I am trying to build a simple slideshow. So far, the basic markup looks like this:
<h1>My Slideshow</h1>
<p>This paragraph behaves as expected.</p>
<div class="slide-container">
<div class="slide">
<h2>First Slide</h2>
<p>Some stuff on this slide…</p>
</div>
<div class="slide">
<h2>Second Slide</h2>
<p>And some more stuff here…</p>
</div>
</div>
<p>This paragraph will disappear beneath the stacked images.</p>
This is the corresponding CSS:
.slide-container {
position: relative;
}
.slide {
position: absolute;
top: 0;
/* just for the looks */
width: 20em;
padding: 0 1em;
border: 1px solid steelblue;
background: white;
}
The problem is, that the .slide-container does not fit to the height of its child (or children) .slide (see screenshot).
I know i can set the height of the .slide-container manually, but i want to put this in a fluid grid, where the height is variable. Is there any way to achieve this?
Absolutely-positioned items are logically-associated with their parent, but not "physically". They're not part of the layout, so the parent item can't really see how big they are. You need to code the size yourself, or sniff it with JavaScript and set it at run-time.
You can use this using jquery:
function sliderheight(){
divHeight = $('.slide').height();
$('.slide-container').css({'height' : divHeight});
}
sliderheight();
This will resize the 'slide-container' div to have the same height as the 'slide' div.
You can make it responsive by calling the function on the firing of a 'resize' event:
$(window).resize(sliderheight);
Hope this helps.
Perfect way of doing this is to set the relative parent's dimensions i.e. height & width to fit the absolute children.
http://learn.shayhowe.com/advanced-html-css/detailed-css-positioning/
This guy wrote enough to understand the basics of css positioning. Actually the relative parent is used to position all its absolute child logically. But it does not share the physical position as a result it does not stretch itself to cover the relative children.
Related
I have been fiddling around with this for some time now, but I still don't understand how it should be done.
I would like the image to be maximized (100%/100%) in the background of the itemtemplate div, but right now it just makes it fit inside the div which is 250px/250px.
<div class="itemtemplate" data-win-control="WinJS.Binding.Template">
<img style="-ms-grid-row-span: 2;" src="#" data-win-bind="src: backgroundImage; alt: title" />
<div class="item-overlay">
<h4 class="item-title" data-win-bind="textContent: title"></h4>
<h6 class="item-subtitle win-type-ellipsis" data-win-bind="textContent: subtitle">
</h6>
</div>
</div>
Any ideas ? thx.
You can position the image absolutely and set the height and width to 100% in your CSS files.
.itemtemplate > img {
position: absolute;
top: 0;
left: 0;
height: 100%;
width: 100%;
}
Just make sure you remember to position the parent div and the other children of .itemtemplate relatively:
.itemtemplate, .itemtemplate > div {
position: relative;
}
The parent needs to be positioned relatively to ensure the img is positioned within that element. The other children of the parent need to positioned relatively to ensure that they are drawn above img (as positioned elements are drawn after static elements). If you have trouble seeing the other child elements then you can set their z-index.
Working example: http://jsfiddle.net/sjsNJ/
Need to use CSS background-image.
div.itemtemplate
{
background:url(PATH_TO_IMAGE);
background-size:100% 100%;
background-repeat:no-repeat;
}
See site below for more info.
http://www.w3schools.com/cssref/pr_background-image.asp
I am not familiar with the attributes you are using. But, in order to use an image for the background. There are couple of ways.
If it is <body> or <table> you can also define them by using doing something like this
<body background="link/to/image.jpg">
But the global way, which every element supports would be to define them using CSS
<div style="background-image: url("link/to/image")">...</div>
Now, coming to the image part
Whenever you are using a background image,
It is never going to re-size to fit the container. Unless you use CSS3.
/* CSS3 Snippet to resize a background */
div
{
background-image:url("link/to/image");
-moz-background-size:80px 60px;
background-size:80px 60px;
background-repeat:no-repeat;
}
If the container is big, it will start repeating itself to fill the area. Which can be controlled to repeat or not repeat. Like
div {
background-image: url("link/to/image");
background-repeat: no-repeat; /* similary repeat-x and repeat-y */
}
However, what you are trying to use in using a <img /> to act as a background, which is semantically wrong and I do not recommend it.
I'm writing a website/iPad app (using PhoneGap), where I have 1024x768 images on a slide show. I'd like to position another image, e.g. the home icon, on top of the 1024x768 images, at exactly the same position, no matter the screen size (e.g. high/low resolution PC screen, or 1024x768 tablet display). I tried absolute, but the position changes in different displays, and it's not the same position as I originally set up in CS 5.
Similar to the other answers, but if you prefer not to define the width and height, you can use float:
http://jsfiddle.net/RprTY/
<div>
<img src="http://placekitten.com/300/300">
<img src="http://placekitten.com/30/30" id="smallone">
</div>
CSS:
div{
float: left;
position: relative;
}
img{
vertical-align: bottom;
}
#smallone{
top: 0;
left:0;
position:absolute;
}
As long as the parent container is set to either position: relative or position: absolute, then the absolutely positioned image should be positioned relative to the top left corner of the parent. This should be completely independent of screen resolution.
Put your 1024x768 image in a div of the same size. Include your home icon in that div as well. Give the div position relative, and the home icon position absolute and it will be absolutely positioned inside it's parent div.
I tried the solution proposed here but it didn't work. I have basically the same problem: two images inside a slider, one of them is absolute positioned with percentage values (so when I change the width of the viewport it scrolls sideways). The other image should move along with the first one statically positioned in relation to the latter.
The thing is in my case the images are not children of the same parent div. I have set up a Fiddle example of the code I am currently working with.
http://jsfiddle.net/36QPG/1/
<div class="image">
<img id="back" src="http://placekitten.com/300/300" />
</div>
<div class="slide">
<div class="image">
<img id="front" src="http://www.lionsclublagardiecastelnau.com/data/images/images-sites/images/icone-android.png"></img>
</div>
</div>
It's worth mentioning that I can't change the HTML code set up.
I've been struggling with this problem for a while now, but I haven't been able to figure it out. I hope I've made myself clear enough.
Thank you in advance.
html:
<div id="bottom">
<div id="top"></div>
</div>
css:
#bottom{
background: url(*bottom-image-url*);
position: relative;
width: *??*;
height: *??*;}
#top{
background: url(*top-image-url*);
position: absolute;
width: *??*;
height: *??*;
left: *??*;
right: *??*;}
I have two DIVs that I need to position exactly on top of each other. However, when I do that, the formatting gets all screwed up because the containing DIV acts like there is no height. I think this is the expected behavior with position:absolute but I need to find a way to position these two elements on top of each other and have the container stretch as the content stretches:
The top left edge of .layer2 should be exactly aligned to the top left edge of layer1
<!-- HTML -->
<div class="container_row">
<div class="layer1">
Lorem ipsum...
</div>
<div class="layer2">
More lorem ipsum...
</div>
</div>
<div class="container_row">
...same HTML as above. This one should never overlap the .container_row above.
</div>
/* CSS */
.container_row {}
.layer1 {
position:absolute;
z-index: 1;
}
.layer2 {
position:absolute;
z-index: 2;
}
Actually this is possible without position absolute and specifying any height. All You need to do, is use display: grid on parent element and put descendants, into the same row and column.
Please check example below, based on Your HTML. I added only <span> and some colors, so You can see the result.
You can also easily change z-index each of descendant elements, to manipulate its visibility (which one should be on top).
.container_row{
display: grid;
}
.layer1, .layer2{
grid-column: 1;
grid-row: 1;
}
.layer1 span{
color: #fff;
background: #000cf6;
}
.layer2{
background: rgba(255, 0, 0, 0.4);
}
<div class="container_row">
<div class="layer1">
<span>Lorem ipsum...<br>Test test</span>
</div>
<div class="layer2">
More lorem ipsum...
</div>
</div>
<div class="container_row">
...same HTML as above. This one should never overlap the .container_row above.
</div>
First of all, you really should be including the position on absolutely positioned elements or you will come across odd and confusing behavior; you probably want to add top: 0; left: 0 to the CSS for both of your absolutely positioned elements. You'll also want to have position: relative on .container_row if you want the absolutely positioned elements to be positioned with respect to their parent rather than the document's body:
If the element has 'position: absolute', the containing block is established by the nearest ancestor with a 'position' of 'absolute', 'relative' or 'fixed' ...
Your problem is that position: absolute removes elements from the normal flow:
It is removed from the normal flow entirely (it has no impact on later siblings). An absolutely positioned box establishes a new containing block for normal flow children and absolutely (but not fixed) positioned descendants. However, the contents of an absolutely positioned element do not flow around any other boxes.
This means that absolutely positioned elements have no effect whatsoever on their parent element's size and your first <div class="container_row"> will have a height of zero.
So you can't do what you're trying to do with absolutely positioned elements unless you know how tall they're going to be (or, equivalently, you can specify their height). If you can specify the heights then you can put the same heights on the .container_row and everything will line up; you could also put a margin-top on the second .container_row to leave room for the absolutely positioned elements. For example:
http://jsfiddle.net/ambiguous/zVBDc/
Here's another solution using display: flex instead of position: absolute or display: grid.
.container_row{
display: flex;
}
.layer1 {
width: 100%;
background-color: rgba(255,0,0,0.5); /* red */
}
.layer2{
width: 100%;
margin-left: -100%;
background-color: rgba(0,0,255,0.5); /* blue */
}
<div class="container_row">
<div class="layer1">
<span>Lorem ipsum...</span>
</div>
<div class="layer2">
More lorem ipsum...
</div>
</div>
<div class="container_row">
...same HTML as above. This one should never overlap the .container_row above.
</div>
Great answer, "mu is too short".
I was seeking the exact same thing, and after reading your post I found a solution that fitted my problem.
I was having two elements of the exact same size and wanted to stack them.
As each have same size, what I could do was to make
position: absolute;
top: 0px;
left: 0px;
on only the last element. This way the first element is inserted correctly, "pushing" the parents height, and the second element is placed on top.
Hopes this helps other people trying to stacking 2+ elements with same (unknown) height.
Here's some reusable css that will preserve the height of each element without using position: absolute:
.stack {
display: grid;
}
.stack > * {
grid-row: 1;
grid-column: 1;
}
The first element in your stack is the background, and the second is the foreground.
I had to set
Container_height = Element1_height = Element2_height
.Container {
position: relative;
}
.ElementOne, .Container ,.ElementTwo{
width: 283px;
height: 71px;
}
.ElementOne {
position:absolute;
}
.ElementTwo{
position:absolute;
}
Use can use z-index to set which one to be on top.
Due to absolute positioning removing the elements from the document flow position: absolute is not the right tool for the job. Depending on the exact layout you want to create you will be successful using negative margins, position:relative or maybe even transform: translate.
Show us a sample of what you want to do we can help you better.
Of course, the problem is all about getting your height back. But how can you do that if you don't know the height ahead of time? Well, if you know what aspect ratio you want to give the container (and keep it responsive), you can get your height back by adding padding to another child of the container, expressed as a percentage.
You can even add a dummy div to the container and set something like padding-top: 56.25% to give the dummy element a height that is a proportion of the container's width. This will push out the container and give it an aspect ratio, in this case 16:9 (56.25%).
Padding and margin use the percentage of the width, that's really the trick here.
After much testing, I have verified that the original question is already right; missing just a couple of settings:
the container_row MUST have position: relative;
the children (...), MUST have position: absolute; left:0;
to make sure the children (...) align exactly over each other, the
container_row should have additional styling:
height:x; line-height:x; vertical-align:middle;
text-align:center; could, also, help.
I need a child div to be as high as its parent, but I do not know the parent's height. It can change.
Setting "height: 100%" does not work, as the div will take the height of the entire page.
This is the layout of the divs:
<div id="deelnemersballoon">
<div class="balloonarrow"></div>
<div class="balloonborder">
<div class="ballooncontent">
<div id="aantaldeelnemers">1</div>
<div id="deelnemertekst">deelnemer werd toegevoegd.</div>
<div class="clear">
<button>Add something</button>
</div>
</div>
</div>
</div>
.balloonarrow should be as high as #deelnemersballoon
set parent div height in pixels (for ex height:100px ) and set child as 100% (height:100%) . Child only occupies parent div width fully
I never had much luck with height: 100%; even when playing by the rules. What does .balloonarrow do? If you're just trying to snap a graphic to the bottom of the div, you can try position: absolute; and bottom: 0px;, as long as #deelnemersballoon is set to position: relative;.
If you're just looking to make a solid/patterned visual contained by .balloonarrow, you're better off making a stretch image: create an image 3px or 4px tall, make it the background of #deelnemersballoon, and set it to repeat-y. Quick and dirty way to make a 100% height sidebar.
Hope this helps, can't tell much more without seeing your css.
A child div will not take up 100% of its parent if it has something in the markup before it:
Html:
<div id='parent'>Parent (Mark up before child)<div id='child'>Child</div></div>
css:
#parent {background:blue; height:500px; color:white}
#child {background:red; height:100%}
You can find a working example here. (Removing the text from the #parent div will make the child fill it 100%)
http://jsfiddle.net/wcprA/2/
The same thing applies if you have markup after the 100% child aswell, as seen here
http://jsfiddle.net/wcprA/5/
Try adding position:relative to the parent div. Then the 100% on the child div should reference the parent div. In general 100% height is going to look for the nearest parent element that has a position set on it - and if it doesn't find any it will eventually find the body tag and use that.
<div id="calendar">
<p>Text</p>
<div class="section">blah</div>
</div>
I'm applying the PNG to #calendar, in IE6 I use filter but it makes the content not clickable - I believe the way around this was to force everything inside to be positioned ( eg position:relative ) and have a z-index + hasLayout but sometimes it doesn't work.
Should I instead wrap all my stuff in another div and apply the png BG to a sibling node such like this, or what?
<div id="calendar">
<div id="calendar-bg"></div>
<div id="calendar-content">
<p>Text</p>
<div class="section">blah</div>
</div>
</div>
Then force the calendar-bg to be absolutely positioned and 100% width/height, and relatively position #calendar-content on top of it? Or is there some other hidden way that the mainstream png fixer scripts ( ala htc, jquery.pngFix ) work?
That is indeed the (only) correct solution to this problem I ever came across. You can't rely on your first solution (positioning the childs relatively), because the opacity filter in IE is thrown over all child elements, with the child elements not being clickable as a result.
So just make sure the png is not in the parent element of a clickable element.
So, create a parent with the property 'position: relative' (or absolute, depends on your layout) and insert two children for the background and the actual content.
Example:
<div id="calendar">
<div id="calendar-bg"></div>
<div id="calendar-content">
<p>Text</p>
</div>
</div>
#calendar { position: relative; }
#calendar #calendar-bg {
position: absolute;
left: 0;
top: 0;
height: 100%; /* Or the height and width in pixels if you know them */
width: 100%; }
#calendar #calendar-content {
position: relative;
z-index: 1; }
I believe the way around this was to force everything inside to be positioned ( eg position:relative ) and have a z-index + hasLayout but sometimes it doesn't work.
Position:relative doesn't trigger hasLayout. You should try something simple like zoom:1 with a z-index.
I'm pretty sure (going from my memory of dealing with a similar problem) that trying to relatively position stuff on top of a png in IE6 doesn't work, but specifying z-index does.