I'm having some problems defining my question properly in the title, but here is what I'm looking for:
I have defined some menu items in the menu function in my module, and somehow I would like to retrieve this data in the template files and use it to build a menu.
Is there any good way to do this, or am I approaching the issue in the wrong way?
The simplest way would be to call the menu function directly and build up a list of links:
$items = array();
foreach (mymodule_menu() as $path => $item) {
$items[] = l($item['title'], $path);
}
// For Drupal 6
$rendered_menu = theme('item_list', $items);
// Or for Drupal 7
$rendered_menu = theme('item_list', array('items' => $items));
Related
I've successfully created a custom view template for my Drupal 7 site but am having issues adding attributes to the content which is outputted. I've searched high and low for the answer to this but to no avail.
I have a view called: views-view-fields--homepage-articles.tpl.php
I am printing content like :
$fields['title']->content
This is fine and expected, and outputs:
Title
But I want to add classes to it - how? I'm thinking I need to write a hook, but I cannot find this documented anywhere. At the moment my solution is a string replace:
<?php print str_replace('<a ', '<a class="brand-blue uppercase nodecoration"', $fields['title']->content); ?>
As you can imagine, this is not a satisfactory or long-term solution.
Many thanks!
You should be able to add the classes to the field using template_preprocess_views_view_fields().
Edit: Couldn't do it the way I thought, but you can overwrite the output of the field like so:
function MY_THEME_preprocess_views_view_fields(&$vars) {
$view = $vars['view'];
if ($view->name == 'node_listing') {
foreach ($vars['fields'] as $id => $field) {
if ($id == 'title') {
$field_output = l($view->result[$view->row_index]->node_title, 'node/'. $view->result[$view->row_index]->nid, array('attributes' => array('class' => 'brand-blue uppercase nodecoration')));
$vars['fields'][$id]->content = $field_output;
}
}
}
}
Have you tried using Semantic Views? https://drupal.org/project/semanticviews - that way you can override the classes within the UI instead of template files, may suit your needs better.
I have created a customized theme called "test", and I am trying to display the search results.
I added the function test_preprocess_search_results() to the template.php (copied the code from drupal page "function template_preprocess_search_results", then copy the search-result.tpl.php from search module to the "test"'s template folder.
function test_preprocess_search_results(&$variables) {
$variables['search_results'] = '';
if (!empty($variables['module'])) {
$variables['module'] = check_plain($variables['module']);
}
foreach ($variables['results'] as $result) {
$variables['search_results'] .= theme('search_result', array('result' => $result, 'module' => $variables['module']));
}
$variables['pager'] = theme('pager', array('tags' => NULL));
$variables['theme_hook_suggestions'][] = 'search_results__' . $variables['module'];
}
I am new in drupal, my concern is how can I make the search result display in some certain div which claimed in my page.tpl.php file? Do something like <?php print render($page['search_result']); ?> in page.tpl.php div ? I am not sure how does the default theme know where to display the search result? Can anyone help thanks
ps: after what I did, and refresh the cache, nothing show up
For search results you should use the search-results.tpl.php (all results list) and search-result.tpl.php (single list item) templates. Copy them from ROOT/modules/search folder into your theme folder and override them as you prefer.
I have added a menu page on my WordPress backend with some submenu items.
A snippet of the code i use is:
// Add to admin_menu function
add_menu_page(__('New Menu'), __('New Menu Title'), 'edit_themes', 'new_menu_item', 'functiontocallonclick', '', 3.5);
// Add to secondlevel menu
add_submenu_page('new_menu_item', __('New |Sub Menu item'), __('New Menu Title item'), 'edit_themes', 'new_menu_sub_item', 'subfunctiontocallonclick',');
As you can see above it is calling the function functiontocallonclick when you go to the New menu item in the backend.
What i am wondering now:
I would like to pass a variable with the function.
functiontocallonclick($value);
Ofcourse it can't be done that way, so what is the good way?
I use this:
switch($_GET['page']){
case 'suppliers': $type='c';
break;
case 'contractors': $type='s';
break;
default: $type='';
break;
}
but I try to find some better solution.
This answer might seem late but I'll share how I work around this because it looks like quite a few people are looking for an answer to this question.
My answer is going to be passing variables to a nested function within a class-based context so if you're using functional programming then disregard the $this.
The Main hook action:
function mainSetup(){
add_action('admin_menu', array($this, 'mainMenuSetup'));
add_action('admin_menu', array($this, 'subMenuSetup'));
}
Menu Setup:
function mainMenuSetup(){
add_menu_page('DashBoard',
'DashBoard',
'manage_options',
'[yoursitesname]-admin-menu',
function(){ $this->pageSelect("admin"); },
'',
200
);
}
Within the example of the Main menu navigation option, we are passed a string in the nested function that will be passed as an argument to the method(function) 'pageSelect', but the string is hardcoded and can't be changed easily. We'll address this problem when setting up the submenu(s).
TODO: You should replace [yoursitename].
SubMenu Setup:
For the submenu let's say we want to make it easier to go back and add new submenus and change who has access to which submenus. For this, I'm going to make an associative array called 'subMenuObjects' where the array's keys are the submenu objects and their values are the page's permissions.
function subMenuSetup(){
$subMenuObjects = array(
'Settings' => 'manage_options',
'Services' => 'manage_options'
);
foreach ($subMenuObjects as $subMenu => $value) {
add_submenu_page('[yoursitesname]-admin-menu',
$subMenu . 'Page',
$subMenu,
$value,
'[yoursitesname]' . strtolower($subMenu) . '-menu',
function() use ($subMenu){ $this->pageSelect($subMenu); }
);
}
}
Here we use the 'use' to pass the $subMenu to the nested function.
Page select:
function pageSelect($page){
switch ($page) {
case 'admin':
echo '<div>Welcome to the Admin page</div>';
break;
case 'Settings':
echo '<div>Welcome to the Settings page</div>';
break;
case 'Services':
echo '<div>Welcome to the Service page</div>';
break;
default:
echo '<div>something happened, contact dev</div>';
break;
}
}
Yes, the way you're doing it is the way WordPress does it itself. To re-use admin screens, you have to pass some query var in the URL and then show/hide elements based on that.
You can also create invisible admin screens: How to enable additional page in WordPress custom plugin?. And this may be useful too: Redirect from add_menu_page
I've been stuck on how to manipulate in the template file what a menu block outputs in it's html. The regular < ul class="menu" > with li links is fine and I don't need to completely gut this html that drupal creates for all menus but I want to inject classes 'inline' and 'links' like the system main menu (usually) already has under it's ul element. I could print the menu directly in the theme skipping blocks altogether but it would be more helpful in the long run to learn injecting class names into the output of menu blocks that are generated.
So far from googling around I've only been able to find a module that can enter ID's and Class names on the individual li's but not the ul wrapping them and I've been unable to get any similar template file snippets I've come across to work.
There is a way to use a hook function to do this isn't there?
Why don't you add the classes you want via javascript?!
Example:
jQuery("#MY_MENU_WRAPPER ul.menu").addClass("inline");
If that's the case, try the following code in your theme's template.php file
function return_menu_markup($menu_name, $attributes)
{
$items = array();
$menu_tree = menu_tree_all_data($menu_name);
$menu_tree_output = menu_tree_output($menu_tree);
foreach($menu_tree_output as $item_id => $item_data)
{
if(is_numeric($item_id) && is_array($item_data))
{
$items[] = l('<span>' . $item_data['#title'] . '</span>', $item_data['#href'], array(
'attributes' => $item_data['#attributes'],
'html' => TRUE,
)
);
}
}
return theme('item_list', array('items' => $items, 'type' => 'ul'));
}
Then anywhere in the template, simply do the following:
$attributes = array();
$attributes['id'] = "MY_MENU_ID";
attributes['class'] = array('MY_CLASS_1', 'MY_CLASS_2', 'MY_CLASS_3');
return_menu_markup("main-menu", $attributes);
Hope you find what needed :)
-Muhammad.
You can use template.php in your theme folder, use hook:
function THEMENAME_menu_tree__menu_main_navigation($variables){
return "<ul class=\"inline\">\n" . $variables['tree'] ."</ul>\n";
}
also note this menu_main_navigation is menu URL path, other values are always same. Do some cache delete few times, maybe it want work immediately.
I’ve been using Views to selectively returned nodes, but right now I want to return my nodes and use the Taxonomy term as a group header. I can't see anyway to get Views to do this for me, other then create multiple views on one page.
So I thought I'd right a module. I've written the SQL to return the correct nodes, but I can't work out how to send them to the themeing engine properly. I would like some advice on how to go about this, my tutorial book has examples of building a list as shown below.
foreach ($result as $row2) {
$items[] = l($row2->title,'node/'.$row2->nid.'/edit');
}
return array('#markup' => theme('item_list',array('items' => $items)));
now I want to return my nodes attached image file in Teaser mode, and the title of the node, plus (and I dont want to get ahead of myself) I may also want a couple of the addition node fields appended to the title. Should be easy right? I can't work it out at all.
I have wrangled my way around it (a bit) by using what I'm sure is a non drupal method which looks a bit like this, trouble is I can't get my output to work with ColorBox module, so I'm thinking if I can get official Teaser node data out it might work better, and i'd feel better knowing I was doing things in a drupaly way :)
foreach ($result as $row2) {
$items .= '<img title="'.$row2->title.' '.$row2->fielddata.'" alt="'.$row2->title.'" src="http://localhost/theme/sites/default/files/styles/thumbnail/public/field/image/'.$row2->filename .'"></a>';
$items .= '</div></div></div></div>';
}
return array('#markup' => $items);
Really appreciate any time you take to help me out and thanks in advance.
The following code should help. If you don't already have it, install the devel module, it gives you a wonderful function called dpm() which will print the contents of an array/object to the messages area.
// Get some nodes ids
$nids = db_query('SELECT nid FROM {node}')->fetchCol();
// Load up the node objects
$nodes = node_load_multiple($nids);
// This will print the node object out to the messages area so you can inspect it to find the specific fields you're looking for
dpm($nodes);
// I guess you'll want to do something like this:
$terms = array();
foreach ($nodes as $node) {
// Load the taxonomy term associated with this node. This will be found in a field as this is how taxonomy terms and nodes are related in D7
$term = taxonomy_term_load($node->field_vocab_name['und'][0]['tid']);
// Set up the array
if (!isset($terms[$term->name])) {
$terms[$term->name] = array();
}
// Create some markup for this node
$markup = '<h3>' . l($node->title . ' ' . $node->field_other_field['und'][0]['value'], "node/$node->nid") . '</h3>';
// Add an image
$image = theme('image', array('path' => $node->field_image['und'][0]['uri'], 'alt' => $node->title));
$markup.= $image;
// Add the markup for this node to this taxonomy group's list
$terms[$term->name][] = $markup;
}
// Make up the final page markup
$output = '';
foreach ($terms as $term_name => $node_list) {
$output .= '<h2>' . check_plain($term_name) . '</h2>';
$output .= theme('item_list', array('items' => $node_list));
}
return $output;
Hope that helps
You can get views to group the returned nodes by the taxonomy term for you. Assuming you are using a field view type, just add the taxonomy field and then where it says Format:Unformatted list | Settings click on Settings at the right hand side and choose your taxonomy field as the grouping field.
Note: if you are not using a field view type, or if you are not using unformatted list then the instructions will be a variation of the above.