How to include Facebook-SDK - symfony

I'm using an example of FOSUserBundle with FOSFacebookBundle. Hereon i have build my application.
The relevant Project Structure is like following:
src\ABC\MainBundle\
src\ABC\UserBundle\
src\ABC\MainBundle\Controller\DefaultController.php
src\ABC\UserBundle\Security\User\Provider\FacebookProvider.php
vendor\facebook\php-sdk\src\base_facebook.php
Part of the FacebookProvider:
use \BaseFacebook;
use \FacebookApiException;
class FacebookProvider implements UserProviderInterface
{
protected $facebook;
public function __construct(BaseFacebook $facebook, $userManager, $validator)
{
$this->facebook = $facebook;
}
public function loadUserByUsername($username)
{
try {
$fbdata = $this->facebook->api('/me');
...
As you can see there is the Facebook-Object already available.
What i want to do now is nearly the same, but in my DefaultController:
use \BaseFacebook;
use \FacebookApiException;
class DefaultController extends BaseController
{
public function indexAction(){
$facebook = new Facebook('key', 'secret');
$fbfriends_obj = $facebook->api('/'.$fbid.'/friends');
...
But there i get the message
Fatal error: Class 'ABC\MainBundle\Controller\Facebook' not found in C:\xampp\htdocs\...\src\ABC\MainBundle\Controller\DefaultController.php on line x
Why is that? How can i access the facebook-class from inside my defaultcontroller? If its already possible for the facebookprovider, why it aint possible for my controller?
any hints will be really appreciated!

The solution to that problem is, that the facebook-class has no namespace and you have to do something like
$facebook = new \Facebook(...)

Problem is here:
use \BaseFacebook;
use \FacebookApiException;
You are importing BaseFacebook class from namespace you should use \Facebook (in Controller and FacebookProvider classes)

Related

spryker extend DummyPaymentHandlerPlugin class

I am new to spryker and I want to extend this class DummyPaymentHandlerPlugin. I tried by adding the class to the factory but is not working. Can anyone help me to do this
Extending plugins in Spryker is possible. But instead of changing the factory method, you just have to change the use statement in the appropriate dependency provider.
In your case, it's \Pyz\Yves\CheckoutPage\CheckoutPageDependencyProvider::extendPaymentMethodHandler:
protected function extendPaymentMethodHandler(Container $container): Container
{
$container->extend(static::PAYMENT_METHOD_HANDLER, function (StepHandlerPluginCollection $paymentMethodHandler) {
$paymentMethodHandler->add(new DummyPaymentHandlerPlugin(), DummyPagmentConfig::PAYMENT_PROVIDER_NAME);
return $paymentMethodHandler;
});
return $container;
}

how to use Symfony methods Action excluding the "Action" word

I am currently migrating an existent application to Symfony2 that has about 100 controllers with approximately 8 actions in each controller. All the current Actions are named as follow:
public function index(){}
However the default naming convention for Symfony is indexAction().
Is it possible to keep all my current actions and tell Symfony to use as it is without the "Action" word after the method name?
thank you.
Yes, this is possible. You should be able to define routes as normal, but you need to change the way the kernel finds the controller. The best way to do this is to replace/decorate/extends the service 'controller_name_converter'. This is a private service and is injected into the 'controller_resolver' service.
The source code of the class you want to replace is at 'Symfony\Bundle\FrameworkBundle\Controller\ControllerNameParser'.
Basically, the code runs like this. The 'bundle:controller:action' you specified when creating the route is saved in the cache. When a route is matched, that string is given back to the kernel, which in turn calls 'controller_resolver' which calls 'controller_name_resolver'. This class convert the string into a "namespace::method" notation.
Take a look at decorating services to get an idea of how to do it.
Here is an untested class you can work with
class ActionlessNameParser
{
protected $parser;
public function __construct(ControllerNameParser $parser)
{
$this->parser = $parser;
}
public function parse($controller)
{
if (3 === count($parts = explode(':', $controller))) {
list($bundle, $controller, $action) = $parts;
$controller = str_replace('/', '\\', $controller);
try {
// this throws an exception if there is no such bundle
$allBundles = $this->kernel->getBundle($bundle, false);
} catch (\InvalidArgumentException $e) {
return $this->parser->parse($controller);
}
foreach ($allBundles as $b) {
$try = $b->getNamespace().'\\Controller\\'.$controller.'Controller';
if (class_exists($try)) {
// You can also try testing if the action method exists.
return $try.'::'.$action;
}
}
}
return $this->parser->parse($controller);
}
public function build($controller)
{
return $this->parser->build($controller);
}
}
And replace the original service like:
actionless_name_parser:
public: false
class: My\Namespace\ActionlessNameParser
decorates: controller_name_converter
arguments: ["#actionless_name_parser.inner"]
Apparently the Action suffix is here to distinguish between internal methods and methods that are mapped to routes. (According to this question).
The best way to know for sure is to try.
// src/AppBundle/Controller/HelloController.php
namespace AppBundle\Controller;
use Symfony\Component\HttpFoundation\Response;
use Sensio\Bundle\FrameworkExtraBundle\Configuration\Route;
class HelloController
{
/**
* #Route("/hello/{name}", name="hello")
*/
public function indexAction($name)
{
return new Response('<html><body>Hello '.$name.'!</body></html>');
}
}
Try to remove the Action from the method name and see what happens.

PHPUnit test if class methods were called

I have model class that calls mailer class inside one of its methods:
class someModel{
public function sendEmail($data){
$mailer = new Mailer();
$mailer->setFrom($data['from']);
$mailer->setTo($data['to']);
$mailer->setSubject($data['subject']);
return $mailer->send();
}
}
How can I test sendEmail method? Maybe I should mock mailer class and check if all these mailer methods were called in sendMail method?
Your help would be appreciated.
IMO wrapping the Mailer class does not solve the problem you're facing, which is you don't have control over the Mail instance being used.
The problem comes from creating the dependencies inside the object that needs them instead of injecting them externally like this:
class someModel{
private $mailer;
public function __construct(Mailer $mailer) {
$this->mailer = $mailer;
}
public function sendEmail($data){
$this->mailer->setFrom($data['from']);
$this->mailer->setTo($data['to']);
$this->mailer->setSubject($data['subject']);
return $this->mailer->send();
}
}
When creating the someModel instance, you must pass a Mail instance (which is an external dependency). And in the test you can pass a Mail mock that will check that the correct calls are being made.
Alternative:
If you feel that injecting a Mail instance is bad (maybe because there are lots of someModel instances), or you just can't change your code this way, then you could use a Services repository, that will keep a single Mail instance and that allows you to set it externally (again, in the test you would set a mock).
Try a simple one like Pimple.
I would (and have in my own code with Mailer!) wrap your instance of Mailer inside a class that you write. In other words, make your own Email class that uses Mailer under the hood. That allows you to simplify the interface of Mailer down to just what you need and more easily mock it. It also gives you the ability to replace Mailer seamlessly at a later date.
The most important thing to keep in mind when you wrap classes to hide external dependencies is keep the wrapper class simple. It's only purpose is to let you swap out the Email libraries class, not provide any complicated logic.
Example:
class Emailer {
private $mailer = new Mailer();
public function send($to, $from, $subject, $data) {
$this->mailer->setFrom($from);
$this->mailer->setTo($to);
...
return $mailer->send();
}
}
class EmailerMock extends Emailer {
public function send($to, $from, $subject, $data) {
... Store whatever test data you want to verify ...
}
//Accessors for testing the right data was sent in your unit test
public function getTo() { ... }
...
}
I follow the same pattern for all classes/libraries that want to touch things external to my software. Other good candidates are database connections, web services connections, cache connections, etc.
EDIT:
gontrollez raised a good point in his answer about dependency injection. I failed to explicitly mention it, but after creating the wrapper the way you would want to use some form of dependency injection to get it into the code where you want to use it. Passing in the instance makes it possible to setup the test case with a Mocked instance.
One method of doing this is passing in the instance to the constructor as gontrollez recommends. There are a lot of cases where that is the best way to do it. However, for "external services" that I am mocking I found that method became tedious because so many classes ended up needing the instance passed in. Consider for example a database driver that you want to Mock for your tests, but you use in many many different classes. So instead what I do is create a singleton class with a method that lets me mock the whole thing at once. Any client code can then just use the singleton to get access to a service without knowing that it was mocked. It looked something like this:
class Externals {
static private $instance = null;
private $db = null;
private $email = null;
...
private function __construct() {
$this->db = new RealDB();
$this->mail = new RealMail();
}
static function initTest() {
self::get(); //Ensure instance created
$db = new MockDB();
$email = new MockEmail();
}
static function get() {
if(!self::$instance)
self::$instance = new Externals();
return self::$instance;
}
function getDB() { return $this->db; }
function getMail() { return $this->mail; }
....
}
Then you can use phpunit's bootstrap file feature to call Externals::initTest() and all your tests will be setup with the mocked externals!
First, as RyanW says, you should write your own wrapper for Mailer.
Second, to test it, use a mock:
<?php
class someModelTest extends \PHPUnit_Framework_TestCase
{
public function testSendEmail()
{
// Mock the class so we can verify that the methods are called
$model = $this->getMock('someModel', array('setFrom', 'setTo', 'setSubject', 'send'));
$controller->expects($this->once())
->method('setFrom');
$controller->expects($this->once())
->method('setTo');
$controller->expects($this->once())
->method('setSubject');
$controller->expects($this->once())
->method('send');
$model->sendEmail();
}
}
The above code is untested, but it basically mocks the someModel class, creating dummy functions for each each function called within sendEmail. It then tests to make sure each of the functions called by sendEmail is called exactly once when sendEmail is called.
See the PHPUnit docs for more info on mocking.

In phpunit what is the difference between __construct versus setup?

I am curious to know it is good practice to create object in test class __construct or we should always use setup/teardown approach ( or setUpBeforeClass/tearDownAfterClass approach)?
I aware of the fact set/teardown gets called for each test so will it do any good if I put my object creation code in it? e.g.
//mytestclass.php
class MyTestClass extends PHPUnit_Framework_TestCase
{
private $obj;
protected function setUp()
{
$this->obj = new FooClass();
}
public testFooObj()
{
//assertions for $this->obj
}
...
}
what could be the issues if I create object in constructor like this:
class MyTestClass extends PHPUnit_Framework_TestCase
{
private $obj;
protected function __construct()
{
$this->obj = new FooClass();
}
public testFooObj()
{
//assertions for $this->obj
}
...
}
I tried googling around as well as PHPUnit documentation couldn't get much information about, Can you please help me to understand which one is good practice?
setUp() gets called before each of your tests is ran. __construct() happens when your class is instantiated. So if you have multiple tests and they use local properties and modify them, using setUp() you can ensure that they are the same before each test is ran. The opposite of setUp() is tearDown() where you can ensure that test data gets cleaned up after each test.
As I have just found out, implementing the default class constructor instead of the setupBeforeClass() method breaks the #dataProvider annotations (probably all kinds of annotations), yielding a "Missing argument" exception for any parameterized tests.
Missing argument 1 for AppBundle\Tests\Service\InvitationVerifierTest::testDireccionInvalida()
Replacing public function __construct() for public static function setUpBeforeClass() gets rid of the exception. So there it goes, favor the setupBeforeClass() method over the regular constructor.
PHPUnit version 4.5.0

Eloquent class not found when testing new models

I'm trying to test my eloquent models but my tests keep failing with "Class 'Eloquent' not found" errors. If I add a route that uses my eloquent model and simply prints some of the information stored in the database, everything works fine. It is only when trying to run phpunit that I get the issues with eloquent not being found. My model is in app/models so it should be included in the composer classmap and I've done composer dump-autoload. I'm sure I'm overlooking something really obvious but I can't pick it out. Any idea what the issue is?
My test:
class GameTest extends TestCase {
public function setUp(){
$this->game = Game::find(1);
}
public function testGameInstance(){
$this->assertInstanceOf('Game', $this->game);
}
}
My model:
class Game extends Eloquent{
protected $table = 'gm_game';
protected $primaryKey = 'game_id';
}
Try adding parent::setUp() in your test's setUp function. This solved the issue for me.
Example:
class GameTest extends TestCase {
public function setUp(){
parent::SetUp();
$this->game = Game::find(1);
}
public function testGameInstance(){
$this->assertInstanceOf('Game', $this->game);
}
}

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