I'm in the process of making my own package for an Ada main program. I read a string followed by an integer and another string and the problem is I need to cut the first string at sign of first space. I don't know how to do it and I've searched stack overflow only to find solutions in other languages.
My code right now in the package body is:
Get_Line(Item.String, Item.X1)
where X1 is an integer and String is the string. This works if you define the length in the type to match the exact length of your input but of course you want to be able to insert whatever you want and thus it doesn't work.
Can somebody point me in the right direction?
Thanks
Why do you need to make a package for an Ada main program? Most compilers need them to be parameterless library-level procedures.
Anyway, this might give you some tips.
with Ada.Text_IO;
with Ada.Integer_Text_IO;
procedure Agrell is
begin
declare
Line : constant String := Ada.Text_IO.Get_Line;
This is how to deal with reading a string of unknown length. You have to work out how to preserve it for future use (maybe use an Unbounded_String?)
The_Integer : Integer;
begin
Looking_For_Space :
for J in Line'Range loop
if Line (J) = ' ' then
Everything from Line’First to J - 1 is the string you wanted.
declare
Dummy : Positive;
begin
Ada.Integer_Text_IO.Get (From => Line (J .. Line'Last),
Item => The_Integer,
Last => Dummy);
end;
OK, now we have The Integer...
...
exit Looking_For_Space;
... and we’re done with the first line.
end if;
end loop Looking_For_Space;
end;
end Agrell;
I am learning Ada (by trying https://adventofcode.com/2018/ problems). To start with, I am trying to develop a number of "utility" packages that will help with text processing etc.
I have successfully written a function that will read from stdin and return an array of Unbounded_Strings for each input line.
I am trying to modify that function to do the same, but instead convert each Unbounded_String to an Integer before insertion into the array.
Here is my package:
get_stdin.ads:
with Ada.Strings.Unbounded;
package get_stdin is
type IntegerArray is array (Natural range <>) of Integer;
function get_ints return IntegerArray;
end get_stdin;
get_stdin.adb:
with Ada.Text_IO;
with Ada.Text_IO.Unbounded_IO;
with Ada.Strings.Unbounded;
with Ada.Strings;
package body get_stdin is
function get_ints return IntegerArray is
Counter : Natural := 0;
Str : Ada.Strings.Unbounded.Unbounded_String;
Arr : IntegerArray(0..10000);
begin
while not Ada.Text_IO.End_Of_File loop
Str := Ada.Text_IO.Unbounded_IO.Get_Line;
Arr(Counter) := Integer'Value(Ada.Strings.Unbounded.To_String(Str));
Counter := Counter + 1;
end loop;
return Arr(0..Counter-1);
end get_ints;
end get_stdin;
I am calling using this package inside this procedure:
procedure d1 is
StdinArr : get_stdin.IntegerArray := get_stdin.get_ints;
begin
null; -- Array processing to follow
end;
This successfully compiles, and I then pipe in my input text file:
me#mypc /cygdrive/c/Users/me/aoc2018
$ cat d1.txt
-6
-1
-18
-10
...etc
me#mypc /cygdrive/c/Users/me/aoc2018
$ cat d1.txt | ./d1.exe
raised CONSTRAINT_ERROR : bad input for 'Value: "-6"
"-6" is the first value in the text file. My string-to-integer conversion code was essentially copied from this question.
I am not sure why a bad input error is raised.
It raises the same error if I replace -6 with a positive integer in the file
This is running under Cygwin on Windows 10.
Compiled/linked with gnatmake version 7.3.0
Note: I'm just getting started with Ada so there's probably lots of issues with my code in general.
What am I doing wrong and how can I fix this function/package to return my IntegerArray type correctly filled with Integers?
This was a line endings issue. I was running under cygwin on Windows 10. My text file has Windows-style line endings.
Using dos2unix:
$ cat d1.txt | dos2unix.exe | ./d1.exe
was sufficient to make it work correctly.
If anyone can explain precisely why, that would be interesting. I'm guessing that Get_Line only strips off the \n character, not the \r.
I hope I get someone who understand this. I have been trying to concatenate Julia string for quit a while now but I still have an issue. I have this loop where I am trying to concatenate the string and a number from the loop then add the new value to an array, everything is fine when I print the value in the loop but printing the arrays then all the elements of the array are split again to individual characters.
my code is as bellow
a = 1
for i in nums_loop
i_val = i[a]
append!(const_names, (string(x, string(a))))
println(string(x, string(a)))
a += 1
end
print(const_names)
the output is as bellow
X1
X2
Any['X', '1', 'X', '2']
This seems the easiest way: first initiliaze your array_names with an empty string, later removing it with popfirst! (bad practise to call the array constant if you are actually changing its content)
array_names=[" "]
num_loops=2
for i=1:num_loops
push!(array_names, "X$i")
end
popfirst!(array_names)
println(array_names)
This gives me the result:
julia> println(array_names)
["X1", "X2"]
Someone please help me understand this. I have the following code below. I am trying to append index[i]-1 to an empty array. However I am getting this error: "BoundsError: attempt to access 0-element Array{Any,1} at index [1]" :
sample_size_array = [9,5,6,9,2,6,9]
n_minus_1 = []
array_length = length(sample_size_array)
for i in 1:array_length
n_minus_1[i].append(sample_size_array[i] -1)
end
println(n_minus_1)
If Julia does not understand array[0] then why is i starting at 0 and not at 1?
Your code has two problems:
in the first iteration you are trying to access n_minus_1 array at index 1 while this array is still empty (has 0 length) - this throws you an error;
in Julia you do not invoke methods using a . (this symbol is used for different purposes - in this case it is parsed as field access and also would throw an error later)
To solve both those problems use push! function which appends an element at the end of an array. The code could look like this:
sample_size_array = [9,5,6,9,2,6,9]
n_minus_1 = []
array_length = length(sample_size_array)
for i in 1:array_length
push!(n_minus_1, sample_size_array[i]-1)
end
println(n_minus_1)
However in this case the whole operation can be written even simpler as:
n_minus_1 = sample_size_array .- 1
and you do not need any loop (and here you see another use of . in Julia - in this case we use it to signal that we want to subtract 1 from every element of sample_size_array).
I am trying to learn Erlang and I am working on the practice problems Erlang has on the site. One of them is:
Write the function time:swedish_date() which returns a string containing the date in swedish YYMMDD format:
time:swedish_date()
"080901"
My function:
-module(demo).
-export([swedish_date/0]).
swedish_date() ->
[YYYY,MM,DD] = tuple_to_list(date()),
string:substr((integer_to_list(YYYY, 3,4)++pad_string(integer_to_list(MM))++pad_string(integer_to_list(DD)).
pad_string(String) ->
if
length(String) == 1 -> '0' ++ String;
true -> String
end.
I'm getting the following errors when compiled.
demo.erl:6: syntax error before: '.'
demo.erl:2: function swedish_date/0 undefined
demo.erl:9: Warning: function pad_string/1 is unused
error
How do I fix this?
After fixing your compilation errors, you're still facing runtime errors. Since you're trying to learn Erlang, it's instructive to look at your approach and see if it can be improved, and fix those runtime errors along the way.
First let's look at swedish_date/0:
swedish_date() ->
[YYYY,MM,DD] = tuple_to_list(date()),
Why convert the list to a tuple? Since you use the list elements individually and never use the list as a whole, the conversion serves no purpose. You can instead just pattern-match the returned tuple:
{YYYY,MM,DD} = date(),
Next, you're calling string:substr/1, which doesn't exist:
string:substr((integer_to_list(YYYY,3,4) ++
pad_string(integer_to_list(MM)) ++
pad_string(integer_to_list(DD))).
The string:substr/2,3 functions both take a starting position, and the 3-arity version also takes a length. You don't need either, and can avoid string:substr entirely and instead just return the assembled string:
integer_to_list(YYYY,3,4) ++
pad_string(integer_to_list(MM)) ++
pad_string(integer_to_list(DD)).
Whoops, this is still not right: there is no such function integer_to_list/3, so just replace that first call with integer_to_list/1:
integer_to_list(YYYY) ++
pad_string(integer_to_list(MM)) ++
pad_string(integer_to_list(DD)).
Next, let's look at pad_string/1:
pad_string(String) ->
if
length(String) == 1 -> '0' ++ String;
true -> String
end.
There's a runtime error here because '0' is an atom and you're attempting to append String, which is a list, to it. The error looks like this:
** exception error: bad argument
in operator ++/2
called as '0' ++ "8"
Instead of just fixing that directly, let's consider what pad_string/1 does: it adds a leading 0 character if the string is a single digit. Instead of using if to check for this condition — if isn't used that often in Erlang code — use pattern matching:
pad_string([D]) ->
[$0,D];
pad_string(S) ->
S.
The first clause matches a single-element list, and returns a new list with the element D preceded with $0, which is the character constant for the character 0. The second clause matches all other arguments and just returns whatever is passed in.
Here's the full version with all changes:
-module(demo).
-export([swedish_date/0]).
swedish_date() ->
{YYYY,MM,DD} = date(),
integer_to_list(YYYY) ++
pad_string(integer_to_list(MM)) ++
pad_string(integer_to_list(DD)).
pad_string([D]) ->
[$0,D];
pad_string(S) ->
S.
But a simpler approach would be to use the io_lib:format/2 function to just format the desired string directly:
swedish_date() ->
io_lib:format("~w~2..0w~2..0w", tuple_to_list(date())).
First, note that we're back to calling tuple_to_list(date()). This is because the second argument for io_lib:format/2 must be a list. Its first argument is a format string, which in our case says to expect three arguments, formatting each as an Erlang term, and formatting the 2nd and 3rd arguments with a width of 2 and 0-padded.
But there's still one more step to address, because if we run the io_lib:format/2 version we get:
1> demo:swedish_date().
["2015",["0",56],"29"]
Whoa, what's that? It's simply a deep list, where each element of the list is itself a list. To get the format we want, we can flatten that list:
swedish_date() ->
lists:flatten(io_lib:format("~w~2..0w~2..0w", tuple_to_list(date()))).
Executing this version gives us what we want:
2> demo:swedish_date().
"20150829"
Find the final full version of the code below.
-module(demo).
-export([swedish_date/0]).
swedish_date() ->
lists:flatten(io_lib:format("~w~2..0w~2..0w", tuple_to_list(date()))).
UPDATE: #Pascal comments that the year should be printed as 2 digits rather than 4. We can achieve this by passing the date list through a list comprehension:
swedish_date() ->
DateVals = [D rem 100 || D <- tuple_to_list(date())],
lists:flatten(io_lib:format("~w~2..0w~2..0w", DateVals)).
This applies the rem remainder operator to each of the list elements returned by tuple_to_list(date()). The operation is needless for month and day but I think it's cleaner than extracting the year and processing it individually. The result:
3> demo:swedish_date().
"150829"
There are a few issues here:
You are missing a parenthesis at the end of line 6.
You are trying to call integer_to_list/3 when Erlang only defines integer_to_list/1,2.
This will work:
-module(demo).
-export([swedish_date/0]).
swedish_date() ->
[YYYY,MM,DD] = tuple_to_list(date()),
string:substr(
integer_to_list(YYYY) ++
pad_string(integer_to_list(MM)) ++
pad_string(integer_to_list(DD))
).
pad_string(String) ->
if
length(String) == 1 -> '0' ++ String;
true -> String
end.
In addition to the parenthesis error on line 6, you also have an error on line 10 where yo use the form '0' instead of "0", so you define an atom rather than a string.
I understand you are doing this for educational purpose, but I encourage you to dig into erlang libraries, it is something you will have to do. For a common problem like this, it already exists function that help you:
swedish_date() ->
{YYYY,MM,DD} = date(), % not useful to transform into list
lists:flatten(io_lib:format("~2.10.0B~2.10.0B~2.10.0B",[YYYY rem 100,MM,DD])).
% ~X.Y.ZB means: uses format integer in base Y, print X characters, uses Z for padding