For example I have index.css that contains links to another css files:
#import "http://<some_url>/bootstrap.css";
#import "http://<some_url>/plugin.css";
#import "app.css";
It is possible to concatenate these files with Grunt JS?
Looking at the Grunt API, the file stuff appears to apply exclusively to local files.
http://gruntjs.com/api/grunt.file
Furthermore I haven't seen anything in the source code where it parses CSS files looking for imports.
To get them concatenated together:
I'd recommend that you download the files locally, put them in your usual css folder then use Grunt concat as normal.
I'd then write a small script using wget to download fresh copies of these dependencies before building with grunt.
I know it's been a while since this was asked, but I came across it while trying to do something similar. Here is one way to save a file from a url using a grunt task.
module.exports = function(grunt) {
'use strict';
var http = require('http');
grunt.initConfig({
watch: {
scripts: {
files: ['**/*.cfc'],
tasks:['saveURL']
}
},
open:{
error:{
path:'http://<server>/rest/error.html'
}
}
});
grunt.loadNpmTasks('grunt-contrib-watch');
grunt.loadNpmTasks('grunt-open');
grunt.registerTask('default', ['watch']);
grunt.registerTask('saveURL', 'Write stuff to a file', function() {
var done = this.async();
var reloadurl = 'http://<server>/rest/index.cfm?rl';
grunt.log.writeln('Loading URL:' + reloadurl + ' ...');
http.get(reloadurl, function(res) {
var pageData = "";
if(res.statusCode != '200'){
//if we don't have a successful response queue the open:error task
grunt.log.error('Error Reloading Application!: ' + res.statusCode);
grunt.task.run('open:error');
}
res.setEncoding('utf8');
//this saves all the file data to the pageData variable
res.on('data', function (chunk) {
pageData += chunk;
});
res.on('end', function(){
//This line writes the pageData variable to a file
grunt.file.write('error.html', pageData)
done();
});
}).on('error', function(e) {
console.log("Got error: " + e.message);
done(false);
});
});
};
Related
I have different *.scss files in my src folder and I want one file to be compiled in its own separate folder.
Lets assume I have the files normalFile_1.scss, specialFile.scss, normalFile_2.scss. I want the two normal files to be compiled to the folder Public/Css, the special file however should end up in the folder Public/Css/Special.
I have tried to get the current filename in the task with gulp-tap, which works fine.
.pipe($.tap(function (file, t) {
filename = path.basename(file.path);
console.log(filename); //outputs normalFile_1.css, specialFile.css, normalFile_2.css
}))
And with gulp-if I then wanted to switch the output folder based on the filename variable (PATHS.dist is the output "root" folder Public):
.pipe($.if(filename == 'specialFile.css', gulp.dest(PATHS.dist + '/Css/Special'), gulp.dest(PATHS.dist + '/Css')));
But everything still ends up in the Public/Css folder. Why does this not work? Is this even a good way of trying to accomplish that or are there better methods?
There are two ways to do this shown below:
var gulp = require("gulp");
var sass = require("gulp-sass");
var rename = require("gulp-rename");
var path = require('path');
gulp.task('sass', function () {
return gulp.src('src/*.scss')
.pipe(sass().on('error', sass.logError))
.pipe(rename(function (path) {
if (path.basename == "specialFile") {
path.dirname = "Special";
}
}))
.pipe(gulp.dest('Public/Css'))
// .pipe(gulp.dest(function(file) {
// var temp = file.path.split(path.sep);
// var baseName = temp[temp.length - 1].split('.')[0];
// console.log(baseName);
// if (baseName == "specialFile") {
// return 'Public/Css/Special';
// }
// else return 'Public/Css';
// }))
});
gulp.task('default', ['sass']);
Obviously I suggest the rename version.
[Why a simple file.stem or file.basename doesn't work for me in the gulp.dest(function (file) {} version I don't know - that would certainly be easier but I just get undefined.]
I’m using a pretty simple setup for Gulp with SASS and BrowserSync.
//require plugins here
// Paths
var styleSRC = './assets/css/style.scss'; // Path to main .scss file.
var styleDestination = './ ';
var styleWatchFiles = './assets/css/**/*.scss';
// BrowserSync
gulp.task('browser-sync', function () {
browserSync.init({
proxy: projectURL,
open: false,
injectChanges: true
});
});
//Task
gulp.task('styles', function () {
gulp.src(styleSRC)
.pipe(sass({
errLogToConsole: true,
}))
.on('error', console.error.bind(console)).pipe(autoprefixer(AUTOPREFIXER_BROWSERS))
.pipe(gulp.dest(styleDestination))
.pipe(browserSync.reload({
stream: true
}));
});
// Watch
gulp.task('default', ['styles', 'browser-sync'], function () {
gulp.watch(styleWatchFiles, ['styles']);
});
The issue is though this setup doesn’t recognize when new partial file is created. So if I create a partial and then add it to style.scss nothing is happening, Sass is not compiled -> so you have manually call the task from the console.
Is it possible to automatically compile Sass when new partial is added?
if you remove './' from the source path it will work the way you would expect it
as far as i know this is a windows only problem
here is a github issue that describes the problem : https://github.com/gulpjs/gulp/issues/1422
should be fixed in gulp 4.x , but thats still in alpha
I try to convert my less files into css files using gulp-less and then use gulp-recess to change properties order in css files. Task less works properly but task recess doesn't work.
This is my gulpfile.js file
'use strict';
var gulp = require('gulp'),
less = require('gulp-less'),
path = require('path'),
recess = require('gulp-recess');
// less
gulp.task('less', function () {
return gulp.src(['less/style.less', 'less/fonts.less'])
.pipe(less({
paths: [ path.join(__dirname, 'less', 'includes') ]
}))
.pipe(gulp.dest('css'));
});
// recess
gulp.task('recess', ['less'], function () {
return gulp.src(['css/style.css', 'css/fonts.css'])
.pipe(recess())
.pipe(recess.reporter())
.pipe(gulp.dest('css'));
});
// watch
gulp.task('watch', function () {
gulp.watch('less/*.less', ['less']),
gulp.watch('css/*.css', ['recess']);
});
// default
gulp.task('default', ['less', 'recess', 'watch']);
Errors in Node.js console
What's wrong? How to fix it?
gulp-recess won't reorder your css properties, its purpose is to 'lint' your css/less files - checks for syntax errors so you can fix there warnings/errors yourself in the source files.
i have tried to configure sourcemaps in less files. When I inspect an Element I see the correct less file with the file extension. So it seems to work
But when I do changes the file name for Example style.less:1120 change to style.css:129
What went wrong?
Another problem is, that chrome shows me only the style.less file. This file imports only my components. So instead of seeing component.less:10 i see style.less:221
My gulpfile:
var gulp = require('gulp');
var less = require('gulp-less');
var rename = require('gulp-rename');
var sourcemaps = require('gulp-sourcemaps');
var paths = {
scripts: ['client/js/**/*.coffee', '!client/external/**/*.coffee'],
images: 'client/img/**/*',
less: 'web/style/style.less'
};
gulp.task('less' , function() {
// Minify and copy all JavaScript (except vendor scripts)
// with sourcemaps all the way down
return gulp.src(paths.less)
.pipe(sourcemaps.init())
.pipe(less())
.pipe(rename(function(path) {
path.extname = ".css";
}))
.pipe(sourcemaps.write())
.pipe(gulp.dest('web/style/.'));
});
// Rerun the task when a file changes
gulp.task('watch', function() {
gulp.watch(paths.less, ['less']);
});
// The default task (called when you run `gulp` from cli)
gulp.task('default', ['watch']);
I'd like to have the same gulpfile.js for my projects where I use a pre-compiler (sass) and for older/smaller projects in pure css.
Also I use browser-sync and I want to inject css into the browser (not reload the whole page).
My following configuration works, i.e. when I edit a sass file, it compiles and injects the compiled css, and when I edit a css file, it injects it correctly. But a little detail is still frustrating me : when I edit a sass file, browser-sync is notified 2 times that the css file has changed. 1 time in the sass watcher and 1 time in the css watcher. It doesn't seem to be a problem for him, since it correctly injects the css in my browser. But this is not very "clean".
I'd like to find a way to do some sort of exclusion for this. Ideally, just with a bit more logic in my coding, without the need to add some other packages like gulp-watch, gulp-if...
var gulp = require('gulp'),
rubySass = require('gulp-ruby-sass'),
sourcemaps = require('gulp-sourcemaps'),
browsersync = require('browser-sync').create();
gulp.task('rubySass', function() {
return rubySass('sources/', {
style: 'expanded',
sourcemap: true
})
.on('error', function (err) {
console.error('Error!', err.message);
})
.pipe(sourcemaps.write('maps', {
includeContent: false,
sourceRoot: '/sources'
}))
.pipe(gulp.dest('./css'))
.pipe(browsersync.stream({match: "**/*.css"}));
// If I remove this line, browser-sync is still notified 2 times
// (the console is still showing 2 times "[BS] 1 file changed (main.css)")
// but, moreover, the css is no longer injected : the whole page is reloading.
});
gulp.task('browsersync', function() {
browsersync.init({
server: './',
logConnections: true
});
});
gulp.task('default', ['rubySass', 'browsersync'], function (){
gulp.watch('**/*.html', browsersync.reload);
gulp.watch('**/*.php', browsersync.reload);
gulp.watch('js/**/*.js', browsersync.reload);
gulp.watch('**/*.css', function(file){
console.log("In gulp watch : css");
gulp.src(file.path)
.pipe(browsersync.stream());
});
gulp.watch('./sources/**/*.scss', ['rubySass']).on('change', function(evt) {
console.log("In gulp watch : sass");
});
});
Here's the console output, when saving a sass file :
As we can see, we enter successively in the 2 watchers and browser-sync is saying 2 times "[BS] 1 file changed (main.css)".
Since your SASS always compiles to .css you just need to watch for changes in your .css files. It will fire on SASS change anyway (because .css will be generated and gulp.watch triggered by this .css change). Otherwise you can use exclusions in gulp.watch() and use some kind of pattern (ex. subdirectory) to identify .css files generated from SASS. You can try this one:
var gulp = require('gulp'),
rubySass = require('gulp-ruby-sass'),
sourcemaps = require('gulp-sourcemaps'),
browsersync = require('browser-sync').create();
gulp.task('rubySass', function() {
return rubySass('sources/', {
style: 'expanded',
sourcemap: true
})
.on('error', function (err) {
console.error('Error!', err.message);
})
.pipe(sourcemaps.write('maps', {
includeContent: false,
sourceRoot: '/sources'
}))
// note the destination change here
.pipe(gulp.dest('./css/sass')) // note the destination change here
.pipe(browsersync.stream({match: "**/*.css"}));
});
gulp.task('browsersync', function() {
browsersync.init({
server: './',
logConnections: true
});
});
gulp.task('default', ['rubySass', 'browsersync'], function (){
gulp.watch('**/*.html', browsersync.reload);
gulp.watch('**/*.php', browsersync.reload);
gulp.watch('js/**/*.js', browsersync.reload);
// added exclusion for the CSS files generated from SASS
gulp.watch(['**/*.css', '!./css/sass/**/*.css'], function(file){
console.log("In gulp watch : css");
gulp.src(file.path)
.pipe(browsersync.stream());
});
gulp.watch('./sources/**/*.scss', ['rubySass']).on('change', function(evt) {
console.log("In gulp watch : sass");
});
});