How to override a CSS class - css

I have a webpage that is generated by Drupal and it comes with a certain stylesheet attached to it.
I would like to override one of the styles. It is set with a class like this:
<div class="description"></div>
So instead of using the ".description" style that comes with the Drupal CSS, I would like the page to use my ".description" style. In other words - if the page has 2 ".description" styles, how do I tell the page to use mine?

Use a selector with higher specificity:
div.description {
/* will take precedence over just .description */
}
Place your stylesheet after the one you want to override:
/* Drupal's style */
.description {
foo: bar;
}
/* Your style */
.description {
foo: baz; /* takes precedence over foo: bar */
}
Do not use !important. Just don't.
See also CSS 3: Calculating Selector Specificity.

Related

How I exclude more than one element with CSS selector group? [duplicate]

I'm trying to select input elements of all types except radio and checkbox.
Many people have shown that you can put multiple arguments in :not, but using type doesn't seem to work anyway I try it.
form input:not([type="radio"], [type="checkbox"]) {
/* css here */
}
Any ideas?
Why :not just use two :not:
input:not([type="radio"]):not([type="checkbox"])
Yes, it is intentional
If you're using SASS in your project, I've built this mixin to make it work the way we all want it to:
#mixin not($ignorList...) {
//if only a single value given
#if (length($ignorList) == 1){
//it is probably a list variable so set ignore list to the variable
$ignorList: nth($ignorList,1);
}
//set up an empty $notOutput variable
$notOutput: '';
//for each item in the list
#each $not in $ignorList {
//generate a :not([ignored_item]) segment for each item in the ignore list and put them back to back
$notOutput: $notOutput + ':not(#{$not})';
}
//output the full :not() rule including all ignored items
&#{$notOutput} {
#content;
}
}
it can be used in 2 ways:
Option 1: list the ignored items inline
input {
/*non-ignored styling goes here*/
#include not('[type="radio"]','[type="checkbox"]'){
/*ignored styling goes here*/
}
}
Option 2: list the ignored items in a variable first
$ignoredItems:
'[type="radio"]',
'[type="checkbox"]'
;
input {
/*non-ignored styling goes here*/
#include not($ignoredItems){
/*ignored styling goes here*/
}
}
Outputted CSS for either option
input {
/*non-ignored styling goes here*/
}
input:not([type="radio"]):not([type="checkbox"]) {
/*ignored styling goes here*/
}
Starting from CSS Selectors 4 using multiple arguments in the :not selector becomes possible (see here).
In CSS3, the :not selector only allows 1 selector as an argument. In level 4 selectors, it can take a selector list as an argument.
Example:
/* In this example, all p elements will be red, except for
the first child and the ones with the class special. */
p:not(:first-child, .special) {
color: red;
}
Unfortunately, browser support is somewhat new.
I was having some trouble with this, and the "X:not():not()" method wasn't working for me.
I ended up resorting to this strategy:
INPUT {
/* styles */
}
INPUT[type="radio"], INPUT[type="checkbox"] {
/* styles that reset previous styles */
}
It's not nearly as fun, but it worked for me when :not() was being pugnacious. It's not ideal, but it's solid.
If you install the "cssnext" Post CSS plugin, then you can safely start using the syntax that you want to use right now.
Using cssnext will turn this:
input:not([type="radio"], [type="checkbox"]) {
/* css here */
}
Into this:
input:not([type="radio"]):not([type="checkbox"]) {
/* css here */
}
https://cssnext.github.io/features/#not-pseudo-class

CSS Modules & ReactJS: Parent and child CSS classes in different components

So I am building a react application and have a quick question. If I have two separate components:
and
with CSS classes navigation.css and navigationLogo.css respectively. In navigation.css I have a class named .main and in navigationLogo.css I want to have a class like so:
.main .main_in_logo {
color: red;
}
But with CSS Modules I am unable to do this, any ideas on a work around?
I just feel that the explanations here are not complete enough. In css you do .parentSelector .childSelector in order to select the child. The same rule is for css modules, but in your html/jsx you should add to the parent and the child the relevant className -> styles.parentSelector , styles.childSelector.
<div className={styles.container}>text</div>
This way you can have in your css something like:
.banner .container{
background-color:reb;
}
.banner .container{
background-color:blue;
}
Sometimes you use libraries and you want to change something somewhere down the DOM inside the library and you can't change its source code. In this case you can use the :global like this:
.parentElement :global(div)
.parentElement :global(#some-lib-element-selector)
I was looking for the same problem and didn't find the solution here, maybe because the post is 3 years old. The accepted answer is, in my opinion but not mine only, not scalable.
I don't really know if this is something new, but I found out what I would do in vanilla CSS adapted to CSS modules.
Here is what I did and fully suits my needs:
/* parent.css */
.main {
...some CSS...
}
/* logo.css */
#value main from "./parent.css";
.logo {
...some CSS...
}
.main .logo {
color: red
}
Here, we are using #value, which is a CSS modules variable and allows us to bind with another file to build a selector including the final name of the parent "main".
As strange as it looks to me, it took some time to find out about this solution, I hope this will save some time and help other people!
Why you need to create .main .main_in_logo - the main idea of styles with parent elements its not to broke your css with other styles in the future. But its impossible with css modules, because your styles will be unique forever.
But even you really need it you can use global css for these 2 components - documentation about global css for react-css-modules.
The child component should not have a css rule that is dependent upon the parent css classname.
the child should just be:
.main_in_logo { color: red; }
If you need to define styles that involve both parent and child, then the easiest way is to define the styles completely in the parent:
/* navigation.css */
.main .main_in_logo {
color: red;
}
Then have the parent pass the css class to the child and tell the child to use it:
// Navigation.js
<NavigationLogo className={navigationCss.main_in_logo} />
// NavigationLogo.js
<div className={"foo " + this.props.className}>stuff</div>
You don't need to be specify which child class you are referring to when using CSS modules in ReactjS.
so doing:
.main_in_logo {
color: red;
}
will be enough in the stylesheet.
I ended up using CSS the normal way but with BEM convention.
I mean after all, what the CSS modules do is adding the [this_name].module.css to your css classes anyway. If you typed it correctly in the first place, there's no need of using this. It's just a new abstract that allow newbies so they can just do stuff without having to worry about class names clashing.
// Main.jsx
import './Main.css'
import Logo from './Logo.jsx'
const Main = () => {
return (
<div className="main">
<Logo className="main__logo" />
</div>
)
}
/* Main.css */
.main {/* do magic */}
.main__logo {/* do magic but for Logo component */}
So maybe you had Logo component like this..
// Logo.jsx
import './Logo.css'
const Logo = () => {
return (
<div className="logo">
<img className="logo__img" />
</div>
)
}
/* Logo.css */
.logo {/* do magic for logo */}
.logo__img {/* do magic for logo's image */}
This feels much more natural.

Inherit attributes from another object in css

I have a class in my css called .btn:
.btn {
//stuff here
}
and I am going to create another class, lets say .btn2. I want to be able to inherit the characteristics from .btn into btn2, as I only want to change the color of button 2. Is there a way in CSS for this? Or should I just copy and paste the original stuff into the new class?
I'd suggest:
/* comma-separated selectors: */
.btn,
.btn2 {
/* shared properties */
}
.btn2 {
/* properties unique to btn2 */
}
JS Fiddle demo.
You can do it with dynamic stylesheets. Check out LESS or SASS.
EDIT:
Some additional info at a commenter's request. Here are the official sites. They both have examples on their home pages.
http://lesscss.org/
http://sass-lang.com/
What you can do is this
.btn, .btn2 {
/* Styles goes here */
}
This way, both the classes will share common properties defined in the rule block.
As far as the inheritance goes, something you would like to have..
.btn2 {
.btn; /* Won't work in pure CSS */
}
Won't work in pure CSS, you need to take a look at SASS or LESS

Every h2 except for ones that don't have a class?

I'm wondering how can I apply a style to EVERY h2 that DOES have ANY any class attached to it, thus having the effect that the style will NOT be applied on a plain h2..eg..
<h2 class="1"></h2>
<h2 class="2"></h2>
<h2 class="3"></h2>
<h2 class="a"></h2>
<h2></h2>
All the ones with a class should have a style - and just plain h2 should not, (This is a huge site with hundreds of styles)...so any easy way to do this?
There is a method to do it but it's only possible with browsers that support CSS3 :not pseudo class.
h2[class] {
/* Styles for <h2> with a class, regardless of the value */
}
h2:not([class]) {
/* Styles for <h2> without classes */
}
I hope it works!
[Edit] I've made a simple demo for you here - http://jsfiddle.net/fL2sT/
What you're asking for is how CSS works by default.
The correct way to style elements which have no specific class assigned to them is to style the base element, as Ahsan demonstrated above. I don't know why he got downvoted.
h2 { property: value; }
Note that if H2 elements do have classes assigned to them, then that styling may override your base style.
So if you have: h2 { color:#333; font-size:2em; } as your base style, and then apply class="myClass" to it where: .class { color: #000; }, then the base style's color will be overriden (but not the font size). This is the cascade in Cascading Style Sheets.
Another way is to target them conditionally:
div#nav h2:first-child { property:value; }
which gives you contextual control, but again, class assignment will always override base styling, and may also override context targeting if the class application has higher specificity.
Why not simply use
h2[class] { ... }

Can the :not() pseudo-class have multiple arguments?

I'm trying to select input elements of all types except radio and checkbox.
Many people have shown that you can put multiple arguments in :not, but using type doesn't seem to work anyway I try it.
form input:not([type="radio"], [type="checkbox"]) {
/* css here */
}
Any ideas?
Why :not just use two :not:
input:not([type="radio"]):not([type="checkbox"])
Yes, it is intentional
If you're using SASS in your project, I've built this mixin to make it work the way we all want it to:
#mixin not($ignorList...) {
//if only a single value given
#if (length($ignorList) == 1){
//it is probably a list variable so set ignore list to the variable
$ignorList: nth($ignorList,1);
}
//set up an empty $notOutput variable
$notOutput: '';
//for each item in the list
#each $not in $ignorList {
//generate a :not([ignored_item]) segment for each item in the ignore list and put them back to back
$notOutput: $notOutput + ':not(#{$not})';
}
//output the full :not() rule including all ignored items
&#{$notOutput} {
#content;
}
}
it can be used in 2 ways:
Option 1: list the ignored items inline
input {
/*non-ignored styling goes here*/
#include not('[type="radio"]','[type="checkbox"]'){
/*ignored styling goes here*/
}
}
Option 2: list the ignored items in a variable first
$ignoredItems:
'[type="radio"]',
'[type="checkbox"]'
;
input {
/*non-ignored styling goes here*/
#include not($ignoredItems){
/*ignored styling goes here*/
}
}
Outputted CSS for either option
input {
/*non-ignored styling goes here*/
}
input:not([type="radio"]):not([type="checkbox"]) {
/*ignored styling goes here*/
}
Starting from CSS Selectors 4 using multiple arguments in the :not selector becomes possible (see here).
In CSS3, the :not selector only allows 1 selector as an argument. In level 4 selectors, it can take a selector list as an argument.
Example:
/* In this example, all p elements will be red, except for
the first child and the ones with the class special. */
p:not(:first-child, .special) {
color: red;
}
Unfortunately, browser support is somewhat new.
I was having some trouble with this, and the "X:not():not()" method wasn't working for me.
I ended up resorting to this strategy:
INPUT {
/* styles */
}
INPUT[type="radio"], INPUT[type="checkbox"] {
/* styles that reset previous styles */
}
It's not nearly as fun, but it worked for me when :not() was being pugnacious. It's not ideal, but it's solid.
If you install the "cssnext" Post CSS plugin, then you can safely start using the syntax that you want to use right now.
Using cssnext will turn this:
input:not([type="radio"], [type="checkbox"]) {
/* css here */
}
Into this:
input:not([type="radio"]):not([type="checkbox"]) {
/* css here */
}
https://cssnext.github.io/features/#not-pseudo-class

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