I'm trying to replace a placeholder string inside a selection of 10 random records with a random string (a name) taken from another table, using only sqlite statements.
i've done a subquery in order to replace() of the placeholder with the results of a subquery. I thought that each subquery loaded a random name from the names table, but i've found that it's not the case and each placeholder is replaced with the same string.
select id, (replace (snippet, "%NAME%", (select
name from names
where gender = "male"
) )
) as snippet
from imagedata
where timestamp is not NULL
order by random()
limit 10
I was expecting for each row of the SELECT to have different random replacement every time the subquery is invoked.
hello i'm %NAME% and this is my house
This is the car of %NAME%, let me know what you think
instead each row has the same kind of replacement:
hello i'm david and this is my house
This is the car of david, let me know what you think
and so on...
I'm not sure it can be done inside sqlite or if i have to do it in php over two different database queries.
Thanks in advance!
Seems that random() in the subquery is only evaluated once.
Try this:
select
i.id,
replace(i.snippet, '%NAME%', n.name) snippet
from (
select
id,
snippet,
abs(random()) % (select count(*) from names where gender = 'male') + 1 num
from imagedata
where timestamp is not NULL
order by random() limit 10
) i inner join (
select
n.name,
(select count(*) from names where name < n.name and gender = 'male') + 1 num
from names n
where gender = 'male'
) n on n.num = i.num
I'm trying to use DB Browser for SQLite to construct a nested query to determine the SECOND highest priced item purchased by the top 10 spenders. The query I have to pick out the top 10 spenders is:
SELECT user_id, max(item_total), SUM (item_total + shipping_cost -
discounts_applied) AS total_spent
FROM orders AS o
WHERE payment_reject = "FALSE"
GROUP BY user_id
ORDER BY total_spent DESC
LIMIT 10
This gives the user_id, most expensive item they purchased (not counting shipping or discounts) as well as the total amount they spent on the site.
I was trying to use a nested query to generate a list of the second most expensive items they purchased, but keep getting errors. I've tried
SELECT user_id, MAX(item_total) AS second_highest
FROM orders
WHERE item_total < (SELECT user_id, SUM (item_total + shipping_cost -
discounts_applied) AS total_spent
FROM orders
WHERE payment_reject = "FALSE"
GROUP BY user_id
ORDER BY total_spent DESC
LIMIT 10)
group by user_id
I keep getting a row value misused error. Does anyone have pointers on this nested query or know of another way to find the second highest item purchased from within the group found in the first query?
Thanks!
(Note: The following assumes you're using Sqlite 3.25 or newer since it uses window functions).
This will return the second-largest item_total for each user_id without duplicates:
WITH ranked AS
(SELECT DISTINCT user_id, item_total
, dense_rank() OVER (PARTITION BY user_id ORDER BY item_total DESC) AS ranking
FROM orders)
SELECT user_id, item_total FROM ranked WHERE ranking = 2;
You can combine it with your original query with something like:
WITH ranked AS
(SELECT DISTINCT user_id, item_total
, dense_rank() OVER (PARTITION BY user_id ORDER BY item_total DESC) AS ranking
FROM orders),
totals AS
(SELECT user_id
, sum (item_total + shipping_cost - discounts_applied) AS total_spent
FROM orders
WHERE payment_reject = 0
GROUP BY user_id)
SELECT t.user_id, r.item_total, t.total_spent
FROM totals AS t
JOIN ranked AS r ON t.user_id = r.user_id
WHERE r.ranking = 2
ORDER BY t.total_spent DESC, t.user_id
LIMIT 10;
Okay, after fixing your table definition to better reflect the values being stored in it and the stated problem, and fixing the data and adding to it so you can actually get results, plus an optional but useful index like so:
CREATE TABLE orders (order_id INTEGER PRIMARY KEY
, user_id INTEGER
, item_total REAL
, shipping_cost NUMERIC
, discounts_applied NUMERIC
, payment_reject INTEGER);
INSERT INTO orders(user_id, item_total, shipping_cost, discounts_applied
, payment_reject) VALUES (9852,60.69,10,0,FALSE),
(2784,123.91,15,0,FALSE), (1619,119.75,15,0,FALSE), (9725,151.92,15,0,FALSE),
(8892,153.27,15,0,FALSE), (7105,156.86,25,0,FALSE), (4345,136.09,15,0,FALSE),
(7779,134.93,15,0,FALSE), (3874,157.27,15,0,FALSE), (5102,108.3,10,0,FALSE),
(3098,59.97,10,0,FALSE), (6584,124.92,15,0,FALSE), (5136,111.06,10,0,FALSE),
(1869,113.44,20,0,FALSE), (3830,129.63,15,0,FALSE), (9852,70.69,10,0,FALSE),
(2784,134.91,15,0,FALSE), (1619,129.75,15,0,FALSE), (9725,161.92,15,0,FALSE),
(8892,163.27,15,0,FALSE), (7105,166.86,25,0,FALSE), (4345,146.09,15,0,FALSE),
(7779,144.93,15,0,FALSE), (3874,167.27,15,0,FALSE), (5102,118.3,10,0,FALSE),
(3098,69.97,10,0,FALSE), (6584,134.92,15,0,FALSE), (5136,121.06,10,0,FALSE),
(1869,123.44,20,0,FALSE), (3830,139.63,15,0,FALSE);
CREATE INDEX orders_idx_1 ON orders(user_id, item_total DESC);
the above query will give:
user_id item_total total_spent
---------- ---------- -----------
7105 156.86 373.72
3874 157.27 354.54
8892 153.27 346.54
9725 151.92 343.84
4345 136.09 312.18
7779 134.93 309.86
3830 129.63 299.26
6584 124.92 289.84
2784 123.91 288.82
1619 119.75 279.5
(If you get a syntax error from the query now, it's because you're using an old version of sqlite that doesn't support window functions.)
I have:
TABLE MESSAGES
message_id | conversation_id | from_user | timestamp | message
I want:
1. SELECT * WHERE from_user <> id
2. GROUP BY conversation_id
3. SELECT in every group row with MAX(timestamp) **(if there are two same timestamps in a group use second factor as highest message_id)** !!!
4. then results SORT BY timestamp
to have result:
2|145|xxx|10000|message
6|1743|yyy|999|message
7|14|bbb|899|message
with eliminated
1|145|xxx|10000|message <- has same timestamp(10000) as message(2) belongs to the same conversation(145) but message id is lowest
5|1743|me|1200|message <- has message_from == me
example group with same timestamp
i want from this group row 3 but i get row 2 from query
SELECT max(message_timestamp), message_id, message_text, message_conversationId
FROM MESSAGES
WHERE message_from <> 'me'
GROUP BY message_conversationId
ORDER by message_Timestamp DESC
what is on my mind to do union from message_id & timestamp and then get max???
Your query is based on non-standard use of GROUP BY (I think SQLite allows that only for compatibility with MySQL) and I'm not at all sure that it will produce determinate results all the time.
Plus it uses MAX() on concatenated columns. Unless you somehow ensure that the two (concatenated) columns have fixed widths, the results will not be accurate for that reason as well.
I would write the query like this:
SELECT
m.message_timestamp,
m.message_id,
m.message_text,
m.message_conversationId
FROM
( SELECT message_conversationId -- for every conversation
FROM messages as m
WHERE message_from <> 'me'
GROUP BY message_conversationId
) AS mc
JOIN
messages AS m -- join to the messages
ON m.message_id =
( SELECT mi.message_id -- and find one message id
FROM messages AS mi
WHERE mi.message_conversationId -- for that conversation
= mc.message_conversationId
AND mi.message_from <> 'me'
ORDER BY mi.message_timestamp DESC, -- according to the
mi.message_id DESC -- specified order
LIMIT 1 -- (this is the one part)
) ;
Try below sql to achieve your purpose by group by twice.
select m.*
from
Messages m
-- 3. and then joining to get wanted output columns
inner join
(
--2. then selecting from this max timestamp - and removing duplicates
select conversation_id, max(timestamp), message_id
from
(
-- 1. first select max message_id in remainings after the removal of duplicates from mix of cv_id & timestamp
select conversation_id, timestamp, max(message_id) message_id
from Messages
where message <> 'me'
group by conversation_id, timestamp
) max_mid
group by conversation_id
) max_mid_ts on max_mid_ts.message_id = m.message_id
order by m.message_id;
http://goo.gl/MyZjyU
ok it was more simple than I thought:
basically to change select from:
max(message_timestamp)
to:
max(message_timestamp || message_id)
or max(message_timestamp + message_id)
so it will search for max on concatenation of timestamp and message_id
ps. after a digging - it's working only if message id is growing with timestamp ( order of insertion is preserved )
edit:
edit2 :
so why it works ?
SELECT max(message_timestamp+message_id), message_timestamp, message_id, message_conversationId, message_from,message_text
FROM MESSAGES
WHERE message_conversationId = 1521521
AND message_from <> 'me'
ORDER by message_Timestamp DESC
I have two tables named "likes" and "comments" and I want to have a table which has counts of likes and comments for each specific user, I wrote following query in SQLite but result is not true for all users, count values for users in both tables are multiple of number of likes and number of comments.
SELECT
likes.liker_name, likes.liker_id, likes.profile_picture ,
COUNT(comments.commenter_name) AS comment_count, COUNT( likes.liker_id) AS like_count
FROM likes
LEFT JOIN comments
ON likes.liker_name = comments.commenter_name
GROUP BY
likes.liker_name
ORDER BY
COUNT( likes.liker_id) DESC
How can I get correct value of count for users that exist in both tables?
The problem is: Some users have comments but no likes, others have likes but no comments, some have both and some have none. Therefore I suggest using a union query and summing that one again
SELECT
u.name, u.id, u.profile_picture,
SUM(u.like_count) AS like_count, SUM(u.comment_count) AS comment_count
FROM (
SELECT
liker_name AS name, liker_id AS id, profile_picture,
COUNT(*) AS like_count, 0 AS comment_count
FROM
likes
GROUP BY
liker_name, liker_id, profile_picture
UNION ALL
SELECT
commenter_name AS name, commenter_id AS id, profile_picture,
0 AS like_count, COUNT(*) AS comment_count
FROM
comments
GROUP BY
commenter_name, commenter_id, profile_picture
) AS u
GROUP BY
u.name, u.id, u.profile_picture
If you have a separate user table you could also left join the likes count and the comments count subqueries to the user table
SELECT
u.name, u.id, u.profile_picture, l.cnt AS like_count, c.cnt AS comment_count
FROM
users u
LEFT JOIN
(SELECT liker_id, COUNT(*) AS cnt
FROM likes
GROUP BY liker_id
) AS l
ON u.user_id = l.liker_id
LEFT JOIN
(SELECT commenter_id, COUNT(*) AS cnt
FROM comments
GROUP BY commenter_id
) AS c
ON u.user_id = c.commenter_id
WHERE l.cnt > 0 OR c.cnt > 0
No matter how you make it, you must count the comments and the likes in separate subqueries. If you count after joining you are summing on a result where records might be duplicated (the ones on the left side) and you are getting the wrong count.
SELECT gameratingstblx245v.gameid,avg( gameratingstblx245v.rating ) as avgrating, count(gameratingstblx245v.rating) as count,gamedata.name ,gamedata.gameinfo
FROM gameratingstblx245v
LEFT JOIN gamedata ON gamedata.id = gameratingstblx245v.game_id
WHERE gameratingstblx245v.game_id=gameratingstblx245v.game_id
GROUP BY gameid
ORDER BY avg( gameratingstblx245v.rating ) DESC LIMIT 0,8
Table gameratingstblx245v - gameid, rating
Rable gamedata - id, gameinfo, name, releasedate
This is the query I am currently using to extract data from two tables gamedata and gameratingstblx245v.... What I am doing here is taking the avg. of all the ratings from table gameratingstblx245v in descending order of their avg. rating and I am also extracting the related info corresponding to the selected gameid's from table gamedata...
Now what I want to extract is the top avg. ratings from game_ratingstblx245v but for the games whose field releasedate from table gamedata is in the last 90 days...
Help would be appreciated..Thanks
Here's how I'd design that query:
SELECT d.id, d.name, d.gameinfo,
AVG(r.rating) AS avgrating, COUNT(r.rating) AS count
FROM gamedata d
LEFT JOIN gameratingstblx245v r ON (d.id = r.game_id)
WHERE d.releasedate BETWEEN NOW() - INTERVAL 90 DAY AND NOW()
GROUP BY d.id
ORDER BY avgrating DESC LIMIT 0,8;