HI I am tiring to implement a CFB with DES. I think i am able to encrypt using with CFB but how can I decrypt?? My main issue is CFB code for encrypting using CFB correct ??. Due to the restriction I have, I am unable to use other library.
for (int i = 0; i < VecMSG.size(); i++) {
DESEncrypt(IV, Key);
stringstream str;
str << bitset < 32 > (V[0]); //First 32 bits convert to string
str << bitset < 32 > (V[1]); //Second 32 bits covert to string and join with the first
VText2 = VText = str.str(); //Store in 2 different strings
VText = VText.substr(0, 5); //Take the most significant first 5 bits in the form of
str.str("");
bitset < 2 > mybits(VText); //covert to bits
bitset < 2 > mybits2(VecMSG[i]); //covert plaintext bits from string to bits
str << (mybits ^= mybits2); //XOR with and convert to string
VecCipher.push_back(str.str()); //Store in a different vector
str.str("");
VText2 = VText2.substr(5) + VecCipher[i]; //Remove the first 5 bits and join ciphertext to the end
V[0] = (unsigned int)VText2.substr(0,32).c_str();
V[1] = (unsigned int)VText2.substr(32).c_str();
}
Related
I have an arudino code where I get some temperature reading:
double c1 = device.readCelsius();
Serial.println(c1);
The output is for example: 26.23
What I need is to get this converted to 2623 and then to HEX value so I get: 0x0A3F
Any clue?
I guess your float values always get numbers up to two decimal. So, you can just multiply the value which you read from sensor with a 100.
decimalValue = 100 * c1
And then you can use this small code for converting the decimal value to HEX.
Thanks to GeeksforGeeks
You can find the full tutorial here
// C++ program to convert a decimal
// number to hexadecimal number
#include <iostream>
using namespace std;
// function to convert decimal to hexadecimal
void decToHexa(int n)
{
// char array to store hexadecimal number
char hexaDeciNum[100];
// counter for hexadecimal number array
int i = 0;
while (n != 0) {
// temporary variable to store remainder
int temp = 0;
// storing remainder in temp variable.
temp = n % 16;
// check if temp < 10
if (temp < 10) {
hexaDeciNum[i] = temp + 48;
i++;
}
else {
hexaDeciNum[i] = temp + 55;
i++;
}
n = n / 16;
}
// printing hexadecimal number array in reverse order
for (int j = i - 1; j >= 0; j--)
cout << hexaDeciNum[j];
}
// Driver program to test above function
int main()
{
int n = 2545;
decToHexa(n);
return 0;
}
The usual hash-functions, e.g. from digest create hex output. I want to create a hash with character from a given set, e.g [a-z,0-9]; no strong cryptographic security is required.
Using base64encode on a hashed string comes close, but the character set is fixed in that function.
It is ugly div/mod manipulation for an arbitrary character table, so I decided to use a 32 character table without l 0, O
#include <Rcpp.h>
using namespace Rcpp;
static const std::string base32_chars = "abcdefghijkmnpqrstuvwxyz23456789";
// [[Rcpp::export]]
String encode32(uint32_t hash_int, int length = 7)
{
String res;
std::ostringstream oss;
if (length > 7 || length < 1)
length = 7;
for (int i = 0; i < length; i++) {
oss << base32_chars[hash_int & 31];
hash_int = hash_int >> 5;
}
res = oss.str();
return res;
}
/*** R
print(encode32(digest::digest2int("Hellod")))
*/
My question will be Arduino specific, I wrote a code that turns array of characters (text) into binary string, but the problem is that the binary representation is not 8 bits, its sometimes 7 bits, 6 bits or even 1 bit representation (if you have a value of 1 as decimal). I'm using String constructor String(letter, BIN) to store the binary representation of letter in a string.
I would like to have a 8 bits representation or even a 7 bits representation.
String text = "meet me in university";
String inbits;
byte after;
byte bits[8];
byte x;
char changed_char;
void setup() {
Serial.begin(9600);
}
void loop() {
Serial.println("Press anything to begin");
inbits = convertToBits(text);
}
String convertToBits(String plaintext)
{
String total,temp;
total = String(plaintext[0],BIN);
total = String(total + " ");
for (int i=1;i<plaintext.length();i++)
{
temp = String (plaintext[i],BIN);
total = String(total + temp);
total = String(total + " ");
}
Serial.println(total);
return total;
}
If the length of the argument string is less then 8, prepend "0"s until it is 8 bits long.
You could do something similar to the following:
void PrintBinary(const std::string& test)
{
for (int c = 0; c < test.length(); c++)
{
unsigned bits = (unsigned)test[c];
for (int i = 0; i < 8; i++)
{
std::cout << ((bits >> (7 - i)) & 1U);
}
std::cout << " ";
}
}
Modifying the above example to use String and Serial.println instead of std::string and std::cout should be trivial. I don't own an arduino to test with so I couldn't modify your code and test if the above is possible in the environment you work in but I assume it is.
PrintBinary("Hello"); //Output: 01001000 01100101 01101100 01101100 01101111
String(letter, BIN) doesn't zero pad the string. You have to do it yourself.
You need to prepend the 0 character until your binary string is 8 characters long.
String convertToBits(String plaintext)
{
String total, temp;
total = "";
for (int i=0; i<plaintext.length(); i++)
{
temp = String (plaintext[i], BIN);
while (temp.length() < 8)
temp = '0' + temp;
if (i > 0)
total = String(total + " ");
total = String(total + temp);
}
Serial.println(total);
return total;
}
Recently, I have been trying to educate myself on how to encrypt and decrypt using the Vigenere Cipher.
I have successfully encrypted the message and these are the steps I undertook to achieve encryption:
Encryption Key: Set
Message: Top secret
Step 1: Numerical representation of key is 18, 4, 19 (Using the table below)
Working Out:
Reminder:
P is the set of plaintext units
C is the set of ciphertext units
K is the set of keys
E: P x K -> C is the encryption function
D: C x K -> P is the decryption function
Plaintext: top secret
Ciphertext: ISIKIVJIM
Although I have managed to encrypt the message "top secret" I am struggling to decrypt messages using the Vigenere Cipher method using the numerical technique I used above. Can someone explain to me how I can decrypt lets say: ISIKIVJIM (the ciphertext from above) to its original plain text message which is "top secret".
Thanks.
As pointed out in the comments the decryption formula is : p = c - k mod 26, also note that we have to perform modular arithmetic so our answer for any input should belong in the range of 0 - 25, i.e if we get a negative number we can add 26(i.e the number we are taking modulo by) until we are within this range you can read more about this here :
https://en.wikipedia.org/wiki/Modular_arithmetic
So the decryption will be like :
L = 11 - 18 = -7 mod 26 = -7 + 26 = 19 = T
S = 18 - 4 = 14 mod 26 = 14 = O
I = 8 - 19 = -11 mod 26 = -11 + 26 = 15 = P
ans so on...
I have also written a c++ code : http://ideone.com/M3BAmq
I recently wrote a java program that encrypts and decrypts in Vigenere using bytes. You need to convert the plain text/ crypt text into byte array and pass it in.
public static byte [] encryptVigenere (byte [] pt, String key)
{
byte [] c_text = new byte [pt.length];
byte [] key_text = key.getBytes();
byte tmp;
int shift;
for (int i = 0, j = 0; i < pt.length; i++)
{
if (j >= key_text.length)
j = 0;
shift = key_text[j] - 65; //index of alphabet
tmp = (byte) (pt[i] + shift);
if (tmp > 'Z')
tmp = (byte) (pt[i] - (26-shift));
c_text[i] = tmp;
j++;
}
return c_text;
}
public static byte [] decryptVigenere (byte [] ct, String key)
{
byte [] p_text = new byte [ct.length];
byte [] key_text = key.getBytes();
byte tmp;
int shift;
for (int i = 0, j = 0; i < ct.length; i++)
{
if (j >= key_text.length)
j = 0;
shift = key_text[j] - 65; //index of alphabet
tmp = (byte) (ct[i] - shift);
if (tmp < 'A')
tmp = (byte) (ct[i] + (26-shift));
p_text[i] = tmp;
j++;
}
return p_text;
}
I've got the following function to make a conversion from a Hex String to a Byte array. Then, I calculate the Checksum:
private String CalcChecksum (String message) {
/**Get string's bytes*/
//byte[] bytes = DatatypeConverter.parseHexBinary(message.replaceAll("\\s","")).getBytes();
message = message.replaceAll("\\s","");
byte[] bytes = hexToByteArray(message);
byte b_checksum = 0;
for (int byte_index = 0; byte_index < bytes.length; byte_index++) {
b_checksum += bytes[byte_index];
}
int d_checksum = b_checksum; //Convert byte to int(2 byte)
int c2_checksum = 256 - d_checksum; //Hacer complemento a 2
String hexString = Integer.toHexString(c2_checksum); //Convertir el entero (decimal) a hexadecimal
return hexString;
}
public static byte[] hexToByteArray(String s) {
int len = s.length();
byte[] data = new byte[len / 2];
for (int i = 0; i < len; i += 2) {
data[i / 2] = (byte) ((Character.digit(s.charAt(i), 16) << 4) + Character.digit(s.charAt(i+1), 16));
}
return data;
}
Making some test, for example for the hex value "e0", the hexToByteArray is getting the value "-32". So the final returning value in the CalcChecksum is "17a".
What I need is to get unsigned values in the hexToByteArray function. This is because i need to send the Checksum in a hexString to a MCU where the Checksum is calculated with unsigned values, so isntead of get the "-32" value, it gets "224" and the final hex value is "7a" instead of "17a".
i think that doing some kind of conversion like when the byte result is a negative value, do something like 255 + "negative value" + 1. This will convert "-32" into "224".
The problem is that i'm trying to do it, but i'm having some errors making the conversions between bytes, int, etc...
So, how could i do?
For the moment, I think that this can be the solution.
Just including in the CalcChecksum function the next code after int d_checksum = b_checksum;:
if (d_checksum < 0) {
d_checksum = 255 + d_checksum + 1;
}