How can I set attr id and class in twig, something like :
{{ form_widget(form.description,{'attr':{'id':"editor-one",'class':"editor-wrapper"}}) }}
If I understand your question correctly, wou want to add a class to a form. You can do so by passing the class as an attribute option to createFormBuilder.
$this->createFormBuilder($entity, array('attr' => array('class' => 'classname')));
I imagine you can do the same with ID, although I have not tried that myself.
You must move 'id' outside of 'attr', like this:
{{ form_widget(form.description,{'id':"editor-one", 'attr':{'class':"editor-wrapper"}}) }}
I'm trying to set the id of an element using a variable in a Twig template (not a form) without using JavaScript.
The template code looks like this:
{% set show_id = 'show' ~ entity.id %}
{{ dump(show_id) }}
<div class="event_option" id="show_id">
show
</div>
The show_id variable is dump'ed correctly, but when I try to use it as the html id in id="show_id", the id that gets assigned to the div is the string "show_id", and not the actual value of show_id. I get the same result when no parenthesis are used when assigning the html id, as in id=show_id. How can I access the Twig variable when assigning the html id attribute?
You should enclose with double bracket to tell Twig to print the value of variable
<div class="event_option" id="{{show_id}}">
show
</div>
I'm busy with templating my forms inside Symfony 2.0.
It is possible to add attributes to a formfield like this:
$form->add('name', 'text', array('attr' => array('class' => 'my_class')));
But how can I dynamically add attributes to the formfield widget? If i look to the form_div_layout.html.twig content, their is a
{{ block('widget_container_attributes') }}
which can load attributes, but I have no idea where I can add attributes to my FormBuilder in the Controller. Could anyone help me?
Thx!
You should do that in twig layer:
{{ form_row(form.name, {attr: {class: 'my_class'}}) }}
I wrote the last days on my nav-bar-menu whit KnpMenuBundle. I want simply to give the template a few parameters on the way and then react on it. Is it possible? I tried this:
$menu->addChild('Registration', array('route' => 'fos_user_registration_register',
'icon' => array('glyphicon' => 'briefcase')));
And then I want to pick this in Twig template:
{% if icon['glyphicon'] is defined %}
<span class="glyphicon glyphicon-{{icon['glyphicon']}} "></span>
{% endif %}
I tried a lot, but nothing works. What can I try next?
Here is how i did it
The Menu class:
$menu->addChild('Home', array(
'route' => 'home',
'extras' => array('icon' => 'home')
));
My menu call in the template, i ask for a specific twig template
{{ knp_menu_render('MyBundle:Menu:primaryNav', {'template': 'MyBundle:Menu:primaryNav.html.twig'}) }}
In the twig template, i copy/paste the knpmenubundle template and edit some blocks. you may be able to do this with 'extends' and template's inheritance stuffs as well (probably a better idea).
Example of edited block for icon :
{% block spanElement %}
<a href="#" class="dropdown-toggle">
{% if item.extras.icon is defined %}<i class="icon-{{ item.extras.icon }}"></i>{% endif %}
<span class="menu-text"> {{ block('label') }}</span>
<b class="arrow icon-angle-down"></b>
</a>
{% endblock %}
What you needed was probably this "extras" field in the menu class :)
I don't know if this can still help but there's a much easier way to use font awesome with knp menu. There's an option where you can give a class to your link. You just need to create a child without a label an add setLinkAttribute. Ex:
$menu
->addChild('', array('route' => 'backend_index'))
->setLinkAttribute('class', 'fa fa-home');
This will create an "a" tag with the class fa fa-home. Even if Font Awesome documentation says the icons are designed for inline elements, it will work with "a" tag. You can then use some css to improve the design. In my case, I just changed font-size and line-height.
I would like to style the following:
forms.py:
from django import forms
class ContactForm(forms.Form):
subject = forms.CharField(max_length=100)
email = forms.EmailField(required=False)
message = forms.CharField(widget=forms.Textarea)
contact_form.html:
<form action="" method="post">
<table>
{{ form.as_table }}
</table>
<input type="submit" value="Submit">
</form>
For example, how do I set a class or ID for the subject, email, message to provide an external style sheet to?
Taken from my answer to:
How to markup form fields with <div class='field_type'> in Django
class MyForm(forms.Form):
myfield = forms.CharField(widget=forms.TextInput(attrs={'class': 'myfieldclass'}))
or
class MyForm(forms.ModelForm):
class Meta:
model = MyModel
def __init__(self, *args, **kwargs):
super(MyForm, self).__init__(*args, **kwargs)
self.fields['myfield'].widget.attrs.update({'class': 'myfieldclass'})
or
class MyForm(forms.ModelForm):
class Meta:
model = MyModel
widgets = {
'myfield': forms.TextInput(attrs={'class': 'myfieldclass'}),
}
--- EDIT ---
The above is the easiest change to make to original question's code that accomplishes what was asked. It also keeps you from repeating yourself if you reuse the form in other places; your classes or other attributes just work if you use the Django's as_table/as_ul/as_p form methods. If you need full control for a completely custom rendering, this is clearly documented
-- EDIT 2 ---
Added a newer way to specify widget and attrs for a ModelForm.
This can be done using a custom template filter. Consider rendering your form this way:
<form action="/contact/" method="post">
{{ form.non_field_errors }}
<div class="fieldWrapper">
{{ form.subject.errors }}
{{ form.subject.label_tag }}
{{ form.subject }}
<span class="helptext">{{ form.subject.help_text }}</span>
</div>
</form>
form.subject is an instance of BoundField which has the as_widget() method.
You can create a custom filter addclass in my_app/templatetags/myfilters.py:
from django import template
register = template.Library()
#register.filter(name='addclass')
def addclass(value, arg):
return value.as_widget(attrs={'class': arg})
And then apply your filter:
{% load myfilters %}
<form action="/contact/" method="post">
{{ form.non_field_errors }}
<div class="fieldWrapper">
{{ form.subject.errors }}
{{ form.subject.label_tag }}
{{ form.subject|addclass:'MyClass' }}
<span class="helptext">{{ form.subject.help_text }}</span>
</div>
</form>
form.subjects will then be rendered with the MyClass CSS class.
If you don't want to add any code to the form (as mentioned in the comments to #shadfc's Answer), it is certainly possible, here are two options.
First, you just reference the fields individually in the HTML, rather than the entire form at once:
<form action="" method="post">
<ul class="contactList">
<li id="subject" class="contact">{{ form.subject }}</li>
<li id="email" class="contact">{{ form.email }}</li>
<li id="message" class="contact">{{ form.message }}</li>
</ul>
<input type="submit" value="Submit">
</form>
(Note that I also changed it to a unsorted list.)
Second, note in the docs on outputting forms as HTML, Django:
The Field id, is generated by
prepending 'id_' to the Field name.
The id attributes and tags are
included in the output by default.
All of your form fields already have a unique id. So you would reference id_subject in your CSS file to style the subject field. I should note, this is how the form behaves when you take the default HTML, which requires just printing the form, not the individual fields:
<ul class="contactList">
{{ form }} # Will auto-generate HTML with id_subject, id_email, email_message
{{ form.as_ul }} # might also work, haven't tested
</ul>
See the previous link for other options when outputting forms (you can do tables, etc).
Note - I realize this isn't the same as adding a class to each element (if you added a field to the Form, you'd need to update the CSS also) - but it's easy enough to reference all of the fields by id in your CSS like this:
#id_subject, #id_email, #email_message
{color: red;}
Per this blog post, you can add css classes to your fields using a custom template filter.
from django import template
register = template.Library()
#register.filter(name='addcss')
def addcss(field, css):
return field.as_widget(attrs={"class":css})
Put this in your app's templatetags/ folder and you can now do
{{field|addcss:"form-control"}}
You can do like this:
class ContactForm(forms.Form):
subject = forms.CharField(max_length=100)
subject.widget.attrs.update({'id' : 'your_id'})
Hope that works.
Ignas
You could use this library: https://pypi.python.org/pypi/django-widget-tweaks
It allows you to do the following:
{% load widget_tweaks %}
<!-- add 2 extra css classes to field element -->
{{ form.title|add_class:"css_class_1 css_class_2" }}
Write your form like:
class MyForm(forms.Form):
name = forms.CharField(widget=forms.TextInput(attr={'class':'name'}),label="Your Name")
message = forms.CharField(widget=forms.Textarea(attr={'class':'message'}), label="Your Message")
In your HTML field do something like:
{% for field in form %}
<div class="row">
<label for="{{ field.name}}">{{ field.label}}</label>{{ field }}
</div>
{% endfor %}
Then in your CSS write something like:
.name{
/* you already have this class so create it's style form here */
}
.message{
/* you already have this class so create it's style form here */
}
label[for='message']{
/* style for label */
}
Hope this answer is worth a try! Note you must have written your views to render the HTML file that contains the form.
You can do:
<form action="" method="post">
<table>
{% for field in form %}
<tr><td>{{field}}</td></tr>
{% endfor %}
</table>
<input type="submit" value="Submit">
</form>
Then you can add classes/id's to for example the <td> tag. You can of course use any others tags you want. Check Working with Django forms as an example what is available for each field in the form ({{field}} for example is just outputting the input tag, not the label and so on).
Didn't see this one really...
https://docs.djangoproject.com/en/1.8/ref/forms/api/#more-granular-output
More granular output
The as_p(), as_ul() and as_table() methods are simply shortcuts for lazy developers – they’re not the only way a form object can be displayed.
class BoundField
Used to display HTML or access attributes for a single field of a Form instance.
The str() (unicode on Python 2) method of this object displays the HTML for this field.
To retrieve a single BoundField, use dictionary lookup syntax on your form using the field’s name as the key:
>>> form = ContactForm()
>>> print(form['subject'])
<input id="id_subject" type="text" name="subject" maxlength="100" />
To retrieve all BoundField objects, iterate the form:
>>> form = ContactForm()
>>> for boundfield in form: print(boundfield)
<input id="id_subject" type="text" name="subject" maxlength="100" />
<input type="text" name="message" id="id_message" />
<input type="email" name="sender" id="id_sender" />
<input type="checkbox" name="cc_myself" id="id_cc_myself" />
The field-specific output honors the form object’s auto_id setting:
>>> f = ContactForm(auto_id=False)
>>> print(f['message'])
<input type="text" name="message" />
>>> f = ContactForm(auto_id='id_%s')
>>> print(f['message'])
<input type="text" name="message" id="id_message" />
One solution is to use JavaScript to add the required CSS classes after the page is ready. For example, styling django form output with bootstrap classes (jQuery used for brevity):
<script type="text/javascript">
$(document).ready(function() {
$('#some_django_form_id').find("input[type='text'], select, textarea").each(function(index, element) {
$(element).addClass("form-control");
});
});
</script>
This avoids the ugliness of mixing styling specifics with your business logic.
You may not need to override your form class' __init__, because Django sets name & id attributes in the HTML inputs. You can have CSS like this:
form input[name='subject'] {
font-size: xx-large;
}
There is a very easy to install and great tool made for Django that I use for styling and it can be used for every frontend framework like Bootstrap, Materialize, Foundation, etc. It is called widget-tweaks Documentation: Widget Tweaks
You can use it with Django's generic views
Or with your own forms:
from django import forms
class ContactForm(forms.Form):
subject = forms.CharField(max_length=100)
email = forms.EmailField(required=False)
message = forms.CharField(widget=forms.Textarea)
Instead of using default:
{{ form.as_p }} or {{ form.as_ul }}
You can edit it your own way using the render_field attribute that gives you a more html-like way of styling it like this example:
template.html
{% load widget_tweaks %}
<div class="container">
<div class="col-md-4">
{% render_field form.subject class+="form-control myCSSclass" placeholder="Enter your subject here" %}
</div>
<div class="col-md-4">
{% render_field form.email type="email" class+="myCSSclassX myCSSclass2" %}
</div>
<div class="col-md-4">
{% render_field form.message class+="myCSSclass" rows="4" cols="6" placeholder=form.message.label %}
</div>
</div>
This library gives you the opportunity to have well separated yout front end from your backend
In Django 1.10 (possibly earlier as well) you can do it as follows.
Model:
class Todo(models.Model):
todo_name = models.CharField(max_length=200)
todo_description = models.CharField(max_length=200, default="")
todo_created = models.DateTimeField('date created')
todo_completed = models.BooleanField(default=False)
def __str__(self):
return self.todo_name
Form:
class TodoUpdateForm(forms.ModelForm):
class Meta:
model = Todo
exclude = ('todo_created','todo_completed')
Template:
<form action="" method="post">{% csrf_token %}
{{ form.non_field_errors }}
<div class="fieldWrapper">
{{ form.todo_name.errors }}
<label for="{{ form.name.id_for_label }}">Name:</label>
{{ form.todo_name }}
</div>
<div class="fieldWrapper">
{{ form.todo_description.errors }}
<label for="{{ form.todo_description.id_for_label }}">Description</label>
{{ form.todo_description }}
</div>
<input type="submit" value="Update" />
</form>
For larger form instead of writing css classed for every field you could to this
class UserRegistration(forms.ModelForm):
# list charfields
class Meta:
model = User
fields = ('username', 'first_name', 'last_name', 'email', 'password', 'password2')
def __init__(self, *args, **kwargs):
super(UserRegistration, self).__init__(*args, **kwargs)
for field in self.fields:
self.fields[field].widget.attrs['class'] = 'form-control'
Edit: Another (slightly better) way of doing what I'm suggesting is answered here: Django form input field styling
All the above options are awesome, just thought I'd throw in this one because it's different.
If you want custom styling, classes, etc. on your forms, you can make an html input in your template that matches your form field. For a CharField, for example, (default widget is TextInput), let's say you want a bootstrap-looking text input. You would do something like this:
<input type="text" class="form-control" name="form_field_name_here">
And as long as you put the form field name matches the html name attribue, (and the widget probably needs to match the input type as well) Django will run all the same validators on that field when you run validate or form.is_valid() and
Styling other things like labels, error messages, and help text don't require much workaround because you can do something like form.field.error.as_text and style them however you want. The actual fields are the ones that require some fiddling.
I don't know if this is the best way, or the way I would recommend, but it is a way, and it might be right for someone.
Here's a useful walkthrough of styling forms and it includes most of the answers listed on SO (like using the attr on the widgets and widget tweaks).
https://simpleisbetterthancomplex.com/article/2017/08/19/how-to-render-django-form-manually.html
Styling widget instances
If you want to make one widget instance look different from another, you will need to specify additional attributes at the time when the widget object is instantiated and assigned to a form field (and perhaps add some rules to your CSS files).
https://docs.djangoproject.com/en/2.2/ref/forms/widgets/
To do this, you use the Widget.attrs argument when creating the widget:
class CommentForm(forms.Form):
name = forms.CharField(widget=forms.TextInput(attrs={'class': 'special'}))
url = forms.URLField()
comment = forms.CharField(widget=forms.TextInput(attrs={'size': '40'}))
You can also modify a widget in the form definition:
class CommentForm(forms.Form):
name = forms.CharField()
url = forms.URLField()
comment = forms.CharField()
name.widget.attrs.update({'class': 'special'})
comment.widget.attrs.update(size='40')
Or if the field isn’t declared directly on the form (such as model form fields), you can use the Form.fields attribute:
class CommentForm(forms.ModelForm):
def __init__(self, *args, **kwargs):
super().__init__(*args, **kwargs)
self.fields['name'].widget.attrs.update({'class': 'special'})
self.fields['comment'].widget.attrs.update(size='40')
Django will then include the extra attributes in the rendered output:
>>> f = CommentForm(auto_id=False)
>>> f.as_table()
<tr><th>Name:</th><td><input type="text" name="name" class="special" required></td></tr>
<tr><th>Url:</th><td><input type="url" name="url" required></td></tr>
<tr><th>Comment:</th><td><input type="text" name="comment" size="40" required></td></tr>
I was playing around with this solution to maintain consistency throughout the app:
def bootstrap_django_fields(field_klass, css_class):
class Wrapper(field_klass):
def __init__(self, **kwargs):
super().__init__(**kwargs)
def widget_attrs(self, widget):
attrs = super().widget_attrs(widget)
if not widget.is_hidden:
attrs["class"] = css_class
return attrs
return Wrapper
MyAppCharField = bootstrap_django_fields(forms.CharField, "form-control")
Then you don't have to define your css classes on a form by form basis, just use your custom form field.
It's also technically possible to redefine Django's forms classes on startup like so:
forms.CharField = bootstrap_django_fields(forms.CharField, "form-control")
Then you could set the styling globally even for apps not in your direct control. This seems pretty sketchy, so I am not sure if I can recommend this.