Closed. This question needs to be more focused. It is not currently accepting answers.
Want to improve this question? Update the question so it focuses on one problem only by editing this post.
Closed 7 years ago.
Improve this question
Does anybody know the examples on how to run paired ttest in Matlab/R/SAS or Python/Java on many columns (I have 1139 variables) in all combinations or selected respective columns in a loop.
thank you
MATLAB Solution:
If I understand correctly, you're just looking for a way to feed ttest with two different columns from your input matrix everytime. You can get all possible combinations of column pairs using nchoosek:
pairs = nchoosek(1:size(X, 2), 2);
Now you can iterate over these indices, each time invoking ttest with a different pair:
for idx = transpose(pairs)
h = ttest(X(:, idx(1)), X(:, idx(2)));
%// Do something with the result...
end
Related
Closed. This question needs to be more focused. It is not currently accepting answers.
Want to improve this question? Update the question so it focuses on one problem only by editing this post.
Closed 4 years ago.
Improve this question
I have a set of 20 column, each contains number value. I would like to have a function in excel or in r or somewhere else to extract the shared values among all the columns.
Several of the online Venn tools can visualize and list among up to 6 columns.
Any tool?
Thanks
in R, we can use intersect with Reduce to get the common values across all the columns
Reduce(intersect, dftest)
data
dftest <- data.frame(col1 = 1:5, col2 = 2:6, col3 = 3:7)
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 4 years ago.
The community reviewed whether to reopen this question 11 months ago and left it closed:
Duplicate This question has been answered, is not unique, and doesn’t differentiate itself from another question.
Improve this question
How can I scale(x) only certain columns of a dataframe? I have a dataframe with 7 columns and I want to scale only column 3 and 6. The rest should stay as it is.
We can do this with lapply. Subset the columns of interest, loop through them with lapply, assign the output back to the subset of data. Here, we are using c because the outpuf of scale is a matrix with a single column. Using c or as.vector, it gets converted to vector
df[c(3,6)] <- lapply(df[c(3, 6), function(x) c(scale(x)))
Or another option is mutate_at from dplyr
library(dplyr)
df %>%
mutate_at(c(3,6), funs(c(scale(.))))
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 6 years ago.
Improve this question
I am trying to make a histogram of grades. Here are my variables.
> grade <- factor(c("A","A","A","B","A","A","A","A","B","A","C","B","B","B"))
> numberBook <- c(53,42,40,40,39,34,34,30,28,24,22,21,20,16)
But when I plot it, I get an error message.
> hist(numberBook~grade)
Error in hist.default(numberBook ~ grade) : 'x' must be numeric
What can I do?
I'm not sure why you've got multiple letters so I've guessed that you want a total of all the A, B and Cs. This may not be quite right. I've recreated your data like this using rep and summing the counts of grades (could be wrong)
data <-c(rep("A",(53+42+40+34+34+30+28+22)), rep("B",(39+24+20+16+22)),rep("C",22))
Then I can plot the data using barplot:
barplot(prop.table(table(data)))
Barplot is probably what you want here.
Closed. This question needs to be more focused. It is not currently accepting answers.
Want to improve this question? Update the question so it focuses on one problem only by editing this post.
Closed 6 years ago.
Improve this question
dat = runif(10,1,10)
dat2 = runif(10,1,10)
dat3 = runif(10,1,10)
data = rbind(dat,dat2,dat3)
In the case of above data, I am wondering how I can filter out rows as long as there is one element in that row exceeding 5.
I know that I can use loop to achieve this, but I am wondering if there is more succinct way to do this.
try this:
data[apply(data>5, 1, sum)>0,]
This says "for condition having more than zero number exceeding 5 in each row, filter data".
data[do.call(pmax,data.frame(data))<=5,]
Cheers,
Bert
Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 7 years ago.
Improve this question
When I submit this code to R:
x <- c(1,2,4)
z <- c(7,6,3)
a <- x * z
I get:
a
[1] 7 12 12
So R just multiples element by element. But the two vectors are not compatible for multiplication because the first one has three columns and the second one does not have three rows.
What is happening internally?
Please note that these are vectors; not tables.
This means they can of course be multiplied with each other and would give the expected result through their inner product.