Greedy optimization in R - r

I am trying to replicate Caruana et al.'s method for Ensemble selection from libraries of models (pdf). At the core of the method is a greedy algorithm for adding models to the ensemble (models can be added more than once). I've written an implementation for this greedy optimization algorithm, but it is very slow:
library(compiler)
set.seed(42)
X <- matrix(runif(100000*10), ncol=10)
Y <- rnorm(100000)
greedOpt <- cmpfun(function(X, Y, iter=100){
weights <- rep(0, ncol(X))
while(sum(weights) < iter) {
errors <- sapply(1:ncol(X), function(y){
newweights <- weights
newweights[y] <- newweights[y] + 1
pred <- X %*% (newweights)/sum(newweights)
error <- Y - pred
sqrt(mean(error^2))
})
update <- which.min(errors)
weights[update] <- weights[update]+1
}
return(weights/sum(weights))
})
system.time(a <- greedOpt(X,Y))
I know R doesn't do loops well, but I can't think of any way to do this type of stepwise search without a loop.
Any suggestions for improving this function?

Here is an R implementation that is 30% faster than yours. Not as fast as your Rcpp version but maybe it will give you ideas that combined with Rcpp will speed things further. The two main improvements are:
the sapply loop has been replaced by a matrix formulation
the matrix multiplication has been replaced by a recursion
greedOpt <- cmpfun(function(X, Y, iter = 100L){
N <- ncol(X)
weights <- rep(0L, N)
pred <- 0 * X
sum.weights <- 0L
while(sum.weights < iter) {
sum.weights <- sum.weights + 1L
pred <- (pred + X) * (1L / sum.weights)
errors <- sqrt(colSums((pred - Y) ^ 2L))
best <- which.min(errors)
weights[best] <- weights[best] + 1L
pred <- pred[, best] * sum.weights
}
return(weights / sum.weights)
})
Also, I maintain you should try upgrading to the atlas library. You might see significant improvements.

I took a shot at writing an Rcpp version of this function:
library(Rcpp)
cppFunction('
NumericVector greedOptC(NumericMatrix X, NumericVector Y, int iter) {
int nrow = X.nrow(), ncol = X.ncol();
NumericVector weights(ncol);
NumericVector newweights(ncol);
NumericVector errors(nrow);
double RMSE;
double bestRMSE;
int bestCol;
for (int i = 0; i < iter; i++) {
bestRMSE = -1;
bestCol = 1;
for (int j = 0; j < ncol; j++) {
newweights = weights + 0;
newweights[j] = newweights[j] + 1;
newweights = newweights/sum(newweights);
NumericVector pred(nrow);
for (int k = 0; k < ncol; k++){
pred = pred + newweights[k] * X( _, k);
}
errors = Y - pred;
RMSE = sqrt(mean(errors*errors));
if (RMSE < bestRMSE || bestRMSE==-1){
bestRMSE = RMSE;
bestCol = j;
}
}
weights[bestCol] = weights[bestCol] + 1;
}
weights = weights/sum(weights);
return weights;
}
')
It's more than twice as fast as the R version:
set.seed(42)
X <- matrix(runif(100000*10), ncol=10)
Y <- rnorm(100000)
> system.time(a <- greedOpt(X, Y, 1000))
user system elapsed
36.19 6.10 42.40
> system.time(b <- greedOptC(X, Y, 1000))
user system elapsed
16.50 1.44 18.04
> all.equal(a,b)
[1] TRUE
Not bad, but I was hoping for a bigger speedup when making the leap from R to Rcpp. This is one of the first Rcpp functions I've ever written, so perhaps further optimization is possible.

Related

Fast random sampling from matrix of cumulative probability mass functions in R

I have a matrix (mat_cdf) representing the cumulative probability an individual in census tract i moves to census tract j on a given day. Given a vector of agents who decide not to "stay home", I have a function, GetCTMove function below, to randomly sample from this matrix to determine which census tract they will spend time in.
# Random generation
cts <- 500
i <- rgamma(cts, 50, 1)
prop <- 1:cts
# Matrix where rows correspond to probability mass of column integer
mat <- do.call(rbind, lapply(i, function(i){dpois(prop, i)}))
# Convert to cumulative probability mass
mat_cdf <- matrix(NA, cts, cts)
for(i in 1:cts){
# Create cdf for row i
mat_cdf[i,] <- sapply(1:cts, function(j) sum(mat[i,1:j]))
}
GetCTMove <- function(agent_cts, ct_mat_cdf){
# Expand such that every agent has its own row corresponding to CDF of movement from their home ct i to j
mat_expand <- ct_mat_cdf[agent_cts,]
# Probabilistically sample column index for every row by generating random number and then determining corresponding closest column
s <- runif(length(agent_cts))
fin_col <- max.col(s < mat_expand, "first")
return(fin_col)
}
# Sample of 500,000 agents' residence ct
agents <- sample(1:cts, size = 500000, replace = T)
# Run function
system.time(GetCTMove(agents, mat_cdf))
user system elapsed
3.09 1.19 4.30
Working with 1 million agents, each sample takes ~10 seconds to run, multiplied by many time steps leads to hours for each simulation, and this function is by far the rate limiting factor of the model. I'm wondering if anyone has advice on faster implementation of this kind of random sampling. I've used the dqrng package to speed up random number generation, but that's relatively miniscule in comparison to the matrix expansion (mat_expand) and max.col calls which take longest to run.
The first thing that you can optimise is the following code:
max.col(s < mat_expand, "first")
Since s < mat_expand returns a logical matrix, applying the max.col function is the same as getting the first TRUE in each row. In this case, using which will be much more efficient. Also, as shown below, you store all your CDFs in a matrix.
mat <- do.call(rbind, lapply(i, function(i){dpois(prop, i)}))
mat_cdf <- matrix(NA, cts, cts)
for(i in 1:cts){
mat_cdf[i,] <- sapply(1:cts, function(j) sum(mat[i,1:j]))
}
This structure may not be optimal. A list structure is better for applying functions like which. It is also faster to run as you do not have to go through a do.call(rbind, ...).
# using a list structure to speed up the creation of cdfs
ls_cdf <- lapply(i, function(x) cumsum(dpois(prop, x)))
Below is your implementation:
# Implementation 1
GetCTMove <- function(agent_cts, ct_mat_cdf){
mat_expand <- ct_mat_cdf[agent_cts,]
s <- runif(length(agent_cts))
fin_col <- max.col(s < mat_expand, "first")
return(fin_col)
}
On my desktop, it takes about 2.68s to run.
> system.time(GetCTMove(agents, mat_cdf))
user system elapsed
2.25 0.41 2.68
With a list structure and a which function, the run time can be reduced by about 1s.
# Implementation 2
GetCTMove2 <- function(agent_cts, ls_cdf){
n <- length(agent_cts)
s <- runif(n)
out <- integer(n)
i <- 1L
while (i <= n) {
out[[i]] <- which(s[[i]] < ls_cdf[[agent_cts[[i]]]])[[1L]]
i <- i + 1L
}
out
}
> system.time(GetCTMove2(agents, ls_cdf))
user system elapsed
1.59 0.02 1.64
To my knowledge, with R only there is no other way to further speed up the code. However, you can indeed improve the performance by re-writing the key function GetCTMove in C++. With the Rcpp package, you can do something as follows:
# Implementation 3
Rcpp::cppFunction('NumericVector fast_GetCTMove(NumericVector agents, NumericVector s, List cdfs) {
int n = agents.size();
NumericVector out(n);
for (int i = 0; i < n; ++i) {
NumericVector cdf = as<NumericVector>(cdfs[agents[i] - 1]);
int m = cdf.size();
for (int j = 0; j < m; ++j) {
if (s[i] < cdf[j]) {
out[i] = j + 1;
break;
}
}
}
return out;
}')
GetCTMove3 <- function(agent_cts, ls_cdf){
s <- runif(length(agent_cts))
fast_GetCTMove(agent_cts, s, ls_cdf)
}
This implementation is lightning fast, which should fulfil all your needs.
> system.time(GetCTMove3(agents, ls_cdf))
user system elapsed
0.07 0.00 0.06
The full script is attached as follows:
# Random generation
cts <- 500
i <- rgamma(cts, 50, 1)
prop <- 1:cts
agents <- sample(1:cts, size = 500000, replace = T)
# using a list structure to speed up the creation of cdfs
ls_cdf <- lapply(i, function(x) cumsum(dpois(prop, x)))
# below is your code
mat <- do.call(rbind, lapply(i, function(i){dpois(prop, i)}))
mat_cdf <- matrix(NA, cts, cts)
for(i in 1:cts){
mat_cdf[i,] <- sapply(1:cts, function(j) sum(mat[i,1:j]))
}
# Implementation 1
GetCTMove <- function(agent_cts, ct_mat_cdf){
mat_expand <- ct_mat_cdf[agent_cts,]
s <- runif(length(agent_cts))
fin_col <- max.col(s < mat_expand, "first")
return(fin_col)
}
# Implementation 2
GetCTMove2 <- function(agent_cts, ls_cdf){
n <- length(agent_cts)
s <- runif(n)
out <- integer(n)
i <- 1L
while (i <= n) {
out[[i]] <- which(s[[i]] < ls_cdf[[agent_cts[[i]]]])[[1L]]
i <- i + 1L
}
out
}
# Implementation 3
Rcpp::cppFunction('NumericVector fast_GetCTMove(NumericVector agents, NumericVector s, List cdfs) {
int n = agents.size();
NumericVector out(n);
for (int i = 0; i < n; ++i) {
NumericVector cdf = as<NumericVector>(cdfs[agents[i] - 1]);
int m = cdf.size();
for (int j = 0; j < m; ++j) {
if (s[i] < cdf[j]) {
out[i] = j + 1;
break;
}
}
}
return out;
}')
GetCTMove3 <- function(agent_cts, ls_cdf){
s <- runif(length(agent_cts))
fast_GetCTMove(agent_cts, s, ls_cdf)
}
system.time(GetCTMove(agents, mat_cdf))
system.time(GetCTMove2(agents, ls_cdf))
system.time(GetCTMove3(agents, ls_cdf))

Efficient way of computing quadratic forms for outer product matrices

I'm currently computing a quadratic form by taking a known vector and using the element wise multiplication of two outer products as the input matrix. To be specific, my code looks something like this
set.seed(42) # for sake of reproducibility
library(emulator)
Fun <- function(a,b) sqrt((1/(2*pi)))*exp(-0.5*(a-b)^2)
n <- 5000
x <- rnorm(n)
y <- rnorm(n)
u <- rnorm(n)
I <- quad.form(outer(x,x,Fun)*outer(y,y,Fun),u)
This is quite slow and the problem gets significantly worse as n increases. As far as I can make out, the part that causes the problem is the outer(x,x,Fun)*outer(y,y,Fun) term inside the quadratic form.
Is there any way to speed this up?
You can half the timings by making use of the symmetry. I find it easiest to quickly write an Rcpp function:
#include <Rcpp.h>
using namespace Rcpp;
// [[Rcpp::export]]
NumericMatrix foo(NumericVector x, NumericVector y) {
double n = x.size();
NumericMatrix M(n, n);
for(double i = 0; i < n; i++) {
for(double j = 0; j <= i; j++) {
M(i,j) = ((1/(2*M_PI))) *
(exp(-0.5*(pow(x(i)-x(j), 2) + pow(y(i)-y(j), 2))));
M(j,i) = M(i,j);
}
}
return M;
}
Timings:
set.seed(42) # for sake of reproducibility
library(emulator)
Fun <- function(a,b) sqrt((1/(2*pi)))*exp(-0.5*(a-b)^2)
n <- 1e4
x <- rnorm(n)
y <- rnorm(n)
u <- rnorm(n)
system.time({
I <- quad.form(outer(x,x,Fun)*outer(y,y,Fun),u)
})
# user system elapsed
# 4.287 1.373 5.687
system.time({
J <- quad.form(foo(x, y),u)
})
# user system elapsed
# 2.232 0.168 2.409
all.equal(I, J)
#[1] TRUE
Further improvements would require parallelization (or possibly use of some maths).

How to make function perform faster?

I have following function: http://i.stack.imgur.com/yXA67.png, where mu is matrix (n_X rows and n_Y columns). d_X and d_Y are distance matrices.
One way to implement this function in R would be:
H_mu <- function(mu, d_X, d_Y){
value <- 0
for(i in 1:nrow(d_X)){
for(ii in 1:nrow(d_X)){
for(j in 1:nrow(d_Y)){
for(jj in 1:nrow(d_Y)){
value <- value + mu[i,j]*mu[ii,jj]*abs(d_X[i,ii]-d_Y[j,jj])
}}}}
}
For example:
X <- matrix(rep(1,50),nrow = 50)
Y <- matrix(c(1:50),nrow = 50)
d_X <- as.matrix(dist(X, method = "euclidean", diag = T, upper = T))
d_Y <- as.matrix(dist(Y, method = "euclidean", diag = T, upper = T))
mu <- matrix(1/50, nrow = nrow(X), ncol = nrow(Y))
H_mu(mu, d_X, d_Y)
[1] 41650
> system.time(H_mu(mu, d_X, d_Y))
user system elapsed
22.67 0.01 23.06
Only with 50 points calculations take 23 seconds.
How to speed up this function?
Seems like #Marat Talipov's suggestion is way to go. If you are not comfortable with coding in C++, you can use typedFunction to auto-generate Rcpp code for simple R functions. It takes R function and it's arguments along with their types, assuming that there is explicit return call, and returns text code.
H_mu <- function(mu, d_X, d_Y){
value <- 0
for(i in 1:nrow(d_X)){
for(ii in 1:nrow(d_X)){
for(j in 1:nrow(d_Y)){
for(jj in 1:nrow(d_Y)){
value <- value + mu[i,j]*mu[ii,jj]*abs(d_X[i,ii]-d_Y[j,jj])
}}}}
return (value)
}
Here I've added return(value) to your H_mu function
text <- typedFunction(H_mu, H_mu='double', value='double',
mu='NumericVector',
d_X='NumericVector',
d_Y='NumericVector',
i='int',
ii='int',
jj='int',
j='int')
cat(text)
Copy-paste the outcome to your Rcpp editor, and after little tweaking you have executable H_mu_typed function.
Rcpp::cppFunction('double H_mu_typed(NumericMatrix mu, NumericMatrix d_X, NumericMatrix d_Y) {
double value=0;
value = 0;
for (int i = 0; i <d_X.nrow(); i++) {
for (int ii = 0; ii < d_X.nrow(); ii++) {
for (int j = 0; j < d_Y.nrow(); j++) {
for (int jj = 0; jj < d_Y.nrow(); jj++) {
value = value + mu(i, j) * mu(ii, jj) * abs(d_X(i, ii) - d_Y(j, jj));
};
};
};
};
return(value);
}
')
Enjoy the C++ speed.
H_mu_typed(mu, d_X, d_Y)
[1] 41650
system.time(H_mu_typed(mu, d_X, d_Y))[3]
elapsed
0.01
This will save you 2 name look ups and a function call (i.e. [) per loop, which is a wopping 8% faster (so really #Marat Talipov's suggestion is the way to go) :
H_mu_2 <- function(mu, d_X, d_Y){
value <- 0
for(i in 1:nrow(d_X))
for(j in 1:nrow(d_Y)){
tmp <- mu[i,j]
for(ii in 1:nrow(d_X))
for(jj in 1:nrow(d_Y)){
value <- value + tmp*mu[ii,jj]*abs(d_X[i,ii]-d_Y[j,jj])
}}
}

Minimum id with non-repetitive elements

I am stuck in a difficult problem in R and am not able to resolve it. The problem goes like this.
x and y are two vectors, as given below:
x<- c(1,2,3,4,5)
y<- c(12,4,2,5,7,18,9,10)
I want to create a new vector p, where length(p) = length(x), in the following manner:
For each id in x, find the id in y which has minimum absolute distance in terms of values. For instance, for id=1 in x, value_x(id=1)=1, min_value_y =2, and id_y(value==2) = 3. Thus, the answer to id 1 in x is 3. Thus, we create a new vector p, which will have following values: p = (3,3,3,2,4);
Now we have to update p, in the following manner:
As 3 has been the id corresponding to id_x=1, it can't be the id for id_x=2. Hence, we have to discard id_y =3 with value 2, to calculate the next minimum distance for id_x=2. Next best minimum distance for id_x=2 is id_y=2 with value 4. Hence, updated p is (3,2,3,2,4).
As 3 has been the id corresponding to id_x=1, it can't be the id for id_x=3. Hence, we have to discard id_y =3 with value 2, to calculate the next minimum distance for id_x=3. Next best minimum distance for id_x=3 is 2. Hence, updated p is (3,2,4,2,4).
As next values in p is 2, and 4 we have to repeat what we did in the last two steps. In summary, while calculating the minimum distance between x and y, for each id of x we have to get that id of y which hasn't been previously appeared. Thus all the elements of p has to be unique.
Any answers would be appreciated.
I tried something like this, though not a complete solution:
minID <- function(x,y) {return(which(abs(x-y)==min(abs(x-y))))};
p1 <- sapply(x,minID,y=y);
#Calculates the list of all minimum elements -no where close to actual solution :(
I have a x and y over 1 million, hence for loop would be extremely slow. I am looking for a faster solution.
This can be implemented efficiently with a binary search tree on the elements of y, deleting elements as they're matched and added to p. I've implemented this using set from the stl in C++, using Rcpp to get the code into R:
library(Rcpp)
getVals = cppFunction(
'NumericVector getVals(NumericVector x, NumericVector y) {
NumericVector p(x.size());
std::vector<std::pair<double, int> > init;
for (int j=0; j < y.size(); ++j) {
init.push_back(std::pair<double, int>(y[j], j));
}
std::set<std::pair<double, int> > s(init.begin(), init.end());
for (int i=0; i < x.size(); ++i) {
std::set<std::pair<double, int> >::iterator p1, p2, selected;
p1 = s.lower_bound(std::pair<double, int>(x[i], 0));
p2 = p1;
--p2;
if (p1 == s.end()) {
selected = p2;
} else if (p2 == s.begin()) {
selected = p1;
} else if (fabs(x[i] - p1->first) < fabs(x[i] - p2->first)) {
selected = p1;
} else {
selected = p2;
}
p[i] = selected->second+1; // 1-indexed
s.erase(selected);
}
return p;
}')
Here's a runtime comparison against the pure-R solution that was posted -- the binary search tree solution is much faster and enables solutions with vectors of length 1 million in just a few seconds:
# Pure-R posted solution
getVals2 = function(x, y) {
n <- length(x)
p <- rep(NA, n)
for(i in 1:n) {
id <- which.min(abs(y - x[i]))
y[id] <- Inf
p[i] <- id
}
return(p)
}
# Test with medium-sized vectors
set.seed(144)
x = rnorm(10000)
y = rnorm(20000)
system.time(res1 <- getVals(x, y))
# user system elapsed
# 0.008 0.000 0.008
system.time(res2 <- getVals2(x, y))
# user system elapsed
# 1.284 2.919 4.211
all.equal(res1, res2)
# [1] TRUE
# Test with large vectors
set.seed(144)
x = rnorm(1000000)
y = rnorm(2000000)
system.time(res3 <- getVals(x, y))
# user system elapsed
# 4.402 0.097 4.467
The reason for the speedup is because this approach is asymptotically faster -- if x is of size n and y is of size m, then the binary search tree approach runs in O((n+m)log(m)) time -- O(m log(m)) to construct the BST and O(n log(m)) to compute p -- while the which.min approach runs in O(nm) time.
n <- length(x)
p <- rep(NA, n)
for(i in 1:n) {
id <- which.min(abs(y - x[i]))
y[id] <- Inf
p[i] <- id
}
I have tried to develop a code in R and have gotten around 20x improvement over for loop. The piece of code goes as follows:
Generalized.getMinId <- function(a,b)
{
sapply(a, FUN = function(x) which.min(abs(x-b)))
}
Generalized.getAbsDiff <- function(a,b)
{
lapply(a, FUN = function(x) abs(x-b))
}
min_id = Generalized.getMinId(tlist,clist);
dup = which(duplicated(min_id));
while(length(dup) > 0)
{
absdiff = Generalized.getAbsDiff(tlist[dup],clist);
infind = lapply(dup, function(x,y)
{l <- head(y,x-1); l[l>0]}, y = min_id);
absdiff = Map(`[<-`, absdiff, infind, Inf);
dupind = sapply(absdiff, which.min);
min_id[dup] = dupind;
dup = which(duplicated(min_id));
}
In case someone can make an improvement over this piece of code, it would be awesome.

fminsearch in R is worse than in Matlab

There is my data (x and y columns are relevant):
https://www.dropbox.com/s/b61a7enhoa0p57p/Simple1.csv
What I need is to fit the data with the polyline. Matlab code that does this is:
spline_fit.m:
function [score, params] = spline_fit (points, x, y)
min_f = min(x)-1;
max_f = max(x);
points = [min_f points max_f];
params = zeros(length(points)-1, 2);
score = 0;
for i = 1:length(points)-1
in = (x > points(i)) & (x <= points(i+1));
if sum(in) > 2
p = polyfit(x(in), y(in), 1);
pred = p(1)*x(in) + p(2);
score = score + norm(pred - y(in));
params(i, :) = p;
else
params(i, :) = nan;
end
end
test.m:
%Find the parameters
r = [100,250,400];
p = fminsearch('spline_fit', r, [], x, y)
[score, param] = spline_fit(p, x, y)
%Plot the result
y1 = zeros(size(x));
p1 = [-inf, p, inf];
for i = 1:size(param, 1)
in = (x > p1(i)) & (x <= p1(i+1));
y1(in) = x(in)*param(i,1) + param(i,2);
end
[x1, I] = sort(x);
y1 = y1(I);
plot(x,y,'x',x1,y1,'k','LineWidth', 2)
And this does work fine, producing following optimization: [102.9842, 191.0006, 421.9912]
I've implemented the same idea in R:
library(pracma);
spline_fit <- function(x, xx, yy) {
min_f = min(xx)-1;
max_f = max(xx);
points = c(min_f, x, max_f)
params = array(0, c(length(points)-1, 2));
score = 0;
for( i in 1:length(points)-1)
{
inn <- (xx > points[i]) & (xx <= points[i+1]);
if (sum(inn) > 2)
{
p <- polyfit(xx[inn], yy[inn], 1);
pred <- p[1]*xx[inn] + p[2];
score <- score + norm(as.matrix(pred - yy[inn]),"F");
params[i,] <- p;
}
else
params[i,] <- NA;
}
score
}
But I get very bad results:
> fminsearch(spline_fit,c(100,250,400), xx = Simple1$x, yy = Simple1$y)
$xval
[1] 100.1667 250.0000 400.0000
$fval
[1] 4452.761
$niter
[1] 2
As you can see, it stops after 2 iterations and doesn't produce good points.
I'll be very glad for any help in resolving this issue.
Also, if anyone knows how to implement this in C# using any free library, it will be even better. I know whereto get polyfit, but not fminsearch.
The problem here is that the likelihood surface is very badly behaved -- there are both multiple minima and discontinuous jumps -- which will make the results you get with different optimizers almost arbitrary. I will admit that MATLAB's optimizers are remarkably robust, but I would say that it's pretty much a matter of chance (and where you start) whether an optimizer will get to the global minimum for this case, unless you use some form of stochastic global optimization such as simulated annealing.
I chose to use R's built-in optimizer (which uses Nelder-Mead by default) rather than fminsearch from the pracma package.
spline_fit <- function(x, xx = Simple1$x, yy=Simple1$y) {
min_f = min(xx)-1
max_f = max(xx)
points = c(min_f, x, max_f)
params = array(0, c(length(points)-1, 2))
score = 0
for( i in 1:(length(points)-1))
{
inn <- (xx > points[i]) & (xx <= points[i+1]);
if (sum(inn) > 2)
{
p <- polyfit(xx[inn], yy[inn], 1);
pred <- p[1]*xx[inn] + p[2];
score <- score + norm(as.matrix(pred - yy[inn]),"F");
params[i,] <- p;
}
else
params[i,] <- NA;
}
score
}
library(pracma) ## for polyfit
Simple1 <- read.csv("Simple1.csv")
opt1 <- optim(fn=spline_fit,c(100,250,400), xx = Simple1$x, yy = Simple1$y)
## [1] 102.4365 201.5835 422.2503
This is better than the fminsearch results, but still different from the MATLAB results, and worse than them:
## Matlab results:
matlab_fit <- c(102.9842, 191.0006, 421.9912)
spline_fit(matlab_fit, xx = Simple1$x, yy = Simple1$y)
## 3724.3
opt1$val
## 3755.5 (worse)
The bbmle package offers an experimental/not very well documented set of tools for exploring optimization surfaces:
library(bbmle)
ss <- slice2D(fun=spline_fit,opt1$par,nt=51)
library(lattice)
A 2D "slice" around the optim-estimated parameters. The circles show the optim fit (solid) and the minimum value within each slice (open).
png("splom1.png")
print(splom(ss))
dev.off()
A 'slice' between the matlab and optim fits shows that the surface is quite rugged:
ss2 <- bbmle:::slicetrans(matlab_fit,opt1$par,spline_fit)
png("slice1.png")
print(plot(ss2))
dev.off()

Resources