I'm trying to work out how to print a list of all available grunt tasks. With rake it would be:
$ rake -T
What's the equivalent for grunt? e.g.
$ grunt -T
concat
jasmine
minify
grunt --help lists available tasks.
Workaround for the list in sh/bash in case you need to trigger something and can't modify the original code:
grunt -h --no-color | sed -n '/^Available tasks/,/^$/ {s/^ *\([^ ]\+\) [^ ]\+.*$/\1/p}'
Related
I try to setup my zsh-completions. I also use oh-my-zsh .
A lot of shell commands provide a some_command completion zsh
and they often suggest sourcing it directly in .zshrc like so:
source <(kubeone completion zsh)
source <(tilt completion zsh)
source <(civo completion zsh)
I can't get it working. Only when I output the command into a file echo "$(kubeone completion zsh)" > ~/.dotfiles/completions/_kubeone.
(That ~/.dotfiles/completions/-path is in my fpath):
fpath=(/usr/local/share/zsh-completions $fpath)
fpath=(~/.dotfiles/completions $fpath)
But that approach is not that neat. I wanna make the use of adding
source $(my_command completion zsh) to my .zsh_rc file.
Interestingly SOME commands are working with that approach: like: source <(kompose completion zsh) but source <(kubeone completion zsh) wont???
Here is an excerpt from my ~/.zshrc:
#!/bin/sh
[ -f ~/.dotfiles/fubectl.source ] && source ~/.dotfiles/fubectl.source
export ZSH_THEME="powerlevel10k/powerlevel10k"
export DOTFILES=$HOME/.dotfiles
export ZSH=$DOTFILES/oh-my-zsh
BUNDLED_COMMANDS=(rubocop)
UNBUNDLED_COMMANDS=(berks foreman mailcatcher rails ruby spin rubocop)
plugins=(zsh-completions zsh-autosuggestions docker fzf bundler brew cask capistrano codeclimate coffee dotenv gem git github grunt helm heroku history iterm2 minikube node redis-cli redis-cli rails rake rake-fast ruby rbenv textmate macos pod zeus terraform)
source $ZSH/oh-my-zsh.sh
complete -o nospace -C /usr/local/bin/terraform terraform
# load autocomplete
fpath=(/usr/local/share/zsh-completions $fpath)
fpath=(~/.dotfiles/completions $fpath)
autoload -U compinit && compinit
source <(kompose completion zsh) # WORKS
source <(kubeone completion zsh) # DONT WORK
(kompose a→tab WORKS)
kubeone a→tab returns only my folder structure
❯ kubeone completion zsh
Application\ Support/ MAMP/ VirtualBox\ VMs/ oh-my-zsh
Applications/ Movies/ Wine\ Files/ output.json
Coding/ Music/ builds/
...
..
.
but should return:
❯ kubeone apply
apply -- Reconcile the cluster
completion -- Generates completion scripts for bash and zsh
config -- Commands for working with the KubeOneCluster configuration manifests
document -- Generates documentation
help -- Help about any command
install -- Install Kubernetes
...
..
.
What I tried so far:
after opening terminal rm ~/.zcompdump*, then tried command, then reopened terminal and tried command again.
autoload -Uz compinit && compinit -i with different arguments
I think there is some misconfiguration or maybe a brew formula is disturbing?
Here is the complete output of my brew list command, as well my complete .zshrc file: https://gist.github.com/exocode/79c9acfad9828b73d05d2abfa39f1724
I want to remove all files in a directory except some in UNIX. Part I desired files have a known name and for the other part, I'm using ls|grep command. But the ls | grep is working when there is only one occurrence and not when there is more than one. it is the same with find|grep. here are my commands:
rm -v !("R1.r"|"R2.r"|"r2.par"|$(ls|grep nario)|"sh.sh")
rm -v !("R1.r"|"R2.r"|"r2.par"|$(find|grep nario)|"sh.sh")
Is there any problem with my commands???
It looks like you're trying to use BASH specific extglob syntax. ls|grep won't work in the middle of the glob, because each pattern needs to be separated by a |, which won't happen with ls|grep. The easier way to do what you want is to use the shell globbing to find the files under the directory you're looking for instead. Make sure you do the following:
Are using BASH
Have extglob enabled: shopt -s extglob
Have globstar enabled: shopt -s globstar
Use file globbing rather than ls | grep
Then try again:
rm -v !("R1.r"|"R2.r"|"r2.par"|**/*nario*|"sh.sh")
Note: globstar requires BASH version 4 or higher.
I've just started Api-Platform framework and while executing:
php bin/schema generate-types src/ app/config/schema.yml
I get this:
C:\wamp\www\sf2-api>php bin/schema generate-types src/ app/config/schema.yml
dir=$(d=${0%[/\\]*}; cd "$d"; cd "../vendor/api-platform/schema-generator/bin" &
& pwd)
# See if we are running in Cygwin by checking for cygpath program
if command -v 'cygpath' >/dev/null 2>&1; then
# Cygwin paths start with /cygdrive/ which will break windows PHP,
# so we need to translate the dir path to windows format. However
# we could be using cygwin PHP which does not require this, so we
# test if the path to PHP starts with /cygdrive/ rather than /usr/bin
if [[ $(which php) == /cygdrive/* ]]; then
dir=$(cygpath -m $dir);
fi
fi
dir=$(echo $dir | sed 's/ /\ /g')
"${dir}/schema" "$#"
I am using Symfony 2.7.8 on window7.
I have the same issue on ubunbu 14.04.
Finally, I replace the bin directory with the one in blog-api.
Updated:
The bin-api-platform is the one generated by api-platform.
The bin-blog-api is the one I copy from blog-api. This works fine.
Use :
php vendor/api-platform/schema-generator/bin/schema generate-types src/app/config/schema.yml
instead of :
php bin/schema generate-types src/ app/config/schema.yml
The correct syntax is:
php vendor/api-platform/schema-generator/bin/schema generate-types src/ app/config/schema.yml
In a Unix environment, I have a bash script that removes some files:
rm -f foo bar* baz*
My problem: not always the wildcard returns any result. And as a result of that, I fail to remove even 'foo' which always exists. The output written is "rm: No match".
A simple workaround would be to split the command:
rm -f foo
rm -f bar*
rm -f baz*
But it's a bad solution.
No it should work. Which shell is used ? Is rm an internal version or an external ? (Try /bin/rm instead to ensure the external version). You may have some shell option set that prevent you to execute the command in that case (this may depend on your shell).
Is it possible to check if a directory exists and delete if it does,in Unix using a single command? I have situation where I use ANT 'sshexec' task where I can run only a single command in the remote machine. And I need to check if directory exists and delete it...
Why not just use rm -rf /some/dir? That will remove the directory if it's present, otherwise do nothing. Unlike rm -r /some/dir this flavor of the command won't crash if the folder doesn't exist.
Assuming $WORKING_DIR is set to the directory... this one-liner should do it:
if [ -d "$WORKING_DIR" ]; then rm -Rf $WORKING_DIR; fi
(otherwise just replace with your directory)
Try:
bash -c '[ -d my_mystery_dirname ] && run_this_command'
This will work if you can run bash on the remote machine....
In bash, [ -d something ] checks if there is directory called 'something', returning a success code if it exists and is a directory. Chaining commands with && runs the second command only if the first one succeeded. So [ -d somedir ] && command runs the command only if the directory exists.
Here is another one liner:
[[ -d /tmp/test ]] && rm -r /tmp/test
&& means execute the statement which follows only if the preceding
statement executed successfully (returned exit code zero)
I recommend opening documentation of rm command.
If open then you will see that there is a
-f flag does what you want. Example: rm -f -R ./my_folder