It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center.
Closed 10 years ago.
I have a huge csv file of sports (EPL) data which encompasses player performance in every game for their respective teams. I would like to run a loop to compare the amount of times a team has scored first in a match (the data is called First.Goal).
I know how to calculate them individually, e.g for Liverpool from a csv called Prem1112:
Prem<-read.csv("Prem1112.csv")
sum(subset(Prem,Team=='Liverpool',First.Goal))
Ideally I'd like to run the loop so I wouldn't have to calculate all 20 teams individually. Any ideas?
What about this:
aggregate(First.Goal ~ Team, Prem, sum)
Related
It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center.
Closed 9 years ago.
How do we find the solution of x
say in
2*x=6
using R?
It must be very trivial but I cant find out the appropriate answer.
You can use the solve() function, which can actually handle multiple equations:
solve(2, 6)
The first argument is the left side of the equation, the second is the right side.
It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center.
Closed 9 years ago.
Have a dataframe in R, I want to delete all rows in that dataframe where column X has values >100%. Whats the best way to do this?
Appreciate the help.
If your column X contains numbers (which I'm pretty sure it does although your use of % symbols gives bit different impression), then you can select the rows i where X[i]<100 like this:
datasetnew <- dataset[dataset$X<=100,]
But if you really have percentages in the column, i.e. values in X are something like "10%","23%","103%", then you need to remove the % first, for example using the gsub function:
datasetnew <- dataset[as.numeric(gsub(dataset$X,"%",""))<=100,]
It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center.
Closed 10 years ago.
I need to represent vectors in 7- dimensional space.
How can I draw them and plot points on them?
I don't think there is a reasonable way to draw something 7-dimensional. Best thing to do is to draw several projections in fewer dimensions for instance 2 or 3. Even 4 dimensions is hard to comprehend for men.
It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center.
Closed 10 years ago.
I have boxscore data from the NFL and some of the data is obviously incorrect. For example for some games the number of sacks is negative, which is impossible. This column is named SackNumOff. How do I change any negative values in this column to zero?
Something like this:
dat$columnname[dat$columnname < 0] = 0
Replaces all negative numbers by 0. The idea is that you can use a subset [] both to extract a subset and assign values to a subset.
It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center.
Closed 10 years ago.
In many programming problems (e.g. some Project Euler problems) we are asked to report the answer as the remainder left after dividing the answer by 1,000,000,007.
Why not any other number?
Edit:
2 years later, here's what I know: the number is a big prime, and any answer to such a question is so large that it makes sense to report a remainder instead (as the number may be too large for a native datatype to handle).
Let me play a telepathist. 1000...7 are prime numbers and 1000000007 is the biggest one that fits in 32-bit integer. Since prime numbers are used to calculate hash (by finding the remainder of the division by prime), 1000000007 is good for calculating 32-bit hash.