Bind Collections To Gridview - asp.net

Question

protected void BindGV()
{
List<List<string>> list = new List<List<string>>()
{
new List<string>() {"Hussain","IT","Hyderabad" },
new List<string>() { "Sharief","IT","Bangalore"},
new List<string>() { "Shaik","IT","Chennai"}
};
gv1.DataSource = list;
gv1.DataBind();
}
I want to display only Name and City in Gridview. I want to use like:
<asp:Boundfield Datafield="" Headertext="Name"/>
How to use DataField in this case??

Answer 1

First of all, you should create a List with some class, rather than string. Then you can use class properties in you DataGrid as columns.
For example:
public class Personnel
{
public string Name { get; set; }
public string Department { get; set; }
public string Location { get; set; }
}
Then you can create a data source like:
protected void BindGV()
{
List< Personnel > list = new List< Personal >()
{
new Personnel {Name = "Hussain", Department = "IT", Location = "Hyderabad" },
new Personnel {Name = "Sharief", Department = "IT", Location = "Bangalore"},
new Personnel {Name = "Shaik", Department = "IT", Location = "Chennai"}
};
gv1.DataSource = list;
gv1.DataBind();
}
In your code behind create DataGrid like
<asp:DataGrid runat="server" ID="gv1" AutoGenerateColumns="False>
<Columns>
<asp:BoundColumn HeaderText="Name" DataField="Name" />
<asp:BoundColumn HeaderText="Dept" DataField="Department" />
<asp:BoundColumn HeaderText="City" DataField="Location" />
</Columns>
</asp:DataGrid>
And that should be it.
UPDATE: According to you comment, you want to access DataField programatically. You can do this by enumerating gv1.Columns property and then cast the result to BoundColumn. This will give you access to DataField and other properties.

Answer 2

as Husein said, first create class with Get , Set .
like
Public class BindGV
{
public string name { get; set ;}
public string Profile { get; set ;}
public string loc { get; set ;}
}
In aspx page Gridview BoundField....
<ItemTemplate..>
<b><%# DataBinder.Eval(Container, "DataItem.Title") %> </b>
<br />
<%# DataBinder.Eval(Container, "DataItem.Description") %>
</ItemTemplate>
... Or Apsx.cs code
BindGV.datasource=object.GetDetails();
BindGV.dataBind();

Answer 3

You can take benefit of linq
List<List<string>> list = new List<List<string>>()
{
new List<string>() {"Hussain", "IT", "Hyderabad"},
new List<string>() {"Sharief", "IT", "Bangalore"},
new List<string>() {"Shaik", "IT", "Chennai"}
};
linq query
var v = from li in list select new {Name = li[0], City=li[2]};
gv1.DataSource = v;
gv1.DataBind();
And gridview
<asp:DataGrid runat="server" ID="gv1" AutoGenerateColumns="False>
<Columns>
<asp:BoundColumn HeaderText="Name" DataField="Name" />
<asp:BoundColumn HeaderText="City" DataField="City" />
</Columns>
</asp:DataGrid>
But this is not a good Idea to use.
You should have a proper structure of you property as suggested by the two gentle men.