I want to get Inbox via RSS, I can get XML when I use Response.Redirect , but can not get as XML format, it throws (401) unauthorized error My Code is
string url = "https://myusername:mypassword#mail.google.com/mail/feed/atom";
XmlReader reader = XmlReader.Create(url);
SyndicationFeed feed = SyndicationFeed.Load(reader);
reader.Close();
-->Response.redirect(url); //it is working
Can any one have any idea about it,
or
is any verson of AE.Net.Mail.dll for Framework 2.0
Thanks you
The XmlReader class cannot parse authentication information from the URL, you have to create an XmlSettings instance and set its XmlResolver property to an XmlUrlResolver instance that has its credentials set to the username and password. Then when you create the XmlReader instance, you supply the custom XmlSettings instance. The following code would do the trick:
// Create a resolver with your credentials
XmlUrlResolver resolver = new XmlUrlResolver();
resolver.Credentials = new NetworkCredential("myusername", "mypassword");
// Set the reader settings object to use the resolver.
XmlReaderSettings settings = new XmlReaderSettings();
settings.XmlResolver = resolver;
string url = "https://mail.google.com/mail/feed/atom";
// Create the reader using the specified URL and settings
XmlReader reader = XmlReader.Create(url, settings);
SyndicationFeed feed = SyndicationFeed.Load(reader);
reader.Close();
However, I tried this code and the following XmlException was thrown:
"The element with name 'feed' and namespace 'http://purl.org/atom/ns#' is not an allowed feed format."
It appears that the feeds Google outputs are in a format that is incompatible with the SyndicationFeed class. For more information see: http://www.eggheadcafe.com/tutorials/csharp/9faa101f-0a1a-465f-a41a-3e52dd9f7526/everything-rss--atom-feed-parser.aspx
Related
Can objects be appended to post requests in Java or do they have to be converted to Strings first? I know for sure they can be sent as a String using the NameValuePair class, but is there a way to send a serializable plain old Java object through a post request? How would I do that?
EDIT: I found an example, but the post request isn't going through... this is my code:
URL url = new URL("http://localhost:8080/test123/User");
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("POST");
conn.setDoOutput(true); // to be able to write.
conn.setDoInput(true); // to be able to read.
ObjectOutputStream out = new ObjectOutputStream(conn.getOutputStream());
out.writeObject(myObj);
out.close();
Illegal Argument exception: Host name may not be null
I am getting this error at last line
HttpResponse httpResponse = httpClient.execute(get)
I tried all possible solutions like encoding url if contains space etc.. and variables like name and phone all these are from my calling class
Calendar cal = Calendar.getInstance();
SimpleDateFormat sdf = new SimpleDateFormat("HH:mm:ss.SSS");
String time = sdf.format(cal.getTime());
String value="Dish:"+cr.getString(1)+"Quantity:"+cr.getInt(2)+"Price"+cr.getString(3).trim()+"TotalPrice:"+Integer.parseInt(cr.getString(3))*cr.getInt(2)+"Address:"+address+"CustomerName:"+name+"RestaurantName:"+cr.getString(4).trim();
url = "http:twowaits.in/orderapp.php?name="+name.trim()+"&no="+phone.trim()+"&add="+URLEncoder.encode(address, "UTF-8")+"&rest="+URLEncoder.encode(cr.getString(4),"UTF-8")+"&cost="+cr.getString(3).trim()+"&value="+URLEncoder.encode(value, "UTF-8")+"&dishname="+cr.getString(1).trim()+"&qty="+cr.getInt(2)+"&time="+time;
HttpGet get = new HttpGet(url);
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpResponse httpResponse = httpClient.execute(get);
You forgot the // after http:.
url = "http://twowaits.in/......
The stacktrace says it all; your URL does not contain a hostname (a domain name or IP). That means you either didn't supply one, or you made a formatting error somewhere so the URL couldn't be parsed properly. In this case, you did supply a domain name, it's just that the URL isn't formatted properly.
Note that the Apache HttpClient that you are using is deprecated and Google recommends you switch to something else, e.g. URLConnection. Square's OKHttp is also a great alternative.
Also, you might want to try and make your code more readable. Using a builder pattern for your URI would probably help a lot. See URIBuilder or you could just use a StringBuilder.
I have a Debugging Official Account with WeChat. I have entered my public URL and Token into the field provided http://admin.wechat.com/debug/sandbox and also attempted debugging the request with http://admin.wechat.com/debug/
My ASP.Net [.Net4.5] Web API application's POST Method looks like the following :
public HttpResponseMessage PostMessage([FromBody]Strikemedia.Api.WeChat.TextMessage value)
{
if (value == null)
{
var richMediaMessage = new RichMediaMessage();
richMediaMessage.touser = value.FromuserName;
//Create Article
var item = new Article()
{
title = "Didn't receive anything back",
description = "Mind entering 'test'",
picurl = "URL",
url = "URL"
};
var articles = new List<Article>();
articles.Add(item);
richMediaMessage.articles = articles;
richMediaMessage.articleCount = articles.Count;
return Request.CreateResponse(HttpStatusCode.OK, richMediaMessage, "application/json");
}
var exploded = value.Content.Split(' ')[0];
var richMedia = new RichMediaMessage();
richMedia.touser = value.FromuserName;
//Create Article
var article = new Article() {
title = response.KeywordDescription,
description = response.Response,
picurl = "URL",
url = "URL"
};
var _articles = new List<Article>();
_articles.Add(article);
richMedia.articles = _articles;
richMedia.articleCount = _articles.Count;
//Return response
var resp = Request.CreateResponse(HttpStatusCode.OK, richMedia, "application/json");
//resp.RequestMessage.Content.Headers.ContentType = new System.Net.Http.Headers.MediaTypeHeaderValue("application/json");
return resp;
}
It needs to respond with a RichMessageType in JSON format and is received in XML format
Am i missing something or have i overlooked something?
Can you confirm that you have submitted the URL and token into admin.wechat.com and that the URL and token was accepted?
Also note you get XML and you respond with XML no json response.
Have you had a look at: http://youtu.be/kB20Zf51QWU
And then this
http://youtu.be/_2FSzD2B2F0
This is the documentation for the XML can be found when you google "wechat guide to message api"
So if you still not receiving a success message when submitting your app on admin.wechat.com then you can send me your test URL here. To find this URL check your access logs to see exactly what URL wechat is calling. Then post it here. Please note that when you hit the URL as wechat will you should only see the "echostr" printed on the screen (when viewing the source in your browser). No XML no HTML just the echostr.
Also make sure there are no spaces or newlines after or before the "echostr". When you view the source it should only be one line which is the echostr GET param's value.
The XML response only comes in later when you actually start responding to messages from users. For now Wechat is just confirming if your security is setup correctly.
Also note if your server is load balanced you will have to skip the signature validation and build your own validation when a echostr GET parameter gets passed through and only echo the "echostr" param to screen.
I would like to know how best to handle file upload and addtional information added to the file to be uploaded using ASP.NET Web API 2 without MVC components. I have google the net and I can tell you I am more confused than I expected.
The Additional info will be stored in db and the file on the disk.
So far the Web API app I am building does not support multipart/form-data. It only supports the default media types. I know I need to create a media formatter.
Pls help.
I had wrote Javascript split File and upload to WEB API . i think you can reference my backend codes
In front-end you need using below code to upload your File
var xhr = new self.XMLHttpRequest();
xhr.open('POST', url, false);
xhr.setRequestHeader('Content-Type', 'application/octet-stream');
xhr.send(chunk);
In backend use Request.InputStream.Read to catch your file bytes
[HttpPost]
[ValidateInput(false)]
public string fileUpload(string filename)
{
byte[] file = new byte[Request.InputStream.Length];
Request.InputStream.Read(file, 0, Convert.ToInt32(Request.InputStream.Length));
BinaryWriter binWriter = new BinaryWriter(new MemoryStream());
binWriter.Write(file);
StreamReader reader = new StreamReader(binWriter.BaseStream);
reader.BaseStream.Position = 0;
//This example is recevied text file
while ((line = reader.ReadLine()) != null)
{
};
}
You can just serialize your file data into BASE64 and send them as a string in case of multipart/from-data is not allowed for some reason.
I have given
[WebGet(UriTemplate = "/{year}/{issue}/{article}")]
Article GetArticle(string year, string issue, string article);
[OperationContract]
[WebInvoke(UriTemplate = "/{year}/{issue}",Method="POST")]
Article AddArticle(string year, string issue, Article article);
My URL is http://localhost:1355/Issues.svc/
if I give this I am fetching all data from the database
http://localhost:1355/Issues.svc/2010/June/A
GetArticle method fires for the filtered data to bring from db.
Similarly I have to call the Add Article(WebInvoke) method to insert data in to the database.
How should I call this method in the browser
how my url should be should I give method=post
check this post help you to achieve the task you want :Create REST service with WCF and Consume using jQuery
You won't be able to send an HTTP post from a browser by just modifying the URL. You'll have to have a web page with a HTML form, some Javascript code, some server-side code, or something else that has the ability to make an HTTP POST request to your service URL.
If you are just wanting to test your service while in development, here's a good HTTP debugging tool that you might want to check out: http://fiddler2.com
You can't use post it using browser url.
Try this code
//Creating the Web Request.
HttpWebRequest httpWebRequest = HttpWebRequest.Create("http://localhost/DemoApp/Default.aspx") as HttpWebRequest;
//Specifing the Method
httpWebRequest.Method = "POST";
//Data to Post to the Page, itis key value pairs; separated by "&"
string data = "Username=username&password=password";
//Setting the content type, it is required, otherwise it will not work.
httpWebRequest.ContentType = "application/x-www-form-urlencoded";
//Getting the request stream and writing the post data
using (StreamWriter sw = new StreamWriter(httpWebRequest.GetRequestStream()))
{
sw.Write(data);
}
//Getting the Respose and reading the result.
HttpWebResponse httpWebResponse = httpWebRequest.GetResponse() as HttpWebResponse;
using (StreamReader sr = new StreamReader(httpWebResponse.GetResponseStream()))
{
MessageBox.Show(sr.ReadToEnd());
}
Source : http://www.dotnetthoughts.net/2009/11/10/post-data-using-httpwebrequest-in-c-sharp/