry.Value);
}
sb.AppendLine("}");
return Content(sb.ToString(), "text/css");
}
}
Now in your page you can reference it like so:
<link href="<%: Url.RouteUrl(new { controller= "CssController", action = "GetCss" }) %>" rel="stylesheet" type="text/css" />
OP EDIT: I made some small changes to the method, but the general premise remains. This is the version I used:
public class CssController : Controller
{
public ContentResult GetTheme()
{
var builder = new StringBuilder();
IDictionary<string, IDictionary<string, string>> css = new Dictionary<string, IDictionary<string, string>>();
/* Populate css object from the database */
foreach (var selector in css)
{
builder.Append(selector.Key);
builder.Append(" { ");
foreach (var entry in selector.Value)
{
builder.Append(string.Format("{0}: {1}; ", entry.Key, entry.Value));
}
builder.AppendLine("}");
}
return Content(builder.ToString(), "text/css");
}
}
Can I create a Controller that simply returns an image asset?
I would like to route this logic through a controller, whenever a URL such as the following is requested:
www.mywebsite.com/resource/image/topbanner
The controller will look up topbanner.png and send that image directly back to the client.
I've seen examples of this where you have to create a View - I don't want to use a View. I want to do it all with just the Controller.
Is this possible?
Use the base controllers File method.
public ActionResult Image(string id)
{
var dir = Server.MapPath("/Images");
var path = Path.Combine(dir, id + ".jpg"); //validate the path for security or use other means to generate the path.
return base.File(path, "image/jpeg");
}
As a note, this seems to be fairly efficient. I did a test where I requested the image through the controller (http://localhost/MyController/Image/MyImage) and through the direct URL (http://localhost/Images/MyImage.jpg) and the results were:
MVC: 7.6 milliseconds per photo
Direct: 6.7 milliseconds per photo
Note: this is the average time of a request. The average was calculated by making thousands of requests on the local machine, so the totals should not include network latency or bandwidth issues.
Using the release version of MVC, here is what I do:
[AcceptVerbs(HttpVerbs.Get)]
[OutputCache(CacheProfile = "CustomerImages")]
public FileResult Show(int customerId, string imageName)
{
var path = string.Concat(ConfigData.ImagesDirectory, customerId, "\\", imageName);
return new FileStreamResult(new FileStream(path, FileMode.Open), "image/jpeg");
}
I obviously have some application specific stuff in here regarding the path construction, but the returning of the FileStreamResult is nice and simple.
I did some performance testing in regards to this action against your everyday call to the image (bypassing the controller) and the difference between the averages was only about 3 milliseconds (controller avg was 68ms, non-controller was 65ms).
I had tried some of the other methods mentioned in answers here and the performance hit was much more dramatic... several of the solutions responses were as much as 6x the non-controller (other controllers avg 340ms, non-controller 65ms).
To expland on Dyland's response slightly:
Three classes implement the FileResult class:
System.Web.Mvc.FileResult
System.Web.Mvc.FileContentResult
System.Web.Mvc.FilePathResult
System.Web.Mvc.FileStreamResult
They're all fairly self explanatory:
For file path downloads where the file exists on disk, use FilePathResult - this is the easiest way and avoids you having to use Streams.
For byte[] arrays (akin to Response.BinaryWrite), use FileContentResult.
For byte[] arrays where you want the file to download (content-disposition: attachment), use FileStreamResult in a similar way to below, but with a MemoryStream and using GetBuffer().
For Streams use FileStreamResult. It's called a FileStreamResult but it takes a Stream so I'd guess it works with a MemoryStream.
Below is an example of using the content-disposition technique (not tested):
[AcceptVerbs(HttpVerbs.Post)]
public ActionResult GetFile()
{
// No need to dispose the stream, MVC does it for you
string path = Path.Combine(AppDomain.CurrentDomain.BaseDirectory, "App_Data", "myimage.png");
FileStream stream = new FileStream(path, FileMode.Open);
FileStreamResult result = new FileStreamResult(stream, "image/png");
result.FileDownloadName = "image.png";
return result;
}
This might be helpful if you'd like to modify the image before returning it:
public ActionResult GetModifiedImage()
{
Image image = Image.FromFile(Path.Combine(Server.MapPath("/Content/images"), "image.png"));
using (Graphics g = Graphics.FromImage(image))
{
// do something with the Graphics (eg. write "Hello World!")
string text = "Hello World!";
// Create font and brush.
Font drawFont = new Font("Arial", 10);
SolidBrush drawBrush = new SolidBrush(Color.Black);
// Create point for upper-left corner of drawing.
PointF stringPoint = new PointF(0, 0);
g.DrawString(text, drawFont, drawBrush, stringPoint);
}
MemoryStream ms = new MemoryStream();
image.Save(ms, System.Drawing.Imaging.ImageFormat.Png);
return File(ms.ToArray(), "image/png");
}
You can create your own extension and do this way.
public static class ImageResultHelper
{
public static string Image<T>(this HtmlHelper helper, Expression<Action<T>> action, int width, int height)
where T : Controller
{
return ImageResultHelper.Image<T>(helper, action, width, height, "");
}
public static string Image<T>(this HtmlHelper helper, Expression<Action<T>> action, int width, int height, string alt)
where T : Controller
{
var expression = action.Body as MethodCallExpression;
string actionMethodName = string.Empty;
if (expression != null)
{
actionMethodName = expression.Method.Name;
}
string url = new UrlHelper(helper.ViewContext.RequestContext, helper.RouteCollection).Action(actionMethodName, typeof(T).Name.Remove(typeof(T).Name.IndexOf("Controller"))).ToString();
//string url = LinkBuilder.BuildUrlFromExpression<T>(helper.ViewContext.RequestContext, helper.RouteCollection, action);
return string.Format("<img src=\"{0}\" width=\"{1}\" height=\"{2}\" alt=\"{3}\" />", url, width, height, alt);
}
}
public class ImageResult : ActionResult
{
public ImageResult() { }
public Image Image { get; set; }
public ImageFormat ImageFormat { get; set; }
public override void ExecuteResult(ControllerContext context)
{
// verify properties
if (Image == null)
{
throw new ArgumentNullException("Image");
}
if (ImageFormat == null)
{
throw new ArgumentNullException("ImageFormat");
}
// output
context.HttpContext.Response.Clear();
context.HttpContext.Response.ContentType = GetMimeType(ImageFormat);
Image.Save(context.HttpContext.Response.OutputStream, ImageFormat);
}
private static string GetMimeType(ImageFormat imageFormat)
{
ImageCodecInfo[] codecs = ImageCodecInfo.GetImageEncoders();
return codecs.First(codec => codec.FormatID == imageFormat.Guid).MimeType;
}
}
public ActionResult Index()
{
return new ImageResult { Image = image, ImageFormat = ImageFormat.Jpeg };
}
<%=Html.Image<CapchaController>(c => c.Index(), 120, 30, "Current time")%>
Why not go simple and use the tilde ~ operator?
public FileResult TopBanner() {
return File("~/Content/images/topbanner.png", "image/png");
}
You can write directly to the response but then it isn't testable. It is preferred to return an ActionResult that has deferred execution. Here is my resusable StreamResult:
public class StreamResult : ViewResult
{
public Stream Stream { get; set; }
public string ContentType { get; set; }
public string ETag { get; set; }
public override void ExecuteResult(ControllerContext context)
{
context.HttpContext.Response.ContentType = ContentType;
if (ETag != null) context.HttpContext.Response.AddHeader("ETag", ETag);
const int size = 4096;
byte[] bytes = new byte[size];
int numBytes;
while ((numBytes = Stream.Read(bytes, 0, size)) > 0)
context.HttpContext.Response.OutputStream.Write(bytes, 0, numBytes);
}
}
Below code utilizes System.Drawing.Bitmap to load the image.
using System.Drawing;
using System.Drawing.Imaging;
public IActionResult Get()
{
string filename = "Image/test.jpg";
var bitmap = new Bitmap(filename);
var ms = new System.IO.MemoryStream();
bitmap.Save(ms, ImageFormat.Jpeg);
ms.Position = 0;
return new FileStreamResult(ms, "image/jpeg");
}
UPDATE: There are better options than my original answer. This works outside of MVC quite well but it's better to stick with the built-in methods of returning image content. See up-voted answers.
You certainly can. Try out these steps:
Load the image from disk in to a byte array
cache the image in the case you expect more requests for the image and don't want the disk I/O (my sample doesn't cache it below)
Change the mime type via the Response.ContentType
Response.BinaryWrite out the image byte array
Here's some sample code:
string pathToFile = #"C:\Documents and Settings\some_path.jpg";
byte[] imageData = File.ReadAllBytes(pathToFile);
Response.ContentType = "image/jpg";
Response.BinaryWrite(imageData);
Hope that helps!
Solution 1: To render an image in a view from an image URL
You can create your own extension method:
public static MvcHtmlString Image(this HtmlHelper helper,string imageUrl)
{
string tag = "<img src='{0}'/>";
tag = string.Format(tag,imageUrl);
return MvcHtmlString.Create(tag);
}
Then use it like:
#Html.Image(#Model.ImagePath);
Solution 2: To render image from database
Create a controller method that returns image data like below
public sealed class ImageController : Controller
{
public ActionResult View(string id)
{
var image = _images.LoadImage(id); //Pull image from the database.
if (image == null)
return HttpNotFound();
return File(image.Data, image.Mime);
}
}
And use it in a view like:
# { Html.RenderAction("View","Image",new {id=#Model.ImageId})}
To use an image rendered from this actionresult in any HTML, use
<img src="http://something.com/image/view?id={imageid}>
This worked for me.
Since I'm storing images on a SQL Server database.
[HttpGet("/image/{uuid}")]
public IActionResult GetImageFile(string uuid) {
ActionResult actionResult = new NotFoundResult();
var fileImage = _db.ImageFiles.Find(uuid);
if (fileImage != null) {
actionResult = new FileContentResult(fileImage.Data,
fileImage.ContentType);
}
return actionResult;
}
In the snippet above _db.ImageFiles.Find(uuid) is searching for the image file record in the db (EF context). It returns a FileImage object which is just a custom class I made for the model and then uses it as FileContentResult.
public class FileImage {
public string Uuid { get; set; }
public byte[] Data { get; set; }
public string ContentType { get; set; }
}
you can use File to return a file like View, Content etc
public ActionResult PrintDocInfo(string Attachment)
{
string test = Attachment;
if (test != string.Empty || test != "" || test != null)
{
string filename = Attachment.Split('\\').Last();
string filepath = Attachment;
byte[] filedata = System.IO.File.ReadAllBytes(Attachment);
string contentType = MimeMapping.GetMimeMapping(Attachment);
System.Net.Mime.ContentDisposition cd = new System.Net.Mime.ContentDisposition
{
FileName = filename,
Inline = true,
};
Response.AppendHeader("Content-Disposition", cd.ToString());
return File(filedata, contentType);
}
else { return Content("<h3> Patient Clinical Document Not Uploaded</h3>"); }
}
Look at ContentResult. This returns a string, but can be used to make your own BinaryResult-like class.
if (!System.IO.File.Exists(filePath))
return SomeHelper.EmptyImageResult(); // preventing JSON GET/POST exception
else
return new FilePathResult(filePath, contentType);
SomeHelper.EmptyImageResult() should return FileResult with existing image (1x1 transparent, for example).
This is easiest way if you have files stored on local drive.
If files are byte[] or stream - then use FileContentResult or FileStreamResult as Dylan suggested.
I see two options:
1) Implement your own IViewEngine and set the ViewEngine property of the Controller you are using to your ImageViewEngine in your desired "image" method.
2) Use a view :-). Just change the content type etc.
You could use the HttpContext.Response and directly write the content to it (WriteFile() might work for you) and then return ContentResult from your action instead of ActionResult.
Disclaimer: I have not tried this, it's based on looking at the available APIs. :-)
I also encountered similar requirement,
So in my case I make a request to Controller with the image folder path, which in return sends back a ImageResult object.
Following code snippet illustrate the work:
var src = string.Format("/GenericGrid.mvc/DocumentPreviewImageLink?fullpath={0}&routingId={1}&siteCode={2}", fullFilePath, metaInfo.RoutingId, da.SiteCode);
if (enlarged)
result = "<a class='thumbnail' href='#thumb'>" +
"<img src='" + src + "' height='66px' border='0' />" +
"<span><img src='" + src + "' /></span>" +
"</a>";
else
result = "<span><img src='" + src + "' height='150px' border='0' /></span>";
And in the Controller from the the image path I produce the image and return it back to the caller
try
{
var file = new FileInfo(fullpath);
if (!file.Exists)
return string.Empty;
var image = new WebImage(fullpath);
return new ImageResult(new MemoryStream(image.GetBytes()), "image/jpg");
}
catch(Exception ex)
{
return "File Error : "+ex.ToString();
}
Read the image, convert it to byte[], then return a File() with a content type.
public ActionResult ImageResult(Image image, ImageFormat format, string contentType) {
using (var stream = new MemoryStream())
{
image.Save(stream, format);
return File(stream.ToArray(), contentType);
}
}
}
Here are the usings:
using System.Drawing;
using System.Drawing.Imaging;
using System.IO;
using Microsoft.AspNetCore.Mvc;
Yes you can return Image
public ActionResult GetImage(string imageFileName)
{
var path = Path.Combine(Server.MapPath("/Images"), imageFileName + ".jpg");
return base.File(path, "image/jpeg");
}
(Please don't forget to mark this as answer)
From a byte[] under Core 3.2, you can use:
public ActionResult Img(int? id) {
MemoryStream ms = new MemoryStream(GetBytes(id));
return new FileStreamResult(ms, "image/png");
}