Select an element with empty class attribute (class="") using CSS? - css

Is there a CSS way to select an element that looks like that by class?
<a class="" href="...">
Like a selector for empty class declarations?

Provided the class attribute is present as you say you can use the attribute selector like this:
jsFiddle
<a class="" href="...">asd</a>
a[class=""] {
color: red;
}
If you want this to work when there is no class attribute present on the element you can use :not([class]).
jsFiddle
asd
a:not([class]) {
color: red;
}
These can then be combined together to handle both cases.
jsFiddle
asd
<a class="" href="...">asd</a>
a[class=""],
a:not([class]) {
color: red;
}

You can use element-attribute selector here with an empty class value
div[class=""] {
color: red;
}
Demo
Note: You can replace the div with required element

Related

Is there a way to use variable CSS selector which can selectively apply css to html element which has classes which is a variable?

I have say 3 spans as below :
<span class = "testVar1" onClick = "testFunction(Var1)">
<span class = "testVar2" onClick = "testFunction(Var2)">
<span class = "testVar3" onClick = "testFunction(Var3)">
testFunction(var){
here I assign class "on" to the span which calls this function
}
If span with class testVar1 calls this then it becomes
<span class = "testVar1 on" onClick = "testFunction(Var1)"></span>
My Css is as below
.test .on {
some CSS
}
Is there a way in CSS where I can use a variable and apply css to those span which is clicked?
Like
.test[Var1 or Var2 or Var3] .on {
some CSS
}
I have achieved it by using multiple selectors manually like#
.testVar1 .on {
some CSS
}
.testVar2 .on {
some CSS
}
I have read the post Using regular expression in css? , it,s helpful but not answering my question.
In this post css is applied to all the element, but I want css to be applied only to the element which called the function.
and so on.
Any help or pointers would be appreciated!
Thanks!
You are making things too complicated. Just use the same CSS class on all of them, then add the click listener programmatically, not as an inline onlick listener:
document.querySelectorAll('span.test').forEach(
span =>
span.addEventListener('click', () => {
console.log(`you clicked ${span.innerText}`)
span.classList.toggle('on')
})
)
.test {
background: red;
color: white;
display: inline-block;
padding: 40px;
}
.test.on {
background: green;
}
<span class="test">foo</span>
<span class="test">bar</span>
<span class="test">baz</span>
If you insist on inline event listeners (you really shouldn't, it's widely considered bad practice), for this simple example it's probably even easier:
function foobar(span) {
console.log(`you clicked ${span.innerText}`)
span.classList.toggle('on')
}
.test {
background: red;
color: white;
display: inline-block;
padding: 40px;
}
.test.on {
background: green;
}
<span class="test" onclick="foobar(this)">foo</span>
<span class="test" onclick="foobar(this)">bar</span>
<span class="test" onclick="foobar(this)">baz</span>
You can use regex selector: span[class^='test'] which means select every span with class start with "test".
You can combine it with another class (.on) like that: span[class^='test'].on
As for inline code, you can do something like that:
const spans = document.querySelectorAll('span[class^="test"]'); // select all spans
for (var i=0; i < spans.length; i++) { // iterate them
spans[i].addEventListener('click',function() { // add event listener to them
this.classList.add('on'); // set class on click
});
}
span[class^='test'] {color: blue;}
span[class^='test'].on { color: red; }
<span class="testVar1">1</span>
<span class="testVar2">2</span>
<span class="testVar3">3</span>
Check this for selecting element with more then one class.
And this for regExp selector.
Enjoy code!

Primeng's [styleClass] with conditional styling

I'd like to put a conditional styling on a primeng 'p-overlayPanel' element. I have tried:
<p-overlayPanel [styleClass]="#{(bean.comment) ? 'style1' : 'style2'}">, but it's not working.
[ng-class]="bean.comment ? 'style1' : 'style2'" - this is not working either.
Styleclass works only without a condition like so:
<p-overlayPanel [styleClass]="style1"> // html file
p-overlayPanel .style1.ui-overlay { background-color: yellow; } // css file
While [ng-class] doesn't work at all (but works fine on vanilla JS elements). Have I missed something? My questions are following:
Is 'ng-class' not working for some of the elements from ngPrime collection?
How to correctly conditionally apply 'styleClass' for p-overlayPanel element?
I'm using Angular 8.
styleClass accept string as a css class or list of classes and apply to the elemnt at that already have a list of these classes overlaypanel ui-widget ui-widget-content ui-corner-all ui-shadow
so if you want to change the background color you have to do it like this
.style1.ui-overlaypanel{
background-color: red;
}
.style2.ui-overlaypanel{
background-color: green;
}
you have to add the class to the global style file not the component style file and if you use style property the value will pass to ngStyle directive.
demo 🚀
🦑 overlaypanel.ts
Updated 🌟
you can use ngClass but the style must be change like the example below , because now the css classes will apply to the element directly.
.style1 .ui-overlaypanel{
background-color: red;
}
.style2 .ui-overlaypanel{
background-color: green;
}
demo 🥈
You can use [ngClass] like this:
<input pInputText [ngModel]="vendor.iban" name="pIban" #pIban="ngModel" (click)="some(pIban)" class="col-md-7 ui-inputtext ui-widget ui-state-default ui-corner-all " [ngClass]="{'errorVendor': vendor.iban=='' && pIban.touched}" />

How to deal with cascading priority in CSS?

Let's say I have links looking like buttons all over my app. They are orange, unless they are "disabled" (having no href):
a.button {
background-color: orange;
}
a.button:not([href]) {
background-color: grey;
}
Now, I'm not sure how to allow certain buttons look different in their context, but keep the disabled ones as they were. Let's say I need the "buttons" inside my <footer> to be green, or - as usual - grey if disabled:
footer a.button {
background-color: green;
}
The problem is that this rule has higher priority, as it's more specific. How can I allow disabled buttons in the footer to still be grey without repeating my code? I know I can use !important, but please assume that my real-life example is more complex and I want to avoid using it.
Use CSS variables. You define the default value and you simply set the variable to define a new one.
a.button {
background-color: var(--main, orange);
}
a.button:not([href]) {
background-color: var(--disable, grey);
}
footer#foo a.button { /*I am adding an ID to make it really more specific*/
--main: green;
}
<a class="button">a link</a>
a link
<footer id="foo">
<a class="button">a link</a>
a link
</footer>
Check out http://qnimate.com/dive-into-css-specificity/ to see a full list of CSS specificity.
Assuming you have more than one a.button in your footer, we'll skip using a plain id selector. You could pair an id and attribute selector, using the title attribute to identify all disabled "buttons":
index.html
<a class="button">a link</a>
a link
<footer id="foo">
<a class="button" title="disabled">a link</a>
a link
</footer>
and styles.css
#foo a[title="disabled"] {
color: green;
}

Is self defined property in CSS selector a good choice?

<button bg="blue">blue</button>
<button bg="red">red</button>
[bg="blue"] {
background-color: blue;
}
[bg="red"] {
background-color: red;
}
http://codepen.io/Integ/pen/YPRpWE
No class, no ID, just properties.
Use class is more efficient.
.bg-blue {
background: blue;
}
<div class="bg-blue"></div>
That is called attribute equal selector. Yes, you can use it on your own depending the requirement. Of course, if you don't have set class or id then you can use attribute selectors.
Suggestion:
Use data-* attributes instead of attributes for your custom attributes(It is valid in html5). Example:
<button data-bg="blue">blue</button>

CSS selected/active property

I have twelve <a href> links that lead to different categories. As a means of orientation for the user I would like to emphasise the very category (<a href>-button) that the user is in right now.
How can I achieve this in CSS? I read about selected and active, but I haven't been able to make it work yet.
This is one of the links/buttons:
<span class="category_item"></span><span class="category_description">Handy & Co.</span>
The corresponding CSS:
.category_item {
display:inline-block;
background:url(../img/category_item/ph.png) no-repeat;
width: 45px;
height: 45px;
margin-right: 11px;
margin-bottom: 20px;
}
.category_item:hover {
background:url(../img/category_item/hover.png);
}
.category_description {
position: absolute;
font-size: 11px;
color: #000;
margin-top: 43px;
margin-left: -62px;
z-index: 1;
opacity: 0;
}
Thank you in advance!
You can run some jquery code when you load the page that checks the link urls with the current page's url and setting a class on the links that match.
JSFiddle: http://jsfiddle.net/og4o1tdh/2/
something like this:
HTML:
<div id="categories">
<span class="category_description">Google</span>
<!-- jsfiddle code is apparently run on fiddle.jshell.net -->
<span class="category_description">JSFiddle</span>
</div>
JS:
$('#categories a').each(function (){
var link = $(this).attr('href');
if (window.location.href.indexOf(link) > -1) {
$(this).find('span').addClass('currentCategory');
}
});
CSS:
.currentCategory {
color: orange;
font-weight: bold;
}
To give a special class to an anchor when a user clicks you can use simple javascript and jQuery.
Give all the anchor's you want to be in the scope of this a class for instance:
HTML:
<a class="nav-link" href="http://www.google.com"> Google </a>
<a class="nav-link" href="http://www.yahoo.com"> Yahoo </a>
Javascript:
$(".nav-link").on("click", function() {
$(this).addClass("active");
});
To make sure you only have one anchor with "active" class I would do the following:
$(".nav-link").on("click", function() {
$(".nav-link").removeClass("active");
$(this).addClass("active")
});
There is no built-in way of knowing which link is the current one. The easiest way may be to use javascript to check the current URL by document.URL and add a CSS class to the link with an equal href attribute. Then, you may style this class in CSS.
CSS doesn't know what page you are on.
To do this you will have to change your HTML markup, for example: to add:
<a class="current-page" href="index.php?category=handy&location=&sort=" ...
on the relevant link which you can use to 'hook' an new CSS style onto:
.current-page { color: red; }
The alternative is to use Javascript to 'read' the URL and apply a style.
You could...
Simply add a unique classname to the body tag or (some element that wraps around the anchor tags). And then style your links accordingly. This option is quite easy if you have access to change the HTML in your pages:
HTML
<body class="category_handy">
...
<a href="..." class="category_handy">
<span class="category_item"></span>
<span class="category_description">Handy & Co.</span>
</a>
....
</body>
CSS
body.category_handy a.category_handy {
color:red;
}
body.category_dandy a.category_dandy {
color:yellow;
}
body.category_something a.category_something {
color: blue;
}
If you don't have access to directly edit each page, you may have to dynamically check the URL, and then add a classname (like "current") to the anchor tag who's href attribute matches.
Either way, the solution will not involve "css only".

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