I have a form for people to put in info on my contact page. I'm trying to figure out how once they click submit to NOT show the form anymore and show a simple thankyou.
Thank You
Create a multiview control with 2 views.Place all your controls into one and a "thank you" message in the other and toggle the ActiveViewIndex on submit click
The simplest way would just be to use Panel controls:
<asp:Panel ID="pnlForm" runat="server">
... form here ...
<asp:Button ID="btnSubmit" OnClick="btnSubmit_Click" Text="Submit" runat="server" />
</asp:Panel>
<asp:Panel ID="pnlThankYou" Visible="False" runat="server">
Thanks!
</asp:Panel>
C#
protected void btnSubmit_Click(object sender, EventArgs e)
{
pnlForm.Visible = false;
pnlThankYou.Visible = true;
}
Try to put both sections in separate divs and make divs runat=server
and set the div which not required visible to false or just add attribute display to hide at server side
and show the other div by visible true or by attribute to block
Related
I want to set the textbox contol located in the panel control via code
I know to retrieve the inputted value in the textbox control:
string myVal = Request.Form["txtResult"];
I want to set the txtResult.text = "some text";
makeup snippet:
<asp:Panel ID="Panel1" runat="server" Style="display: none" Width="233px">
<asp:TextBox ID="txtResult" runat="server" AutoPostBack="True"></asp:TextBox>
<br />
<div align="center">
<asp:Button ID="OkButton" runat="server" Text="OK" />
<asp:Button ID="CancelButton" runat="server" Text="Cancel" />
</div>
</asp:Panel>
txtResult is not available within code, I tried to see if it is available in the page_load, it's not
texReults was a typo, its txtResult, I updated the ID
the intellisense does not recognize any cntr by the name txtResult
its a new web application and the panel visibility=True
maybee this wil help, above the snipet, I use ScriptManager from the AJAX Exstension
I am aware of he Asnchronius affects, partial potback, etc.
It's a managed control, you should be able to set it on the Page_Load event:
protected void Page_Load(object sender, System.EventArgs e)
{
txtResult.Text = "some text";
}
Update: Based on your update, there are a couple of things that you would need to check:
Spelling: Are you sure you're spelling the control name correctly?
Its ID in your code is "txtResults", but you're referencing it as
"txtResult".
Designer: Did you copy the aspx page or bypass VS in some way for this page? If so check the .designer file for the reference to the control: i.e. "Page1.aspx.designer.cs"
Visibility: Is the Panel control's visibility set to true? If not, then it won't render the controls that are contained within it.
Update 2: If you're doing this through scriptmanager, then I highly recommend that you read through this: http://www.wrox.com/WileyCDA/Section/Using-the-ASP-NET-AJAX-ScriptManager.id-305492.html
I am creating a ModalPopupExtender inside a Web User Control.
When i click on the OK Button in the panel, which is showing as model popup, the Event Handeler of the button is not executing.
This problen does not occure when i do not use the Web User Control.
Here is the user control (.ascx) file code.
<script type="text/javascript" language="javascript">
function OkClicked(sender, e) {
__doPostBack('Button1', e);
}
</script>
<asp:Button ID="Button2" runat="server" Text="Show" />
<asp:Panel ID="Panel1" runat="server">
<asp:TextBox ID="TextBox1" runat="server"></asp:TextBox>
<asp:Button ID="Button1" runat="server" Text="Button" onclick="Button1_Click" />
</asp:Panel>
<asp:ModalPopupExtender ID="ModalPopupExtender1" runat="server"
DropShadow="True" OkControlID="Button1" PopupControlID="Panel1"
TargetControlID="Button2" onokscript="OkClicked()">
</asp:ModalPopupExtender>
<p>
<asp:Label ID="Label1" runat="server" Text="Label"></asp:Label>
</p>
And the Event Handeler for the click event of the 'Button1' is
protected void Button1_Click(object sender, EventArgs e)
{
Label1.Text = TextBox1.Text;
}
In the javascript you shouldn't put 'Button1' as the name of the control. Instead, on the PreRender event of your control, fill that out with this.Button1.ClientID .
ClientID is the unique identifier across the entire generated page of your button control, allowing the server to pinpoint exactly what control triggered the postback.
If this wasn't like that, you wouldn't be able to place multiple instances of a same control on one page.
In code:
<script type="text/javascript" language="javascript">
function OkClicked(sender, e) {
__doPostBack('<%= this.Button1.ClientID %>', e);
}
Couple of suggestions:
Do you have any kind of validation on this page. If so, then it's possible that when you click the ok button, that validation is failing. When you click the button, likely the ModalPopup Extender will close, and if validation fails it may cancel the event happening. If this is the case, add an attribute: CausesValidation="false"
If that doesn't work, you may add an attribute to MAKE it post back, I believe there's an attribute -> AutoPostBack="true".
#Joachim is correct that you'll need to use the clientID, but at the same time, I don't think you'll need to call javascript to run the backend code.
Also, you may consider putting this into an UpdatePanel so that you do an AJAX postback without sending the entire page back and forth when the page is posted back.
I have successfully added controls to pop up, like many check boxes ... now on check box checked event I want to show another check boxes on same popup. how can I do that plz can any one help me?
Make sure autopostback is true and wrap them in an updatepanel inside of the modal. Now you will be able to show/hide whatever you want on postback without the modal closing.
Do you want to just display check boxes(that's hidden) on checked event of other checkbox? You can attach javascript function to onClick event of check box and you can set visibility of other check boxes.
If you want to handle that in server side, you need to set autopostback to true and specify OnCheckedChanged event.
<asp:CheckBox AutoPostBack="true" runat="server" ID="chk1" OnCheckedChanged="chk1_OnCheckedChanged" />
protected void chk1_OnCheckedChanged(object sender, EventArgs e)
{
}
And put the modal popup control inside the update panel.
<ajaxtoolkit:modalpopupextender runat="server" ID="mpe"
BehaviorID="mpe_ID" PopupControlID="pnlModalPopup"
TargetControlID="btnSomething" CancelControlID="lnkUploadSongListOverlayClose"
DropShadow="false" />
<asp:Panel runat="server" ID="pnlModalPopup" CssClass="modal">
<asp:UpdatePanel runat="server" ID="updatePanel">
<ContentTemplate>
<!-- modal popup control -->
</ContentTemplate>
</asp:UpdatePanel>
</asp:Panel>
Here are the steps:
1- Set autopost back for the checkbox to true
2- Double click on the checkbox and on the checkbox1_OnCheckedChanged
if(checkbox1.Checked==true){Modalpopupextender.show();}
How to close Modal Popup Extender from server side code on click on close link inside the popup?
there is a property in extender for closing popup " CancelControlID" give button id in it and popup will close,if you want to close popup from server side mean from code behind then there is extender property hide(),in button code behind body write id of popup and enter "." after that you get all properties of popup in those property you get hide property.use it hopefully you will get the solution
example
private void btnSubmit_Click(object sender, EventArgs e)
{
modelpopupextender.hide();
}
Answering this question might not be useful to the person who posted it but it might be useful to others.
The following needs to be done to close the modal popup from server side.
Instead of giving the close button id to "CancelControlID" of the modalpopupextender, create a dummy hiddenfield and give this id to "CancelControlID" of the modalpopupextender.
for example
<pre>
<asp:HiddenField ID="hidForModel" runat="server" />;
/*Are you sure you want to know the answer? */
<asp:Button ID="btnYes" runat="server" Text="Yes!" onclick="btnYes_Click" />;
<br />;
<asp:Panel ID="pnlModal" runat="server" CssClass="modalPopup" Style="display: none;">
<asp:Panel ID="pnlControls" runat="server" CssClass="insideModalPopup></asp:Panel>
<br />
<asp:Button ID="btnClose" runat="server" Text="Close" onclick="btnClose_Click" />
</asp:Panel>
<cc1:ModalPopupExtender TargetControlID="hidForModel" ID="pnlModal_ModalPopupExtender"
runat="server" DynamicServicePath="" Enabled="True" BackgroundCssClass="modalBackground"
PopupControlID="pnlModal" CancelControlID="hidForModel" DropShadow="true">
</cc1:ModalPopupExtender>
</pre>
Here i have given both TargetControlID and CancelControlID as hidForModel as I want to show as well as hide the modal popup from code-behind.
In Code-Behind
<pre>
protected void btnYes_Click(object sender, EventArgs e)
{
pnlModal_ModalPopupExtender.Show();
TextBox txt = new TextBox();
txt.Text = "aaa";
pnlControls.Controls.Add(txt);
}
protected void btnClose_Click(object sender, EventArgs e)
{
pnlModal_ModalPopupExtender.Hide();
}
</pre>
Here I have made the modal popup seen and added a textbox from code-behind on click of yes button and hidden the modal popup on click of Close button.
You can use CancelControlID attribute to close the Popup box.
<asp:ModalPopupExtender ID="mpe_login" runat="server"
TargetControlID="btn_login_popup" PopupControlID="panel_login"
BackgroundCssClass="LoginBackground1"
CancelControlID="btn_Cancel" />
is it possible to display, with a click of a button an entirely different form on the same aspx page? please take note that although i have experience with vb.net, i have almost none with asp.net. thank you very much for your responses
I would use and in your code behind, load up the page and then place it in the placeHolder. And then hide the old form using javascript. The idea the other person said would also work, but I like using the placeholder, myself.
I think it's all really determinate on what you want to do with the forms and how badly you would want the code for the other form laying on the page, or not.
If I understand, what you need is, on the click event:
response.redirect "newpage.aspx"
Create each of the forms on the same page, one with visible=true and the other visible=false, and when the user clicks on the appropriate button, switch the visibilities.
<form id="Form1" runat="server" visible="true">
<div>
<asp:Button ID="Button1" runat="server" Text="Show Form 2" onclick="Button1_Click" />
</div>
</form>
<form id="Form2" runat="server" visible="false">
<div>
<asp:Button ID="Button2" runat="server" Text="Show Form 1" onclick="Button2_Click" />
</div>
</form>
And in the code behind:
protected void Button1_Click(object sender, EventArgs e)
{
this.form2.Visible = true;
this.form1.Visible = false;
}
protected void Button2_Click(object sender, EventArgs e)
{
this.form2.Visible = false;
this.form1.Visible = true;
}
Probably not the most "Ajaxy" solution, but you could use an iframe, with the src set to the forms location.
You should be aware of ASP.NET's MultiView control. It does require a postback to change views, and it is kinda heavy on the ViewState, but its an option to consider.
Well, there's several ways to go about that I suppose. Riffing off tekBlues, you can do a Server.Transfer "yourpage.aspx". You can then use the PreviousPage property to get to data from the old page.
You can use user controls and a placeholder on the main page. Of course dynamically loaded controls holds extra complexity.
You could use a MultiView control. Asp.Net will maintain all vars for you. Useful for the quick and dirty.
These are all webform solutions though. If you're looking for an AJAX solution, might need to keep on looking for answers.
It is NOT allowed to have more then 1 form runat="server" on an asp.net page. What you could do, is create 2 panels on your page, 1 with the Visible property set to false. Then when a button is clicked in the event handler you set the Visisble property to true, while setting the other 1 to false. Wrap the Panel in an UpdatePanel to get rid of the postback.
<asp:UpdatePanel><ContentTemplate>
<asp:Panel ID="pnl1" runat="server">
<asp:Button OnClick="Button_CLick" />
</asp:Panel>
<asp:Panel ID="pnl2" runat="server" Visible="false">
</asp:Panel></ContentTemplate></asp:UpdatePanel>
the code in the Button_CLick handler would then be pnl1.Visible = false; pnl2.Visible = true;
You could do it with CSS/Javascript, here is what I would do first:
1) code up two forms, place them in a separate divs
2) using CSS hide one div on page load
3) then place a button on the page, in the onlick button event unhide the second form and hide the first one.
Make sure that you only have ONE form tag, but 2 divs inside it which you will hide/unhide. Keep in Mind that that the form can only be submitted to its own page, that's asp.net.
in your HTML:
<form runat="server" id="myForm">
<div id="myForm1">
<! -- form 1 code goes here -- !>
</div>
<div id="myForm2">
<! -- form 2 code goes here -- !>
</div>
<input type="button" onclick="toggleVisibility();" />
</form>
Then in your CSS
#myForm1 {
display: none;
}
Then ToggleVisibility() will change the display attribute of divs.
Use AJAX to load the content of another page into the same page.
Use Response.Redirect or Server.Transfer to move to the next page.