Im trying to figure out how to make shopping cart tab that would be positioned on the right corner and also rotated 90 degrees. The rotation naturally mixes the position but maybe there's a workaround of wrapping to different wrappers etc....
Extra points if there wouldn't need to define width. I don't care about older browsers
How about using transform-origin? See DEMO.
Relevant CSS:
#box {
position: relative;
}
.bg {
right: 40px; /* same as height */
height: 40px;
transform: rotate(-90deg);
transform-origin: 100% 0;
position: absolute;
line-height: 40px; /* same as height, for vertical centering */
}
Ana's answer is excellent and pointed me in the right direction, but I realised you could achieve the same effect without having to explicitly set the height, line-height and position for the element you want to move - instead, just set translate(0, -100%):
body {
margin: 0;
}
#box {
position: relative;
}
.bg {
right: 0;
padding: 1em;
transform: rotate(-90deg) translate(0, -100%);
transform-origin: 100% 0;
position: absolute;
background: #FF1493;
}
<div id="box">
<div class="bg">
<div class="txt">He's not the Messiah. He's a very naughty boy.</div>
</div>
</div>
...and a jsFiddle for good measure.
To rotate text at 90° using CSS, consider using writing-mode.
Set position: relative; on the parent div, then use something like this on the rotated element:
#rot {
position: absolute; /* only handy here because its parent is set to `position: relative;` */
left: 0;
top: 0px;
/* writing-mode: sideways-lr; /* Webkit browsers don't support `sideways-lr` yet */
writing-mode: vertical-rl; /* `vertical-rl` and a rotation will achieve the same effect */
transform: scaleX(-1) scaleY(-1);
height: 100%;
background: rgba(0, 0, 0, 0.1);
text-align: center;
line-height: 2.85;
color: white;
font-weight: bold;
}
You'll end up with a div stacked on the side of your parent div, with the text at a 90° angle.
This way you don't have to think about the rotation origin.
If you need to position wrapper div.and rotate child div so that its always centered vertically and horizontally, try something like this!
.togglewrap{
position:relative;
float:left;left:20%;top:0;
width:30px;
height:120px;
background-color: #ffde21;
}
.sbartoggle {
background:#f5f5f5;
position:absolute;
left:0;
top:0;
right:0;
bottom:0;
margin:auto;
width:100%;
height:30px;/*equal to parent width*/
line-height:30px;/*center text*/
transform: rotate(-90deg);
background-size:10px 10px;
}
Related
I've looked into this a fair bit but can't seem to find a good, solid answer to find how to make a responsive circle around a div element of variable height.
It's easy to make a simple responsive circle using vw units.
<div style="height:20vw; width:20vw"></div>
However, I'm looking to use a min-height of an element and have a circle around this div.
Another way to create a responsive circle is using something like the snippet below, but again I can't adapt this to work for a variable height (again, I can't use vh units as the div will change in height.
.square {
position: relative;
width: 10%;
background: gray;
border-radius: 50%;
}
.square:after {
content: "";
display: block;
padding-bottom: 100%;
}
.content {
position: absolute;
width: 100%;
height: 100%;
}
<div class="square">
<div class="content">
</div>
</div>
I am trying to create something like the below, where the circle will never cut into the corners of the div (with around a 10px padding). I personally was trying to avoid javascript and would have preferred a css only approach, but it seems it's unavoidable. Maybe the only solution is to use a jquery to calculate the height of the element in order to apply this to a wrapper element?
I was playing around with this:
.square {
position: absolute;
top: 50%;
display: inline-block;
left: 50%;
transform: translate(-50%, -50%);
min-height: 100px;
border-radius: 50%;
background: url('https://i.imgur.com/2dxaFs9_d.webp?maxwidth=640&shape=thumb&fidelity=medium');
background-size: 100% 100%;
padding: 20px;
}
.content {
width: 300px;
min-height: 100px;
background: tomato;
}
<div class="square">
<div class="content">
Hello!<br>
<br><br><br>This has a variable height but fixed width<br><br><br>Hello
</div>
</div>
Clip-path can easily do this if you consider solid coloration.
Resize the element and the circle will follow:
.box {
width: 200px;
height: 200px;
overflow: hidden;
resize: both;
background: blue;
box-shadow: 0 0 0 200vmax red;
clip-path: circle(71%);
margin: 100px auto;
}
<div class="box"></div>
Related question to understand the magic number 71%: clip-path:circle() radius doesn't seem to be calculated correctly
To use an image we can consider pseudo elements. You can also rely on calc() to add the offset:
.box {
width: 200px;=
resize: both;
clip-path: circle(calc(71% + 10px));
margin: 100px auto;
position: relative;
font-size:35px;
color:#fff;
}
/* the background layer */
.box::before {
content:"";
position: absolute;
z-index:-1;
top:0;
left:0;
right:0;
bottom:0;
background:blue;
}
/* the image layer */
.box::after {
content:"";
position: fixed; /* to make sure the image cover all the screen */
z-index:-2;
top:0;
bottom:0;
left:0;
right:0;
background:url(https://picsum.photos/id/1015/1000/1000) center/cover no-repeat;
}
<div class="box" contenteditable="true"> Edit this<br>text </div>
I tried my hardest to figure this out with pure css. Though the problem with css I could not figure out how to calculate the diameter of the circle based on the content div size; the length from top left corner to bottom right corner of the variable height div.
I'm not sure if can be done using the calc() css function.
But I did manage to do it with a little jquery (which could easily be changed to pure javascript if you are not using jquery).
See working resizable example below (follow my comments in code)
Note: If you are using internet explorer the resizable demo content div will not resize.
// circumscriber for variable size divs
function circumscriber() {
// for each variable size div on page
$(".variable-size").each(function() {
// get the variable size div content width and height
let width = $(this).outerWidth();
let height = $(this).outerHeight();
// get the diameter for our pefect circle based on content size
let diameter = Math.sqrt(width ** 2 + height ** 2);
// extra 15 pixel circle edge around variable size div
let edge = 15;
// add current circle size width css
$('.circle', this).css({
'width': (diameter + (edge * 2)) + 'px'
})
});
}
// run the circumscriber (you might wana do this on ready)
circumscriber();
// if the window is resized responsively
$(window).on('resize', function() {
circumscriber();
});
// for demo purpose to fire circumscriber when resizing content
// not needed for real thing
$('.content').on('input', function() {
this.style.height = "";
this.style.height = ( this.scrollHeight - 30 ) + "px";
circumscriber();
}).on('mouseup', function() {
circumscriber();
});
/* variable size container to be circumscribed by circle */
/* none of these styles are required, this just to center the variable size div in the window for demo purposes */
.variable-size {
position: absolute;
top: 50%;
left: 50%;
transform: translate(-50%, -50%);
}
/* resizable text area for demo */
/* again not needed */
.variable-size .content {
padding: 15px;
background: #fff;
resize: both;
overflow: auto;
color: #000;
border: none;
width: 200px;
font-weight: bold;
}
.variable-size .content:focus {
outline: 0;
}
/* child circle div css */
.variable-size .circle {
position: absolute;
background-image: url('https://i.imgur.com/2dxaFs9_d.webp?maxwidth=640&shape=thumb&fidelity=medium');
background-position: center center;
z-index: -1;
border-radius: 50%;
left: 50%;
top: 50%;
transform: translate(-50%, -50%);
transition: all 0.5s ease;
width: 0;
}
/* fast way to make circle height the same as current width */
.variable-size .circle:before {
display: block;
content: '';
width: 100%;
padding-top: 100%;
}
/* demo window css */
HTML,
BODY {
height: 100%;
min-height: 100%;
background: black;
position: relative;
font-family: "Lucida Console", Courier, monospace;
}
<div class="variable-size">
<textarea class="content" rows="1" placeholder="TYPE TEXT OR RESIZE ME ↘"></textarea>
<div class="circle"></div>
</div>
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
See jsfiddle here... https://jsfiddle.net/joshmoto/6d0zs7uq/
var c = document.getElementById("myCanvas");
var ctx = c.getContext("2d");
ctx.beginPath();
ctx.arc(100, 75, 50, 0, 2 * Math.PI);
ctx.stroke();
Source: https://www.w3schools.com/
You could use flex display and insert empty flex-items around the inner div and use flex-basis to fix their width.
Try this
.square {
display: flex;
justify-content: center;
align-items: center;
position: absolute;
top: 50%;
left: 50%;
transform: translate(-50%, -50%);
min-height: 100px;
border-radius: 50%;
background: black;
background-size: 100% 100%;
padding: 20px;
}
.content {
width: 300px;
min-height: 100px;
background: tomato;
}
.emptyDiv {
flex-basis: 120px
}
<div class="square">
<div class="emptyDiv"></div>
<div class="content">
Hello!<br>
<br><br><br>This has a variable height but fixed width<br><br><br>Hello
</div>
<div class="emptyDiv"></div>
</div>
Here is a short codepen of a simple css animation that I'm struggling to work with. Code also below:
.navscroll {
width: 100%;
height: 100px;
padding: 5px;
overflow: hidden;
position: relative;
background-color: red;
}
.navscroll div {
position: relative;
width: 200px;
height: 100%;
line-height: 50px;
text-align: center;
background-color: blue;
opacity: 1;
border-radius: 5px;
transform: translateX(100%);
animation: navscroll 15s linear infinite;
}
#keyframes navscroll {
0% {
transform: translateX(100%);
}
100% {
transform: translateX(-100%);
}
}
<div class="navscroll">
<div>Why arent these</div>
<div>Side by side</div>
<div>or sliding across the WHOLE navbar</div>
</div>
Its supposed to be a scrolling navbar of divs, but I'm having two issues:
The inner divs are stacking vertically, not horizontally...
The inner divs are scrolling across only a small percentage of the nav bar / outer div...
Ideally, if there were many divs in the navscroll div, only 5-6 of them would display anytime on the screen, although the navbar would always be scrolling and those other divs would make their way onto the screen eventually. (similar to stock tickers ticking across the top of the TV screen). Any help with this is appreciated, thanks!!
div is a block level element (means it has display: block; by default). These create a line break before and after themselves. Use display: inline-block; and make sure they align properly using vertical-align: middle;.
2nd problem: translateX(100%) here the percentage does not refer to the parent element, but to the div being animated.
.navscroll {
width: 100%;
height: 100px;
padding: 5px;
overflow: hidden;
position: relative;
background-color: red;
white-space: nowrap;
}
.navscroll div {
position: relative;
width: 200px;
height: 100%;
line-height: 50px;
text-align: center;
background-color: blue;
opacity: 1;
border-radius: 5px;
transform: translateX(100%);
animation: navscroll 15s linear infinite;
/* this does the magic: */
display: inline-block;
vertical-align: middle;
}
#keyframes navscroll {
0% {
left: 100%;
}
100% {
left: -100%;
}
}
<div class="navscroll">
<div>Why arent these</div>
<div>Side by side</div>
<div>or sliding across the WHOLE navbar</div>
</div>
As per your question about how to create a snippet here:
The inner divs are stacking vertically because the default styling for a div is display: block. Adding the styles display: inline-block; vertical-align: top; to your .navscroll div rules will set them side by side, aligned to their top edges.
The animation is starting in the middle, and not all the way to the right like you intend because of how transform: translate() works. transform refers to the object being transformed, not its parent. So, translating something 100% of it refers to the width of the object. Try animating the position, something like this instead:
#keyframes navscroll {
0% {
left: 100%;
}
100% {
left: -600px;
}
}
EDIT: Also, remove the initial transform: translateX(100%); and you can simply animate the left position to -600px (3x the width of the each block).
This is what i am trying to achive
i have :
#image1 {
position: absolute;
bottom: 0px;
align-self: auto;
background-color: #dc022e;
width: 340px;
height: 100px;
border-radius: 50% / 100%;
border-bottom-left-radius: 0;
/*transform: rotate(10deg);*/
border-bottom-right-radius: 0;
opacity: 0.8;
}
#image2 img {
width: 80%;
}
<div>
<div id="image2">
<img src="http://t1.gstatic.com/images?q=tbn:ANd9GcThtVuIQ7CBYssbdwtzZjVLI_uw09SeLmyrxaRQEngnQAked5ZB">
</div>
<div id="image1"></div>
</div>
Finally I don't know how to make it rotated and with the margins cut like in the picture
A Quick example of this would use a pseudo element and have the image set in the background.
div {
position: relative;
height: 300px;
width: 500px;
background: url(http://lorempixel.com/500/300);/*image path*/
overflow: hidden;/*hides the rest of the circle*/
}
div:before {
content: "";
position: absolute; /*positions with reference to div*/
top: 100%;
left: 50%;
width: 0;/*define value if you didn't want hover*/
height: 0;
border-radius: 50%;
background: tomato;/*could be rgba value (you can remove opacity then)*/
opacity: 0.5;
transform: translate(-50%, -50%);/*ensures it is in center of image*/
transition: all 0.4s;
}
/*Demo Only*/
div:hover:before {/*place this in your pseudo declaration to remove the hover*/
height: 100%;
width: 150%;/*this makes the shape wider than square*/
transform: translate(-50%, -50%) rotate(5deg);/*ensures it is in center of image + rotates*/
}
div {/*This stuff is for the text*/
font-size: 40px;
line-height: 300px;
text-align: center;
}
<div>HOVER ME</div>
Instead of nested elements, you can just use a pseudo element. This is placed at the bottom of the container div. For this to work, you need position:relative and overflow:hidden on the container div. Also, pseudo elements always need the content declaration.
To modify the border radius, you just play around with left | width | height of the pseudo element. You don't need any rotation.
Instead of hex color and opacity you can as well use the "new" color space rgba(r,g,b,a) where a is the opacity value.
For the passepartout you simply use the border declaration.
#image2{
position:relative;
border:10px solid #888;
overflow:hidden;
box-shadow:0 0 4px #aaa;
}
#image2::after {
content:"";
display:block;
position: absolute;
bottom: 0;left:-10%;
background-color: #dc022e;
width: 120%;
height: 60%;
border-radius: 100% 100% 0 0;
opacity: 0.8;
}
#image2 img {
width: 100%;
display:block;
position:relative;
}
<div id="image2">
<img src="http://t1.gstatic.com/images?q=tbn:ANd9GcThtVuIQ7CBYssbdwtzZjVLI_uw09SeLmyrxaRQEngnQAked5ZB">
</div>
You can just use position: absolute for your image and position: relative for your overlay, adjusting the top position and width according to your needs. Here's a Fiddle. Hope this helps!
Edit: Here's an updated version of the Fiddle demonstrating border and overflow properties on the img container. As CBroe mentioned, rotating a circle is probably not a good use of your time in this case. Also, I definitely agree that using a pseudo element is a much cleaner approach than nesting images.
I tried to make a shape using div and put an image inside. I want the image to maintain its default shape (rectangle or square) without skewing, but when I put image inside, the image skewed with the div. For the div shape I am using transform: skewY(-10deg);
.intro {
width: 180px;
height: 400px;
/* border-radius:50%;*/
cursor: pointer;
position: relative;
background: #fff;
transform: skewY(-10deg);
margin: 35px 35px 35px 0px;
}
.intro img {
width: 100%;
height: 100%;
}
<div class="intro">
<img src="http://lorempixel.com/180/400/sports">
</div>
You are trying to accomplish this: distort the shape of the outer object but keep the inner shape the same. The only way to do that is to transform the inner shape by the negative of the outer shape transform (aka, if your skewY(10deg) on the outer shape, do skewY(-10deg) on the inner), then hiding the overflow.
See this snippet:
.intro {
width: 180px;
height: 400px;
cursor: pointer;
position: relative;
background: #fff;
/* I added the -webkit- prefix as I'm using Safari 8 and
* it wouldn't show up otherwise. Might want to prefix that! */
-webkit-transform: skewY(-10deg);
transform: skewY(-10deg);
margin: 35px 35px 35px 0px;
overflow: hidden;
}
.intro img {
width: 100%;
height: 100%;
-webkit-transform: skewY(10deg);
transform: skewY(10deg);
}
<div class="intro">
<img src="http://lorempixel.com/180/400/sports">
</div>
An annoying sideeffect of this is that your contents will seem cut off. The only way to solve that is to make the inner shape larger than the outer shape an potentially padding the inside. For your image, I'd suggest:
.intro {
position: relative;
}
.intro img {
/* Use min width and heights higher than 100%
* (you might need to experiment here as it depends
* on the angle you chose for your skew) to fill
* the outer shape completely. */
min-width: 110%;
min-height: 110%;
/* Position the element absolute and 50%
* from the top and left */
position: absolute;
left: 50%;
top: 50%;
/* Now add a transform to it to move it with
* half of its width and height, therefore centering it. */
-webkit-transform: skewY(10deg) translate(-50%, -50%);
transform: skewY(10deg) translate(-50%, -50%);
}
Now you could also do width: 110%; height: 110%; left: -5%; top: -5%; and it would accomplish similar results. Play around with it.
Update
As per #vals suggestion, it might be a lot simpeler to just use the scale transform instead of all the positioning mumbo jumbo. Its always the simplest solution thats easiest to overlook:
.intro img {
-webkit-transform: skewY(10deg) scale(1.2, 1.2);
transform: skewY(10deg) scale(1.2, 1.2);
}
Translating an elements Y axis 50% will move it down 50% of its own height, not 50% of the parents height as I would expect. How do I tell a translating element to base it's translation percentage on the parent element? Or am I not understanding something?
http://jsfiddle.net/4wqEm/2/
When using percentage in a transform translate on a non-SVG element, it refers to the width or height of itself. Take a look at https://davidwalsh.name/css-vertical-center (demo):
One interesting thing about CSS transforms is that, when applying them with percentage values, they base that value on the dimensions of the element which they are being implemented on, as opposed to properties like top, right, bottom, left, margin, and padding, which only use the parent's dimensions (or in case of absolute positioning, which uses its closest relative parent).
On an SVG element, a transform percentage refers to the size of the parent instead!
Here is a pen:
https://codepen.io/trusktr/pen/gOdwWXv
svg, [outer] {
border: 1px solid black;
}
rect {
transform: translate3d(50%, 50%, 0);
}
[inner] {
background: black;
transform: translate3d(50%, 50%, 0);
}
<svg width="100" height="80">
<rect width="20" height="20" />
</svg>
<div outer style="width: 100px; height: 80px;">
<div inner style="width: 20px; height: 20px;"></div>
</div>
Strange, huh?
You can use vw and vh to translate based on the viewport size
#keyframes bubbleup {
0% {
transform: translateY(100vh);
}
100% {
transform: translateY(0vh);
}
}
What works for me using only CSS is:
.child {
position: relative;
top: 50%;
left: 50%;
transform: translate(-50%, -50%);
/* Backward compatibility */
-webkit-transform: translate(-50%, -50%);
-moz-transform: translate(-50%, -50%);
-o-transform: translate(-50%, -50%);
-ms-transform: translate(-50%, -50%);
}
How it works:
top and left positioning move child widget according to parent coordinates. Child widget's top-left corner will appear exactly in the center of parent (this is not what we want at this time).
translation will move child widget -50% to top and left based on its size (not the parent). It means, widget's center point will be moved exactly where top-left point was - which previously was set up as center of a parent, and this is what we want.
To use percentage in the translate property, you have to use Javascript : http://jsfiddle.net/4wqEm/27/
HTML code :
<div id="parent">
<div id="children"></div>
</div>
CSS code :
#parent {
width: 200px;
height: 200px;
background: #ff0;
}
#children {
width: 10%;
height: 10%;
background: #f00;
}
Javascript code :
parent = document.getElementById('parent');
children = document.getElementById('children');
parent_height = parent.clientHeight;
children_translate = parent_height * 50/100;
children.style.webkitTransform = "translateY("+children_translate+"px)";
I hope I could help you and say me if you have any other problem.
Your statement is absolutely right about the percentages coming from the very translated element. Instead of using translate property in your case you should be using absolute positioning to stay relative to the parent div. I absolutely positioned vertically your red div here:(don`t forget about adding position relative to the parent div.It has to be positioned other than static default):
js fiddle pen here
body {
margin: 0;
width: 100%;
height: 100%;
}
body > div {
width: 200px;
height: 200px;
background: #ff0;
position: relative;
}
body > div > div {
width: 10%;
height: 10%;
-webkit-transform: translateY(-50%);
background: #f00;
position: absolute;
top: 50%;
}
You can also use one extra block and use the transition for it except the child node
HTML code :
<div id="parent">
<div id="childrenWrapper">
<div id="children"></div>
</div>
</div>
css should be something like this
#parent {
position: relative;
width: 200px;
height: 200px;
background: #ff0;
}
#childrenWrapper{
width: 100%;
height: 100%;
}
#children {
width: 10%;
height: 10%;
background: #f00;
}
You can make the element absolute positioned and use left and top property to take the percentage value as parent.
Its forked with positioning required on the following URL
working sample
body {
margin: 0;
width: 100%;
height: 100%;
}
body>div {
position: relative;
width: 200px;
height: 200px;
background: #ff0;
}
body>div>div {
position: absolute;
left: 50%;
top: 50%;
width: 10%;
height: 10%;
background: #f00;
transform: translate(-50%, -50%);
}
notes :
you can absolute positioning of your red square by changing parent element to position relative
then using 50% top and 50% left will position red square according to its upper left corner
using transform:translate(-50%,-50%) will position red square according to its center
The solution to this problem is not to use translate at all. When you are translating an element, the percentage you select is based on it's own height.
If you want to position the element based on the parent's height, use top: 50%;
So the code will look like this:
body {
margin: 0;
width: 100%;
height: 100%;
}
body > div {
width: 200px;
height: 200px;
background: #ff0;
position: relative;
}
body > div > div {
position: absolute;
top: 50%;
width: 10%;
height: 10%;
/* -webkit-transform: translateY(50%); */
background: #f00;
}