Is there any protocol for reverse traceroute? [closed] - networking

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Say i'm communicating with a computer A in a remote network .
Is it possible to know what are the hops that he is going through?
In other word, is it possible to detect what is computer A route to my computer?
I know that A might have a various routes to my computer , it just want to find a route. My whole problem begins with that fact that some networks "hides" there inside computer ( like NAT ) and just give you the gateway ip.
(I'm not talking about my route to his computer that can be easly achived by traceroute)
thanks!

The IP option Record Route asks routers along the way to include their address in the datagram so the route can be tracked. The trick is, many routers and firewalls are not keen on giving out this information and DROP packets with this option set. And, you'd have to get the remote peer to set the flag, so it would only be useful if you're in control of the software on the remote peer too.

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Implication of lack of default gateway [closed]

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I am studying networking and operating systems and I stumbled upon this statement:
If there is no default gateway in the routing table we can't transfer packets to all the addresses.
I am asking whether the above statement is correct?
Yes the statement is true. Here is the definition from wikipedia
A default gateway in computer networking is the node that is assumed
to know how to forward packets on to other networks. Typically, in a
TCP/IP network, nodes such as servers, workstations and network
devices each have a defined default route setting, (pointing to the
default gateway), defining where to send packets for IP addresses for
which they can determine no specific route.
A routing table can not store information of all the possible routes to which the computer may connect. So it needs a default mechanism to send traffic to computers for which no known path exists. The way is to route all such packets to default gateway.

Finding a specific computer from an IP address on a network [closed]

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I'm having trouble with my network at work.
We have a LOT of computers on our network and one of them is causing me problems.
I'm rendering from 3ds Max via Backburner and I can see that there is a another manager distributing jobs.
I can see the IP adress of the computer (198.162.1.61), I just don't know where it is or what it's called.
Is there any way to get a specefic computers information if I only know its IP address?
Consult the ARP table. Then you'll get the MAC address, this you can match with the vendor via:
http://www.adminsub.net/mac-address-finder
command:
arp -a
use the following command to see the name of the computer:
nbtstat –a <ipaddress>
if you are lucky, you can also gather information via scans (ex program: autoscan, nmap, ...)

Would a custom IP-based protocol work? [closed]

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Let's say somebody invented a new protocol I would put on top of IP. Would two computers from the other ends of the world be able to communicate with it, i.e. would routers forward the frames that aren't standard TCP/UDP/ICMP?
Yes, if it is build on top of IP then it would be routable over the internet. The IP protocol defines the header and payload. The header is used for routing. So you would be able to send custom IP-based protocol data from one computer to another over the internet.
However, both computers will need custom drivers to send, receive and understand the data.
I'm not sure why you'd bother though. If you're sending custom data, you're much better off writing an application level protocol on top of tcp or udp and take advantage of the networking layer built into all computers and operating systems already. It'll be easier to write, maintain, and debug.

Programatically change ip address of DSL connection [closed]

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I'm working on a project for my company. I'm using a DSL connection. My IP address changes every time I restart my router. Is there a faster way to request a new IP from my ISP programatically? I've seen that RDSL services can change the IP in a few seconds, but I'm looking for a more "legal" way to do this other than RDSL.
Thank you!
Does your router have firmware you can browse to? There may be a link to reboot your router (or even release/renew your IP lease) there. You can set up a cron job to call cURL to access that URL every so often. You might also have to authenticate in order to do that, but cURL should handle that.
If you're on a system that does not have cURL or cron, you may have equivalents, but they're pretty simple programs and you should be able to find them for any popular OS.

Doubling Internet Connection Speed [closed]

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Scenario: I have two ADSL modem that are connected to to different ISPs. Each has 256KBps Speed.
Question:Is it possible to have 512KBps speed?(I have one PC that can be host any OS)
Is any special appliance essential for doing that?
Thanks in Advance,
Ashkan.
This is called multihoming or load-balancing.
The simplest way to do this would be to buy a router with two WAN ports that supports load balancing. These are generally expensive.
Alternatively you can set up a computer with 3 network interfaces to do the routing for you.
Windows
Using regedit navigate to
HKEY_LOCAL_MACHINE\SYSTEM\CurrentControlSet\services\NetBT\Parameters
Create 32-bit dword value "RandomAdapter" with a value of 1
You will need to set the "metric" value of the different adapters if you find traffic is still favouring one connection over the other.
From my answer on serverfault, the
"route" command is used to set this metric. The basic syntax is;
route ADD <destination> <subnet mask> <gateway (vpn dhcp server)> <metrix> IF <interface number> -p
There's some tutorials floating around here and there.
Linux
See the answers on serverfault
RJFalconer is right, but you should know that if you do this, no single TCP connection will be able to get more than 256kBps. It's much like SMP in that manner.
You may also run into trouble with (web) applications and protocols that assume every user has a single IP address at any one time. If you can replace the two connections with a single faster one, that would be vastly preferable.

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