So yet another question about vertically aligning an image within a div, but I think mine is different than the others I've found on here. I can't seem to find a solution that works for my situation.
I have a DIV that is 100% width (to it's container, which is floating left and has a set pixel width) and has a set pixel height. I have an image inside that I am positioning absolute to get it to the background of content within the DIV. The image is fluid with a width of 100%.
All works well, but I want to get the image to vertically align to the middle of the container and height is unknown.
Here is some sample code that shows what I'm trying to do:
<div class="container">
<div class="image-wrapper">
<img src="http://farm5.staticflickr.com/4111/4968056789_d872094672_o.jpg"
width="100%" />
</div>
<p>Some text</p>
</div>
And some sample CSS:
.container {
width:100%;
margin-top:10px;
height:100px;
overflow:hidden;
}
.image-wrapper {
position: relative;
}
.image-wrapper > img {
position: absolute;
z-index: -1;
}
p {
text-align: center;
padding-top: 10px;
color:#fff;
font-weight: bold;
}
But the flower should show up with it's center visible within the container div.
Any thoughts? I'm trying to avoid any Javascript sizing (the outer container, not shown in this sample, is already being sized). I'm not opposed to more DIVs, tables.. whatever you got!
A jsFiddle to demo this:
http://jsfiddle.net/JonMcL/sNz9h/
Why not go for the background-image property? That allows vertical centering...
http://jsfiddle.net/urrWS/
Assuming you want to only scale the image down and not stretch it beyond its native resolution this should do the trick. A little bit of jQuery is involved but it's minimal. Essentially, this adjusts the top-margin of the IMG on the window.resize event.
HTML
<div id="container">
<img id="image" src="image.jpg"> <!-- native size is 480x300 -->
</div>
CSS
#container {
margin: auto;
width: 80%;
height: 300px;
border: 1px solid gray;
}
#image {
display: block;
width: 100%;
max-width: 480px;
margin: auto;
}
jQuery
function adjustImage() {
$("#image").css('margin-top', ($("#container").height() - $("#image").height()) / 2);
}
$(window).load(function() {
adjustImage();
$(window).resize(function() {
adjustImage();
});
});
If I get what you need I would suggest setting the background image via css, then you can set the position correctly etc.
.container {
width:100%;
margin-top:10px;
background-image:url("http://farm5.staticflickr.com/4111/4968056789_d872094672_o.jpg");
background-repeat:no-repeat;
background-position:left center;
height:100px;
overflow:hidden;
}
http://jsfiddle.net/sNz9h/6/
Related
First, please consider this fiddle.
I need to get some links over specific image regions, however those images are scaled according to the parent size...
that's why the link's position and size are relative(percentages) to the image.
But the fiddle shows the problem of this approach.
Is there anyway to get the .image-wrapper to "mimic" the img size and position after scaled?! Any trick or whatever?
Note: I'm OK with webkit-only solutions!
Edit 1
Actually I'm more focused in making the image fit on the content div, then making the image wrapper follow the resulting image size. Here's what I achieved so far...
Now I'm trying to get it working with the image centralized.
Here is the CSS skeleton for a solution.
Suppose your HTML looks like the following:
<div id="content1" class="content portrait">
<div class="panel-wrapper">
<div class="image-wrapper">
<img src="http://placekitten.com/200/250" />
</div>
</div>
</div>
<div id="content2" class="content landscape">
<div class="panel-wrapper">
<div class="image-wrapper">
<img src="http://placekitten.com/300/200" />
</div>
</div>
</div>
The HTML is similar to your original code except that there is an extra wrapper .panel-wrapper.
I used the following CSS:
.content {
background: lightgray;
display: table;
margin: 40px 0;
}
#content1 {
width:100px;
height:150px;
}
#content2 {
width:150px;
height:150px;
}
.panel-wrapper {
display: table-cell;
vertical-align: middle;
text-align: center;
}
.image-wrapper {
outline: 1px solid green;
position:relative;
display: inline-block;
}
.content img {
display: block;
width: 100%;
}
.portrait .image-wrapper {
height: calc(100% - 2px);
}
.portrait .img {
height: 100%;
}
.landscape .image-wrapper {
width: calc(100% - 2px);
}
.landscape .img {
width: 100%;
}
.sample-link {
background:rgba(0, 0, 255, 0.3);
position:absolute;
display:block;
width: 50%;
height:20%;
top:5%;
left:5%;
}
I apply display: table to .content and display: table-cell to .panel-wrapper so that I can get a get the image centered both vertically and horizontally.
The .image-wrapper has display: inline-block.
To get the scaling right, you need to consider two cases depending on the aspect ratio of the image.
For portrait images, apply height: 100% to the .image-wrapper and the child img.
For landscape images, apply width: 100% respectively.
If you have a border on .image-wrapper, use the CSS calc() function to adjust for the 2px width of the borders.
What you need to do is use JavaScript/jQuery to determine the aspect ratio of the image and then apply the correct class (.portrait or .landscape) to the .content block.
See demo at: http://jsfiddle.net/audetwebdesign/SZjvJ/
A possible way is to work with image ratio and to adjust link ratio and margins according to image dimensions, with Jquery.
Have a look at this example fiddle: http://jsfiddle.net/t7Ucj/
The Js measures width and height of the image and according to its ratio, it works on the width or on the height of the link.
var width = $('#content2 img').width();
var height = $('#content2 img').height();
//vertical image
if(height > width){
var left = $('#content2 img').css('margin-left');
$('#content2 .sample-link').css({'width': width, 'left' : left});
}
else{
var top = $('#content2 img').css('margin-top');
$('#content2 .sample-link').css({'height': height*0.2, 'top' : top + height*0.4});
}
Then you can wrap all the instructions in a simple function obviously.
I know it can be tricky to put all the possible cases but i had a similar problem and solved in this way.
hope it helps
I'm building a responsive page that has an image and <div> side by side:
The width and height of the image retain their proportions and expand/contract with the browser window.
The width of the <div> does the same, but I'd like it to match the image in terms of height.
Is there any way of achieving this? Here's a Fiddle of the problem: http://jsfiddle.net/alecrust/xwJHw/
You can use display:table property for this. Write like this:
section{
display:table;
width:100%;
}
.text-box,.image{
display:table-cell;
vertical-align:top;
}
Check this http://jsfiddle.net/xwJHw/8/
Note: display:table works till IE8 & above.
You can use jQuery.
Calculate the hight of the image using $('#imgId').height() and the set the same to Div.
Also see the code, how heights are adjusted here http://filamentgroup.com/examples/equalHeights/
EDITED:
#alecrust: This is a fine solution and also implemented in your fiddle, See Here
A pure css solution: SEE DEMO
CSS:
#wrapper {
overflow: hidden;
background: #ccc;
}
.placeholder_image {
float: left;
width: 430px;
height: 264px;
background: #fff;
padding: 0 20px 0 0;
}
.placeholder_text {
background: #ccc;
margin-left: 450px;
display: block;
}
HTML:
<div id="wrapper">
<div class="placeholder_image">
<img src="http://www.qesign.com/templates/designs/christmas-after-effects-animated-e-card-template-31966.jpg" alt="" />
</div>
<div class="placeholder_text">
A block of text
</div>
</div>
The following code has a DIV that needs to be positioned at the top of the container, another at the bottom and then the content needs to come through in the middle.
<div style="position:absolute; top:0; width:100%; height:40px"></div>
<div class="howto"></div>
<div style="position:absolute; bottom:0; width:100%; height:40px"></div>
So we don't know the height of the containing DIV. How without JS can the div with class howto have the height of the container DIV less the height of the absolute positioned div at the top and bottom so as to contain content between these 2 DIVs.
For what you wish to accomplish, this is one possible solution:
#tinkerbin: http://tinkerbin.com/QsaCPgR6
HTML:
<div class="container">
<div class="header"></div>
<div class="howto">
Has height set to auto. You may change that if you want to.
</div>
<div class="footer"></div>
</div>
CSS:
.container {
position: relative;
padding: 40px 0; /* top and bottom padding = .header and .footer padding*/
}
.header,
.footer {
position: absolute;
height: 40px;
width: 100%;
}
.header {
top: 0;
}
.footer {
bottom: 0;
}
.howto {
height: /*specifiy one if you wish to*/;
}
As far as I know there isn't a pure CSS way to do what you're trying to do without JS.
See this previous post on SA:
Make a div fill the height of the remaining screen space
I've found a lot of variations to this question within SO, but it seems no matter what I try I can't get this (seemingly very simple!) thing working!
What I'm trying to do is to keep the 'centered' div in the center of the viewport and to place the 'sidebar' div directly to its right (i.e. not right-aligned to the viewport) without affecting the centering of the 'centered' div.
Here's some test code on jsfiddle:
http://jsfiddle.net/6wCyr/13/
Everything I've read seems to imply that the float property is exactly what I'm looking for, but the results in the link show that I get weird results wherein the right sidebar is placed below the 'centered' div rather than beside it. That's what's shown in the link.
I've also seen a solution involving using a negative value for the right property, and setting the width of the sidebar exactly, but I couldn't get that one going either.
Hopefully this question is as easy to solve as I think it should be! Just can't seem to find the right set of div inside div and so forth. Hard to debug these alignment issues!
Thanks!
Live Demo
I moved div.sidebar inside div.centered.
I added position: relative to div.centered.
We're using this technique.
You don't have to declare a fixed width on div.sidebar.
CSS:
div.centered {
margin-left: auto;
margin-right: auto;
border: dashed;
width: 100px;
height: 100px;
position: relative
}
div.sidebar {
border: dotted;
position: absolute;
top: 0;
left: 100%
}
HTML:
<div class="holder">
<div class="centered">
CENTERED
<div class="sidebar">
RIGHT SIDEBAR
</div>
</div>
</div>
Try this.
http://jsfiddle.net/DOSBeats/6wCyr/16/
.holder {
margin:0 auto;
width:100px;
}
.centered {
border: dashed;
float:left;
height: 100px;
}
.sidebar {
border: dotted;
float:left;
margin-right:-100px;
width:100px;
}
If you do not set a width to your holder and center it, the sidebar will float to the edge of the window.
Try this:
HTML:
<div id="holder">
<div id="sidebar">Sidebar</div>
<div id="centered">Centered</div>
</div>
CSS:
#holder{
margin:auto;
width:500px;
}
#sidebar{
border:dotted;
float:left;
width:100px;
}
#centered{
border:dashed;
margin-left:110px;
width:380px;
}
A simple (one might think!) question to all CSS gurus: I would like to shrink a DIV snugly around an IMG. The IMG is 600 x 800 and I needed it much smaller. So I go {height: 100%; width: auto;} and constrain the height via a wrapper DIV. However, to maintain the (unknown to me) AR, I cannot fix the width on the DIV. I tried to set the wrapping DIV to "display: inline-block" or "float: left" or "position: absolute" or ... - no matter: most browsers will stretch that DIV 800px wide - the original width of the full-size IMG - so it looks sthg like this:
[[IMG].............................]
Bizarrely, I can add some text to the DIV (just to test), and that text will actually appear right next to the scaled IMG:
[[IMG]Hello world..................]
Does anyone here know why the original size of the IMG matters (for dimensioning the width, it does not affect the height)? And what I might be able to do to shrink the DIV?
Thanks for looking.
EDIT:
To test Pär Wieslander's idea, I wrote a little test bed that should help clarify what I am on about:
<style type="text/css">
html, body {
height: 100%;
}
#dialog {
background: green;
height: 50%;
position: relative;
}
#frame {
border: 2px solid black;
display: inline-block;
height: 100%;
position: absolute;
}
#img {
height: 100%;
width: auto;
}
</style>
<body>
<div id="dialog">
<div id="frame">
<img id='img' src='...' />
</div>
</div>
</body>
Just pick any large IMG of your choice. You should find an inexplicably wide frame around and image that has squeezed - height-wise - onto the green carpet.
If you specify the image's width or height as a percentage, that percentage is calculated in proportion to the size of the parent block. So specifying width: 50% on the image doesn't mean 50% of the original image width -- it means 50% of the width of the parent block. The same goes for the height. Thus, there will always be extra space around the image as long as you specify the width or height as a percentage.
The solution is simple -- specify the dimensions in pixels, ems or any other unit other than a percentage:
HTML
<div class="wrapper">
<img class="small" src="myimage.jpg">
</div>
CSS
img.small {
width: 150px; /* or whatever you like */
display: block; /* to avoid empty space below the image */
}
div.wrapper {
display: inline-block;
border: 1px solid #000;
}
Edit: Based on your comments and updated post, I understand that what you really want to do is to set the width of the surrounding div and make the image fill up that div. Here's an example that does that:
HTML
<div class="wrapper big">
<img src="myimage.jpg">
</div>
<div class="wrapper small">
<img src="myimage.jpg">
</div>
CSS
img {
display: block;
width: 100%;
}
.wrapper {
margin-top: 1em;
border: 1px solid #000;
}
.big {
width: 600px;
}
.small {
width: 300px;
}
So I go height="50%", say, and width="auto" (to maintain AR).
Why not just go width="50%" too as this would resolve it.
I think Pär's approach is right: don't do { height: fix; width: auto; } but do instead { height: auto; width: fix; } Works better.