openerp report with corporate header - report

i'm trying to make a report with corporate header but it doesn't work, the report is working fine but i don't have any corporate header, here is my code:
report.xml:
<report id="tracker_Labels"
model="noc.trajet"
name="noc.trajet"
string="Tracker Labels"
xml="module_coll/report/tracker_label.xml"
xsl="module_coll/report/tracker_label.xsl"
header="True"/>
tracker_label.xsl:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format">
<xsl:import href="../../base/report/corporate_defaults.xsl" />
<xsl:template match="/">
<xsl:call-template name="rml" />
</xsl:template> <!-- CONTENT -->
</xsl:stylesheet>
Regards,

Related

How to get current date in xslt executed by XslCompiledTransform in .net core?

XslCompiledTransform is a xsl 1.0 processor, which doesn't support the current-dateTime() function. I've tried using my own script like this:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:msxsl="urn:schemas-microsoft-com:xslt"
xmlns:user="urn:my-scripts"
exclude-result-prefixes="msxsl user">
<xsl:output method="xml" indent="yes"/>
<msxsl:script language="CSharp" implements-prefix="user">
public string current-dateTime()
{
return DateTime.Now.ToString("yyyy-MM-ddTHH:mm:ssZ");
}
</msxsl:script>
<xsl:template match="...">
...
<xsl:value-of select="user:current-dateTime()"/></xsl:element>
...
</xsl:template>
</xsl:stylesheet>
And this works in .net framework, but not in .net core because it doesn't support scripts. How can I do this in .net core?

how to tokenize a paragraph in xslt

XML
<?xml version="1.0" encoding="UTF-8"?>
<!-- Edited by XMLSpy -->
<catalog>
<example>
:20:FT13261793408907
N23B:CRED
SA32A:130918USD111670,00
</example>
</catalog>
XSLT
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>
<xsl:template match="/">
<xsl:for-each select="catalog">
<tr>
<td><xsl:value-of select="example"> </td>
</tr>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
Current OUTPUT
:20:FT13261793408907 N23B:CRED SA32A:130918USD111670,00
Desired OUTPUT
:20:FT13261793408907
N23B:CRED
SA32A:130918USD111670,00
output must not be in a same line its must be as shown in the desired o/p
A template match should do it;
$ cat catalog.xsl
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>
<xsl:template match="catalog">
<xsl:value-of select="example"/>
</xsl:template>
</xsl:stylesheet>
$ xsltproc catalog.xsl catalog.xml
:20:FT13261793408907
N23B:CRED
SA32A:130918USD111670,00

XLST to find ASP.NET roles in web.sitemap

I am using the web.sitemap which is created using VS.net 2010 along with a XSLT to create a clean CSS-able menu.
I have modified the xslt from Cyotec to strip out the first node however I am so far unable to work out how to search within to display only the links depending on the role of the user.
The XSLT is as below:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:map="http://schemas.microsoft.com/AspNet/SiteMap-File-1.0" exclude-result-prefixes="map">
<xsl:output method="xml" encoding="utf-8" indent="yes"/>
<xsl:template name="mapNode" match="/">
<ul id="main-menu">
<xsl:apply-templates select="*"/>
</ul>
</xsl:template>
<xsl:template match="/*/*">
<xsl:apply-templates select="*"/>
</xsl:template>
<xsl:template match="map:siteMapNode">
<xsl:if test="/siteMap/SiteMapNode[#roles != 'Admin']">
<li>
<a href="{substring(#url, 2)}" title="{#description}">
<xsl:value-of select="#title"/>
</a>
<xsl:if test="map:siteMapNode">
<xsl:call-template name="mapNode"/>
</xsl:if>
</li>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
The XML looks like this:
<?xml version="1.0" encoding="utf-8" ?>
<siteMap xmlns="http://schemas.microsoft.com/AspNet/SiteMap-File-1.0" >
<siteMapNode url="~/" title="" description="Anon" roles="*">
<siteMapNode url="~/anon.aspx" title="Anon" description="Anon" roles="*" />
<siteMapNode url="~/admin1.aspx" title="Admin1" description="Admin Only" roles="Admin"/>
<siteMapNode url="~/admin2.aspx" title="Admin2" description="Admin Only" roles="Admin">
<siteMapNode url="~/admin3.aspx" title="Admin3" description="Admin Only" roles="Admin"/>
</siteMapNode>
</siteMapNode>
</siteMap>
I am wanting to only output the urls titles and descriptions where roles != Admin
Everything works fine without the search.
Is anyone able to shed some light on the 'if' function, or suggest a better way of achieving this?
Thanks in advance
The problem with your current xsl:if condition....
<xsl:if test="/siteMap/SiteMapNode[#roles != 'Admin']">
.... is that the first forward slash means it is an absolute path, starting from the root element, so all the xsl:if is saying is whether there is any SiteMapNode, immediately under the siteMap element, that is not an Admin role. This means it will always be true in your case.
You really only want to check the role of the current element
<xsl:if test="#roles != 'Admin'">
However, there is a tidier way of doing this. Remove the xsl:if condition, and just have a separate template to match the admin role elements, and ignore them.
<xsl:template match="map:siteMapNode[#roles='Admin']"/>
Here is the full XSLT
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:map="http://schemas.microsoft.com/AspNet/SiteMap-File-1.0" exclude-result-prefixes="map">
<xsl:output method="xml" encoding="utf-8" indent="yes"/>
<xsl:template name="mapNode" match="/">
<ul id="main-menu">
<xsl:apply-templates select="*"/>
</ul>
</xsl:template>
<xsl:template match="/*/*">
<xsl:apply-templates select="*"/>
</xsl:template>
<xsl:template match="map:siteMapNode[#roles='Admin']"/>
<xsl:template match="map:siteMapNode">
<li>
<a href="{substring(#url, 2)}" title="{#description}">
<xsl:value-of select="#title"/>
</a>
<xsl:if test="map:siteMapNode">
<xsl:call-template name="mapNode"/>
</xsl:if>
</li>
</xsl:template>
</xsl:stylesheet>
When applied to your sample XML, the following is output
<ul id="main-menu">
<li>
Anon
</li>
</ul>
Do note the template that matches the admin role element is more specific that the template that matches any SiteMapNode element and so the XSLT processor will give priority to this when matching.

XML Transform for ASP.Net TreeView Control

Not being an XML expert I'm struggling with this:
I need to populate an ASP.Net Treeview control from an XML dataSource. I can usually do this no problem except on this occasion the data I've been provided with is in this format:
<Staff>
<ID>1</ID>
<Name>Boss 1</Name>
<JobTitle>Top Boss</JobTitle>
<Staff>
<ID>2</ID>
<Name>Boss 2</Name>
<JobTitle>2nd Top Boss</JobTitle>
<Staff>
<ID>3</ID>
<Name>Boss 3</Name>
<JobTitle>3rd Top Boss</JobTitle>
<Staff>
<ID>4</ID>
<Name>Worker 1</Name>
<JobTitle>Worker</JobTitle>
</Staff>
</Staff>
</Staff>
</Staff>
and I need it to be like this for the treeview control:
<Staff ID="1" Name="Boss 1" JobTitle="Top Boss">
<Staff ID="2" Name="Boss 2" JobTitle="2nd Top Boss" >
<Staff ID="3" Name="Boss 3" JobTitle="3rd Top Boss" >
<Staff ID="4" Name="Worker 1" JobTitle="Worker" ></Staff>
</Staff>
</Staff>
</Staff>
I know this should be a doddle to do with an xsl file, but I'm failing miserably. My last attempt was:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="Staff">
<Staff>
<xsl:apply-templates/>
</Staff>
</xsl:template>
<xsl:template match="Staff">
<Staff>
<xsl:for-each select="*">
<xsl:attribute name="{name()}">
<xsl:value-of select="text()"/>
</xsl:attribute>
</xsl:for-each>
</Staff>
</xsl:template>
</xsl:stylesheet>
Any ideas?
Predictably I figured it out 30mins after posting. The following converts the xml above to the required format and appears to transform any xml elements to attibutes.
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl">
<xsl:template match="*">
<xsl:copy>
<xsl:for-each select="#*|*[not(* or #*)]">
<xsl:attribute name="{name(.)}">
<xsl:value-of select="."/>
</xsl:attribute>
</xsl:for-each>
<xsl:apply-templates select="*[* or #*]|text()"/>
</xsl:copy>
</xsl:template>

Trying to use an XSLT for an XML in ASP.NET

i have the following xslt sheet:
<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:variable name="nhits" select="Answer[#nhits]"></xsl:variable>
<xsl:output method="html" indent="yes"/>
<xsl:template match="/">
<div>
<xsl:call-template name="resultsnumbertemplate"/>
</div>
</xsl:template>
<xsl:template name="resultsnumbertemplate">
<xsl:value-of select="$nhits"/> matches found
</xsl:template>
</xsl:stylesheet>
And this is the xml that im trying to mix with the previous xslt:
<Answer xmlns="exa:com.exalead.search.v10" context="n%3Dsl-ocu%26q%3Dlavadoras" last="9" estimated="false" nmatches="219" nslices="0" nhits="219" start="0">
<time>
<Time interrupted="false" overall="32348" parse="0" spell="0" exec="1241" synthesis="15302" cats="14061" kwds="14061">
<sliceTimes>15272 </sliceTimes>
</Time>
</time>
</Answer>
Im using a xslcompiledtransform and that's working fine:
XslCompiledTransform transformer = new XslCompiledTransform();
transformer.Load(HttpContext.Current.Server.MapPath("xslt\\" + requestvariables["xslsheet"].ToString()));
transformer.Transform(xmlreader, null, writer);
My problems comes when im trying to put into a variable the "nhits" attribute value placed on the Answer element, but i'm not rendering anything using my xslt sheet.
Do you know what could be the cause?
Could be the xmlns attribute in my xml file?
Thanks in advance.
Best Regards.
Jose
Your immediate problem is that your XPath is wrong. Try
<xsl:variable name="nhits" select="/Answer/#nhits" />
However, I suggest a change to get rid of the variable altogether, you don't need it.
<xsl:stylesheet
version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
>
<xsl:output method="html" indent="yes"/>
<xsl:template match="Answer">
<div>
<xsl:value-of select="#nhits"/>
<xsl:text> matches found</xsl:text>
</div>
</xsl:template>
</xsl:stylesheet>
Your variable should be select="Answer/#nhits"
Your currect xpath of "Answer[#nhits]" tries to select Answer element that has an attribute named nhits..

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