I tried a lot on oval shape which have cut in both sides but not able to do it please
I need code for oval shape with cut in both side..
Here's my code below:-
.demo{
width: 100%;
height: 600px;
background: white;
-moz-border-radius: 100px / 50px;
-webkit-border-radius: 100px / 178px;
border-radius: 694px / 208px;
z-index: 100;
position: relative;
}
Is this OK ?
HTML
<div id="oval_parent">
<div id="oval"></div>
</div>
CSS
#oval_parent{
background:black;
width:200px;
height:120px;
overflow:hidden;
}
#oval{
width: 220px;
height: 100px;
margin:10px 0 0 -10px;
background: white;
-moz-border-radius: 100px / 50px;
-webkit-border-radius: 100px / 50px;
border-radius: 100px / 50px;
}
DEMO.
Try this:
#oval-shape {
width: 200px;
height: 100px;
background: blue;
-moz-border-radius: 100px / 50px;
-webkit-border-radius: 100px / 50px;
border-radius: 100px / 50px;
}
Notice the ratios in the corner values in relation to the height.
Demo - http://jsfiddle.net/XDLVx/
Change the values on css:
#demo {
width: 100%;
height: 600px;
background: white;
-moz-border-radius: 50% / 250px;
-webkit-border-radius: 40% / 250px;
border-radius: 50% / 250px;
z-index: 100;
position: relative;
}
Put it inside another div which is high enough to show all the oval, not quite wide enough, and set overflow: hidden. If it's positioned at the centre the edges will be cut off, but you won't be able to side-scroll.
Here are two possible variants:
Method #01:
Use radial-gradient():
background: radial-gradient(ellipse 65% 40%, transparent 0, transparent 90%, black 90%);
body {
background: linear-gradient(orange, red);
padding: 0 20px;
margin: 0;
}
.oval {
background: radial-gradient(ellipse 65% 40%, transparent 0, transparent 90%, black 90%);
height: 100vh;
}
<div class="oval">
</div>
Method #02:
Create an overlay with :before or :after pseudo element.
Add border-radius.
Apply a large box-shadow with overflow: hidden on parent to hide undesired area.
body {
background: linear-gradient(orange, red);
padding: 0 20px;
margin: 0;
}
.oval {
position: relative;
overflow: hidden;
height: 100vh;
}
.oval:before {
box-shadow: 0 0 0 500px #000;
border-radius: 100%;
position: absolute;
content: '';
right: -10%;
left: -10%;
top: 10%;
bottom: 10%;
}
<div class="oval">
</div>
Related
how can I replicate this?
I need to do this with CSS, but I only can do the outside part with 2 separate lines:
.top-left {
position: absolute;
background: black;
height: 3px;
width: 4rem;
top: 0;
left: 0;
border-top-left-radius: 150px;
}
.left-top {
position: absolute;
background: black;
height: 4rem;
width: 3px;
top: 0;
left: 0;
border-bottom-left-radius: 150px;
}
<div class="top-left"></div>
<div class="left-top"></div>
You can do this with one element and some gradient but without transparency:
.box {
width:200px;
height:100px;
border-radius:20px;
padding:5px;
background:
linear-gradient(#fff,#fff) content-box,
linear-gradient(red,red) top left /60px 40px,
linear-gradient(blue,blue) top right /60px 40px,
linear-gradient(green,green) bottom left /60px 40px,
linear-gradient(purple,purple) bottom right/60px 40px;
background-repeat:no-repeat;
}
<div class="box"></div>
I've been trying to make this shape in CSS, but unfortunately could not find a way how to. It's half pipe like shaped:
The pixelated corner should be smooth (it's a zoomed in image).
Anyone knows how to create this? Or can get me on the right tracks?
You will need to use pseudo element :after for the inner block and then apply border-radius for curved corner.
div {
height: 60px;
width: 60px;
border: solid red;
position: relative;
background: red;
border-width: 0 10px 10px 0;
box-sizing: border-box;
}
div:after {
content: "";
position: absolute;
top: 0;
left: 0;
right: 0;
bottom: 0;
border-bottom-right-radius: 10px;
background: #fff;
}
<div></div>
simple
.shape {
width: 140px;
height: 200px;
background-color: gray;
}
.shape:after {
content: '';
position: absolute;
width: 100px;
height: 160px;
background-color: #fff;
border-bottom-right-radius: 50px;
}
<div class="shape"></div>
I assume that the problem here is to create the "outer" curve, on the arbitrary background. It's achievable by the trick with clipping the needed part from the thick rounded border of the pseudo-element:
div {
width: 50%;
min-height: 4em;
margin: auto;
border: #888 solid;
border-width: 0 1em 1em 0;
position: relative;
}
div::after {
content: '';
border: #888 solid;
border-width: 0 1em 1em 0;
border-radius: 0 0 100% 0;
position: absolute;
right: -1em;
bottom: -1em;
width: 1em;
height: 1em;
clip: rect(0 1em 1em 0);
}
div:hover::after {
border-color: red; /* highlight the curved part */
}
body {
/* just as a background example */
background: repeating-linear-gradient(-45deg, #ddd, #ddd 1px, transparent 1px, transparent 10px);
min-height: 90vh;
}
<div></div>
You can do this with one element and with transparency like this:
.box {
width:80px;
height:100px;
border-right:20px solid grey;
border-bottom:20px solid grey;
box-sizing:border-box;
background:
radial-gradient(farthest-side at top left,transparent 98%,grey ) bottom right/20px 20px no-repeat;
}
body {
background:pink;
}
<div class="box">
</div>
Is a gradient like this is possible with pure CSS3? I haven't found a way to create the "swirl".
If you set a pseudo element with a style similar to this, and some transparency applied, I think that you can achieve your request
.test {
height: 400px;
width: 400px;
position: relative;
border-top-left-radius: 180px 250px;
margin: 100px 200px;
box-shadow: -15px -15px 60px -20px lightgreen,
inset 10px 10px 15px -10px lightblue;
}
<div class="test"></div>
I have a prototype going using box-shadows:
.box {
width: 500px;
height:200px;
background: linear-gradient(to right, #50bcf3 , #60ec94);
overflow: hidden;
}
.box:before, .box:after {
content: "";
height: 100%;
width: 200px;
display: block;
position: relative;
border-radius: 50% 50% 50% 50% / 60% 60% 40% 40%;
}
.box:before {
left: 200px;
top: 100px;
box-shadow: -30px 0 40px -10px #60ec94;
transform: skewX(-10deg);
}
.box:after {
left: 200px;
top: -300px;
transform: skewX(-10deg);
box-shadow: inset -40px 0 70px -30px #60ec94;
}
<div class="box"></div>
The code below will create an arrow right below an <a> element:
JSFiddle
.btn {
position: relative;
display: inline-block;
width: 100px;
height: 50px;
text-align: center;
color: white;
background: gray;
line-height: 50px;
text-decoration: none;
}
.btn:after {
content: "";
position: absolute;
bottom: -10px;
left: 0;
width: 0;
height: 0;
border-width: 10px 50px 0 50px;
border-style: solid;
border-color: gray transparent transparent transparent;
}
Hello!
The problem is that we have to indicate the link width to get an arrow of a proper size because we cannot indicate the border width in pixels.
How to make a responsive triangle percent based?
You could use a skewed and rotated pseudo element to create a responsive triangle under the link :
DEMO (resize the result window to see how it reacts)
The triangle maintains it's aspect ratio with the padding-bottom property.
If you want the shape to adapt it's size according to it's content, you can remove the width on the .btn class
.btn {
position: relative;
display: inline-block;
height: 50px; width: 50%;
text-align: center;
color: white;
background: gray;
line-height: 50px;
text-decoration: none;
padding-bottom: 15%;
background-clip: content-box;
overflow: hidden;
}
.btn:after {
content: "";
position: absolute;
top:50px; left: 0;
background-color: inherit;
padding-bottom: 50%;
width: 57.7%;
z-index: -1;
transform-origin: 0 0;
transform: rotate(-30deg) skewX(30deg);
}
/** FOR THE DEMO **/
body {
background: url('http://i.imgur.com/qi5FGET.jpg');
background-size: cover;
}
Hello!
For more info on responsive triangles and how to make them, you can have a look at
Triangles with transform rotate (simple and fancy responsive triangles)
Another solution to this would be to use a CSS clip-path to clip a triangle out of a coloured block. No IE support however, but could be used for internal tools etc.
DEMO
Written with SCSS for ease.
.outer {
background: orange;
width: 25%;
position: absolute;
top: 50%;
left: 50%;
transform: translate(-50%, -50%);
padding: 1em;
p {
margin: 0;
text-align: center;
color: #fff;
}
&:after {
content: '';
position: absolute;
top: 100%;
left: 0;
right: 0;
padding-bottom: 10%;
background: orange;
-webkit-clip-path: polygon(0% 0%, 100% 0%, 50% 100%);
clip-path: polygon(0% 0%, 100% 0%, 50% 100%);
}
}
I found solution that works with any width/height. You can use two pseudo-elements with linear-gradient background, like this, (fiddle):
.btn {
position: relative;
display: inline-block;
width: 100px;
height: 50px;
text-align: center;
color: white;
background: gray;
line-height: 50px;
text-decoration: none;
}
.btn:before {
content: "";
position: absolute;
top: 100%;
right: 0;
width: 50%;
height: 10px;
background: linear-gradient(to right bottom, gray 50%, transparent 50%)
}
.btn:after {
content: "";
position: absolute;
top: 100%;
left: 0;
width: 50%;
height: 10px;
background: linear-gradient(to left bottom, gray 50%, transparent 50%)
}
A modified version of the below code can help you to achieve this
HTML
<div class="triangle-down"></div>
CSS
.triangle-down {
width: 10%;
height: 0;
padding-left:10%;
padding-top: 10%;
overflow: hidden;
}
.triangle-down:after {
content: "";
display: block;
width: 0;
height: 0;
margin-left:-500px;
margin-top:-500px;
border-left: 500px solid transparent;
border-right: 500px solid transparent;
border-top: 500px solid #4679BD;
}
For further reading on responsive triangles: CSS triangles made responsive
(archived link)
I tried the other answers and found them to be either too complex and/or unwieldy to manipulate the shape of the triangle. I decided instead to create a simple triangle shape as an svg.
The triangle height can be set to an absolute value, or as a percentage of the rectangle so it can be responsive in both directions if necessary.
html, body{
height:100%;
width:100%;
}
.outer{
width:20%;
height:25%;
background:red;
position:relative;
}
.inner{
height:100%;
width:100%;
background-color:red;
}
.triangle-down{
height:25%;
width:100%;
position:relative;
}
.triangle-down svg{
height:100%;
width:100%;
position:absolute;
top:0;
}
svg .triangle-path{
fill:red;
}
<div class="outer">
<div class="inner"></div>
<div class="triangle-down">
<svg xmlns="http://www.w3.org/2000/svg" preserveAspectRatio="none" viewBox="0 0 2 1">
<g>
<path class="triangle-path" d="M0,0 l2,0 l-1,1 z" />
</g>
</svg>
</div>
Tested FF, Chrome, IE, Edge, mob Safari and mob Chrome
Another option would be to use background liner gradients, and flex positioning to make sure that the triangle always scales to its parent container. No matter how wide or narrow you make that container, the triangle always scales with it. Here is the fiddle:
https://jsfiddle.net/29k4ngzr/
<div class="triangle-wrapper-100">
<div class="triangle-left"></div>
<div class="triangle-right"></div>
</div>
.triangle-wrapper-100 {
width: 100%;
height: 100px;
display:flex;
flex-direction: column;
flex-wrap: wrap;
}
.triangle-right {
right: 0px;
background: linear-gradient(to right bottom, #6940B5 50%, transparent 50%);
width: 50%;
height: 100px;
}
.triangle-left {
left: 0px;
background: linear-gradient(to right bottom, #6940B5 50%, transparent 50%);
width: 50%;
height: 100px;
transform: scaleX(-1);
}
I took #Probocop's answer and come up with the following:
<style>
.btn {
background-color: orange;
color: white;
margin-bottom: 50px;
padding: 15px;
position: relative;
text-align: center;
text-decoration: none;
}
.btn:after {
background-color: inherit;
clip-path: url('data:image/svg+xml;utf8,%3Csvg xmlns="http://www.w3.org/2000/svg"%3E%3Cdefs%3E%3CclipPath id="p" clipPathUnits="objectBoundingBox"%3E%3Cpolygon points="0 0, 1 0, 0.5 1" /%3E%3C/clipPath%3E%3C/defs%3E%3C/svg%3E#p'); /* fix for firefox (tested in version 52) */
clip-path: polygon(0% 0%, 100% 0%, 50% 100%);
content: '';
height: 50px;
left: 0;
position: absolute;
right: 0;
top: 100%;
}
</style>
Hello!
This works in Chrome and I've added a fix for Firefox. It doesn't work in Edge, however if you decrease the height of the down arrow then it doesn't look so bad.
Please note that if you are using bootstrap you will need to either change the name or override some of the styles it applies. If you decide to rename it then you also need to add the following to the .btn style:
box-sizing: content-box;
I would like a div to look like this:
but would only like to use CSS, how would I go about creating a shape like this?
Do I create custom border for the top and bottom?
You can look at the code here, it does exactly what you want: http://codepen.io/orhanveli/pen/tbGJL
The code from the website:
HTML
<!-- Lets create a CSS3 stamp -->
<div class="stamp">
<!-- the image -->
<img src="http://thecodeplayer.com/uploads/media/css3logo.png" />
</div>
CSS
*{margin: 0; padding: 0;}
body {
background: #B1d202;
padding: 100px;
text-align: center;
}
.stamp {
width: 280px;
height: 180px;
display: inline-block;
padding: 10px;
background: white;
position: relative;
-webkit-filter: drop-shadow(0px 0px 10px rgba(0,0,0,0.5));
/*The stamp cutout will be created using crisp radial gradients*/
background: radial-gradient(
transparent 0px,
transparent 4px,
white 4px,
white
);
/*reducing the gradient size*/
background-size: 20px 20px;
/*Offset to move the holes to the edge*/
background-position: -10px -10px;
}
.stamp:after {
content: '';
position: absolute;
/*We can shrink the pseudo element here to hide the shadow edges*/
left: 5px; top: 5px; right: 5px; bottom: 5px;
/*Shadow - doesn't look good because of the stamp cutout. We can still move this into another pseudo element behind the .stamp main element*/
/*box-shadow: 0 0 20px 1px rgba(0, 0, 0, 0.5);*/
/*pushing it back*/
z-index: -1;
}
/*Some text*/
.stamp:before {
content: 'CSS3';
position: absolute;
bottom: 0; left: 0;
font: bold 24px arial;
color: white;
opacity: 0.75;
line-height: 100%;
padding: 20px;
}
.stamp img {
}
If you want to only have the borders on the top and on the bottom of your image you can create this by using pseudo elements.
.stamp {
margin-top: 50px;
margin-left: 50px;
position: relative;
width: 500px;
height: 300px;
background: #bbb;
-webkit-filter: drop-shadow(3px 3px 1px black);
filter: drop-shadow(0px 0px 5px white);
}
.stamp:before {
position: absolute;
top: -20px;
display: block;
content: "";
background: radial-gradient(circle, transparent 15px, #bbb 16px);
background-size: 50px 40px;
background-position: -20px -20px;
width: 100%;
height: 40px;
z-index: -1;
}
.stamp:after {
position: absolute;
bottom: -20px;
content: "";
display: block;
background: radial-gradient(circle, transparent 15px, #bbb 16px);
background-size: 50px 40px;
background-position: -20px -20px;
width: 100%;
height: 40px;
z-index: -1;
}
body {
margin: 0;
background-color: #333;
}
<div class="stamp">
</div>
You could use the mask-box-image property to do this.
FIDDLE
See this html5 Rocks article on masking
<img src="http://www.html5rocks.com/en/tutorials/masking/adobe/humayun-thom-arno.jpg" />
CSS
img {
-webkit-mask-box-image: url(http://www.html5rocks.com/en/tutorials/masking/adobe/stampTiles.svg) 35 repeat;
mask-box-image: url(http://www.html5rocks.com/en/tutorials/masking/adobe/stampTiles.svg) 35 repeat;
}