I am new to R and, have some problems with looping and grepl functions
I have a data from like:
str(peptidesFilter)
'data.frame': 78389 obs. of 130 variables:
$ Sequence : chr "AAAAAIGGR" "AAAAAIGGRPNYYGNEGGR" "AAAAASSNPGGGPEMVR" "AAAAAVGGR" ...
$ First.amino.acid : chr "A" "A" "A" "A" ...
$ Protein.group.IDs : chr "1" "1;2;4" "2;5 "3" "4;80" ...
I want to filter the data according to $ Protein.group.IDs by using grepl function below
peptidesFilter.new <- peptidesFilter[grepl('(^|;)2($|;)',
peptidesFilter$Protein.group.IDs),]
I want to do it with a loop for every individual data ( e.g 1, 2, 3, etc...)
and re-write name of data frame containing variable peptidesFilter.i
i =1
while( i <= N) { peptidesFilter.[[i]] <-
peptidesFilter[grepl('(^|;)i($|;)',
peptidesFilter$Protein.group.IDs),]
i=i+1 }
i have two problems,
main one i in the grep1 function does not recognized as a variable and how i can re-name filtered data in a way it will contain variable.
any ideas?
For grepl problem you can use paste0 for example:
paste0('(^|;)',i,'($|;)')
For the loop , you can so something like this :
ll <- lapply(seq(1:4),function(x)
peptidesFilter[grepl(paste0('(^|;)',x,'($|;)'),
peptidesFilter$Protein.group.IDs),])
then you can transform it to a data.frame:
do.call(rbind,ll)
Sequence First.amino.acid Protein.group.IDs
1 AAAAAIGGR A 1
2 AAAAAIGGRPNYYGNEGGR A 1;2;4
21 AAAAAIGGRPNYYGNEGGR A 1;2;4
3 AAAAASSNPGGGPEMVR A 2;5
4 AAAAAVGGR A 3
22 AAAAAIGGRPNYYGNEGGR A 1;2;4
Related
I am looking for another way to achieve the same result because the for statement is too slow.
I have the following data frame.
'data.frame': 50000 obs. of 2 variables:
$ user_id: chr "user1#test.com" "user2#test.com" ......
$ result : logi NA NA ......
Function f takes a user ID and returns a specific result.
f <- function(user_id){
......
return(json_result)
}
The result I want is as follows.
'data.frame': 50000 obs. of 2 variables:
$ user_id: chr "user1#test.com" "user2#test.com" ......
$ result : chr "{....}" "{....}" ......
I am running a loop like the code below, but the speed is too slow.
for (t in df$user_id) {
print(t)
df$result[df$user_id==t] <- f(t)
}
It takes about 3 seconds per user, and 3*50000 seconds to get a total of 50,000 users.
Is there any other way to get results faster?
You're looking for lapply function:
df$result <- lapply(df$user_id, f)
Alternatively, you can use purrr's map functions.
library(tidyverse)
purrr::map(df$user_id, f)
This will output a list where each element is the output of the function call. Depending on the output of your function, you could use a map variant to output a vector of some type. You can read about this in the docs: https://purrr.tidyverse.org/reference/map.html
I'm trying to import a csv with blanks read as "". Unfortunately they're all reading as "NA" now.
To better demonstrate the problem I'm also showing how NA, "NA", and "" are all mapping to the same thing (except in the very bottom example), which would prevent the easy workaround dt[is.na(dt)] <- ""
> write.csv(matrix(c("0","",NA,"NA"),ncol = 2),"MRE.csv")
Opening this in notepad, it looks like this
"","V1","V2"
"1","0",NA
"2","","NA"
So reading that back...
> fread("MRE.csv")
V1 V1 V2
1: 1 0 NA
2: 2 NA NA
The documentation seems to suggest this but it does not work as described
> fread("MRE.csv",na.strings = NULL)
V1 V1 V2
1: 1 0 NA
2: 2 NA NA
Also tried this which reads the NA as an actual NA, but the problem remains for the empty string which is read as "NA"
> fread("MRE.csv",colClasses=c(V1="character",V2="character"))
V1 V1 V2
1: 1 0 <NA>
2: 2 NA NA
> fread("MRE.csv",colClasses=c(V1="character",V2="character"))[,V2]
[1] NA "NA"
data.table version 1.11.4
R version 3.5.1
A few possible things going on here:
Regardless of you writing "0" here, the reading function (fread) is inferring based on looking at a portion of the file. This is not uncommon (readr does it, too), and is controllable (with colClasses=).
This might be unique to your question here (and not your real data), but your call to write.csv is implicitly putting the literal NA letters in the file (not to be confused with "NA" where you have the literal string). This might be confusing things, even when you override with colClasses=.
You might already know this, but since fread is inferring that those columns are really integer classes, then they cannot contain empty strings: once determined to be a number column, anything non-number-like will be NA.
Let's redo your first csv-generating side to make sure we don't confound the situation.
write.csv(matrix(c("0","",NA,"NA"),ncol = 2), "MRE.csv", na="")
(Below, I'm using magrittr's pipe operator %>% merely for presentation, it is not required.)
The first example demonstrates fread's inference. The second shows our overriding that behavior, and now we have blank strings in each NA spot that is not the literal string "NA".
fread("MRE.csv") %>% str
# Classes 'data.table' and 'data.frame': 2 obs. of 3 variables:
# $ V1: int 1 2
# $ V1: int 0 NA
# $ V2: logi NA NA
# - attr(*, ".internal.selfref")=<externalptr>
fread("MRE.csv", colClasses="character") %>% str
# Classes 'data.table' and 'data.frame': 2 obs. of 3 variables:
# $ V1: chr "1" "2"
# $ V1: chr "0" ""
# $ V2: chr "" "NA"
# - attr(*, ".internal.selfref")=<externalptr>
This can also be controlled on a per-column basis. One issue with this example is that fread is for some reason forcing the column of row-names to be named V1, the same as the next column. This looks like a bug to me, perhaps you can look at Rdatatable's issues and potentially post a new one. (I might be wrong, perhaps this is intentional/known behavior.)
Because of this, per-column overriding seems to stop at the first occurrence of a column name.
fread("MRE.csv", colClasses=c(V1="character", V2="character")) %>% str
# Classes 'data.table' and 'data.frame': 2 obs. of 3 variables:
# $ V1: chr "1" "2"
# $ V1: int 0 NA
# $ V2: chr "" "NA"
# - attr(*, ".internal.selfref")=<externalptr>
One way around this is to go with an unnamed vector, requiring the same number of classes as the number of columns:
fread("MRE.csv", colClasses=c("character","character","character")) %>% str
# Classes 'data.table' and 'data.frame': 2 obs. of 3 variables:
# $ V1: chr "1" "2"
# $ V1: chr "0" ""
# $ V2: chr "" "NA"
# - attr(*, ".internal.selfref")=<externalptr>
Another way (thanks #thelatemail) is with a list:
fread("MRE.csv", colClasses=list(character=2:3)) %>% str
# Classes 'data.table' and 'data.frame': 2 obs. of 3 variables:
# $ V1: int 1 2
# $ V1: chr "0" ""
# $ V2: chr "" "NA"
# - attr(*, ".internal.selfref")=<externalptr>
Side note: if you need to preserve them as ints/nums, then:
if your concern is about how it affects follow-on calculations, then you can:
fix the source of the data so that nulls are not provided;
filter out the incomplete observations (rows); or
fix the calculations to deal intelligently with missing data.
if your concern is about how it looks in a report, then whatever tool you are using to render in your report should have a mechanism for how to display NA values; for example, setting options(knitr.kable.NA="") before knitr::kable(...) will present them as empty strings.
if your concern is about how it looks on your console, you have two options:
interfere with the data by iterating over each (intended) column and changing NA values to ""; this only works on character columns, and is irreversible; or
write your own subclass of data.frame that changes how it is displayed on the console; the benefit to this is that it is non-destructive; the problem is that you have to re-class each object where you want this behavior, and most (if not all) functions that output frames will likely inadvertently strip or omit that class from your input. (You'll need to write an S3 method of print for your subclass to do this.)
I can't really create a code example because I'm not quite sure what the problem is and my actual problem is rather involved. That said it seems like kind of a generic problem that maybe somebody's seen before.
Basically I'm constructing 3 different dataframes and rbinding them together, which is all as expected smooth sailing but when I try to write that merged frame back to the DB I get this error:
Error in .External2(C_writetable, x, file, nrow(x), p, rnames, sep, eol, :
unimplemented type 'list' in 'EncodeElement'
I've tried manually coercing them using as.data.frame() before and after the rbinds and the returned object (the same one that fails to write with the above error message) exists in the environment as class data.frame so why does dbWriteTable not seem to have got the memo?
Sorry, I'm connecting to a MySQL DB using RMySQL. The problem I think as I look a little closer and try to explain myself is that the columns of my data frame are themselves lists (of the same length), which sorta makes sense of the error. I'd think (or like to think anyways) that a call to as.data.frame() would take care of that but I guess not?
A portion of my str() since it's long looks like:
.. [list output truncated]
$ stcong :List of 29809
..$ : int 3
..$ : int 8
..$ : int 4
..$ : int 2
I guess I'm wondering if there's an easy way to force this coercion?
Hard to say for sure, since you provided so little concrete information, but this would be one way to convert a list column to an atomic vector column:
> d <- data.frame(x = 1:5)
> d$y <- as.list(letters[1:5])
> str(d)
'data.frame': 5 obs. of 2 variables:
$ x: int 1 2 3 4 5
$ y:List of 5
..$ : chr "a"
..$ : chr "b"
..$ : chr "c"
..$ : chr "d"
..$ : chr "e"
> d$y <- unlist(d$y)
> str(d)
'data.frame': 5 obs. of 2 variables:
$ x: int 1 2 3 4 5
$ y: chr "a" "b" "c" "d" ...
This assumes that each element of your list column is only a length one vector. If any aren't, things will be more complicated, and you'd likely need to rethink your data structure anyhow.
I have a dataframe which looks like that:
'data.frame': 3036 obs. of 751 variables:
$ X : chr "01.01.2002" "02.01.2002" "03.01.2002" "04.01.2002" ...
$ A: chr "na" "na" "na" "na" ...
$ B: chr "na" "1,827437365" "0,833922973" "-0,838923572" ...
$ C: chr "na" "1,825300613" "0,813299479" "-0,866639008" ...
$ D: chr "na" "1,820482187" "0,821374034" "-0,875963104" ...
...
I have converted the X row into a date format.
dates <- as.Date(dataFrame$X, '%d.%m.%Y')
Now I want to replace this row. The thing is I cannot create a new dataframe because I after D there are coming over 1000 more rows...
What would be a possible way to do that easily?
I think what you want is simply:
dataFrame$X <- dates
if you you want to do is replace column X with dates. If you want to remove column X, simply do the following:
dataFrame$X <- NULL
(edited with more concise removal method provided by user #shujaa)
for starters: I searched for hours on this problem by now - so if the answer should be trivial, please forgive me...
What I want to do is delete a row (no. 101) from a data.frame. It contains test data and should not appear in my analyses. My problem is: Whenever I subset from the data.frame, the attributes (esp. comments) are lost.
str(x)
# x has comments for each variable
x <- x[1:100,]
str(x)
# now x has lost all comments
It is well documented that subsetting will drop all attributes - so far, it's perfectly clear. The manual (e.g. http://stat.ethz.ch/R-manual/R-devel/library/base/html/Extract.data.frame.html) even suggests a way to preserve the attributes:
## keeping special attributes: use a class with a
## "as.data.frame" and "[" method:
as.data.frame.avector <- as.data.frame.vector
`[.avector` <- function(x,i,...) {
r <- NextMethod("[")
mostattributes(r) <- attributes(x)
r
}
d <- data.frame(i= 0:7, f= gl(2,4),
u= structure(11:18, unit = "kg", class="avector"))
str(d[2:4, -1]) # 'u' keeps its "unit"
I am not yet so far into R to understand what exactly happens here. However, simply running these lines (except the last three) does not change the behavior of my subsetting. Using the command subset() with an appropriate vector (100-times TRUE + 1 FALSE) gives me the same result. And simply storing the attributes to a variable and restoring it after the subset, does not work, either.
# Does not work...
tmp <- attributes(x)
x <- x[1:100,]
attributes(x) <- tmp
Of course, I could write all comments to a vector (var=>comment), subset and write them back using a loop - but that does not seem a well-founded solution. And I am quite sure I will encounter datasets with other relevant attributes in future analyses.
So this is where my efforts in stackoverflow, Google, and brain power got stuck. I would very much appreciate if anyone could help me out with a hint. Thanks!
If I understand you correctly, you have some data in a data.frame, and the columns of the data.frame have comments associated with them. Perhaps something like the following?
set.seed(1)
mydf<-data.frame(aa=rpois(100,4),bb=sample(LETTERS[1:5],
100,replace=TRUE))
comment(mydf$aa)<-"Don't drop me!"
comment(mydf$bb)<-"Me either!"
So this would give you something like
> str(mydf)
'data.frame': 100 obs. of 2 variables:
$ aa: atomic 3 3 4 7 2 7 7 5 5 1 ...
..- attr(*, "comment")= chr "Don't drop me!"
$ bb: Factor w/ 5 levels "A","B","C","D",..: 4 2 2 5 4 2 1 3 5 3 ...
..- attr(*, "comment")= chr "Me either!"
And when you subset this, the comments are dropped:
> str(mydf[1:2,]) # comment dropped.
'data.frame': 2 obs. of 2 variables:
$ aa: num 3 3
$ bb: Factor w/ 5 levels "A","B","C","D",..: 4 2
To preserve the comments, define the function [.avector, as you did above (from the documentation) then add the appropriate class attributes to each of the columns in your data.frame (EDIT: to keep the factor levels of bb, add "factor" to the class of bb.):
mydf$aa<-structure(mydf$aa, class="avector")
mydf$bb<-structure(mydf$bb, class=c("avector","factor"))
So that the comments are preserved:
> str(mydf[1:2,])
'data.frame': 2 obs. of 2 variables:
$ aa:Class 'avector' atomic [1:2] 3 3
.. ..- attr(*, "comment")= chr "Don't drop me!"
$ bb: Factor w/ 5 levels "A","B","C","D",..: 4 2
..- attr(*, "comment")= chr "Me either!"
EDIT:
If there are many columns in your data.frame that have attributes you want to preserve, you could use lapply (EDITED to include original column class):
mydf2 <- data.frame( lapply( mydf, function(x) {
structure( x, class = c("avector", class(x) ) )
} ) )
However, this drops comments associated with the data.frame itself (such as comment(mydf)<-"I'm a data.frame"), so if you have any, assign them to the new data.frame:
comment(mydf2)<-comment(mydf)
And then you have
> str(mydf2[1:2,])
'data.frame': 2 obs. of 2 variables:
$ aa:Classes 'avector', 'numeric' atomic [1:2] 3 3
.. ..- attr(*, "comment")= chr "Don't drop me!"
$ bb: Factor w/ 5 levels "A","B","C","D",..: 4 2
..- attr(*, "comment")= chr "Me either!"
- attr(*, "comment")= chr "I'm a data.frame"
For those who look for the "all-in" solution based on BenBarnes explanation: Here it is.
(give the your "up" to the post from BenBarnes if this is working for you)
# Define the avector-subselection method (from the manual)
as.data.frame.avector <- as.data.frame.vector
`[.avector` <- function(x,i,...) {
r <- NextMethod("[")
mostattributes(r) <- attributes(x)
r
}
# Assign each column in the data.frame the (additional) class avector
# Note that this will "lose" the data.frame's attributes, therefore write to a copy
df2 <- data.frame(
lapply(df, function(x) {
structure( x, class = c("avector", class(x) ) )
} )
)
# Finally copy the attribute for the original data.frame if necessary
mostattributes(df2) <- attributes(df)
# Now subselects work without losing attributes :)
df2 <- df2[1:100,]
str(df2)
The good thing: When attached the class to all the data.frame's element once, the subselects never again bother attributes.
Okay - sometimes I am stunned how complicated it is to do the most simple operations in R. But I surely did not learn about the "classes" feature if I just marked and deleted the case in SPSS ;)
This is solved by the sticky package. (Full Disclosure: I am the package author.) Apply the sticky() to your vectors and the attributes are preserved through subset operations. For example:
> df <- data.frame(
+ sticky = sticky( structure(1:5, comment="sticky attribute") ),
+ nonstick = structure( letters[1:5], comment="non-sticky attribute" )
+ )
>
> comment(df[1:3, "nonstick"])
NULL
> comment(df[1:3, "sticky"])
[1] "sticky attribute"
This works for any attribute and not only comment.
See the sticky package for details:
on Github
on CRAN
I spent hours trying to figure out how to retain attribute data (specifically variable labels) when subsetting a dataframe (removing columns). The answer was so simple, I couldn't believe it. Just use the function spss.get from the Hmisc package, and then no matter how you subset, the variable labels are retained.