I am using it but no value i found...I think there is mistake in this query....Actually I want to know how to use multiple sum, multiplication etc using mutiple tables in sqlite
SELECT
dhid, dprice, dname,
SUM(dmilk) AS totalmilk,
dprice*SUM(dmilk) AS totalmilkamt,
SUM(ghee) AS toalghee,
SUM(ghee*gheeprice) AS totalgheeamt,
SUM(ghee*gheeprice)+dprice*SUM(dmilk) AS totals,
SUM(cashamount) AS totalcash,
SUM(ghee*gheeprice)+dprice*SUM(dmilk)-SUM(cashamount) AS balance
FROM
( SELECT *
FROM costumer
LEFT OUTER JOIN salesdata
ON costumer.dhid=salesdata.ddhid
LEFT OUTER JOIN cashdata
ON salesdata.ddhid=cashdata.uid
AND utype='costumer')
WHERE dmonth='$mikdatem'
AND dyear='$mikdatey'
AND dhid='$dhid'
ORDER BY dhid ASC
Your select above will not help us because we don't have the underlying data to get an idea what you wish to do.
So the generalistic answer is this:
when using grouping-functions (SUM/COUNT...) you always require some form of "GROUP BY" to columns not used in those group-functions.
Example given:
SELECT name, sum(dmilk)
FROM milk_entry
GROUP BY name
Related
I have a query that I run in PostgreSQL like this:
select
c_count, count(*) as custdist
from (
select
c_custkey,
count(o_orderkey)
from
customer left outer join orders on
c_custkey = o_custkey
and o_comment not like '%special%requests%'
group by
c_custkey
)as c_orders (c_custkey, c_count)
group by
c_count
order by
custdist desc,
c_count desc;
And I wanted to run it on SQLite, but I got this error: Error: near" (": syntax error. Maybe he doesn't recognize this as c_orders (c_custkey, c_count).
Is there any way to rewrite this query to execute in SQLite?
SQLite does not allow redefining/renaming columns for an nested, aliased query. You can do that with a WITH clause (i.e. Common Table Expression; CTE). Or you can add aliases to the nested query columns directly using AS keyword.
Interesting that this is exactly how the outer query columns are named. Just use the same pattern for the nested query. I don't use PostgreSQL, but why not add aliases directly on each column and complicate it by using different syntax for each part of the query?
select
c_count, count(*) as custdist
from (
select
c_custkey,
count(o_orderkey) AS c_count
from
customer left outer join orders on
c_custkey = o_custkey
and o_comment not like '%special%requests%'
group by
c_custkey
) AS c_orders
group by
c_count
order by
custdist desc,
c_count desc;
Edit
I would rather explicitly state my problem I'm facing rather than assuming the approach. There could be an easiest solution to my problem.
I need to select records by joining two different table based on the result from another table. And I have to use different joins based on the result from the first table.
If a particular record is present in the first table, I have two use inner join the first table whereas if it's not present, then I have to left join.
bool recordPresent = select exists (select * from firstTable where access_id = 13) as access
if (recordPresent)
results = select * from secondTable s left join firstTable f on f.access_id = s.access_id where f.access_id is null order by access_id
else
results = select * from secondTable s inner join firstTable f on f.access_id = s.access_id
Is it possible to do the following query in SQLite.Swift without resorting to arbitrary SQL (which I do have working but would prefer to avoid)?
select table1.id, sum(table1.col1*table2.col2)
from table1, table2
where table1.id=table2.id
group by table1.id
I've attempted the following: the SQL (through asSQL()) appears to be correct, but I can't find a way to reference the aggregate column from the returned row.
let query = table1.select(id, (table1[column1]*table2[column2]).sum
.join(table2, on: table1[id] == table2[id])
.group(id)
Can you alias columns somehow?
OK, I've found the solution, and it only took me 2 days!
The way to alias a column in SQLite.swift is to use an expression.
The name of the expression becomes the column alias.
So instead of
let query = table1.select(id, (table1[column1]*table2[column2]).sum)
.join(table2, on: table1[id] == table2[id])
.group(id)
Use:
let aggrColumn = (table1[column1]*table2[column2]).sum
let query = table1.select(id, aggrColumn)
.join(table2, on: table1[id] == table2[id])
.group(id)
let results = try db.prepare(query)
for row in results {
myAggrColumn = try row.get(aggrColumn)
}
Using
select id, sum(table1.col1*table2.col2)
from table1, table2
were table1.id=table2.id
group by id
Will result (see below for corrections) in 2 columns, namely id and sum(table1,col*table2.col2)
However both uses of id would be ambiguous as coded as there are two such source columns.
As such the query should be changed (see following code whihc assumes you want the id from table1 (shouldn't matter if table2 were used due to the join))
Additionally were is not a keyword, it should be WHERE
An alias would likely make things easier you make an alias using the AS keyword. The folloiwng also includes AS mysumcolumn thus the resultant columns will be id and mysumcolumn
select table1.id, sum(table1.col1*table2.col2) AS mysumcolumn
from table1, table2
where table1.id=table2.id
group by table1.id
Running this with no data results in :-
I have the following DB structure:
tbl_record(_id,_id_user,...)
tbl_photo(_id,_id_record,...)
tbl_note(_id,_id_record,...)
When listing the records of a specific user while counting the number of photos a record has, I use the following query, which works fine:
SELECT tbl_record._id, COUNT(tbl_photo._id_record) AS photo_count FROM tbl_record
LEFT OUTER JOIN tbl_photo ON tbl_record._id=tbl_photo._id_record
WHERE tbl_record._id_user=? GROUP BY tbl_record._id;
Now, I'd like to do the same as above, but also count the number of notes a record has:
SELECT tbl_record._id, COUNT(tbl_photo._id_record) AS photo_count, COUNT(tbl_note._id_record) AS note_count FROM tbl_record
LEFT OUTER JOIN tbl_photo ON tbl_record._id=tbl_photo._id_record
LEFT OUTER JOIN tbl_note ON tbl_record._id=tbl_note._id_record
WHERE tbl_record._id_user=? GROUP BY tbl_record._id;
The count of the 2nd query does not work properly when a record has >0 photos & >0 notes, e.g. 3 photos & 5 photos which results in a count of 15 (3*5) for each.
Any idea how to make the 2nd query return the proper counts?
Thanks!!
You might be able to filter out duplicates by using COUNT(DISTINCT some_id), but this would be inefficient.
Better use correlated subqueries:
SELECT _id,
(SELECT COUNT(*)
FROM tbl_photo
WHERE _id_record = tbl_record._id
) AS photo_count,
(SELECT COUNT(*)
FROM tbl_note
WHERE _id_record = tbl_record._id
) AS note_count
FROM tbl_record
WHERE _id_user = ?
The question probably is quite confusing.
In affect i have the following:
WatchList table
UserId | FilmId
| 3 77
| etc etc
|
|
|
these are foreign keys for the following tables
FilmDB - Film_title, Film_plot, Film_Id etc.
and
aspnet_memberships - UserId, Username etc..
Now, i presume i will need to use a join but i am struggling with the syntax.
I would like to use 'Count' on the 'WatchList' and return the most frequent filmId's and their counterpart information, but i'd then like to return the REST of the FilmDB results, essentially giving me a list of ALL films, but with those found in the WatchedList my frequently sorted to the top.
Does that make sense? Thanks.
SELECT *
FROM filmdb
LEFT JOIN (
SELECT filmid, count(*) AS cnt
FROM watch_list
GROUP BY filmid) AS a
ON filmdb.film_id = a.filmid
ORDER BY isnull(cnt, 0) DESC;
http://sqlfiddle.com/#!3/46b16/10
You did not specify if the query should be grouped by film_id or user_id. The example I have provided is grouped by user if you change that to film_id then you will get the watch count for all users per film.
You need to use a subquery to get the count and then order the results by the count descending to get an ordered list.
SELECT
*
FROM
(
SELECT
WatchList.Film_Id,
WatchCount=COUNT(*)
FilmDB.Film_Title
FROM
WatchList
INNER JOIN FilmDB ON FilmDB.Film_Id=WatchList.Film_Id
GROUP BY
WatchList.UserID,
WatchList.Film_Id,
FilmDB.Film_Title
)AS X
ORDER BY
WatchCount DESC