Tried to make a floating div, with a -1 z-index to be in the background all the time, but when I make it's position absolute, then it disappears. Also want to place it in the middle with y-repeat image.
.perchament{
position:absolute;
margin:0 auto;
height:100%;
background: url("image_assets/parchment.png") repeat-y;
margin-top:25px;
z-index:-1;
}
It disappears because there is no content in it and no width specified.
Add this to your CSS:
left: 50%;
width: 100px;
margin-left: -50px;
The width needs to be set and the left margin is always half of that.
DEMO
As others have said, why not just do a background image on the body?
body {
background: url("image_assets/parchment.png") center repeat-y;
}
In this particular case, you'll need to add a width to your div (since it's absolutely positioned).
However, what's wrong with a background rule on the body element or something similar?
Absolutely positioning elements should us "top" and other such positioning controls instead of margin etc and set a width and height.
.perchament{
position:absolute;
top: 0;
left: 0;
width: 500px;
margin:0 auto;
height:100%;
background: url("image_assets/parchment.png") repeat-y;
margin-top:25px;
z-index:-1;
}
Does that help?
I'd also avoid using a minus z-index. Instead, you could set this item to z-index: 1 and then set the container above it (with everything else inside) to z-index: 2.
OR, if it's just a background image you want, you could simply put that onto the BODY tag of the document instead of a div. The BODY or HTML element is always the bottom of the stack.
Related
I'm trying to break out of a parent div so I can have a colour div cover the width of the browser.
However, for some reason it pushes the block off to the left.
This is my site.
This is my code:
HTML:
<div class="aboutTop"></div>
CSS:
.aboutTop{
width: 100%;
height: 600px;
background-color: black;
margin-left: -100%;
margin-right: -100%;
}
Where am I going wrong?
To make your div "break out" of its parent, you'll have to use position: relative;
HTML:
<div class="aboutTop">
<div>break out!</div>
</div>
CSS:
div
{
width: 100px;
height: 100px;
border: 1px solid #000;
}
.aboutTop div
{
position: relative;
top: 50px;
left: 50px;
}
This is because child elements are restricted to the boundaries of their parents. USing positioning takes the element out of the document flow. Using relative positioning takes it out of the flow but uses its original position within the parent as the point of reference. Absolute uses the top left corner of the browser window as its reference. :)
http://jsfiddle.net/qkU7F/
The width will always reference the parent div, no matter what. So you can use jQuery to set the width of the element based on the window width.
var winWidth = window.innerWidth;
$('.aboutTop div').css("width", winWidth);
http://jsfiddle.net/qkU7F/3/
In this:
margin-left: -100%;
margin-right: -100%;
The percentages are relative to the parent element.
So if the parent element is 200px wide 100% will be 200px.
If you want something to span the width of the browser you have a couple of options:
Use absolute position and left:0; right:0;
make the element a direct child of the body element and set it's width to 100%
.aboutTop{
position:fixed;
width: 100%;
height: 600px;
background-color: black;
margin-left: -100%;
margin-right: -100%;
}
When you give a width:100% without positioning, it will take 100% with respect to parent division. You need to make it fixed, or you need to change the width of the parent division.
The code you write, must from start be aimed at what you want to achieve. For something like this, you should not have a parent division with less width.
If yo use relative positioning, or absolute with negative margin the width will still be 100% of parent division. You will have to increse width to something like 110% to achieve.
I think it's better to remove padding of your div #site. let it to have full width of browser.
then apply padding to children divs as you want.
You're setting width: 100% but also margin-left: -100%. This means that the element will span from -100% to 0.
Since you're also setting margin-right: -100% it looks like you want it to span from -100% to +200%, which means you need to set width: 300% instead.
I have a CSS background image that will stay centered no matter what the browser size is. The image used does not stretch the entire width of the browser. This being the case, I need the divs I have also placed in the CSS with background images and links to maintain their position relative to the background image that stays centered no matter what the browser size is.
I have dabbled around with.
position:relative;
but it cascades all the elements and doesn't allow specific positioning that I am looking for. Here is the code I am working with. I appreciate any insight to my newb question, and look forward to learning how this behaves better.
When this code is viewed on different sized browsers, with a background image that does not span the entire width, the elements move around because they are set to percentage. I need them to stay where they are but remain centered with the background. I am not sure how to write this in CSS and have been struggling with it for some time. Thankyou for any guidance on this specific issue.
body {
background:#000 url(bg.jpg) no-repeat center 0;
}
#logo {
margin: 0px 11%;
padding: 0;
position:absolute;
}
try grouping elements you want to put next to it together inside a div ~say container~ and set the background to the div.
Then set the div ~container~ position to relative and center it.
Then align other elements using position absolute and top bottom left right property wrt the ~container~div.
here is the code for it
<div id="container">
<div id="element1"></div>
<div id="element1"></div>
</div>
<style type="text/css">
#container {
background:#000 url(bg.jpg) no-repeat center 0;
width: 800px; height: 400px
position: relative;
top: 50%; left: 50%;
margin-top: -200px; margin-left: -400px }
#element1 {
position: absolute;
top: -30px; left: -20px;}
#element2 {
position: absolute;
top: 410px; left: 820px;}
</style>
putting image always in center page(E.x image loading for ajax call), even when move scroll. how is it?
For most browsers, you can use position:fixed
img.centered {
position:fixed;
left: 50%;
top: 50%;
/*
if, for instance, the image is 64x64 pixels,
then "move" it half its width/height to the
top/left by using negative margins
*/
margin-left: -32px;
margin-top: -32px;
}
If the image was, for instance, 40x30 pixels, you'd set margin-left:-20px; margin-top:-15px instead.
Here's a jsfiddle example: http://jsfiddle.net/WnSnj/1/
Please note that position:fixed doesn't work exactly the same in all browsers (though it's ok in all the modern ones). See: http://www.quirksmode.org/css/position.html
<style>
.CenterScreen{
position:fixed;
/*element can move on the screen (only screen, not page)*/
left:50%;top:50%;
/*set the top left corner of the element on the center of the screen*/
transform:translate(-50%,-50%);}
/*reposition element center with screen center*/
z-index:10000;
/*actually, this number is the count of the elements of page plus 1 :)*/
/*if you need that holds the element top of the others. */
</style>
If you add this class your element, it will be always center of the screen.
For example:
Hello world
This might help you : http://skfox.com/2008/04/28/jquery-example-ajax-activity-indicator/
Put the image in a div tag with some class name (centeredImage) and use the following css
div.centeredImage {
margin: 0px auto;
position: fixed;
top: 100px;//whatever you want to set top;
}
I have a footer div with 100% width. It's about 50px high, depending on its content.
Is it possible to give that #footer a background image that kind of overflows this div?
The image is about 800x600px, and I want it to be positioned in the left bottom corner of the footer. It should work sort of like a background image for my website, but I've already set a background image on my body. I need another image positioned at the bottom left corner of my website and the #footer div would be perfect for that.
#footer {
clear: both;
width: 100%;
margin: 0;
padding: 30px 0 0;
background:#eee url(images/bodybgbottomleft.png) no-repeat left bottom fixed;
}
The image is set to the footer, however it doesn't overflow the div. Is it possible to make that happen?
overflow:visible doesn't do the job!
There is a very easy trick. Set padding of that div to a positive number and margin to negative
#wrapper {
background: url(xxx.jpeg);
padding-left: 10px;
margin-left: -10px;
}
I do not believe that you can make a background image overflow its div. Images placed in Image tags can overflow their parent div, but background images are limited by the div for which they are the background.
You can use a css3 psuedo element (:before and/or :after) as shown in this article
https://www.exratione.com/2011/09/how-to-overflow-a-background-image-using-css3/
Good Luck...
No, you can't.
But as a solid workaround, I would suggest to classify that first div as position:relative and use div::before to create an underlying element containing your image. Classified as position:absolute you can move it anywhere relative to your initial div.
Don't forget to add content to that new element. Here's some example:
div {
position: relative;
}
div::before {
content: ""; /* empty but necessary */
position: absolute;
background: ...
}
Note: if you want it to be 'on top' of the parent div, use div::after instead.
Using background-size cover worked for me.
#footer {
background-color: #eee;
background-image: url(images/bodybgbottomleft.png);
background-repeat: no-repeat;
background-size: cover;
clear: both;
width: 100%;
margin: 0;
padding: 30px 0 0;
}
Obviously be aware of support issues, check Can I Use: http://caniuse.com/#search=background-size
Use trasform: scale(1.1) property to make bg image bigger, move it up with position: relative; top: -10px;
<div class="home-hero">
<div class="home-hero__img"></div>
</div>
.home-hero__img{
position:relative;
top:-10px;
transform: scale(1.1);
background: {
size: contain;
image: url('image.svg');
}
}
You mention already having a background image on body.
You could set that background image on html, and the new one on body. This will of course depend upon your layout, but you wouldn't need to use your footer for it.
Not really - the background image is bounded by the element it's applied to, and the overflow properties only apply to the content (i.e. markup) within an element.
You can add another div into your footer div and apply the background image to that, though, and have that overflow instead.
This could help.
It requires the footer height to be a fixed number. Basically, you have a div inside the footer div with it's normal content, with position: absolute, and then the image with position: relative, a negative z-index so it stays "below" everything, and a negative top value of the footer's height minus the image height (in my example, 50px - 600px = -550px). Tested in Chrome 8, FireFox 3.6 and IE 9.
I am create a div with 100% height
HTML
<div id="BottomShelf"></div>
CSS
#BottomShelf{ position:absolute; top:400px; left:0px; width:100%; height:100%;; background:#d4b7a0; z-index:1;}
There is a page scroll showing up on the page, but I need a page scroll (not div scroll) only when there is content. height:auto does not do the trick too.
I need the div to take the browser height irrespective to the height of the monitor.
try to set top: 400px; bottom: 0; instead of top: 400px; height: 100%;
EDIT: note that this might not work in IE6 (don't know about IE7)
The body tag has some default margin, so if you need a div to take the place as body, first set the body style to: margin: 0;
I tried creating a div with the following styles, and it seems to do what you want:
height: 100%;
overflow: auto;
overflow: auto will give the div a vertical scrollbar if the content exceeds the height.
Have you tryd the overflow:hidden; css style property?
Sorry it was overflow:hidden;