Printing the contents of an array to a file - pointers

Question

Pointer related question. I'm going through some example code that currently reads in data from a file called dataFile into a buffer. The reading is done inside a loop as follows:
unsigned char* buffer = (unsigned char*)malloc(1024*768*);
fread(buffer,1,1024*768,dataFile);
redPointer = buffer;
bluePointer = buffer+1024;
greenPointer = buffer+768;
Now, I want to try and write the entire contents of the array buffer to a file, so that I can save just those discrete images (and not have a large file). However, I am not entirely sure how to go about doing this.
I was trying to cout statements, however I get a print-out of garbage characters on the console and also a beep from the PC. So then I end my program.
Is there an alternative method other than this:
for (int i=0; i < (1024*768); i++) {
fprintf(myFile, "%6.4f , ", buffer[i]);
}

Answer 1

By declaring your buffer as a char*, any pointer arithmatic or array indexes will use sizeof(char) to calculate the offset. A char is 1 byte (8 bits).
I'm not sure what you are trying to do with the data in your buffer. Here are some ideas:
Print the value of each byte in decimal, encoded as ASCII text:
for (int i=0; i < (1024*768); i++) {
fprintf(myFile, "%d , ", buffer[i]);
}
Print the value of each byte in hexadecimal, encoded in ASCII text:
for (int i=0; i < (1024*768); i++) {
fprintf(myFile, "%x , ", buffer[i]);
}
Print the value of each floating point number, in decimal, encoded in ASCII text (I think my calculation of the array index is correct to process adjacent non-overlapping memory locations for each float):
for (int i=0; i < (1024*768); i += sizeof(float)) {
fprintf(myFile, "%6.4f , ", buffer[i]);
}
Split the buffer into three files, each one from a non-overlapping section of the buffer:
fwrite(redPointer, sizeof(char), 768, file1);
fwrite(greenPointer, sizeof(char), 1024-768, file2);
fwrite(bluePointer, sizeof(char), (1024*768)-1024, file3);
Reference for fwrite. Note that for the count parameter I simply hard-coded the offsets that you had hard-coded in your question. One could also subtract certain of the pointers to calculate the number of bytes in each region. Note also that the contents of these three files will only be sensible if those are sensibly independent sections of the original data.
Maybe this gives you some ideas.
Updated: so I created a complete program to compile and test the formatting behavior. This only prints the first 20 items from the buffer. It compiles (with gcc -std=c99) and runs. I created the file /tmp/data using ghex and simply filled in some random data.
#include <stdlib.h>
#include <stdio.h>
int main()
{
FILE* dataFile = fopen("/tmp/data", "rb");
if (dataFile == NULL)
{
printf("fopen() failed");
return -2;
}
unsigned char* buffer = (unsigned char*)malloc(1024*768);
if (buffer == NULL)
{
printf("malloc failed");
return -1;
}
const int bytesRead = fread(buffer,1,1024*768,dataFile);
printf("fread() read %d bytes\n", bytesRead);
// release file handle
fclose(dataFile); dataFile = NULL;
printf("\nDecimal:\n");
for (int i=0; i < (1024*768); i++) {
printf("%hd , ", buffer[i]);
if (i > 20) { break; }
}
printf("\n");
printf("\nHexadecimal:\n");
for (int i=0; i < (1024*768); i++) {
printf("%#0hx , ", buffer[i]);
if (i > 20) { break; }
}
printf("\n");
printf("\nFloat:\n");
for (int i=0; i < (1024*768); i += sizeof(float)) {
printf("%6.4f , ", (float)buffer[i]);
if (i > 20) { break; }
}
printf("\n");
return 0;
}