SELECT COUNT (DISTINCT S.PK_Submission)
FROM Fact_Submission FS, Submission S
WHERE
FS.FK_Submission = S.PK_Submission
AND FS.FK_Submission_Date >= 20100101
AND FS.FK_Submission_Date <= 20101231
I've tried this:
SELECT
{[Measures].[Fact Submission Count]} ON AXIS(0),
Distinct({[Submission].[PK Submission] }) ON AXIS(1)
FROM [Submission]
WHERE
([Date].[Calendar Year].[2010])
but the result is the same
any idea how to write this in MDX? I'm pretty new at this so still haven't figured it out.
This is correct answer:
WITH SET MySet AS
{[Measures].[Fact Submission Count]}
*
DISTINCT({ EXCEPT([Submission].[PK Submission].Members, [Submission].[PK Submission].[All]) })
MEMBER MEASURES.DistinctSubmissionCount AS
DISTINCTCOUNT(MySet)
SELECT {MEASURES.DistinctSubmissionCount} ON 0
FROM [Submission]
WHERE
([Date].[Calendar Year].[2010])
I have excluded "All" row because it's also being counted by COUNT function so I always had +1.
Related
I have a table with order information. It is broken down by OrderID, Item Name. How can I get the count of all orders with multiple x and y items. For example, how many orders have more than 1 dumplings and more than 1 water?
You can use the Countif function like:
countIf (
Revenue,
# Conditions
CalendarDay >= ${BasePeriodStartDate} AND
CalendarDay <= ${BasePeriodEndDate} AND
SourcingType <> 'Indirect'
)
Documentation
select
concat(fullvisitorid,cast(visitid as string)) as unique_session_id
,case
when h.item.productSku is not null then h.hitNumber
else max(h.hitnumber)
end
,h.item.transactionid
,h.item.itemrevenue/pow(10,6)
,h.item.productSku
from `myproject.mydataset.ga_sessions_20180101`, unnest(hits) as h
group by 1
Looking at case statement above (line 3)
How do I return that hitnumber where the productsku is populated
otherwise return the max hitnumber and then group this by the unique_session_id?
How to filter out transactionid's that contain '_ABC' at the same time?
I would suggest doing the grouping and finding the max hit number in a subquery. If you are going to use an aggregate function like MAX() in the select clause, then you need to group on or have aggregate functions for the other fields in the select. It can be useful to do aggregate sub-queries using common table expressions.
WITH data AS (
SELECT
CONCAT(fullvisitorid, CAST(visitid AS string)) AS unique_session_id,
h.hitNumber,
h.item.transactionid,
h.item.itemrevenue/POW(10,6) AS itemRevenue,
h.item.productSku
FROM
`bigquery-public-data.google_analytics_sample.ga_sessions_20170801`,
UNNEST(hits) AS h
),
max_hits AS (
SELECT
unique_session_id,
MAX(hitNumber) AS max_hit_number
FROM data
GROUP BY 1
)
SELECT
d.unique_session_id,
CASE
WHEN d.productSku IS NOT NULL THEN d.hitNumber
ELSE m.max_hit_number
END,
d.transactionid,
d.itemrevenue,
d.productSku
FROM
data AS d JOIN max_hits AS m
ON d.unique_session_id = m.unique_session_id
I've got a SQL statement that does what I need, but I'm having trouble converting it into the correlated Peewee statement. Here's the SQL I have now, note that I'm using a subquery right now, but I don't care that it's a subquery either way.
select t.name,
count(a.type_id) as total,
(
select count(id)
from assignment a
where a.course_id = 7
and a.due_date < date()
and a.type_id = t.id
group by a.type_id
order by a.type_id
) as completed
from assignment a
inner join type t on t.id = a.type_id
where a.course_id = 7
group by a.type_id
order by a.type_id
Here's the closest I've come to the Peewee statement. Currently I'm aliasing a static number in the query just so that I have a value to work with in my template, so please ignore that part.
Assignment.select(
Type.name,
fn.Lower('1').alias('completed'),
fn.Count(Type.id).alias('total'),
).naive().join(Type).where(
Assignment.course==self,
).group_by(Type.id).order_by(Type.id)
Have you tried just including the subquery as part of the select?
Something like this?
query = (Assignment
.select(
Type.name,
fn.COUNT(Type.id).alias('total'),
Assignment.select(fn.COUNT(Assignment.id)).where(
(Assignment.due_date < fn.DATE()) &
(Assignment.course == 7) &
(Assignment.type == Type.id)
).group_by(Assignment.type).alias('completed'))
.join(Type)
.where(Assignment.course == 7)
.group_by(Type.name))
How can I get a single row result (e.g. in form of a table/array) back from a sql statement. Using Lua Sqlite (LuaSQLite3). For example this one:
SELECT * FROM sqlite_master WHERE name ='myTable';
So far I note:
using "nrows"/"rows" it gives an iterator back
using "exec" it doesn't seem to give a result back(?)
Specific questions are then:
Q1 - How to get a single row (say first row) result back?
Q2 - How to get row count? (e.g. num_rows_returned = db:XXXX(sql))
In order to get a single row use the db:first_row method. Like so.
row = db:first_row("SELECT `id` FROM `table`")
print(row.id)
In order to get the row count use the SQL COUNT statement. Like so.
row = db:first_row("SELECT COUNT(`id`) AS count FROM `table`")
print(row.count)
EDIT: Ah, sorry for that. Here are some methods that should work.
You can also use db:nrows. Like so.
rows = db:nrows("SELECT `id` FROM `table`")
row = rows[1]
print(row.id)
We can also modify this to get the number of rows.
rows = db:nrows("SELECT COUNT(`id`) AS count FROM `table`")
row = rows[1]
print(row.count)
Here is a demo of getting the returned count:
> require "lsqlite3"
> db = sqlite3.open":memory:"
> db:exec "create table foo (x,y,z);"
> for x in db:urows "select count(*) from foo" do print(x) end
0
> db:exec "insert into foo values (10,11,12);"
> for x in db:urows "select count(*) from foo" do print(x) end
1
>
Just loop over the iterator you get back from the rows or whichever function you use. Except you put a break at the end, so you only iterate once.
Getting the count is all about using SQL. You compute it with the SELECT statement:
SELECT count(*) FROM ...
This will return one row containing a single value: the number of rows in the query.
This is similar to what I'm using in my project and works well for me.
local query = "SELECT content FROM playerData WHERE name = 'myTable' LIMIT 1"
local queryResultTable = {}
local queryFunction = function(userData, numberOfColumns, columnValues, columnTitles)
for i = 1, numberOfColumns do
queryResultTable[columnTitles[i]] = columnValues[i]
end
end
db:exec(query, queryFunction)
for k,v in pairs(queryResultTable) do
print(k,v)
end
You can even concatenate values into the query to place inside a generic method/function.
local query = "SELECT * FROM ZQuestionTable WHERE ConceptNumber = "..conceptNumber.." AND QuestionNumber = "..questionNumber.." LIMIT 1"
I have to implement a solution where two date ranges can overlap each other. within the overlapped dates, I have to count how many days overlap each other. Once I know the overlapped days I can calculate a total figure based on the price that's attached per day.
A scenario would be that
A customer is booking a hotel
Customer booking dates - 17/02/2011 to 26/02/2011
Normal price (All year) - 01/01/2011 - 31/12/2011 (price per day :$30.00)
Special Offer 1 dates - 01/01/2011 to 19/02/2011 (price per day :$20.00)
Special Offer 2 dates - 17/02/2011 to 24/02/2011 (price per day :$10.00)
In the above scenario, the proposed algorithm should work out the cheapest offer that the date ranges overlap and work out the price for the booking. If there is no special offer available it uses the normal price.
So for the first two days the system should get the price from "special offer 1" as it's the cheapest available price. Next 5 days should be "Special offer 2 price" and for the next 2 days it'll be normal price.
I'd be grateful to see both SQL(using MS-SQL Server) or Code base answers to get the diffrenet views.
I hope the question is clear and looking foward to see the answers.
Many thanks in advance
Using the standard trick of using an auxiliary calendar table, it is simply a case of joins and grouping to get the best price each day:
SELECT C.dt, MIN(price) AS best_price
FROM Prices P
INNER JOIN Calendar C
ON C.dt >= P.price_start_date
AND C.dt < P.price_end_date
INNER JOIN CustomerBooking B
ON C.dt >= B.booking_start_date
AND C.dt < B.booking_end_date
GROUP
BY C.dt;
The same query as above, including sample data using CTEs:
WITH Prices (price_start_date, price_end_date, narrative, price)
AS
(
SELECT CAST(start_date AS Date), CAST(end_date AS Date), narrative, price
FROM (
VALUES ('2011-01-01T00:00:00', '2011-12-31T00:00:00', 'Normal price', 30),
('2011-01-01T00:00:00', '2011-02-21T00:00:00', 'Special Offer 1', 20),
('2011-02-19T00:00:00', '2011-02-24T00:00:00', 'Special Offer 2', 10)
) AS T (start_date, end_date, narrative, price)
),
CustomerBooking (booking_start_date, booking_end_date)
AS
(
SELECT CAST(start_date AS Date), CAST(end_date AS Date)
FROM (
VALUES ('2011-02-17T00:00:00', '2011-02-26T00:00:00')
) AS T (start_date, end_date)
)
SELECT C.dt, MIN(price) AS best_price
FROM Prices P
INNER JOIN Calendar C
ON C.dt >= P.price_start_date
AND C.dt < P.price_end_date
INNER JOIN CustomerBooking B
ON C.dt >= B.booking_start_date
AND C.dt < B.booking_end_date
GROUP
BY C.dt;
Let's supose that for each day you should apply lowest price.
create function price ( #fromDate date, #toDate date) returns money
as
begin
declare #iterator_day date
declare #total money
set #total = 0
set #iterator_day = #fromDate
WHILE #iterator_day < = #toDate
begin
select #total = #total + min( price )
from offers
where #iterator_day between offers.fromFay and offers.toDay
set #iterator_day = DATEADD (day , 1 , #iterator_day )
end
return #total
end
then you can call function in your query:
select
b.fromDay, b.toDay, dbo.price( b.fromDay, b.toDay )
from
booking b
I've only used ASP.net 4.0, but I can offer some SQL will give you the price for a given date:
SELECT ISNULL(MIN(PricePerDay), 0) AS MinPricePerDay
FROM Offers
WHERE (StartDate <= '18/2/11') AND (EndDate >= '18/2/11')
From your application you could build the query to be something like this:
SELECT ISNULL(MIN(PricePerDay), 0) AS MinPricePerDay
FROM Offers
WHERE (StartDate <= '17/2/11') AND (EndDate >= '17/2/11');
SELECT ISNULL(MIN(PricePerDay), 0) AS MinPricePerDay
FROM Offers
WHERE (StartDate <= '18/2/11') AND (EndDate >= '18/2/11');
SELECT ISNULL(MIN(PricePerDay), 0) AS MinPricePerDay
FROM Offers
WHERE (StartDate <= '19/2/11') AND (EndDate >= '19/2/11');
This would return a dataset of tables containing a single value for the minimum price for that date (in the same order as your query)
Sounds like a good job for a Stored Procedure...
Your problem here is that you're got multiple overlapping time periods. You either need to constrain the problem slightly, or remodel the data slightly. (To get desirable performance.)
Option 1 - Constraints
A data set of 'normal' prices - that never overlap with each other
A data set of 'special' prices - that also never overlap with each other
Every bookable date has a 'normal' price
Every bookable date has a 'special' price (EVEN if it's NULL to mean 'no special price')
The last constraint is the strangest one. But it's needed to make the simple join work. When comparing date ranges, it's alot easier to form the query if the two sets of ranges are gapless and have no overlaps inside them.
This means that you should now be able to work it out with just a few joins...
SELECT
CASE WHEN [sp].started > [np].started THEN [sp].started ELSE [np].started END AS [started]
CASE WHEN [sp].expired < [np].expired THEN [sp].expired ELSE [np].expired END AS [expired]
CASE WHEN [sp].price < [np].price THEN [sp].price ELSE [np].price END AS [price]
FROM
normal_prices AS [np]
LEFT JOIN
special_prices AS [sp]
ON [sp].started < [np].expired
AND [sp].expired > [np].started
AND [sp].started >= (SELECT ISNULL(MAX(started),0) FROM special_prices WHERE started <= [np].started)
-- The third condition is an optimisation for large data-sets.
WHERE
[np].started < #expired
AND [np].expired > #started
-- Note: Inclusive StartDates, Exlusive EndDate
-- For example, "all of Jan" would be "2011-01-01" to "2011-02-01"
Option 2 - Re-Model
This one is often the fastest in my experience; you increase the amount of space being used, and gain a simpler faster query...
Table Of Prices, stored by DAY rather than period...
- calendar_date
- price_code
- price
SELECT
calendar_date,
MIN(price)
FROM
prices
WHERE
calendar_date >= #started
AND calendar_date < #expired
Or, if you needed the price_code as well...
WITH
ordered_prices AS
(
SELECT
ROW_NUMBER() OVER (PARTITION BY calendar_date ORDER BY price ASC, price_code) AS price_rank,
*
FROM
prices
)
SELECT
calendar_date,
price_code,
price
FROM
ordered_prices
WHERE
calendar_date >= #started
AND calendar_date < #expired