I have a method that returns a NSString * successfully.
I want to have the string returned with brackets round it.
ie. Currently the method returns something like #"myString" and I want
#"(myString)". How can I stick a bracket at the start and another at the end?
stringWithFormat should do it;
NSString* result = [NSString stringWithFormat:#"(%#)", myString];
Related
The below print statement always returns empty string. Why is it happening?
let tspanString=strcat(tostring(toint(rand(100))),'d');
print totimespan(tspanString)
the result of strcat(N, 'd') is a non constant string in a format that can't be parsed into a timespan literal, when passed into totimespan().
A valid alternative in your case would be using rand(100) * 1d
See: https://learn.microsoft.com/en-us/azure/data-explorer/kusto/query/datetime-timespan-arithmetic
I'm trying to replace some characters in a String From a map
Case 1
map= ['O':'0', 'L':'1', 'Z':'2', 'E':'3']
"Hey".toUpperCase().toCharArray().each{
print map.get(it,it)
}
The result is
HEY
Case 2 : I dont use toCharArray()
"Hey".toUpperCase().each{
print map.get(it,it)
}
The result is like expected
H3Y
So I tried several alternatives when using toCharArray(), and the only way to access the value is to use map."$it"
Why i can only use map."$it" to access my map when using toCharArray() ?
Because you are trying to get a value from a map using a char whilst every key there are String, and they are not equals:
assert !'E'.equals('E' as char)
$it works because it is converted to String:
e = 'E' as char
assert "$e".toString().equals('E')
(Note the toString() is needed, otherwise the comparison will happen between String and GStringImpl which are not equals)
I have an array -
char name[256];
sprintf(name, "hello://cert=prv:netid=%d:tsid=%d:pid=%d\0", 1010,1200, 1300);
QString private_data_string = name;
At the last offset of this string i.e. '\0',when I try to do the following.
while(private_data_string.at(offset) != ':' &&
private_data_string.at(offset) != ';' &&
private_data_string.at(offset).isNull() == false)
The application aborts. Looks like that the data pointer is also zero at the string '\'. How can I fix this?
QString doesn't contain terminating character as you expect that is why you are failing assertion out of bounds. This is proper approach:
while(offset<private_data_string.length() &&
private_data_string.at(offset) != ':' &&
private_data_string.at(offset) != ';') {
// ...
}
It looks like you are doing something strange. Looks like your question is wrong. You are asking how to fix your strange solution of some mysterious problem, instead explain what are you trying to do and then as a bonus: how did you try to solve it.
You need to know several facts:
Writing \0 at tge end of your string literal is not necessary. String literals are null-terminated by default. Literal "abc" will actually contain 4 characters including terminating null character. Your string literal has 2 null characters at its end.
You have used the default constructor QString(char*). There is no additional data about buffer's length, so QString reads characters from the buffer until it encounters first null character. It doesn't matter how many null characters are actually at the end. The null character is interpreted as a buffer end marker, not a part of the string.
When you have QString "abc", its size is 3 (it would be surprising to have another value). Null character is not a part of the string. QString::at function can be used for positions 0 <= position < size(). This is explicitly specified in the documentation. So it doesn't matter if QString's internal buffer is null-terminated or not. Either way, you don't have access to null terminator.
If you really want null character to be part of your data, you should use QByteArray instead of QString. It allows to specify buffer size on construction and can contain as many null characters as you want. However, when dealing with strings, it's usually not necessary.
You should use QString::arg instead of sprintf:
QString private_data_string =
QString("hello://cert=prv:netid=%1:tsid=%2:pid=%3")
.arg(netid).arg(tsid).arg(pid);
sprintf is unsafe and can overrun your fixed-size buffer if you're not careful. In C++ there's no good reason to use sprintf.
"A QString that has not been assigned to anything is null, i.e., both the length and data pointer is 0" - this has nothing to do with your situation because you have assigned a value to your string.
I'm trying to read text from a file in SML. Eventually, I want a list of individual words; however, I'm struggling at how to convert between a TextIO.elem to a string. For example, if I write the following code it returns a TextIO.elem but I don't know how to convert it to a string so that I can concat it with another string
TextIO.input1 inStream
TextIO.elem is just a synonym for char, so you can use the str function to convert it to a string. But as I replied to elsewhere, I suggest using TextIO.inputAll to get a string right away.
Here is a function that takes an instream and delivers all (remaining) words in it:
val words = String.tokens Char.isSpace o TextIO.inputAll
The type of this function is TextIO.instream -> string list.
I can't get this to work:
NSString *string = #"!#€%&/()*^*_:;;:;_poawolwasnndaw";
NSData *stringData = [string dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:NO];
stringData will be nil. Why?
According to the documentation, setting allowLossyConversion:NO yields the following potential behavior:
Returns nil if flag is NO and the receiver can't be converted without losing some information (such as accents or case).
In this case, the Euro symbol above has no ASCII equivalent, so the entire result will come back nil.