I am opening a text file in Ada with the following code:
Open (File => out_parcial_variante1, Name => "c.txt", Mode => append_file);
put(File => out_parcial_variante1, Item=> "r");
close(out_parcial_variante1);
The file as a structure like this inside:
01 #510.00:1003.00,512.04:1110.00,515.00:998.00,-98.00,-100.00
<second empty line, this text is not in the file>
Note that besides the initial line the cursor is in a second line there with nothing written.
Whenever my code writes in the file, this happens:
01 #510.00:1003.00,512.04:1110.00,515.00:998.00,-98.00,-100.00
r
It creates another newline instead of appending on the 2nd line like this:
01 #510.00:1003.00,512.04:1110.00,515.00:998.00,-98.00,-100.00
r
How do I fix this?
EDIT: It's a pointer problem since I read the whole line before, but I try to close and open the file again and the pointer remains in the second line instead of going back to the beginning.
I threw together a quick test program with GNAT 2012 on Windows and it works as expected.
Code:
with Ada.Text_IO;
use Ada.Text_IO;
procedure Append_Test is
OPV: File_Type;
begin
Open (OPV, Append_File, "c.txt");
Put (OPV, "r");
Close (OPV);
end Append_Test;
I programmatically created the c.txt file, using Put_Line to output the text, this was the contents of the file:
01 #510.00:1003.00,512.04:1110.00,515.00:998.00,-98.00,-100.00
I used Cygwin's od -t x1 to dump the file, and saw that it terminated with a 0d 0a EOL sequence, i.e. CR/LF.
Running the above code resulted in a file containing the expected output:
01 #510.00:1003.00,512.04:1110.00,515.00:998.00,-98.00,-100.00
r
Again dumping with od showed the file ending with 0d 0a 72 0d 0a. That's the original EOL, to which is appended the 'r' and another EOL.
If this isn't happening for you, then it's not clear what you're actually doing. (Note that on Linux the 0d 0a sequences would instead be simply 0a.)
Related
For instance, Epson's TM-T88V esc/pos manual is like
I need to supply my printer with a buffer that contains the FS C code to change the code page.
# doesnt work, the actual code page number just gets interpreted literally
\x1C \x43 0
\x1C \x430
How do you read escpos manuals?
ESC/POS printer accept data as a series of bytes in your shown example to select Kanji characters for the printer. You need to send three bytes 1C 43 0 the printer will then executes the command.
However, before you send a command to an esc/pos printer you need to send a series of command first and then ends with cut command.
For example
Initialize the printer with 1B 40
Switch to standard mode. 1B 53
your commands 1C 43 0
your data.
Print command. 0A
last command cut paper. 1D 56 00
your printer's programming manual should have detail these steps.
I have a 5GB 1 liner file with JSON data and each line starts from this pattern "{"created". I need to be able to use Unix commands on my Mac to convert this monster of a 1 liner into as many lines as it deserves. Any commands?
ASCII English text, with very long lines, with no line terminators
If you have enough memory you can open the file once with the TextWrangler application (the free BBEdit cousin) and use regular search/replace on the whole file. Use \r in replace to add a return. Will be very slow at opening the file, may even hang if low on memory, but in the end it may probably work. No scripting, no commands,.. etc.. I did this with big SQL files and sometimes it did the job.
You have to replace your line-start string with the same string with \n or \r or \r\n in front of it.
Unclear how it can be a “one liner” file but then each line starts with "{"created", but perhaps python -mjson.tool can help you get started:
cat your_source_file.json | python -mjson.tool > nicely_formatted_file.json
Piping raw JSON through ``python -mjson.tool` will cleanly format the JSON to be more human readable. More info here.
OS X ships with both flex and bison, you can use those to write a parser for your data.
You can use PHP as a shell command (if PHP is installed), just save a text file with name "myscript" and appropriate code (I cannot test code now, but the idea is as follows)
UNTESTED CODE
#!/usr/bin/php
<?php
$REPLACE_STRING='{"created'; // anything you like
// open input file with fopen() in read mode
$inFp=fopen('big_in_file.txt', "r");
// open output file with fopen() in write mode
$outFp=fopen('big_out_file.txt', "w+");
// while not end of file
while (!feof($inFp)) {
// read file chunks here with fread() in variable $chunk
$chunk = fread($inFp, 8192);
// do a $chunk=str_replace($REPLACE_STRING,"\r".$REPLACE_STRING; // to add returns
// (or use \r\n for windows end of lines)
$chunk=str_replace($REPLACE_STRING,"\r".$REPLACE_STRING,$chunk);
// problem: if chunk contains half the string at the end
// easily solved if $REPLACE_STRING is a one char like '{'
// otherwise test for fist char { in the end of $chunk
// remove final part and save it in a var for nest iteration
// write $chunk to output file
fwrite($outFp, $chunk);
// End while
}
?>
After you save it you must make it executable whith sudo chmod a+x ./myscript
and then launch it as ./myscript in terminal
After this, the myscript file is a full unix command
I am studying the Ada-> Cobol interface, and am wondering if there is any way to write the files to cobol default, without having to have a Cobol code written too, because I want to write a file using some rules of COBOL, but would to know how to do this directly in Ada.
For example, to read a file with cobol structure, I can use use that way:
with Interfaces.COBOL;
with COBOL_Sequential_IO; -- Assumed to be supplied by implementation
procedure Test_External_Formats is
112
-- Using data created by a COBOL program
-- Assume that a COBOL program has created a sequential file with
-- the following record structure, and that we need to
-- process the records in an Ada program
-- 01 EMPLOYEE-RECORD
-- 05 NAME PIC X(20).
-- 05 SSN PIC X(9).
-- 05 SALARY PIC 99999V99 USAGE COMP.
-- 05 ADJUST PIC S999V999 SIGN LEADING SEPARATE.
-- The COMP data is binary (32 bits), high-order byte first
113
package COBOL renames Interfaces.COBOL;
114
type Salary_Type is delta 0.01 digits 7;
type Adjustments_Type is delta 0.001 digits 6;
115
type COBOL_Employee_Record_Type is -- External representation
record
Name : COBOL.Alphanumeric(1..20);
SSN : COBOL.Alphanumeric(1..9);
Salary : COBOL.Byte_Array(1..4);
Adjust : COBOL.Numeric(1..7); -- Sign and 6 digits
end record;
pragma Convention (COBOL, COBOL_Employee_Record_Type);
116
package COBOL_Employee_IO is
new COBOL_Sequential_IO(COBOL_Employee_Record_Type);
use COBOL_Employee_IO;
117
COBOL_File : File_Type;
118
type Ada_Employee_Record_Type is -- Internal representation
record
Name : String(1..20);
SSN : String(1..9);
Salary : Salary_Type;
Adjust : Adjustments_Type;
end record;
119
COBOL_Record : COBOL_Employee_Record_Type;
Ada_Record : Ada_Employee_Record_Type;
120
package Salary_Conversions is
new COBOL.Decimal_Conversions(Salary_Type);
use Salary_Conversions;
121
package Adjustments_Conversions is
new COBOL.Decimal_Conversions(Adjustments_Type);
use Adjustments_Conversions;
122
begin
Open (COBOL_File, Name => "Some_File");
123
loop
Read (COBOL_File, COBOL_Record);
124
Ada_Record.Name := To_Ada(COBOL_Record.Name);
Ada_Record.SSN := To_Ada(COBOL_Record.SSN);
Ada_Record.Salary :=
To_Decimal(COBOL_Record.Salary, COBOL.High_Order_First);
Ada_Record.Adjust :=
To_Decimal(COBOL_Record.Adjust, COBOL.Leading_Separate);
... -- Process Ada_Record
end loop;
exception
when End_Error => ...
end Test_External_Formats;
Put, I don't know how to write a File with cobol structure, in the documentation, I not find a way; http://www-users.cs.york.ac.uk/~andy/lrm95/b_04.htm
For example, if I have that struct in Cobol ( based on this sample: http://www.csis.ul.ie/cobol/examples/Sort/MaleSort.htm ; http://www.csis.ul.ie/cobol/examples/SeqIns/STUDENTS.DAT )
FILE SECTION.
FD StudentFile.
01 StudentRec PIC X(30).
88 EndOfFile VALUE HIGH-VALUES.
FD MaleStudentFile.
01 MaleStudentRec PIC X(30).
SD WorkFile.
01 WorkRec.
02 FILLER PIC 9(7).
02 WStudentName PIC X(10).
02 FILLER PIC X(12).
02 WGender PIC X.
88 MaleStudent VALUE "M".
How I can make a program to write this struct, in Ada, using Cobol interfaces ?
Think physically. That is, what is the output file's format? Whether you create that file in Cobol or Ada is NOT an immediate issue when designing a file.
Let's assume that Cobol Workrec describes your file's format. Do you want to write an Ada program that calls a cobol subroutine to physically write the file? or do you want to use a Cobol program to write the file? Or do you want an Ada program that writes a file in the smae format as Workrec?? Your choice depends on your customer's requirements.
I want to modify GDLC MP4 Muxer so that
it will not send data to other writer but it will just record it
itself to a file data itself...
It will be not a muxer any more...it will be a writer which have mp4 muxer...
But firstly i have to figure out, where is the last [muxed] data stay , so that i can write it to a file...
To get a playable file, i have to write the data where?
My Attempts:
I put debug info and see that it calls Append and this method call Replace periodically...I write the buffer [ BYTE pBuffer] which is given to Append method of MuxOutput .I get binary data which has some headers but not playable...So it its wrong place or i do it wrong.....Then i check what calls Append --- FillSpace methos and YUVVideoHandler::WriteDescriptor... But can not able to get usefull info from other methods call Append...
UPDATE
Well, i can able to write data to file at MuxOutput::Replace method...The problem is that the header info and footer(tables at the end of file) are wrong... The other data [ payload data] is correct... The playable file which is recorded by File writer started with 00 00 00 18...[hexadecimal] but my recorded data start with 00 00 00 08 [hexadecimal].... when i replace the mp4 header and footer parts with the file generated by the file writer using a hex editor tool, file becomes identical and plays.
What may be the problem?
In Mpeg4Mux::Pause, the MovieWriter is created with a pointer to an AtomWriter interface (in my case, implemented by the output pin by calls to the downstream file-writer filter). All writes to the file are via this interface. The data is written first, and then on stop, the index data (moov chunk) is written and the file header and data chunk headers are updated.
G
I think your problem is caused by Random File Access requirement which is supported by File Writer Filter by default. The steps you need to follow is:
1) Create an empty file at the beginning
std::ofstream outFile;
outFile.open("c:\\out.mp4", ios_base::out | ios_base::binary);
outFile.close();
2) Open file for random access
outFile.open("c:\\out.mp4", ios_base::in | ios_base::out | ios_base::binary);
3) Right after output pin's Write() method add these lines (replace position, buffer and bufferSize with suitable variable names)
outFile.seekp(position);
outFile.write(buffer, bufferSize);
4) At the end of the recording session (somewhere like a Close() method of the muxer) add
outFile.close();
And you are done.
I am trying to write a unix command line utility that will extract the "application" icon from a Windows Mobile executable. When I look inside the .exe with wrestool from the icoutils package, I see multiple icon and group_icon resources. I am trying to figure out which icon the Windows Mobile Programs view would choose to display to the end user.
At first, I figured it would be the icon with name 32512 (IDI_APPLICATION), but then I found several Windows Mobile binaries that lacked this icon resource, but sure enough had visible icons in the Programs view.
Is there a simple but correct algorithm? like lowest resource id? Is there another resource in the .exe that tells me what is the application icon? Is there something obvious that I am missing?
Any insight would be appreciated.
It's the first RT_GROUP_ICON resource in the executable.
Let's show by steps. First, you need to look what is inside your EXE:
wrestool -l file.exe
Normally, the best icon its the first GROUP_ICON, but when the GROUP_ICONs names are words instead of numbers, then is the GROUP_ICON with the biggest size (or the second biggest size if the first GROUP_ICON is blank, you will need to extract both).
wrestool -x -t14 -n(GROUP_ICON name) file.exe > file.ico
If you want to create a perfect code, you probably should include the GROUP_ICON language too (sometimes the exe won't have a language (16-bit applications), so you will need to put both of the codes):
wrestool -x -t14 -n(GROUP_ICON name) -l(GROUP_ICON language) file.exe > file.ico
In some apps, the GROUP_ICON extraction will fail. That's because some new apps (like new games) are using GROUP_ICON as a link, and inserting the real icons inside ICONs. Then, you will need to extract the biggest ICON with that code:
wrestool -x -R -t3 -n(ICON name) -o. file.exe > file.ico
BUT there will be a BIG problem. That will extract the ICON, but a little part of the file will be missing, which is essential to open this file as an .ico. You will need to open that file in a Hexadecimal Editor and insert in the file a little HEX code before everything else.
00 00 01 00 01 00 80 80 00 00 01 00 18 00 28 C8 00 00 16 00 00 00
Probably, now you think this is the end. NO. The worse part is coming: extract the correct pic from the ICO. Firstly, you will need not only wrestool, but icotool. Then, use that code:
icotool -l file.ico
Then, you will need to extract the file with the biggest width, height and bit-depth.
icotool -x -o. -w(Width) -h(Height) -b(Bit-depth) file.ico
The result will be a PNG file with the perfect icon. Sometimes, that code can fail (Example: The program "Robust Motion Deblurring"), then you will need a second conversor to change from ICO to PNG, but that conversor can fail in some cases (Example: The game "Mass Effect"), so you probably will need both in your code.
I have used that logic in an Objective-C program once, so I know that it's functional (and until now, with 99,9% of success).