Is there any way to check in Xquery (A Xquery function) if an input string has only characters A-Z or numbers 0-9 and no other characters.
for example if the string is ABZ10 the function should return true and if the input string is 5& 123x it returns a false.
I am able to do it in java by simply using following.
inputstring.matches("^[0-9A-Z]+$"))
Use:
matches($vYourString, '^[A-Z0-9]+$')
Related
I'm trying to write a regular expression for a username that fits the following criteria...
Must be between 6 and 16 characters,
any 4 of which must be letters (though not necessarily consecutive),
May also contain letters, numbers, dash and underscore.
So _1Bobby1_ and -Bo-By19- would match, but _-bo-_ and -123-456_ wouldn't.
I've tried:
^(?=.*[a-zA-Z].{4})([a-zA-Z0-9_-]{6,16})$
But this doesn't seem to work, I've looked online and can't find anything that works and used Regexper to visualise the expression and try to build it from scratch.
Any pointers would be greatly appreciated.
This regex can be used to verify username
^(?=.{6,16}$)(?=(?:.*[A-Za-z]){4})[\w-]+$
Regex Breakdown
^ #Start of string
(?=.{6,16}$) #There should be between 6 to 16 characters
(?=
(?:.*[A-Za-z]){4} # Lookahead to match 4 letter anywhere in string
)
[\w-]+ #If above conditions are correct, match the string. It should only contain dgits, alphabets and dash
$ #End of string. Not necessary as the first check (?=.{6,16}$) itself does that
bool IsValid(string userName)
{
return userName.Length >= 6 && userName.Length <= 16 && userName.Count(s => char.IsLetter(s)) >= 4;
}
It simpler not to use regular expressions.
And as known you can use other char.Is[something] functions if you need it
Using Asp.net for regex.
I've written an extension method that I want to use to replace whole words - a word might also be a single special character like '&'.
In this case I want to replace '&' with 'and', and I'll need to use the same technique to reverse it back from 'and' to '&', so it must work for whole words only and not extended words like 'hand'.
I've tried a few variations for the regex pattern - started with '\bWORD\b' which didn't work at all for the ampersand, and now have '\sWORD\s' which almost works except that it also removes the spaces around the word, meaning that a phrase like "health & beauty" ends up as "healthandbeauty".
Any help appreciated.
Here's the extension method:
public static string ReplaceWord(this string #this,
string wordToFind,
string replacement,
RegexOptions regexOptions = RegexOptions.None)
{
Guard.String.NotEmpty(() => #this);
Guard.String.NotEmpty(() => wordToFind);
Guard.String.NotEmpty(() => replacement);
var pattern = string.Format(#"\s{0}\s", wordToFind);
return Regex.Replace(#this, pattern, replacement, regexOptions);
}
In order to match a dynamic string that should be enclosed with spaces (or be located at the start or end of string), you can use negative lookaheads:
var pattern = string.Format(#"(?<!\S){0}(?!\S)", wordToFind);
^^^^^^^ ^^^^^^
or even safer:
var pattern = string.Format(#"(?<!\S){0}(?!\S)", Regex.Escape(wordToFind));
^^^^^^^^^^^^^
The (?<!\S) lookbehind will fail the match if the word is not preceded with a non-whitespace character and (?!\S) lookahead will fail the match if the word is not followed with a non-whitespace character.
How to get rest of the values from the variable
${random employee}= Convert To String ${random emp}
${replace}= Remove String Using Regexp ${random employee} ['\\[\\]\\,]
${splitline}= Fetch From Left ${replace} ${SPACE}
Output:
${replace} Alagu kartest1234+3alagu#gmail.cokartest1234+3ramu#gmail.com Developer Team B3 Team lead
${splitline} = Alagu
How to get rest of the values from the variable ${replace}
Keyword Split String from String standard library does this.
Split String string, separator=None, max_split=-1
Splits the string using separator as a delimiter string.
If a separator is not given, any whitespace string is a separator. In that case also possible consecutive whitespace as well as leading and trailing whitespace is ignored.
Split words are returned as a list. If the optional max_split is given, at most max_split splits are done, and the returned list will have maximum max_split + 1 elements.
Examples:
#{words} = Split String ${string}
#{words} = Split String ${string} ,${SPACE}
To get single values from #{words} use common array syntax: #{NAME}[i]. i is the index of the selected value. Indexes start from zero.
I'm new to regular expresions. I have a gigantic text. In the aplication, i need words of 4 characters and delete the rest. The text is in spanish. So far, I can select 4 char length words but i still need to delete the rest.
This is my regular expression
\s(\w{3,3}[a-zA-ZáéíóúäëïöüñÑ])\s
How can i get all words with 4 letters in asp.net vb?
/(?:\A|(?<=\P{L}))(\p{L}{4})(?:(?=\P{L})|\z)/g
Explanation:
Switch /g is for repeatedly search
\A is start of the string (not start of line)
\p{L} matches a single code point in the category letter
\P{L} matches a single code point not in the category letter
{n} specify a specific amount of repetition [n is number]
\z is end of string (not end of line)
| is logic OR operator
(?<=) is lookbehind
(?=) is lookahead
(?:) is non backreference grouping
() is backreference grouping
Using the character class provided above in another answer (\w does NOT match spanish word characters unfortunately).
You can use this for a match (it matches the reverse, basically matches everything that is NOT a 4-character word, so you can replace with " ", leaving only the 4-character words):
/(^|(?<=(?<=\W)[a-zA-ZáéíóúäëïöüñÑ]{4,4}(?=\W)))(.*?)((?=(?<=\W)[a-zA-ZáéíóúäëïöüñÑ]{4,4}(?=\W))|$)/gis
Approximated code in VB (not tested):
Dim input As String = "This is your text"
Dim pattern As String = "/(^|(?<=(?<=\W)[a-zA-ZáéíóúäëïöüñÑ]{4,4}(?=\W)))(.*?)((?=(?<=\W)[a-zA-ZáéíóúäëïöüñÑ]{4,4}(?=\W))|$)/gis"
Dim replacement As String = " "
Dim rgx As New Regex(pattern)
Dim result As String = rgx.Replace(input, replacement)
Console.WriteLine("Original String: {0}", input)
Console.WriteLine("Replacement String: {0}", result)
You can see the result of the regex in action here:
http://regexr.com?30n29
\[^a-zA-ZáéíóúäëïöüñÑ][a-zA-ZáéíóúäëïöüñÑ]{4}[^a-zA-ZáéíóúäëïöüñÑ]\g
Translated:
A non-letter, followed by 4 letters, followed by a non-letter. The 'g' indicated will match globally ... more than once.
Check out this link to find out more info on looping over your matches:
http://osherove.com/blog/2003/5/12/practical-parsing-using-groups-in-regular-expressions.html
Is there any inbuild function to find out the last occurrence of a string pattern in a string in action script .
Yes, check out the lastIndexOf method of the String object.
PS. If by string pattern you mean a regular expression rather than a literal string, you could use the match method instead, passing a RegExp and setting the g (global) flag; then you could check the last match in the returned result.