Hey I was wondering how could I create a listview which had multiple headings..i.e
Heading 1
Details template
Details template
Details template
Heading 2
Details template
Details template
U can use Parent and child list view in Parent list view main heading comes and in child list view remaining headings comes.
Related
I'm pretty new to Drupal,
I have created a View with a custom content type which includes a field collection. When i try to load this view block inside a region in front page, It just shows the title (with the link to the actual content) and not the content itself. I need to view the content in the front-page itself
Can you please help me how to do this?
There are two options:
if in view you selected show format as content then you have to add your field collection field in selected display
if in view you selected shoq format as fields then you have to add your field collection field in view fields section
1- i have menu links HOME | Property(links to property content type) | NEWS.
2- In every News there are tags which reference to the property.
3- I want to link "NEWS" menu item to a separate page which should display only the news list which contains the tags for the property.
Example
i am on a property page say "Property XYZ", so there is a menu item "NEWS", when i click this menu item, a new page opens and this page is showing news which contain the Tag "Property XYZ" in them.
How to do this thing? Thanks in advance.
You can use the Views module to create a new View of nodes of type News, with a display of type Page (since you want the News listing to be a separate page).
Then you can add a Contextual Filter to the View, which is the way you can pass the Property as a parameter to filter to only News with that Property as a tag. You do this by adding the News field containing the tags as Contextual Filter for the view.
At this point you'll have a view page with something like 'news/%' as a path (where % is a placeholder for the Property parameter), so then you only need to use the appropriate substitution for it in each Property page for the News link on that page (like make it link to 'news/propertyxyz' while on PropertyXYZ page).
If the menu containing the NEWS menu item is outside of the scope of the Property page (like in the case of the site main menu or something like that) then you can use https://api.drupal.org/api/drupal/modules!system!system.api.php/function/hook_menu_link_alter/7.x to alter the path, getting the corresponding Property object (and any value you need to pass as parameter) through https://api.drupal.org/api/drupal/includes%21menu.inc/function/menu_get_object/7.x
I use a MvxTableViewController with custom cells within MvxTableViewCell and xib file to display a list of blog post. Each blog post can contains 1 to 3 items of differents type (Picture, Text and Sound).
I added 3 UIImageView. These 3 ImageView appear depending on contents of the blog post. I would like to know what’s the best way to do this with MVVMCross. How can i bind ViewModel property to UIImageView's position ?
The link below represented the desired result :
http://s25.postimg.org/li38jzdsf/Screen.png
I'm building Bootstrap 3 menu webpart and I need to count the number of child elements. The code below does that, but unfortunately counts all elements (hidden, containers, etc...). I need to count only "Page" elements, or at least elements that I have unchecked from being listed in the main menu.
<%# IfCompare(Eval("NodeChildNodesCount"),0,"class='dropdown-toggle' data-toggle='dropdown' ","") %>
Is there any way I could improve the code above to filter out all that is not a "Page" menu item?
I would suggest that you use a nested repeater which would only load the Page menu item below the selected section in the menu.
You could then provide the list item in the item template to match your CSS.
I'm confronted with the following not-knowing-how-to-do-this:
Two content types (CT) : Parent and Child
Parent has a field ChildRef (Field type: Entity Reference; Widget: Select list)
Child has fields Name (Text) , Adress(Text) and so on
When I create a new Parent node, I can select one of the Child nodes (no problem there, the Select list nicely displays the titles of the Child nodes)
What I need is that while editing the Parent, I'd like to preVIEW (no editing there) the fields of the Child, displayed inline, below the Select list.
Of course, once the Parent node is saved, there are many ways to display the Child node inside the Parent node. But it's the preVIEW in the Parent's edit mode that I need.
Try the Entity Reference View Widget
Then in the child content type, manage the display of fields for the widget.