How to generate a n-dimensional "identity matrix"? - functional-programming

I'm building a demonstration any-dimensional Vector class to show some functional programming in Python.
class Vector():
def __init__(self, *coords):
self.coords = coords
def __add__(this, that):
return Point(*[(x+y) for x,y in zip(this.coords, that.coords)])
#...
While trying to come up with an example of a static #classmethod in this example, I decided it'd be nice to have a class method giving me an n-dimensional base of vectors for any n. That is:
>>> Vector.get_base(dimensions = 2)
[Vector(1,0), Vector(0,1)]
>>> Vector.get_base(3)
[Vector(1,0,0), Vector(0,1,0), Vector(0,0,1)]
>>> Vector.get_base(1)
[Vector(1)]
I'm however having a huge brain fart however and am stumbling on the problem of how to "properly" generate those lists.
What I can think up right now is a declarative solution:
def get_base(dimensions):
arrays = []
zeros = [0] * dimensions
for i in range(dimensions):
item = zeros
item[i] = 1
arrays.append(Vector(*array))
return arrays
There has to be a better way! How can I rewrite this function in a hopefully more concise or Pythonic functional style?

Well, you could do this:
def get_base(dimensions):
return [Vector(*coords) for coords in
[[(0,1)[i==j] for i in range(dimensions)] for j in range(dimensions)]]
but I would break it down a little:
def get_base(dimensions):
arrays = [[(0,1)[i==j] for i in range(dimensions)] for j in range(dimensions)]
return [Vector(*coords) for coords in arrays]
Which is a little better. Remember, not everything has to be a one-liner.

How about the next:
>>> def get_base(dimensions):
... for points in set(itertools.permutations([0] * (dimensions - 1) + [1], dimensions)):
... yield Vector(*points)

Related

How to implement self and __init__() in julia

I would like to know what is the correct approach to implement self and __inti__() in Julia?
Example
class rectangle:
def __init__(self, length, breadth, height):
self.length = length
self.breadth = breadth
self.height = height
def get_area(self):
return self.length * self.breadth
r = rectangle(160, 20, 1000)
print("area is", r.get_area())
I have tried this in Julia, but it does neither fits the operation expectation nor the results.
struct rectangle
length
breadth
height
end
function __init__(rectangle)
rectangle.length = length
rectangle.breadth = breadth
rectangle.height = height
end
function get_area(rectangle)
return rectangle.length*rectangle.breadth
end
data_obj = __init__()
r = get_area(data_obj)
end
Please do suggest an appropriate approach to achieve the python example in Julia.
Thanks in advance!!
A bold move to just literally translate from Python. It doesn't work that way, obviously.
However, the following should be enough:
struct Rectangle{T}
length::T
breadth::T
height::T
end
area(rectangle) = rectangle.length * rectangle.breadth
r = Rectangle(160, 20, 1000)
println(area(r))
(The type parameter is not something you asked for, but recommended.)
Now, if you need to do something more than simply assign the fields, you can write an outer constructor:
function Rectangle(l, b, h)
...
return Rectangle(l, b, h)
end
But there's no need for this unless some actual logic is required.

Julia language FEniCS periodic boundary condition

I would like to apply a periodic boundary condition in FEniCS for Julia language but all examples I have found are in either C++ or Python. How to create a periodic boundary condition using Julia? It seems difficult because Julia does not have classes.
here is a minimal example:
using FEniCS
using PyCall
length=2.2
height=0.41
channel = Rectangle(Point([0.0, 0.0]), Point([length, height]))
domain = channel
mesh = generate_mesh(domain, 64)
# insert function here for PeriodicBoundarycondition
Q = FunctionSpace(mesh, "P", 1,constrained_domain=#the function that i am looking for)
I looked at the julia code that makes up FEniCS, the example of periodic boundary condition on the fenics page, and some of my old python codes for fenics and it inspired me to write this:
using FEniCS
using PyCall
#pyimport fenics
py"""
from dolfin import *
from mshr import *
length=2.2
height=0.41
channel = Rectangle(Point([0.0, 0.0]), Point([length, height]))
domain = channel
mesh = generate_mesh(domain, 64)
subdomains = MeshFunction("size_t", mesh, 1)
subdomains.set_all(0)
class Wall(SubDomain):
def inside(self,x,on_boundary):
return (near(x[1],height) or near(x[1],height)) and on_boundary
wall=Wall()
class PeriodicBoundary(SubDomain):
# Left boundary is "target domain" G
def inside(self, x, on_boundary):
return bool(x[0] < DOLFIN_EPS and x[0] > -DOLFIN_EPS and on_boundary)
# Map right boundary (H) to left boundary (G)
def map(self, x, y):
y[0] = x[0] - length
y[1] = x[1]
pbc=PeriodicBoundary()
"""
Q=FunctionSpace(fenics.VectorFunctionSpace(py"mesh", "P", 1,constrained_domain=py"pbc"))
the solution is not optimal as it just does the entire thing in python but I think I will have to live with it.

Dictionary key from pdb file

I'm trying to go through a .pdb file, calculate distance between alpha carbon atoms from different residues on chains A and B of a protein complex, then store the distance in a dictionary, together with the chain identifier and residue number.
For example, if the first alpha carbon ("CA") is found on residue 100 on chain A and the one it binds to is on residue 123 on chain B I would want my dictionary to look something like d={(A, 100):[B, 123, distance_between_atoms]}
from Bio.PDB.PDBParser import PDBParser
parser=PDBParser()
struct = parser.get_structure("1trk", "1trk.pdb")
def getAlphaCarbons(chain):
vec = []
for residue in chain:
for atom in residue:
if atom.get_name() == "CA":
vec = vec + [atom.get_vector()]
return vec
def dist(a,b):
return (a-b).norm()
chainA = struct[0]['A']
chainB = struct[0]['B']
vecA = getAlphaCarbons(chainA)
vecB = getAlphaCarbons(chainB)
t={}
model=struct[0]
for model in struct:
for chain in model:
for residue in chain:
for a in vecA:
for b in vecB:
if dist(a,b)<=8:
t={(chain,residue):[(a, b, dist(a, b))]}
break
print t
It's been running the programme for ages and I had to abort the run (have I made an infinite loop somewhere??)
I was also trying to do this:
t = {i:[((a, b, dist(a,b)) for a in vecA) for b in vecB if dist(a, b) <= 8] for i in chainA}
print t
But it's printing info about residues in the following format:
<Residue PHE het= resseq=591 icode= >: []
It's not printing anything related to the distance.
Thanks a lot, I hope everything is clear.
Would strongly suggest using C libraries while calculating distances. I use mdtraj for this sort of thing and it works much quicker than all the for loops in BioPython.
To get all pairs of alpha-Carbons:
import mdtraj as md
def get_CA_pairs(self,pdbfile):
traj = md.load_pdb(pdbfile)
topology = traj.topology
CA_index = ([atom.index for atom in topology.atoms if (atom.name == 'CA')])
pairs=list(itertools.combinations(CA_index,2))
return pairs
Then, for quick computation of distances:
def get_distances(self,pdbfile,pairs):
#returns list of resid1, resid2,distances between CA-CA
traj = md.load_pdb(pdbfile)
pairs=self.get_CA_pairs(pdbfile)
dist=md.compute_distances(traj,pairs)
#make dictionary you desire.
dict=dict(zip(CA, pairs))
return dict
This includes all alpha-Carbons. There should be a chain identifier too in mdtraj to select CA's from each chain.

where do we use the methods __str__ and __repr__ in python3? [duplicate]

This question already has answers here:
What is the difference between __str__ and __repr__?
(28 answers)
Closed 2 years ago.
I really don't understand where are __str__ and __repr__ used in Python. I mean, I get that __str__ returns the string representation of an object. But why would I need that? In what use case scenario? Also, I read about the usage of __repr__
But what I don't understand is, where would I use them?
__repr__
Called by the repr() built-in function and by string conversions (reverse quotes) to compute the "official" string representation of an object. If at all possible, this should look like a valid Python expression that could be used to recreate an object with the same value (given an appropriate environment).
__str__
Called by the str() built-in function and by the print statement to compute the "informal" string representation of an object.
Use __str__ if you have a class, and you'll want an informative/informal output, whenever you use this object as part of string. E.g. you can define __str__ methods for Django models, which then gets rendered in the Django administration interface. Instead of something like <Model object> you'll get like first and last name of a person, the name and date of an event, etc.
__repr__ and __str__ are similar, in fact sometimes equal (Example from BaseSet class in sets.py from the standard library):
def __repr__(self):
"""Return string representation of a set.
This looks like 'Set([<list of elements>])'.
"""
return self._repr()
# __str__ is the same as __repr__
__str__ = __repr__
The one place where you use them both a lot is in an interactive session. If you print an object then its __str__ method will get called, whereas if you just use an object by itself then its __repr__ is shown:
>>> from decimal import Decimal
>>> a = Decimal(1.25)
>>> print(a)
1.25 <---- this is from __str__
>>> a
Decimal('1.25') <---- this is from __repr__
The __str__ is intended to be as human-readable as possible, whereas the __repr__ should aim to be something that could be used to recreate the object, although it often won't be exactly how it was created, as in this case.
It's also not unusual for both __str__ and __repr__ to return the same value (certainly for built-in types).
Building up and on the previous answers and showing some more examples. If used properly, the difference between str and repr is clear. In short repr should return a string that can be copy-pasted to rebuilt the exact state of the object, whereas str is useful for logging and observing debugging results. Here are some examples to see the different outputs for some known libraries.
Datetime
print repr(datetime.now()) #datetime.datetime(2017, 12, 12, 18, 49, 27, 134411)
print str(datetime.now()) #2017-12-12 18:49:27.134452
The str is good to print into a log file, where as repr can be re-purposed if you want to run it directly or dump it as commands into a file.
x = datetime.datetime(2017, 12, 12, 18, 49, 27, 134411)
Numpy
print repr(np.array([1,2,3,4,5])) #array([1, 2, 3, 4, 5])
print str(np.array([1,2,3,4,5])) #[1 2 3 4 5]
in Numpy the repr is again directly consumable.
Custom Vector3 example
class Vector3(object):
def __init__(self, args):
self.x = args[0]
self.y = args[1]
self.z = args[2]
def __str__(self):
return "x: {0}, y: {1}, z: {2}".format(self.x, self.y, self.z)
def __repr__(self):
return "Vector3([{0},{1},{2}])".format(self.x, self.y, self.z)
In this example, repr returns again a string that can be directly consumed/executed, whereas str is more useful as a debug output.
v = Vector3([1,2,3])
print str(v) #x: 1, y: 2, z: 3
print repr(v) #Vector3([1,2,3])
One thing to keep in mind, if str isn't defined but repr, str will automatically call repr. So, it's always good to at least define repr
Grasshopper, when in doubt go to the mountain and read the Ancient Texts. In them you will find that __repr__() should:
If at all possible, this should look like a valid Python expression that could be used to recreate an object with the same value.
Lets have a class without __str__ function.
class Employee:
def __init__(self, first, last, pay):
self.first = first
self.last = last
self.pay = pay
emp1 = Employee('Ivan', 'Smith', 90000)
print(emp1)
When we print this instance of the class, emp1, this is what we get:
<__main__.Employee object at 0x7ff6fc0a0e48>
This is not very helpful, and certainly this is not what we want printed if we are using it to display (like in html)
So now, the same class, but with __str__ function:
class Employee:
def __init__(self, first, last, pay):
self.first = first
self.last = last
self.pay = pay
def __str__(self):
return(f"The employee {self.first} {self.last} earns {self.pay}.")
# you can edit this and use any attributes of the class
emp2 = Employee('John', 'Williams', 90000)
print(emp2)
Now instead of printing that there is an object, we get what we specified with return of __str__ function:
The employee John Williams earns 90000
str will be informal and readable format whereas repr will give official object representation.
class Complex:
# Constructor
def __init__(self, real, imag):
self.real = real
self.imag = imag
# "official" string representation of an object
def __repr__(self):
return 'Rational(%s, %s)' % (self.real, self.imag)
# "informal" string representation of an object (readable)
def __str__(self):
return '%s + i%s' % (self.real, self.imag)
t = Complex(10, 20)
print (t) # this is usual way we print the object
print (str(t)) # this is str representation of object
print (repr(t)) # this is repr representation of object
Answers :
Rational(10, 20) # usual representation
10 + i20 # str representation
Rational(10, 20) # repr representation
str and repr are both ways to represent. You can use them when you are writing a class.
class Fraction:
def __init__(self, n, d):
self.n = n
self.d = d
def __repr__(self):
return "{}/{}".format(self.n, self.d)
for example when I print a instance of it, it returns things.
print(Fraction(1, 2))
results in
1/2
while
class Fraction:
def __init__(self, n, d):
self.n = n
self.d = d
def __str__(self):
return "{}/{}".format(self.n, self.d)
print(Fraction(1, 2))
also results in
1/2
But what if you write both of them, which one does python use?
class Fraction:
def __init__(self, n, d):
self.n = n
self.d = d
def __str__(self):
return "str"
def __repr__(self):
return "repr"
print(Fraction(None, None))
This results in
str
So python actually uses the str method not the repr method when both are written.
Suppose you have a class and wish to inspect an instance, you see the print doesn't give much useful information
class Person:
def __init__(self, name, age):
self.name = name
self.age = age
p1 = Person("John", 36)
print(p1) # <__main__.Animal object at 0x7f9060250410>
Now see a class with a str, it shows the instance information and with repr you even don't need the print. Nice no?
class Animal:
def __init__(self, color, age, breed):
self.color = color
self.age = age
self.breed = breed
def __str__(self):
return f"{self.color} {self.breed} of age {self.age}"
def __repr__(self):
return f"repr : {self.color} {self.breed} of age {self.age}"
a1 = Animal("Red", 36, "Dog")
a1 # repr : Red Dog of age 36
print(a1) # Red Dog of age 36

How to call a closure with multiple parameters from collect() method of a groovy collection?

Let's say I have a closure:
def increment = {value, step ->
value + step
}
Now I want to loop over every item of my integers collection, increment it with 5, and save new elements to a new collection:
def numbers = [1..10]
def biggerNumbers = numbers.collect {
it + 5
}
And now I want to achieve the same result but by means of using increment closure. How can I do this?
Should be something like this (wrong code below):
def biggerNumbers = numbers.collect increment(it, 5) //what's the correct name of 'it'??
The solution to your problem would be nesting your call of increment in a closure:
def biggerNumbers = numbers.collect {increment(it, 5)}
If you wanted to pass a premade closure to the collect you should have made it compatible with collect - accepting a single parameter that is:
def incrementByFive = {it + 5}
def biggerNumbers = numbers.collect incrementByFive
mojojojo has the right answer, but just thought I'd add that this looks like a good candidate for currying (specifically using rcurry)
If you have:
def increment = {value, step ->
value + step
}
You can then curry the right-hand parameter of this function with:
def incrementByFive = increment.rcurry 5
And then, you can do:
def numbers = 1..10
def biggerNumbers = numbers.collect incrementByFive
Just thought it might be of interest ;-)
The main issue is that [1..10] creates a List<IntRange> which you are trying to increment. You should collect on the IntRange directly (note the lack of brackets):
(1..10).collect { it + 5 }
Or with curry:
def sum = { a, b -> a + b }
(1..10).collect(sum.curry(5))

Resources